Answer:
[tex]y_1=0,y_2=\frac{3}{2},y_3=\frac{3}{2}[/tex]
Step-by-step explanation:
[tex]4y^3-9y=0[/tex]
[tex]y(4y^2-9)=0[/tex]
[tex]y(2y-3)(2y+3)=0[/tex] <-- Difference of squares
[tex]y_1=0,y_2=\frac{3}{2},y_3=\frac{3}{2}[/tex]
Please help my assignment
PLZ HELP!!! I WILL GIVE CORRECT ANSWER BRAINLIEST!!!
QUESTION: Find three consecutive integers where the sum of the first and the twice second is 35.
Answer:
11, 12, 13
Step-by-step explanation:
let's put the first number of the three as a:
a; a+1; a+2
The sum of the first and the twice second is 35 means:
a + 2(a+1) = 35
a + 2a + 2 = 35
3a = 33
a=11
now that we know a, we just need to add 1 and 2 as they are consecutive:
11, 12, 13
graph y + 2 = -3/4 (x+4)
Answer:
Use a website called desmos and type in y=-3/4(x+4)-2
Step-by-step explanation:
1) isolate y by subtracting 2 on both sides
y=-3/4(x+4)-2
Answer:
Clue: two points : (0,-5) ( 4 , -8)
Step-by-step explanation:
Look at the graph.
-3 (-3 - n) - 4 = 3n + 5
[tex]-3 (-3 - n) - 4 = 3n + 5\\\\\implies 9+3n -4 = 3n+5\\\\\implies 5 +3n = 3n+5\\\\\text{The equation is true for all values of n.}[/tex]
The triangles shown bellow must be congruent?
True or False?
please help asap rn thank you
Answer:
1 is acute
2 is a right triangle
3 is obtuse
Step-by-step explanation:
A 90 degree angle will be written as a box in the corner. Any angle less than 90 is acute, and any angle more than 90 is obtuse.
lf the exchange rate of 1 dollar is Rs 72.45. how many dollars exchanged for Rs 1449 ?
Step-by-step explanation:
solution
here,
1 dollar = rs 72.45
or, 1/72.45 dollars= rs 1
or, rs 1 = 1/72.45 dollars
now,
rs 1449= 1449/72.45 dollars
or,rs1449= 20 dollars
therefore, 20 dollars can be exchanged for rs 1449
Cube A has an edge length of 3 inches. Cube B has an edge length double that of Cube A.
What is the volume, in cubic inches, of Cube B?
A. 27in^3
B. 36in^3
C. 216in^3
D. 729in^3
Answer:
216
Step-by-step explanation:
Cube A volume
3*3*3=27
Cube B volume
6*6*6=216
Edge length of cube B=2(3)=6in
Volume:-
[tex]\\ \sf\longmapsto V=(6)^3[/tex]
[tex]\\ \sf\longmapsto V=6(6)(6)[/tex]
[tex]\\ \sf\longmapsto V=216in^3[/tex]
20x^5 y^3 + 8x^6 y^3 - 4x^5 y^2
———————————————
4x^5 y^2
Answer:
1) 4x^{5} y^{2} (5y+2xy-1)
2) Implied to have no solution based on given context.
Step-by-step explanation:
Problem 1:
1) Find the Greatest Common Factor (GCF).
[tex]GCF=4x^{5} y^{2}[/tex]
2) Factor out the GCF. (Write the GCF first. Then, in parentheses, divide each term by the GCF.)
[tex]4x^{5}y^{2} (\frac{20x^{5} y^{3} }{4x^{5}y^{2} } +\frac{8x^{6}y^{3} }{4x^{5} y^{2} } +\frac{-4x^{5} y^{2} }{4x^{5} y^{2} } )[/tex]
3) Simplify each term in parentheses.
[tex]4x^{5} y^{2} (5y+2xy-1)[/tex]
Problem 2:
From the way the problem is given, there is no solution.
Please help me on this!!! I would appreciate it so much!!!
2 2/6 is equivalent to what?
A helicopter starting on the ground is rising directly
into the air at a rate of 25 ft/sec. You are running on the
ground starting directly under the helicopter at a rate of 10
ft/sec. What is the rate at which the distance between you and the helicopter is changing when the helicopter has risen to a height of 60 ft in the air, assuming that, initially, it was 30 ft above you?
I want to understand how any why this is solved. So images/diagrams, detailed step by step breakdowns solutions are VERY much appreciated. Thanks!
