Answer:
1. Empirical formula => C₂H₃O
2. Molecular formula => C₆H₉O₃
Explanation:
From the question given above, the following data were obtained:
Mass of compound = 50 g
Mass of Carbon = 24.66 g
Mass of Hydrogen = 3.43 g
Molecular weight of compound = 146.0 amu
Empirical formula =?
Molecular formula =?
Next, we shall determine the mass of oxygen in the compound. This can be obtained as follow:
Mass of compound = 50 g
Mass of C = 24.66 g
Mass of H = 3.43 g
Mass of O =?
Mass of O = mass of compound – ( mass of C + mass of H)
= 50 – (24.66 + 3.43)
= 50 – 28.09
= 21.91 g
1. Determination of the empirical formula.
Mass of C = 24.66 g
Mass of H = 3.43 g
Mass of O = 21.91 g
Divide by their molar mass
C = 24.66 / 12 = 2.055
H = 3.43 / 1 = 3.43
O = 21.91 / 16 = 1.369
Divide by the smallest
C = 2.055 / 1.369 = 2
H = 3.43 / 1.369 = 3
O = 1.369 / 1.369 = 1
Therefore, the empirical formula of the compound is C₂H₃O
2. Determination of the molecular formula.
Molecular weight of compound = 146.0 amu
Empirical formula => C₂H₃O
Molecular formula =?
Molecular formula = [C₂H₃O]ₙ = molecular weight
Thus,
[C₂H₃O]ₙ = 146
[(12×2) + (3×1) + 16]n = 146
[24 + 3 + 16]n = 146
43n = 146
Divide both side by 43
n = 146 / 43
n = 3
Molecular formula = [C₂H₃O]ₙ
Molecular formula = [C₂H₃O]₃
Molecular formula = C₆H₉O₃
Which waves are blocked by the atmosphere? A. gamma rays B. visible light C. radio waves D. infrared waves
Answer: look at the explanation and try to work it
Explanation: in contrast, our atmosphere blocks most ultraviolet light (UV) and all X-rays and gamma-rays from reaching the surface of Earth. Because of this, astronomers can only study these kinds of light using detectors mounted on weather balloons, in rockets, or in Earth-orbiting satellites.
According to one acid-base theory, water can act as a base because a water molecule can
1) donate an H+ ion
2) accept an H+ ion
3) donate an H- ion
4) accept an H- ion
Answer:
1) donate an H+ ion
Explanation:
option 1 is correct
If the temperature decreases, then the pressure will
What is the [OH-] in a solution if the [H*] = 1.2 x 10-3 M?
We know that [OH⁻] * [H⁺] = 10⁻¹⁴
plugging the value of [H⁺]
[OH⁻] * 1.2 * 10⁻³ = 10⁻¹⁴
[OH⁻] = 10⁻¹⁴ * (10³/1.2)
[OH⁻] = 833.3 * 10⁻¹⁴
[OH⁻] = 8.33 * 10⁻¹²
why the environment in most communities continue to be dirty 2×8
molar absorptivity!
Us Aniline. CH, NH, when reacted with picric acid gives a derivative with a molar ab-
sorptivity of 13 cm E' lat 359 7. What would be the absorbance of a 1.00 x
10" solution or reacico aniline in a 1.00-cm cell? Al 25
Answer:
baba
Explanation:
ndjshddjdjshshshsushs
write 5 acid and 5 akalis
Answer:
5 Acids
Chemical
- Hydrochloric acid in gastric juice
- Sulphuric acid
- Nitric acid
- Uric acid
- Acetic acid
Household
- Vinegar
- Lemon
- Milk
- Batteries
- Soft drinks
5 Alkali
Household
- Dishwashwer soaps
- Detergents
- Toothpaste
- Oven cleaner
- Alkaline batteries
- Sodium bicarbonate
Chemicals
- Sodium hydroxide or lye
- Calcium carbonate (limestone)
- Ammonium hydroxide
- Calcium hydroxide
What are quarks?
A. Particles that bind gluons together within the nucleus
B. Radioactive material that is emitted from a nucleus
C. Subatomic particles that make up protons and neutrons.
D. Fundamental forces acting between two pieces of matter
Answer:
D. Fundamental forces acting between two pieces of matter
Answer:
D. Fundamental forces acting between two pieces of matter
Write a balanced chemical equation for the reaction. Na2CO3Na2CO3 and AgNO3AgNO3 Express your answer as a chemical equation. Identify all of the phases in your answer.
