13. Which has the largest atomic radius?
A. fluorine B. chlorine C. bromine
D. a bromine anion with a charge of 1-

Answers

Answer 1

Answer:

bromine

Explanation:


Related Questions

Why does adding salt allow ice to freeze milk?
A.It increases the freezing point
B.Salt is colder than point
C.It increases the boiling point
D.It decreases the freezing point

Answers

Answer:

It increases the freezing point

Explanation:

The salt lowers the temperature at which water freezes. :)

Determine the number of moles in 4.9*10 raise to the power of 24 of Ag

Answers

Answer:

4.5425806678891E+22mol

Explanation:

the property of matter that determines whether or not an electrical current can pass through it

Answers

The answer is electrical conductivity

Check the box under each molecule in the table below that is an isomer of this molecule:

Answers

The branched alkanes in boxes two and three all have molecular formula C6H14 and are isomers of the compound shown.

Isomers are compounds that has the same molecular formula but different structural formulas. Hence, isomers of compounds can be represented by the same molecular formula since they contain the same number of each atom.

The molecule shown has molecular formula C6H14. The branched alkanes in boxes two and three all have molecular formula C6H14 and are isomers of the compound shown.

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Write the symbol for every chemical element that has atomic number less than 13 and atomic mass greater than 17.2 u.

Answers

I’m so sorry don’t know just need the points asap

The results of Rutherford's gold foil experiment gave him the evidence to conclude that the center of an atom was A) called the nucleus. B) neutral and relatively small. C) positively charged and relatively small. D) a densely packed area containing both positive and negative particles.

Answers

Answer:

c)

Explanation:

because alpha particles can go through it

In what way is the Moon like the Earth?
The Moon has volcanoes.
The Moon has an atmosphere.
The Moon has oceans and seas.
The Moon is a solid, rocky body.
PLS ANSWER RIGHT ILL GIVE BRAINLIST :)

Answers

Answer:

The Moon has an atmosphere.

Explanation:

The Moon has an atmosphere, but it is very tenuous. Gases in the lunar atmosphere are easily lost to space. Because of the Moon's low gravity, light atoms such as helium receive enough energy from solar heating so that they escape in just a few hours.

A block has 73 kg is being pushed and accelerated at rate of 10 m/s. what force is being applied to the block?

A-730 N
B-7.3 N
C-7300 N
D-730 Kg

Answers

Answer:

730 N

Explanation:

force =mass×acceleration

force= 73kg × 10 m/s

f=730N

A mixture contains 220 mmHg of CO, 350 mmHg of Ne and 840 mmHg of He. What is the total pressure of the mixture

a
1.86 at
b
1.59 atm

c
1.46 atm

d
none of these

Answers

Considering the Dalton's partial pressure, the correct answer is option a.: the total pressure of the mixture is 1.86 atm.

The pressure exerted by a particular gas in a mixture is known as its partial pressure. So, Dalton's law states that the total pressure of a gas mixture is equal to the sum of the pressures that each gas would exert if it were alone:

[tex]P_{T} =P_{1} +P_{2} +...+P_{n}[/tex]

where n is the amount of gases present in the sample.

This relationship is due to the assumption that there are no attractive forces between the gases.

In this case, a mixture contains 220 mmHg of CO, 350 mmHg of Ne and 840 mmHg of He. The total pressure of the mixture can be calculated as:

[tex]P_{T} =P_{CO} +P_{Ne} +P_{He}[/tex]

[tex]P_{T} =220 mmHg +350 mmHg+840 mmHg[/tex]

Solving:

[tex]P_{T}[/tex]= 1410 mmHg

Being 760 mmHg=1 atm, then:

[tex]P_{T}=1410 mmHgx\frac{1 atm}{760 mmHg}[/tex]

Solving:

[tex]P_{T}[/tex]= 1.86 atm

Finally, the correct answer is option a.: the total pressure of the mixture is 1.86 atm.

