Answer:
If Jack is 10 years old and scored a mental age of 8 years old on his IQ test, his IQ score would be 80 using the Terman formula. The Terman formula is commonly used to calculate IQ scores based on the ratio of an individual's mental age to their chronological age. In this case, Jack's mental age is 8 and his chronological age is 10, so his IQ score would be calculated as follows:
IQ = (MA / CA) * 100
= (8 / 10) * 100
= 0.8 * 100
= 80
This means that Jack's cognitive abilities are at the level of an average 8-year-old, even though he is actually 10 years old. His IQ score of 80 falls within the average range of IQ scores, which is typically considered to be between 90 and 110.
Write the equation for the velocity component in the y-direction?
Answer:
The equation for the velocity component in the y-direction is : vy (t)= v(0)Sinθ - gt
a(n) 79 kg person is parachuting and experiencing a downward acceleration of 2.7 m/s2. the mass of the parachute is 4.9 kg.
79 kg person is parachuting and experience a down acceleration of 2.7 m/s2. This is slightly different from the downward acceleration of 2.7 m/s2, which suggests that there are additional forces acting.
The downward force acting on the person while they are parachuting is equal to the person's mass multiplied by the acceleration due to gravity (9.8 m/s2). This can be expressed mathematically as:
= F
= ma
= 79 kg x 9.8 m/s2
= 774.2 N
The mass of the parachute also contributes to the downward force acting on the person. The total downward force acting on the person is equal to the sum of the forces acting on the person and the parachute. This can be expressed mathematically as:
= F total
= F person + F parachute
= 774.2 N + (4.9 kg x 9.8 m/s2)
= 783.54 N
The acceleration of the person and parachute system is equal to the total downward force acting on the system divided by the total mass of the system. This can be expressed mathematically as:
= a
= F total / m total
= 783.54 N / (79 kg + 4.9 kg)
= 7.96 m/s2
Therefore, the acceleration of the person and parachute system is 7.96 m/s2. This is slightly different from the downward acceleration of 2.7 m/s2 that the person is experiencing, which suggests that there are additional forces acting on the system besides the downward force of gravity.
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s it possible to change velocity while moving at a constant speed?absolutely not because they are of the same value; a speed is just a magnitude of a velocity.yes, if acceleration has component parallel to the velocity but has no component perpendicular to the velocity.yes, if acceleration has component perpendicular to the velocity but has no component parallel to the velocity.no, change is velocity will be always followed by the change in speed.
Yes, provided that the acceleration contains components that are parallel to and inversely proportional to the velocity.
Explaining an accelerationAcceleration describes the speed and direction changes in velocity over time. Acceleration refers to the change in speed or direction of an item or point traveling straight forward. Due to the frequent changes in direction, motion on a circle accelerates even while the speed stays the same.
What are the 3 different forms of acceleration?The three different categories of accelerated movements are uniform acceleration, non-uniform acceleration, and average acceleration. When an object moves in a straight path while experiencing equal-interval increases in velocity, this motion is referred to as having uniform acceleration.
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The drawings show three examples of the force with which someone pushes against a vertical wall. In each case the magnitude of the pushing force is the same. Rank the normal forces that the wall applies to the pusher in ascending order (smallest first).1st drawing is a medium angle2nd drawing is a small angle3rd drawing is a large angle (almost 90 degrees and perpendicular to the wall)
The normal forces that the wall applies to the pusher in ascending order are :Normal force in the third drawing (large angle),Normal force in the first drawing (medium angle),Normal force in the second drawing (small angle).
The normal force is the force that an object exerts on another object that is in contact with it. In the case of a person pushing against a wall, the normal force is the force that the wall applies to the person.
The magnitude of the normal force is determined by the angle at which the person is pushing against the wall. For a given magnitude of the pushing force, the normal force will be smaller when the angle is larger and larger when the angle is smaller.
In the first drawing, the angle is medium, so the normal force will be between the normal force in the second and third drawings.
In the second drawing, the angle is small, so the normal force will be larger than the normal force in the first drawing and smaller than the normal force in the third drawing.
In the third drawing, the angle is large, so the normal force will be the smallest of the three.
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A 75 kg man falls off his ladder and hangs motionless from the ceiling by a cord. Determine the net force on the man. (don't forget units)
PLEASE HELPP
The net force on the 75 kg man who falls off his ladder and hangs motionless from the ceiling by a cord is zero.