Answer:
Oook, quick setup: pick a cartesian plane, be [tex](0;y(t))[/tex]the position of the helicopter as time passes, and [tex](x(t);0)[/tex] your position as you start running. In my horrible sketch, the green line is the distance when you start running, the red line is the distance you need, in general what you want is to move one end of the segment up, the other right, and stretch it.
That distance is easily found with the formula for the distance between two points in the plane, or [tex]d=\sqrt{(\Delta x)^2+(\Delta y)^2}= \sqrt{x^2(t)+y^2(t)}[/tex] (playing a bit with the squares). At this point we need to write down expressions for both [tex]x(t), y(t)[/tex] and find at what value of t we need to evaluate our distance.
For the sake of semplicity, let's start measuring times the moment you start running. Since speed is constant, both expressions will be of the form [tex]s=vt+s_0[/tex]
The equation for the runner becomes simply [tex]x(t)=10t[/tex], since you haven't moved until the heli is high enough.
The equation of the helicopter is [tex]y=25t+30[/tex] since the heli is 30ft above ground when you start running.
Finally, we need to know how many seconds have passed when the heli is at 60 ft above ground. that happens when [tex]60=25t+30 \rightarrow t=\frac{30}{25} = 1.20s[/tex]. in this time, you are at [tex]x(1.2)=10(1.2)=12ft[/tex] from the origin.
Plugging it in the distance formula you get: [tex]\sqrt{12^2+60^2}= \sqrt{144+3600}=4\sqrt {234}\approx 61.2ft[/tex]
Why does a rectangle with different side lengths have only 2 lines of symmetry?
A.
all four angles are congruent, and all four sides are congruent
B.
all four angles are congruent, and opposite sides are congruent for a horizontal and diagonal line of reflection
C.
all four angles are congruent, and opposite sides are congruent for a horizontal and vertical line of reflection
D.
all four angles are congruent, and opposite sides are congruent for two diagonal lines of reflection that cut through different angles
Answer:
C. all four angles are congruent, and opposite sides are congruent for a horizontal and vertical line of reflection
Step-by-step explanation:
A. isn't correct because all four sides aren't congruent, only the pair of opposite sides are congruent. Sense only opposite side are congruent you can only reflect the opposite sides onto each other and not diagonally meaning B. and D. are incorrect leaving C. all four angles are congruent, and opposite sides are congruent for a horizontal and vertical line of reflection as the correct answer
What’s the y-intercept
Y-14=6(x-2.5)
Answer:
[tex]y=-1[/tex]
Step-by-step explanation:
[tex]y-14=6(x-2.5)[/tex]
[tex]y-14=6(0-2.5)[/tex]
[tex]y-14=6(-2.5)[/tex]
[tex]y-14=-15[/tex]
[tex]y=-1[/tex]
According to the histogram of travel times to work from the US 2000 census (Page 6 of "Journey to Work: 2000"), roughly what percentage of commuters travel more than 45 minutes?
Histograms are used to represent data, where the length of each bar represents the frequency of the data element
The histogram is not given; So, I will give a general explanation.
Assume that the number of commuters that travel more than 45 minutes is 450, while the total number of commuters surveyed is 500.
The percentage of commuters that travel more than 45 minutes is the quotient of the commuters that travel more than 45 minutes and the total number of surveyed commuters.
So, we have:
[tex]\%Percentage = \frac{450}{500}[/tex]
Divide 450 by 500
[tex]\%Percentage = 0.9[/tex]
Express as percentage
[tex]\%Percentage = 90\%[/tex]
Hence, the percentage of commuters that travel more than 45 minutes is 90%
Read more about histograms at:
https://brainly.com/question/2776232
need to evaluate integral pls help me
Answer:
[tex]\displaystyle \int\limits^2_0 {f(x)} \, dx = \frac{159}{10}[/tex]
General Formulas and Concepts:
Calculus
Integration
IntegralsIntegral NotationIntegration Rule [Reverse Power Rule]: [tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]
Integration Rule [Fundamental Theorem of Calculus 1]: [tex]\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)[/tex]
Integration Property [Multiplied Constant]: [tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]
Integration Property [Addition/Subtraction]: [tex]\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx[/tex]
Integration Property [Splitting Integral]: [tex]\displaystyle \int\limits^c_a {f(x)} \, dx = \int\limits^b_a {f(x)} \, dx + \int\limits^c_b {f(x)} \, dx[/tex]
Step-by-step explanation:
Step 1: Define
Identify.
