500 grams of an unknown substance gains 23000 J of heat as it is heated from a temperature of 250C to 1250C. Using mathematical computation and the chart below, determine the identity of the unknown substance.

Answer:

a chart

Explanation:

a chart a chart is the answer

Answer:

The solution to this question can be defined as follows:

Explanation:

The complete question is defined in the attached file.

[tex]W^{180}_{74} \to He^{4}_{2} + Hf^{176}_{72}[/tex]

Here:

[tex]W= Tungsten-180\\\\Hf =Hafnium\\\\He = \alpha \ particle\\\\[/tex]

Answer:

Water, wind, ice, and gravity

Explanation:

I took the quiz ;)

Answer:

The Nucelous helps prevent bad cells in

Explanation:

Answer: Matter is heated, and its particles spread out more

Explanation:

Thermal expansion occurs when there's an expansion of an object or material or when an object becomes bigger because of a rise in its temperature. This brings about the faster movement of the heated molecules and the atoms spreading out.

Therefore, the cause and effect of thermal expansion will be that when matter is heated, and its particles spread out more.

Answer:

5.0g/cm^3

Explanation:

Since we have the mass of the wood (25.0g) and the volume of the wood (5.0cm^3), can use the formula for density to answer this question.

Density=mass/density

Density=25.0g/5.0cm^3

Density=5.0g/cm^3

Therefore, the density of the piece of wood is 5.0g/cm^3.

I hope this helps!

Answer:

the ability to be dissolved, especially in water.

Explanation:

Answer:

fossil layers

Explanation:

Answer:

a. 28.5 min

Explanation:

The computation of the number of minutes would it take to plate out is as follows:

Cu+2 +2e [tex]\rightarrow[/tex]Cu

 The two moles of electrons could be generated for the copper i.e. deposited

Now

moles of copper is

= 4.5 ÷ 63.5

= 0.071

The 63.5 represents the atomic copper weight

Now mole of electrons deposited is

= 0.071 × 2

= 0.142

Now

quantitiy of electricity needed

= moles of electrons deposited × 96500

= 0.142 × 96500

= 13703 coulums

As per electricity quantity needed

=  current ×  time(seconds)

= 13703 = 8 × t

t = 13703 ÷ 8

= 1713 seconds

= 1713 ÷ 60 minutes

=28.5 min

hence, the correct option is a.

Answer:

[tex]M=2.24M[/tex]

Explanation:

Hello!

In this case, since the molarity and volume of the solutions are given, we are able to compute the moles of chloride ions as they are present in NaCl only:

[tex]n_{Cl^-}=3.00L*3.74\frac{molNaCl}{L}*\frac{1molCl^-}{1molNaCl} =11.22molCl^-[/tex]

Next, since the mixing of solution A and B lead to a volume of 5.00 L, the concentration of chloride ions turns out:

[tex]M=\frac{11.22mol}{5.00L}=2.24M[/tex]

Best regards!

Answer:

Of oxygen would be 6 moles (4).

Explanation:

Since it is in a bracket you have to multiply 3 and tge 2 to get 6 oxygens.

Answer:24 atoms

Explanation:

Answer: 24 atoms

Answer and Explanation:

There are 24 atoms in one molecule of C6 H12 06. This chemical compound has 6 atoms of carbon, 12 atoms of hydrogen, and 6 atoms of oxygen.

Hope this helps.... Stay safe and have a Merry Christmas!!!!!!! :D

Answer:

It was the last element first discovered in nature, rather than by synthesis. Outside the laboratory, francium is extremely rare, with trace amounts found in uranium and thorium ores, where the isotope francium-223 continually forms and decays

Answer:

6.50 mol

Explanation:

The question is incomplete but I looked it up on the web.

How many moles of water are produced when 3.25 moles of CO₂ are formed during the combustion of methyl alcohol (CH₃OH)?

Step 1: Write the balanced equation

2 CH₃OH +  3 O₂ → 2 CO₂ + 4 H₂O

Step 2: Establish the appropriate molar ratio

According to the balanced equation, the molar ratio of CO₂ to H₂O is 2:4.

Step 3: Calculate the moles of water formed with 3.25 moles of carbon dioxide

We will use the established molar ratio.

3.25 mol CO₂ × (4 mol H₂O/ 2 mol CO₂) = 6.50 mol H₂O

Answer:

A. Hund's rule has been violated

Explanation:

There must be one electron with the same spin in each orbital of the same energy before you can put two in the same orbital. In the photo, the 2s sublevel is completely filled before the 1s sublevel (if anything the 1s should have an up spin and down spin, with the 2s having one up spin).

From the figure , it can be concluded that Hund's rule is violated as 1s sub shell is not completely filled before moving to the 2s sub shell.

Hund's rule of maximum multiplicity is an atomic rule which is based  on the observation of atomic spectra and is used for prediction of ground state of an atom or molecule which  have one or more open electronic shells.

It states that, for a given electronic configuration  lowest energy term is the one  which has greatest value of multiplicities of spin. It implies to the fact  that if two orbitals are present which are of equal energy, electrons will occupy them singly before pairing of electrons take place.

The rule finds tremendous use in atomic chemistry,spectroscopy and quantum chemistry.