Answer: A balanced chemical equation for the reaction between [tex]Na_{2}CO_{3}[/tex] and [tex]AgNO_{3}[/tex] is [tex]Na_{2}CO_{3}(aq) + 2AgNO_{3}(aq) \rightarrow Ag_{2}CO_{3}(s) + 2NaNO_{3}(aq)[/tex].
Explanation:
The reaction equation between [tex]Na_{2}CO_{3}[/tex] and [tex]AgNO_{3}[/tex] is as follows.
[tex]Na_{2}CO_{3}(aq) + AgNO_{3}(aq) \rightarrow Ag_{2}CO_{3}(s) + NaNO_{3}(aq)[/tex]
Here, number of atoms present on reactant side are as follows.
Na = 2[tex]CO_{3}[/tex] = 1Ag = 1[tex]NO_{3}[/tex] = 1Number of atoms present on product side are as follows.
Na = 1[tex]CO_{3}[/tex] = 1Ag = 2[tex]NO_{3}[/tex] = 1To balance this equation, multiply [tex]AgNO_{3}[/tex] by 2 on reactant side and multiply [tex]NaNO_{3}[/tex] by 2 on product side.
Hence, the equation can be rewritten as follows.
[tex]Na_{2}CO_{3}(aq) + 2AgNO_{3}(aq) \rightarrow Ag_{2}CO_{3}(s) + 2NaNO_{3}(aq)[/tex]
Since, the atoms on both reactant and product side are same. Hence, the equation is now balanced.
Thus, we can conclude that a balanced chemical equation for the reaction between [tex]Na_{2}CO_{3}[/tex] and [tex]AgNO_{3}[/tex] is [tex]Na_{2}CO_{3}(aq) + 2AgNO_{3}(aq) \rightarrow Ag_{2}CO_{3}(s) + 2NaNO_{3}(aq)[/tex].
Answer:
2
Explanation:
A yellow powder and a blue liquid are shaken together in a test tube to produce a clear green mixture that is all liquid.
Which of the following best describes the behavior of the above pair of substances?
Answer:
hkj
Explanation:
how many moles of potassium+hydroxide+would+react+with+one+mole+of+hydrocloric acid
Answer:
1 mole of potassium hydroxide, KOH
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
KOH + HCl —> KCl + H₂O
Considering the balanced equation above, we can see clearly that 1 mole of potassium hydroxide, KOH reacted with 1 mole of hydrochloric acid, HCl.
Therefore, we can conclude that at every given point, 1 mole of potassium hydroxide, KOH is required to react with 1 mole of hydrochloric acid, HCl.
1. For the reaction 3A — C, the initial concentration of A was 0.2 M, and the reaction rate was
1.0 M/s. When [A] was doubled, the reaction rate increased to 4.0 M/s. Determine the rate
law for the reaction.
Answer:
[tex]r=25M^{-1}s^{-1}[A]^2[/tex]
Explanation:
Hello there!
In this case, according to the given information for this chemical reaction, it is possible for us to set up the following general rate law and the ratio of the initial and the final (doubled concentration) condition:
[tex]r=k[A]^n\\\\\frac{r_1}{r_2} =\frac{k[A]_1^n}{k[A]_2^n}[/tex]
Next, we plug in the given concentrations of A, 0.2M and 0.4 M, the rates, 1.0 M/s and 4.0 M/s and cancel out the rate constants as they are the same, in order to obtain the following:
[tex]\frac{1.0}{4.0} =\frac{0.2^n}{0.4^n}\\\\0.25=0.5^n\\\\n=\frac{ln(0.25)}{ln(0.5)} \\\\n=2[/tex]
Which means this reaction is second-order with respect to A. Finally, we calculate the rate constant by using n, [A] and r, to obtain:
[tex]k=\frac{r}{[A]^n} =\frac{1.0M/s}{(0.2M)^2}\\\\k=25M^{-1}s^{-1}[/tex]
Thus, the rate law turns out to be:
[tex]r=25M^{-1}s^{-1}[A]^2[/tex]
Regards!
What volume of 0.686 M HCl would contain 0.037 moles of solute?
Given :
Molarity of HCl solution, M = 0.686 M.
Number of moles, n = 0.037 moles.
To Find :
The volume of solution.
Solution :
We know, molarity is given by :
[tex]M = \dfrac{Number \ of \ moles \ of \ solute}{Volume \ in \ liter}\\\\0.686 = \dfrac{0.037}{V}\\\\V = \dfrac{0.037}{0.686}\ L\\\\V = 0.053935 \ L \\\\V = 53.94 \ ml[/tex]
Hence, this is the required solution.
How many moles of MgCO3 are present in 252.939 grams of MgCO3?
