A beam of light has a wavelength of 620 nm in vacuum.
a. What is the speed of this light in a liquid whose index of refraction at this wavelength is 1.56? (Use 3.00×108 m/s for the speed of light in a vacuum.)
b. What is the wavelength of these waves in the liquid?

Answer:

The answer is false

Explanation:

Though the mostly used SI unit of measurement or the most popular units are the

Length,

Time and

Mass

i.e meter (m), seconds (s), kilogram (kg)

Aside all the above stated units for measurements there are other four basic units which are itemized  bellow.

they are

1. Amount of substance - mole (mole)

2. Electric current - ampere (A)

3. Temperature - kelvin (K)

4. Luminous intensity - candela (cd)

Answer:

a) The police will take 18.056 seconds to catch the speedy car, b) The police will travel 326.019 meters before catching the speedy car, c) The speed of the police car when catches up with the speeder is 36.112 meters per second.

Explanation:

Let suppose that speeder moves in a uniform motion, whereas police car has an uniformly accelerated motion.

a) How long does it take for the police to catch the speeding car:

Kinematic equation of each vehicle's position are described:

Speeder

[tex]s_{A} = s_{A,o}+v_{A}\cdot t[/tex]

Police Car

[tex]s_{B} = s_{B,o}+v_{B,o}\cdot t + \frac{1}{2}\cdot a_{B}\cdot t^{2}[/tex]

If [tex]s_{A} = s_{B}[/tex], [tex]s_{A,o} = s_{B,o}[/tex], [tex]v_{A} = 18.056\,\frac{m}{s}[/tex], [tex]v_{B,o} = 0\,\frac{m}{s}[/tex] and [tex]a_{B} = 2\,\frac{m}{s^{2}}[/tex], the resulting expression is done:

[tex]v_{A} \cdot t = v_{B,o}\cdot t +\frac{1}{2}\cdot a_{B}\cdot t^{2}[/tex]

[tex]\frac{1}{2}\cdot a_{B}\cdot t^{2}+(v_{B,o}-v_{A})\cdot t = 0[/tex]

[tex]t \cdot \left(\frac{1}{2}\cdot a_{B}\cdot t +v_{B,o}-v_{A} \right)= 0[/tex]

[tex]t = 0\,s\,\wedge\, t = \frac{2\cdot (v_{A}-v_{B,o})}{a_{B}}[/tex]

[tex]t = \frac{2\cdot \left(18.056\,\frac{m}{s}-0\,\frac{m}{s} \right)}{2\,\frac{m}{s^{2}} }[/tex]

[tex]t = 18.056\,s[/tex]

The police will take 18.056 seconds to catch the speedy car.

b) How far did the police car travel before police caught up with the speeder?

The distance travelled by the police is: ([tex]s_{B,o} = 0\,m[/tex],  [tex]a_{B} = 2\,\frac{m}{s^{2}}[/tex], [tex]v_{B,o} = 0\,\frac{m}{s}[/tex] and  [tex]t = 18.056\,s[/tex])

[tex]s_{B} = 0\,m + \left(0\,\frac{m}{s} \right)\cdot (18.056\,s)+\frac{1}{2}\cdot \left(2\,\frac{m}{s^{2}} \right) \cdot (18.056\,s)^{2}[/tex]

[tex]s_{B} = 326.019\,m[/tex]

The police will travel 326.019 meters before catching the speedy car.

c) What is the speed of the police car when catches up with the speeder?

The speed of the police car is represented by the following formula:

[tex]v_{B} = v_{B,o} + a_{B}\cdot t[/tex]

Where [tex]v_{B}[/tex] is the speed of the police car, measured in meters per second.

Given that [tex]v_{B,o} = 0\,\frac{m}{s}[/tex], [tex]t = 18.056\,s[/tex] and [tex]a_{B} = 2\,\frac{m}{s^{2}}[/tex], the final speed of the police car when catches up with the speeder is:

[tex]v_{B} = 0\,\frac{m}{s}+\left(2\,\frac{m}{s^{2}} \right)\cdot (18.056\,s)[/tex]

[tex]v_{B} = 36.112\,\frac{m}{s}[/tex]

The speed of the police car when catches up with the speeder is 36.112 meters per second.