What is the weight of a body?The weight of a body is the force of gravity acting on the body. The weight of a body acts downward.
Mathematically, the weight of a body is given below as follows:
Weight = m * g
where;
m is the mass of the object
g is the acceleration due to gravity = 10 m/s²
The weight or the force of gravity acting downwards on a 75 kg man that falls off his ladder and hangs motionless from the ceiling by a cord is calculated as follows:
The force of gravity = 75 * 10
The force of gravity = 750 N
The tension on the cord balances the weight of the man and acts in the opposite direction.
Hence, the tension on the cord is equal to 750 N but in the opposite direction.
Net force = weight - tension
Net force = 750 N - 750 N
Net force = 0 N
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Which of the following statements is not true of tornadoes?
a. usually occur along the warm front of a midlatitude cyclone
b. occur most frequently in the spring of the year
c. most common in the Midwest and Great Plains
d. generally move from the southwest toward the northeast
e. associated with cumulonimbus clouds
The comments below about tornadoes are untrue; they do not typically occur near the warm front associated with a midlatitude cyclone.
Which of these three tornado kinds are they?There are several different kinds of tornadoes, such as multiple vortex tornadoes, landspouts, and waterspouts. Waterspouts as characterized by a wind current that spirals into the shape of a funnel and connects to a sizable cumulus of cumulonimbus cloud.
what is The causes of tornadoes?Warm, humid air rises inside thunderclouds while chilly air descends, bringing with it rain or hail and rain. Air currents within the cloud may spin as a result of these circumstances. Despite their initial horizontal orientation, the whirling currents have the ability to change vertical, drop from the cloud, and eventually form a tornado.
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a plane files from point a to point b. b is 1207 km west 957 km south a. sketch a picture of this situation. what is the total displacement of the plane
The closest distance and angle to this question are 1540.35 kilometers and 38.4 ° S. (depending on how you rounded).
What is Displacement and distance are they equivalent?There is a common misconception that distance & displacement are simply two different terms for the same thing. But separation separates the concepts of distance and displacement. The total distance covered by an object is always larger than the movement between those two sites, even if it changes direction throughout the course of its voyage.
The displacement is which one, which?The smallest (straight line) length between a body's starting position and its final location—represented by an arrow pointing from starting spot to final position—is referred to as a brain's displacement when it moves through one position to another.
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As a person breathes, during the inhale part of the cycle air moves down the windpipe (bronchus) and through a constriction where the air speed doubles. If the air is traveling 46 cm/s before the constriction and we treat air as an incompressible fluid, determine the pressure drop in the constriction. Use the density of air as 1.29 kg/m3. in Pa
If the air is traveling 46 cm/s before the constriction and we treat air as an incompressible fluid, the pressure drop in the constriction is 106.8 Pa.
If we treat air as an incompressible fluid, the pressure drop in the constriction can be determined using Bernoulli’s equation. Bernoulli’s equation states that the sum of the pressure, kinetic energy, and potential energy of a fluid stream is constant.
The equation can be expressed as:
P1 + (1/2)ρv12 + ρgh1 = P2 + (1/2)ρv22 + ρgh2
Where P1 and P2 are the pressures before and after the constriction, ρ is the density of the fluid, v1 and v2 are the velocities before and after the constriction, g is the acceleration due to gravity, and h1 and h2 are the heights before and after the constriction.
Given that the air velocity before the constriction is 46 cm/s and the density of air is 1.29 kg/m3, we can calculate the pressure drop in the constriction as follows:
P1 + (1/2)*(1.29 kg/m3)*(46 cm/s)2 + (1.29 kg/m3)*(9.8 m/s2)*h1 = P2 + (1/2)*(1.29 kg/m3)*(92 cm/s)2 + (1.29 kg/m3)*(9.8 m/s2)*h2
Since h1 and h2 are equal and the acceleration due to gravity is constant, we can simplify the equation to:
P1 + (1/2)*(1.29 kg/m3)*(46 cm/s)2 = P2 + (1/2)*(1.29 kg/m3)*(92 cm/s)2
Substituting the given numerical values, we get
P1 + (1/2)*(1.29 kg/m3)*(46 cm/s)2 = P2 + (1/2)*(1.29 kg/m3)*(92 cm/s)2
P1 + 35.6 Pa = P2 + 142.4 Pa
Therefore, the pressure drop in the constriction is 106.8 Pa.
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