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If 3.31 moles of argon gas occupies a volume of 100 L what volume does 13.15 moles of argon occupy under the same temperature and pressure

Answers

Answer:

397 L

Explanation:

Recall the ideal gas law:

[tex]\displaystyle PV = nRT[/tex]

If temperature and pressure stays constant, we can rearrange all constant variables onto one side of the equation:

[tex]\displaystyle \frac{P}{RT} = \frac{n}{V}[/tex]

The left-hand side is simply some constant. Hence, we can write that:

[tex]\displaystyle \frac{n_1}{V_1} = \frac{n_2}{V_2}[/tex]

Substitute in known values:

[tex]\displaystyle \frac{(3.31 \text{ mol})}{(100 \text{ L})} = \frac{(13.15\text{ mol })}{V_2}[/tex]

Solving for V₂ yields:

[tex]\displaystyle V_2 = \frac{(100 \text{ L})(13.15)}{3.31} = 397 \text{ L}[/tex]

In conclusion, 13.15 moles of argon will occupy 397* L under the same temperature and pressure.

(Assuming 100 L has three significant figures.)

as the ionic compound decreases in size, the melting point __
A. increases
B. decreases
c stays the same

Answers

Answer:

A. increase

Explanation:

the smaller the size of the ionic compounds, the more closer they get packed together. This means electrostatic attraction also increases, which means the ionic bonds gets stronger...therefore increases the melting point

The effect of a catalyst is to: change the stoichiometry of the reaction. lower the activation energy of a reaction whereby making it easier for the reactants to get over the energy hump. change the position of the equilibrium. increase the number of collisions between reactants. increase the temperature of the reactants whereby more products are forme

Answers

The effect of a catalyst is

Option B(lower the activation energy of a reaction whereby making it easier for the reactants to get over the energy hump)What is a catalyst

A catalyst allows an alternative reaction pathway that leaves activation energy than the uncatalysed reaction. This does not change the frequency of collision.

Frequency of collision

Frequency of collision depend upon concentration of reactant temperatures

Catalyst on activation energy

Hence, catalyst lowers the activation energy of reaction thereby making it easier for the reactant to get over the energy hump.

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Equation for the incomplete combustion of methanol

Answers

Answer:

The basis for incomplete combustion is that instead of carbon dioxide being produced alongside water, carbon monoxide and carbon is produced instead, the carbon being released as soot. That handily sets the products up for the equation.

And combustion is simply a reaction between a fuel, in this case, methanol and oxygen.

The chemical formula for methanol is CH3OH. Simply write the reactants and products as a chemical equation and balance it, and you have the equation.

Explanation:

Tums is a popular remedy for acid indigestion. A typical Tums tablet contains calcium carbonate mixed with inert substances. When ingested, it reacts with stomach acids (hydrochloric acid) to produce carbon dioxide gas. When a 1.241 g tablet reacted with 43.435 mL of hydrochloric acid, carbon dioxide gas was produced and the final solution weighed 52.122 g. Calculate the number of liters of carbon dioxide gas released. When a 1.241g Tums tablet reacted with 43.435 mL of hydrochloric acid (density: 1.140 g/mL), carbon dioxide gas was produced and the resulting solution weighed 50.571 g. Calculate the mass of carbon dioxide gas released.

Answers

The mass of CO2 obtained in the reaction by stoichiometry is 30.8 g.

The equation of the reaction is;

2HCl(aq) + CaCO3(s) -----> CaCl2(aq) + H2O(l) + CO2(g)

The mass of the HCl reacted is obtained from;

Density = mass/volume

Mass = Density × volume =  1.140 g/mL ×  43.435 mL = 49.5 g

Number of moles of HCl =  49.5 g/36.5 g/mol = 1.4 moles

If 2 moles of HCl reacts produces 1 mole of CO2

1.4 moles of HCl produces x moles of CO2

x = 1.4 moles × 1 mole/ 2 moles = 0.7 moles

Mass of CO2 produced = 0.7 moles  x 44 g/mol = 30.8 g

In the second case, the same volume of acid is used hence the same mass of CO2 is obtained.

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? Which types of batteries are commonly used in laboratory equipments

Answers

Answer:

your question is not very clear but I think the answer is either

Primary (non-rechargeable)

Secondary (rechargeable) or

Lithium-ion battery.

Rechargeable li-ion button cell.

A ramp is at an angle of elevation of 15° . The distance from the top of the ramp to the ground is 20 feet. What is the length of the ramp?

Answers

Answer:

Length of ramp = 77.27ft

Explanation:

Step 1 - Sketch a diagram

Make a line about 15 deg. above the horizontal x-axis. Draw the horizontal and vertical components to form a right triangle. See image if you don’t understand.