[tex]\displaystyle f(x) = \left \{ {{9x^9 ,\ 0 \leq x \leq 1} \atop {4x^3 ,\ 1 \leq x \leq 2}} \right.[/tex]
[tex]\displaystyle \int\limits^2_0 {f(x)} \, dx = \ ?[/tex]
Step 2: Integrate
[Integral] Rewrite [Integration Property - Splitting Integral]: [tex]\displaystyle \int\limits^2_0 {f(x)} \, dx = \int\limits^1_0 {f(x)} \, dx + \int\limits^2_1 {f(x)} \, dx[/tex][Integrand] Substitute in function: [tex]\displaystyle \int\limits^2_0 {f(x)} \, dx = \int\limits^1_0 {9x^9} \, dx + \int\limits^2_1 {4x^3} \, dx[/tex][Integrals] Rewrite [Integration Property - Multiplied Constant]: [tex]\displaystyle \int\limits^2_0 {f(x)} \, dx = 9 \int\limits^1_0 {x^9} \, dx + 4 \int\limits^2_1 {x^3} \, dx[/tex][Integrals] Integration Rule [Reverse Power Rule]: [tex]\displaystyle \int\limits^2_0 {f(x)} \, dx = 9 \bigg( \frac{x^{10}}{10} \bigg) \bigg| \limits^1_0 + 4 \bigg( \frac{x^4}{4} \bigg) \bigg| \limits^2_1[/tex]Integration Rule [Fundamental Theorem of Calculus 1]: [tex]\displaystyle \int\limits^2_0 {f(x)} \, dx = 9 \bigg( \frac{1}{10} \bigg) + 4 \bigg( \frac{15}{4} \bigg)[/tex]Simplify: [tex]\displaystyle \int\limits^2_0 {f(x)} \, dx = \frac{159}{10}[/tex]Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Integration
Answer:
Step-by-step explanation:
[tex]\int\limits^1_0 {9x^9} \, dx +\int\limits^2_1 {4x^3} \, dx[/tex]
=[tex]\frac{9x^{10}}{10} |_0^1 + x^4|_1^2[/tex]
[tex]=\frac{9}{10}+2^4 -1 = 15\frac{9}{10}[/tex]
Statement of cash flows (partial)
what is the domain and range of : {(2,4) (3'6) (4,8) (5,10) (6,12)}
Answer:
2,3,4,5,6 is the domain
4,6,8,10,12 is the range
Step-by-step explanation:
Answer:
The domain is {2,3,4,5,6} and the range is {4,6,8,10,12}.
Step-by-step explanation:
whats the solution.?
Answer:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
y-(x-4)=0
STEP
1
:
Equation of a Straight Line
1.1 Solve y-x+4 = 0
Tiger recognizes that we have here an equation of a straight line. Such an equation is usually written y=mx+b ("y=mx+c" in the UK).
"y=mx+b" is the formula of a straight line drawn on Cartesian coordinate system in which "y" is the vertical axis and "x" the horizontal axis.
In this formula :
y tells us how far up the line goes
x tells us how far along
m is the Slope or Gradient i.e. how steep the line is
b is the Y-intercept i.e. where the line crosses the Y axis
The X and Y intercepts and the Slope are called the line properties. We shall now graph the line y-x+4 = 0 and calculate its properties
Step-by-step explanation:
Write the word sentence as an equation. Then solve.
The sum of a number a and 12 is -6.
Answer:
a + 12 = -6 , a = -18
Step-by-step explanation:
Hi there!
the first half of the statement says “the *sum* of a number a and 12, so we can write that as a+12. The second half of the statement says that the sum of both of those values is -6, meaning that a + 12 = -6. Knowing this, we can now solve. In order to isolate a, subtract 12 from both sides of the equation. You will be left with a = -18.
Hope this helps!
Wiebe Trucking. Inc. is planning a new warehouse to serve the west. Denver, Santa Fe, and Salt Lake City are under consideration. For each location, annual fixed costs (rent, equipment. and Insurance) and average variable costs per shipment (labor, transportation and utilities) are listed in the following table. Sales projection is range from 550,000 to 600,000 shipments per year.
a. Plot the total cost curves for all the locations on a single graph.
b. Which city provides the lowest overall costs?