Answer:

False

Explanation:

If a point charge has electric field lines point into it,then charge must be negative because electric lines point into negative charges and point out of positive charges

Answer:

first law is your answer, if I'm not wrong

Answer:

i think it's the first law of motion :)

Explanation:

Answer:

I believe the answer is 10.82 m/s.

Explanation:

I just saw that the question asked for the TOTAL DISTANCE.. which means to add. And I added 4.83 and 5.99 together which then lead me to get 10.82 m/s. So yeah i think that's the answer. Hope this helps.

Answer:

[tex] \huge{ \boxed{ \sf{30000 \: kg \: {m/s}^{2}}}}[/tex]

Explanation:

[tex] \text{ \underline{ Given}} : [/tex]

[tex] \star[/tex] Mass of a truck ( m ) = 3000 kg

[tex] \star[/tex] Velocity of a truck ( v ) = 10 m / s

Finding the momentum :

[tex] \boxed{ \sf{momentum \: ( \: p \: ) \: = \: mass \: ∗ \: \: velocity}}[/tex]

[tex] \hookrightarrow{ \sf{momentum \: ( \: p \: ) \: = 3000 \: ∗ \: 10}}[/tex]

[tex] \hookrightarrow{ \sf{ \: momentum \: ( \: p \: ) \: = 30000 \: kg \: m/ {s}^{2} }}[/tex]

Hope I helped!

Best wishes ! :D

~[tex] \sf{TheAnimeGirl}[/tex]

Given:-

To calculate: Momentum of the body.

We know,

p = mv

where,

Thus,

p = (3000 kg)(10 m/s)

→ p = 30000 kg m/s (Ans.)

Answer:

The acceleration of the particle is 2 m/s²

The position of the particle is 9m

Explanation:

Given;

particles velocity, v = 2t m/s

The acceleration of the particle is given by;

a = dv/dt

a = d(2t) /dt

a = 2 m/s²

The acceleration of the particle is 2 m/s²

The position of the particle is given by;

s = ut + ¹/₂at²

Since the particle was released from rest, u = 0

s = 0(3) + ¹/₂(2)(3)²

s = 0 + 9 m

The position of the particle when t = 3 s is 9m

Answer:

a) 4652 cal

b) 8000 cal

Explanation:

Amount of heat transferred

Q1 = mL(v)

Q1 = 8.63 * 539

Q1 = 4652 cal

Amount of heat transferred to the water

Q2 = mcΔT

Q2 = 100 * 1 * (100 - 20)

Q2 = 8000 cal

Q = Q1 + Q2

Q = 4652 + 8000

Q = 12652 cal

b)

Heat transferred to the copper bowl

Q(b) = m(b) * c(b) * ΔT

Q(b) = 0.13 * 0.0923 * (100 - 20)

Q(b) = 0.96 cal

c)

Original heat of the cylinder

Q(c) = Q + Q(b)

m(c) * c(c) * ΔT = Q + Q(b), making ΔT subject of the formula

ΔT = (Q + Q(b))/ (m(c) * c(c))

ΔT = (12652 + 0.96) / (0.42 * 1)

ΔT = 12652.96/0.42

ΔT = 30126.1

Answer:

Vf = 69.56 cm/s

Explanation:

In order to find the final speed of the ramp, we will use the equations of motion. First we use second equation of motion to find out the acceleration of marble:

s = Vi t + (1/2)at²

where,

s = distance traveled = 160 cm

Vi = Initial Speed = 0 cm/s (since, marble starts from rest)

t = time interval = 4.6 s

a = acceleration = ?

Therefore,

160 cm = (0 cm/s)(4.6 s) + (1/2)(a)(4.6 s)²

a = (320 cm)/(4.6 s)²

a = 15.12 cm/s²

Now, we use first equation of motion:

Vf = Vi + at

Vf = 0 cm/s + (15.12 cm/s²)(4.6 s)

Vf = 69.56 cm/s

Answer:To protect the human body from foreign bodies from the outside environment.