Step 2 - Label your diagram

Your triangle creates a 15 deg. angle with the x-axis and we know the vertical distance from the top of the ramp to the ground is 20 ft.

Step 3 - Use trig to make an equation and solve

SOH CAH TOA

I’m this problem we know the angle, know “opposite, and we are solving for the hypotenuse of the triangle. Therefore, it would be easiest to use SOH or sin(theta)= (opp./hyp.) Plug in the numbers and solve for the hypotenuse.

All work is shown in the attached image.

14. Which has the lowest ionization energy?
A. beryllium (Be) B. strontium (Sr) Calcium (Ca) D. magnesium (Mg)

Answers

Answer: B. strontium

Explanation: This is due to electrons being further away from the nucleus in strontium.

Write the IUPAC names for the following compounds.

Answers

Benzine
Bromine
Clorine

What are three Possible overlaps that can occur during bond formation​

Answers

Answer:

The Sigma (σ) Bond

S-S Overlapping. In this kind of overlapping, one 's' orbital from each participating atom undergoes head-on overlapping along the internuclear axis. ...

S-P Overlapping. ...

P-P overlapping.

Need asap thank you

Answers

Answer:

c.boron-11

Explanation:

The atomic mass of boron is 10.81 u.

And 10.81 u is a lot closer to 11u than it is to 10u, so there must be more of boron-11.

To convince you fully, we can also do a simple calculation to find the exact proportion of boron-11 using the following formula:

(10u)(x)+(11u)(1−x)100%=10.81u

Where u is the unit for atomic mass and x is the proportion of boron-10 out of the total boron abundance which is 100%.

Solving for x we get:

11u−ux=10.81u

0.19u=ux

x=0.19

1−x=0.81

And thus the abundance of boron-11 is roughly 81%.

How many moles of chlorine could be produced by decomposing 157g NaCl? 2NaCl --> 2Na+Cl2

Answers

Here is the answer for your question which the mole of chlorine is 1.34

By decomposing 157g of NaCl, approximately 1.35 moles of chlorine can be produced.

To determine the number of moles of chlorine that could be produced by decomposing 157g of NaCl, we need to use the molar mass of NaCl and apply stoichiometry.

The molar mass of NaCl is the sum of the atomic masses of sodium (Na) and chlorine (Cl), which is approximately 22.99 g/mol + 35.45 g/mol = 58.44 g/mol.

Now, we can calculate the number of moles of NaCl:

Moles of NaCl = Mass of NaCl / Molar mass of NaCl

Moles of NaCl = 157 g / 58.44 g/mol

Moles of NaCl ≈ 2.69 mol

According to the balanced equation 2NaCl → 2Na + Cl₂, we can see that for every 2 moles of NaCl, we produce 1 mole of Cl₂.

Therefore, using the stoichiometric ratio, we can calculate the number of moles of chlorine produced:

Moles of Cl₂ = (Moles of NaCl / 2) × 1

Moles of Cl₂ = 2.69 mol / 2

Moles of Cl₂ ≈ 1.35 mol

Thus, by decomposing 157g of NaCl, approximately 1.35 moles of chlorine can be produced.

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A 4.0 L balloon has a pressure of 406 kPa. When the pressure increases to 2,030 kPa, what is the volume? *
0.4 L
0.8 L
0.2 L
1 L

Answers

The new volume when pressure increases to 2,030 kPa is 0.8L

BOYLE'S LAW:

The new volume of a gas can be calculated using Boyle's law equation:

P1V1 = P2V2

Where;

P1 = initial pressure (kPa)P2 = final pressure (kPa)V1 = initial volume (L)V2 = final volume (L)

According to this question, a 4.0 L balloon has a pressure of 406 kPa. When the pressure increases to 2,030 kPa, the volume is calculated as:

406 × 4 = 2030 × V2

1624 = 2030V2

V2 = 1624 ÷ 2030

V2 = 0.8L

Therefore, the new volume when pressure increases to 2,030 kPa is 0.8L.