The total cost curve shows the cost of total shipment from the different
cities.
a. Please find attached the graph of the total cost to quantity of shipment created with MS Excel.b. The city that provides the lowest overall cost is; Salt Lake City.Reasons:
The given parameters are;
The number of shipment per = From 550,000 to 600,000 per year
The given table is presented as follows;
[tex]\begin{tabular}{|l|c|c|c|}Location&Annual Fixed Costs&Variable Cost \\Denver&\$5,000,000&\$4.65 \\Santa Fe&\$4,200,000&\$6.25\\Salt Lake City&\$3,500,000&\$7.25\end{array}\right][/tex]
a. Required:
The plot total cost curve for the locations on a single graph.
Solution:
Please find attached the graph of the total cost curves created with MS Excelb. Required:
The city that provides the lowest overall cost.
Solution:
The two cities with the lowest overall costs are Denver and Salt Lake City.
From the total cost curve, the area under the curves are;Area under the curve for Denver;
(7557500 + 7790000) ÷ 2 × 50,000 = 383687500000
Area under the curve for Salt Lake City
(7487500 + 7850000) ÷ 2 × 50,000 = 383437500000
Therefore;
Salt Lake City provides the lowest overall costs.Learn more about total cost curves here:
https://brainly.com/question/4888738
Alexandra was out at a restaurant for dinner when the bill came. She wanted to leave a tip of 13%. What number should she multiply the cost of the meal by to find the total plus tip in one step?
Answer:
x = Total meal cost
y = Total cost-plus tip
113% * x = y
Alyssa’s bank charges $0.15 for each check written, $0.25 per ATM transaction, and a monthly fee to maintain a checking account. The table shows Alyssa’s checking account activity for December.
HLEPPPP huryyyyyyy
Answer:
Correct answer: 2.25
given 6x+5y=12 find the equation of the line parallel to it passing through (1,10).
Answer:
y = -6/5x+56/5
Step-by-step explanation:
A random sample of 25 boxes of cereal have a mean of 372.5grams and a standard deviation of 15 grams. Does an average box of cereal contain more than 368 grams of cereal? Test hypothesis at the 5% significance level, outline all steps involved. (9mks)
Using the t-distribution, it is found that since the test statistic is less than the critical value for the right-tailed test, there is not enough evidence to conclude that an average box of cereal contain more than 368 grams of cereal.
At the null hypothesis, it is tested if the average box of cereal does not contain more than 368 grams, that is:
[tex]H_0: \mu \leq 368[/tex]
At the alternative hypothesis, it is tested if it contains, that is:
[tex]H_1: \mu > 368[/tex]
We have the standard deviation for the sample, hence, the t-distribution is used to solve this question.
The test statistic is given by:
[tex]t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}[/tex]
The parameters are:
[tex]\overline{x}[/tex] is the sample mean. [tex]\mu[/tex] is the value tested at the null hypothesis. s is the standard deviation of the sample. n is the sample size.In this problem, the values of the parameters are: [tex]\overline{x} = 372.5, \mu = 368, s = 15, n = 25[/tex].
Hence, the value of the test statistic is:
[tex]t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}[/tex]
[tex]t = \frac{372.5 - 368}{\frac{15}{\sqrt{25}}}[/tex]
[tex]t = 1.5[/tex]
The critical value for a right-tailed test, as we are testing if the mean is greater than a value, with a significance level of 0.05, with 25 -1 = 24 df, is of [tex]t^{\ast} = 1.71[/tex].
Since the test statistic is less than the critical value for the right-tailed test, there is not enough evidence to conclude that an average box of cereal contain more than 368 grams of cereal.
You can learn more about the use of the t-distribution to test an hypothesis at https://brainly.com/question/13873630
A shipment contains 25 defective items and 100 nondefective items. Two items are randomly chosen in succession without replacement. Find the probability that both items are defective. 25) ______ A) B) C) D) E) none of these
Answer:
non of these because you are a good friend and look at the house to you nanu you nanu to get the house ☺️ to get well and
Write the expression for the following situation: Roger has 5 toy cars. His sister gives
himxmore for his birthday. He wants to find his totd
solve: s=4 + square rooted s+5
Round 67 to the nearest hundred. Enter your answer in the box below.
in the pediatric unit of a hospital has 165 beds how many are there if each room holds 3 beds
Answer:
There are 55 rooms
Step-by-step explanation:
There are 165 beds in the hospital. Each room contains 3 beds. In order to find the number of beds per room, take the total number of beds and divide it by the number of rooms in each bed. 165/3=55. There are 55 rooms in the hospital, all containing 3 beds.
Hope this helps!