Learn more about Hund's rule here:

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Answer:

The eight protons in oxygen atom's nucleus will exert more force than nitrogen's seven electrons. Also, oxygen has same number of shells as nitrogen. Thus electrons in oxygen atom will be closer to nucleus than in the case of nitrogen. When electrons are closer it means atomic radius is smaller.

Hope this helps! :)

here's the answers.................

Answer:6.12 x 10¹⁴ s⁻¹

Objects get their colors from reflecting only certain wavelengths when hit with white light. Light reflected from a green leaf is found to have a wavelength of 4.90 x 10⁻⁷ m. What is the frequency of the light?

Explanation:

Answer: 6.12 x 10¹⁴ s⁻¹

Explanation:

Answer:

Meh i want to play

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:)

Answer: yeah sure lad

Explanation:

Answer:

Explanation:b

Answer:

[tex]M_2=2.15M[/tex]

Explanation:

Hello!

In this case, since the dilution processes are characterized by the addition of extra solvent, in this case water, to an initial solution in order to decrease the concentration of the solute, in this case sugar; as water is added, the moles of sugar remain unchanged, so the following equation can be written:

[tex]n_1=n_2\\\\M_1V_1=M_2V_2[/tex]

Whereas 1 accounts for the initial 250.0 mL of 4.00 M sugar and 2 for the concentration at the new volume which is:

[tex]V_2=250.0mL+216.1mL=466.1mL[/tex]

Thus, the final concentration is:

[tex]M_2=\frac{M_1V_1}{V_2} =\frac{250.0mL*4.00M}{466.1mL} \\\\M_2=2.15M[/tex]

Best regards!

Answer:

it could by blade knife

Explanation:

fingernail has hardness 2.5; copper penny, about 3.5; a knife blade, 5.5

Answer:  lessons and benefits can seem removed from everyday life. ... If they determine a site is significant, it is ... CRM exists because legislators and their con- ... romance of excavation and discovery of the past for ... Archaeology permits intensive study of a single culture over time, removing the myth

Answer:

It is an amine; it contains a nitrogen atom that will allow nitrogen-hydrogen bonds to form while in water.

Explanation:

The solubility of amines owes largely to the electronegativity difference between nitrogen and hydrogen. Remember that when hydrogen is bonded to highly electronegative element such as nitrogen, intermolecular hydrogen bonding is possible with water molecules. This explains the greater solubility of amines in water.

Ether molecules do have an oxygen atom, however, and engage in hydrogen bonding with water molecules to a lesser extent compared to amines.

Also, amines participate in some acid-base reactions that lead to the formation of diethylammonium hydroxide, an ion which leads to a greater solubility of amines compared to an ether.

Hence, compound A is an amine.

Answer:

0.166M

Explanation:

In a neutralization, the acid, H₂SO₄, reacts with a base, KOH, to produce a salt, K₂SO₄ and water. The reaction is:

H₂SO₄ + 2KOH → K₂SO₄ + 2H₂O

To solve this problem, we need to determine moles of H2SO4 and moles of KOH that reacts to find the moles of sulfuric acid that remains after the reaction:

Moles H2SO4:

0.650L * (0.430mol /L) = 0.2795moles H2SO4

Moles KOH:

0.600L * (0.240mol / L) = 0.144 moles KOH

Moles of sulfuric acid that reacts with 0.144 moles of KOH are:

0.144 moles KOH * (1mol H2SO4 / 2 mol KOH) = 0.072 moles of H2SO4 react.

And remain:

0.2795moles H2SO4 - 0.072moles H2SO4 = 0.2075 moles of H2SO4 reamains.

In 0.650L + 0.600L = 1.25L:

Molar concentration of sulfuric acid:

0.2075 moles of H2SO4 / 1.25L =

Answer:

ExplanationIt is moving from 4s to 8s at a constant speed of 4 cm:

Answer:

Boiling points increase as the number of carbons is increased.

Explanation:

The addition of solutes or other substances usually changes the boiling point. Additionally, changing the pressure on a liquid changes its boiling point. Sugar, salt or other non-volatile solutes in water will usually make the boiling point higher.

The relative strength of the four intermolecular forces is: Ionic > Hydrogen bonding > dipole dipole > Van der Waals dispersion forces. The influence of each of these attractive forces will depend on the functional groups present. Boiling points increase as the number of carbons is increased.

Answer:

Q = 802.6 J

Explanation:

Given data:

Specific heat capacity of water = 4.18 J/g.°C

Mass of water = 12 g

Initial temperature = 23°C

Final temperature = 39°C

Heat required = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 39°C - 23°C

ΔT = 16 °C

Q = 12 g× 4.18 J/g.°C × 16 °C

Q = 802.6 J

Answer:

It's C because Metamorphic rocks were once igneous rocks. And, because Gneiss which is a Metamorphic rock has crystals inside of it.

Different rock types appear during rock formation. The best description of foliated metamorphic rocks is that;

Due to the pressure and heat that is exerted on some rock types, there is an alignment or foliation of rocks. The appearance can be described as ribbon-like.

The examples of rocks that fall under this classification are slate, phyllite, gneiss, and schist.

The non-foliated rocks do not show any alignment in their minerals. Examples are; quartzite, marble, and novaculite.

Summarily, option B best describes a foliated metamorphic rock.

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