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Which element gives up its valence electrons most readily?
Bi
Fr
Be
Ar

Answers

Answer:

Fr

Explanation:

I took the test

Carbon has a half-life of 5,730 years and you found a fossil with 4 atoms of Carbon and 12 atoms of
Nitrogen, how old would it be?

a. 0 years old
b. 5,730 years old
c. 11,460 years old
d. 17,190 years old

Answers

Answer:

D. 17,190 years old

help!!!! the relative formula mass (Mr) of sodium fluoride is 42. Use the correct answer frim the box to complete the sentence.​

Answers

Answer:

mole

Explanation:

Since Sodium Chloride is ionic, it cannot be considered a molecule as per the definition of a molecule requires each of its components to be bonded together.

The formula mass of a compound is the mass of its one molecule. Since molecule is the basic unit of a compound. Thus, the relative formula mass in grams is the mass of one molecule.

What is sodium fluoride?

Sodium fluoride is an ionic compound formed by the combination of sodium and fluorine by loss of one electron from sodium to fluorine. The  formula mass of fluorine is calculated from the atomic masses of sodium and fluorine.

Atomic mass of fluorine is 19 g/mol and mass of sodium is 23 g/mol. Here only one sodium and one fluorine is present. Hence the formula mass is 23+ 19 = 42.

This is the mass of one unit of NaF. Thus mass of one sodium fluoride molecule. Where as its molar mass may differ from the formula mass. Since the molar mass is the mass of one mole of the compound NaF. One mole of compound contains 6.02 × 10²³ molecules.

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3. Given 20g of Barium Hydroxide, how many grams of
Ammonium Nitrate would it take for all the Barium Hydroxide
to react? Balance the chemical equation first

Answers

The number of grams of ammonium nitrate (NH₄NO₃) it would take for all the barium hydroxide to react is 18.7g

First, we will write the balanced chemical equation for the reaction

The balanced chemical equation for the reaction is

Ba(OH)₂ + 2NH₄NO₃ → 2NH₄OH + Ba(NO₃)₂

This means, 1 mole of barium hydroxide is required to react with 2 moles of ammonium nitrate

Now, we will calculate the number of moles of barium hydroxide present.

Mass of barium hydroxide (Ba(OH)₂) = 20 g

Using the formula

[tex]Number\ of\ moles = \frac{Mass}{Molar\ mass}[/tex]

Molar mass of Ba(OH)₂ = 171.34 g/mol

∴ Number of moles of Ba(OH)₂ present =[tex]\frac{20}{171.34}[/tex]

Number of moles of Ba(OH)₂ present = 0.116727 mole

Now,

Since 1 mole of barium hydroxide is required to react with 2 moles of ammonium nitrate

Then,

0.116727 mole of barium hydroxide will react with 2 × 0.116727 mole of ammonium nitrate

2 × 0.116727 = 0.233454 mole

∴ Number of moles of NH₄NO₃ required is 0.233454 mole

Now, for the mass of ammonium nitrate (NH₄NO₃) required

From the formula

Mass = Number of moles × Molar mass

Molar mass of NH₄NO₃ = 80.043 g/mol

∴ Mass of NH₄NO₃ required = 0.233454 × 80.043

Mass of NH₄NO₃ required = 18.68636 g

Mass of NH₄NO₃ required ≅ 18.7g

Hence, the number of grams of ammonium nitrate (NH₄NO₃) it would take for all the barium hydroxide to react is 18.7g

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Heart, 5 stars, and Brainiest to first right answer!
Which layer of the atmosphere reflects radio waves back to Earth?
A. Mesosphere
B. Stratosphere
C. Thermosphere
D. Troposphere

Answers

Answer:

Thermosphere

Explanation:

More specifically the ionosphere, since the ionosphere is the lower part of the thermosphere.

Hope this helps!

How is a mixture different from a compound?

Answers

Answer:

A compound is something like atoms coming together as a team, and a mixture is 2 or more substances mixing together.

Explanation:

I think a compound is something that is permanently together and a mixture is something you mix yourself ❤️

How many moles does 205 g of helium,He, contain ?

Answers

Answer:

4.002602

Explanation:

Seems Am Converting Between Grams Helium And Mole.

No. of moles = mass / relative molecular mass
n = m / Mr
n = 205 g / 4 g/mol
n = 51.25 mol


[tex]{ \red {\sf{Define \: Transportational}}}[/tex]
2+x=19
Find x ​

Answers

Answer:

Easy!!

2+17=19

#hope that helps

Answer:

To find the answer you may

2+17=19

Explanation:

so that is the answer I'm sorry,to not give all the solutions

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