A. 2
B. 3
C.5
D.6
Answer:
Hello, I was doing this and from my caluclations it should be :
Explanation:
3 Moles.
The three moles of MgCO3 are present in 252.939 grams of MgCO3.
So, option B is correct one .
What is molar mass?The molar mass of substance is equal to mass of one mole of that substance.
Example: Molar mass of MgCO3 is equal to mass of one mole of MgCO3.
Molar mass of Mg = 24.305 u
Molar mass of C = 12.011 u
Molar mass of O = 15.999 u
Molar mass of MgCO3 = Molar mass of Mg + Molar mass of C + Molar mass of O*3
Molar mass of MgCO3 = 24.305 + 12.011 + 15.999 * 3
Molar mass of MgCO3 = 84.3139 gram
Molar mass of MgCO3 contain 84.3139 gram
So, 252.939 grams of MgCO3 = 252.939 grams/84.3139 gram
252.939 grams of MgCO3 = 2.999 moles
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11. Beh, has no lone pairs of electrons. What's the structure of this molecule?
O A. Tetrahedral
O B. Octahedral
O C. Linear
D. Bent
What transition energy corresponds to an absorption line at 460 nm?
A. 6.52 x 10-19 J
B. 4.32 x 10-19 J
C. 4.45 x 10-19 J
D. 2.31 x 10-19 J
Answer:
B. 4.32 x 10-19 J is correct via a p e x
Explanation:
A single ___ bond is made when two atoms share a pair of ____
Answer:
covalent
valence electrons
Explanation:
The attraction between two atoms that share a pair of valence electrons is known as a covalent bond. The nuclei of both atoms are drawn to the shared electrons. This results in a molecule with two or more atoms. Covalent bonds are formed solely between nonmetal atoms.
Between atoms of the same element or between atoms of different elements, covalent bonds can form. A new substance termed a covalent compound is formed when atoms of various elements create covalent bonds.
What
is the major engine driving the planet's constant evolution and contains a geological record of much of the Earth's history
1. Mantle
2. Crust
3. Inner Core
4. Outer Core
Butane C4H10, is an easily liquedfied gaseous fuel. calculate the density of butane gas at 0.897 atm and 24°C. give the answer in grams per litre
Answer:
Density = 2.137 gram per liter (Approx.)
Explanation:
Given:
Gaseous fuel Butane C4H10
Pressure = 0.897 atm
Temperature = 24°C = 24 + 273 = 297 k
Find:
Density of butane gas
Computation:
We know that molar mass of butane = 58.12 g/mol
Density = [molar mass x pressure] / Rt
Density = [58.12 x 0.897] / [0.0821 x 297]
Density = [52.13] / [24.3837]
Density = 2.137 gram per liter (Approx.)
The compound aluminum nitride () is a compound semiconductor having mixed ionic and covalent bonding. The electronegativities for and are 1.5 and 3.0 respectively. Calculate the fraction of the bonding that is ionic.
Answer:
Fraction ionic = 0.43
Explanation:
To solve this question, we must, as first, find the fraction of the bond that is covalent using the equation:
Fraction Covalent = exp (-0.25*(Enitride - EAl)²)
Fraction covalent = exp (-0.25*(3.0- 1.5)²)
Fraction covalent = exp (-0.25*2.25)
Fraction covalent = exp (-0.5625)
Fraction covalent = 0.57
As:
1 = Fraction Covalent + Fraction Ionic:
Fraction ionic = 1 - 0.57
Fraction ionic = 0.43
A sample of aluminum absorbed 9.86 J of heat and its temperature increased from 23.2 and 30.5 degrees * C . What is the mass of the aluminum? Th specific heat of aluminum is 0.902 J/g^ C . Round your answer to 2 significant figures. Do not include units in your answer. *
Explanation:
H=mc×∆©
9.86=m×0.902×(30.5-23.2)
m=1.5
Explanation:
The specific heat of a substance is the amount of heat required to raise the temperature of 1 gram of the substance by 1 degree Celsius. The formula for calculating the heat absorbed or released by a substance is `q = mcΔT`, where `q` is the heat absorbed or released, `m` is the mass of the substance, `c` is the specific heat of the substance, and `ΔT` is the change in temperature.
In this case, we can use this formula to solve for the mass of the aluminum sample. We know that `q = 9.86 J`, `c = 0.902 J/g°C`, and `ΔT = 30.5°C - 23.2°C = 7.3°C`. Plugging these values into the formula, we get:
`9.86 J = m * 0.902 J/g°C * 7.3°C`
Solving for `m`, we find that the mass of the aluminum sample is approximately `1.5 g`, rounded to 2 significant figures.
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How much energy is released when 6.0 g of water is condensed from water
vapor?
A. 6.0 g x 1 mol/18.02 g x 4.186 kJ/mol
B. 6.0 g 1 mol/18.02 g 6.03 kJ/mol
O C. 6.0 g x 1 mol/18.02 g * (-285.83 kJ/mol)
O D. 6.0 g x 1 mol/18.02 g x 40.65 kJ/mol
Answer: 6.0g x 1 mol/18.02g x 40,65 kJ/mol which is D
Explanation: Just did
The water vapors change from vapor into water in condensation. The energy released by 6 gm of water is 6.0 g x 1 mol/18.02 g x 40.65 kJ/mol. Thus, option D is correct.
What is the heat of vapourization?The heat of vapourization is the latent heat or enthalpy needed by the liquid to get converted into the vapor or the gaseous phase of the matter. It can be used to determine the energy released or absorbed by the substance.
The heat of vapourization of water is 40.65 kJ/mol, and its molar mass is 18.02 moles.
So, the energy released for the water when it is condensed into vapors will be,
6.0 g x 1 mol/18.02 g x 40.65 kJ/mol
Therefore, the heat of vapourization determines the amount of energy released.
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An electron in a hydrogen atom moves from level 1 to level 4. The electron then drops from level 4 to level 2. Which
statement describes the most likely result?
The energy absorbed in the first move equals the energy released in the second move.
The energy absorbed in the first move is greater than the energy released in the second move.
O The energy released in the first move equals the energy absorbed in the second move.
The energy released in the first move is greater than the energy absorbed in the second move.
Answer:
Your answer would be B because In the first move energy was absorbed, because when energy is gained an electron moves to a higher energy level in the second move energy will be released because that is how an atom moves to a lower energy level. The jump from level 1 to 4 was bigger than the drop from 4 to 2, because in the first move it moved from more orbitals. thus describing the the energy in the first move had a far energy released in the second move.
A chemist adds of a magnesium fluoride solution to a reaction flask. Calculate the mass in micrograms of magnesium fluoride the chemist has added to the flask. Round your answer to significant digits.
The given question is incomplete, the complete question is:
A chemist adds 35.0mL of a 6.19 * 10^−4/mmol magnesium fluorideMgF2 solution to a reaction flask. Calculate the mass in micrograms of magnesium fluoride the chemist has added to the flask. Round your answer to
3 significant digits.
Answer:
The correct answer is 1.35 microgram.
Explanation:
Based on the given information,
The volume of magnesium fluoride given is 35 ml, and the concentration of magnesium fluoride is 6.19 × 10⁻⁴ mmol/L.
Now the moles of MgF₂ can be determined by using the formula,
Moles = Concentration × Volume
Moles of MgF₂ = Concentration of MgF₂ × Volume of MgF₂
= 6.19 × 10⁻⁴ mmol/L × 35 ml × L/1000 ml
= 217 × 10⁻⁷ mmol
The molecular mass of magnesium fluoride is 62.3 gram per mole
Thus, the mass of MgF₂ is,
= 217 × 10⁻⁷ mmol × 62.3 g/mol
= 13500 × 10⁻⁷ mg
= 1.35 microgram
Concentrated aqueous perchloric acid is 70.5 wt% HClO4 and has a concentration of 11.7 M. Calculate the volume of concentrated perchloric acid that should be diluted to 1.90 L to form a 5.00 M HClO4 solution.
Answer:
0.812 L
Explanation:
As this is a dilution process problem, we can solve it by using the C₁V₁ = C₂V₂ formula, where in this case:
C₁ = 11.7 MV₁ = ?C₂ = 5.00 MV₂ = 1.90 LWe input the data:
11.7 M * V₁ = 5.00 M * 1.90 LAnd solve for V₁:
V₁ = 0.812 LThis means that 0.812 L of concentrated perchloric acid should be diluted to a final volume of 1.90 L.
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Answer:
H
Explanation:
UMMM H2O .. im assuming the H missing
Positive or negative , guys?
What mass of HF is produced according to the given equation when 2.397 grams of each reactants are combined?
CaF2 + H2SO4 --> CaSO4 + 2HF
+HF is the answer
Explanation:
Using the periodic table as a reference, which pair of elements are nonmetals?
A. oxygen and sulfur
B. cobalt and zinc
C. mercury and lead
D. sodium and iodine
Answer:
A). oxygen and sulphur Non metals are on the right side of the periodic table they are generally in the gaesous form there are as many as 20 non metals in the periodic group ( including halogens and noble gas). non metal are electron withdrawning groups and they generally forms anion they are poor conductors of heat and electricity