Explanation:

Answer:

False

Explanation:

Becuase the average amu of 40 is represented

Answer:

12.9

Explanation:

1.6x15=24

0.4x4.5=1.8

24+1.8=25.8

1.6+0.4=2

25.8/2=12.9

You haven't described whether they're connected in series or in parallel.  Actually, there are eight (8) different ways they can be arranged, and each way has a different equivalent resistance.

==> All 3 resistors in series.  Equivalent resistance = (2+3+4) = 9.000 ohms

==> All 3 resistors in parallel.

Equivalent resistance = 1 / (1/2 + 1/3 + 1/4) = (12/13) ohm or 0.923 ohm

==> The 2 ohm resistor in series with (the 3 and the 4 in parallel)

Equivalent resistance = 2 + 1/(1/3 + 1/4) =  3.714 ohms

==> The 3 ohm resistor in series with (the 2 and the 4 in parallel)

Equivalent resistance = 3 + 1/(1/2 + 1/4) =  4.333 ohms  

==> The 4 ohm resistor in series with (the 2 and the 3 in parallel)

Equivalent resistance = 4 + 1/(1/2 + 1/3) =  5.200 ohms

==> The 2 ohm resistor in parallel with (the 3 and the 4 in series)

Equivalent resistance = 1.556 ohms

==> The 3 ohm resistor in parallel with (the 2 and the 4 in series)

Equivalent resistance = 2.000 ohms

==> The 4 ohm resistor in parallel with (the 2 and the 3 in series)

Equivalent resistance = 2.222 ohms

Answer:

Explanation:

According to newtons first law of motion;

Force = mass * acceleration

F = ma

where a = v-u/t

v is the final velocity

u is the initial velocity

t is the time taken

F = m(v-u/t)

Ft = m(v-u)

Given parameters;

F = 910,000N

t = 120m = 120 *60 = 7200secs

m = 1400kg

u = 0m/s

Required parameter

Final velocity v

Substituting the given parameters into the formula to get v;

Ft = m(v-u)

910,000 * 72000 = 1400(v-0)

910,000 * 72000  = 1400v

v = (910,000 * 72000)/1400

v = 910,000 * 720/14

v = 910,000 * 60

v = 468,000,000 m/s

Hence the final velocity of the drag racer is 468,000,000 m/s

Answer: Option (1) 70 kJ

Explanation:

Given that;

melting point of the substance T₁ is 20°C , Boiling point of the substance T₂ is 150°C , heat of fusion L₁ is 3.5 x 10⁴ J/kg , heat of vaporization L₂ is 7 x 10⁴ J/kg , Specific heat in solid state C₁ is 600 J/kg.K , Specific heat in liquid state C₂ is 1000 J/kg.K, Specific heat in gaseous state C₃ is 400 J/(kg.K) , Mass of the substance m is 0.5 kg , Initial temperature of the substance T₃ is 170°C , Final temperature of the substance  T₄ is 88°C .

Now  Heat given up by the substance to reach boiling point 150°C is

Q₁ = mC₃(T₃ - T₂)

Q₁ = (0.5)(400)(170 - 150)

Q₁ = 4000 J

Heat given up by the substance to turn into liquid from gaseous state at 150°C

Q₂ = mL₂

Q₂ = (0.5)(7x10⁴)

Q₂ = 35000 J

Heat given up by the substance to reach 88°C in liquid state from 150°C

Q₃ = mC₂(T₂ - T₄)

Q₃ = (0.5)(1000)(150 - 88)

Q₃ = 31000 J

Total heat given up by the substance

Q = Q₁ + Q₂ + Q₃

Q = 4000 + 35000 + 31000

Q = 70000 J

Q = 70 kJ

Therefore The quantity of heat given up by 0.50 kg of the substance when it is cooled from 170◦C to 88◦C, at a pressure of 1.0 atmosphere, is closest to 70 kJ

Answer:

Hewo Otaku Kun Here! (UwU)

Explanation:

1. A rock sitting at the edge of a cliff has potential energy. If the rock falls, the potential energy will be converted to kinetic energy.

2. Tree branches high up in a tree have potential energy because they can fall to the ground.

3. A stick of dynamite has chemical potential energy that would be released when the activation energy from the fuse comes into contact with the chemicals.

4. The food we eat has chemical potential energy because as our body digests it, it provides us with energy for basic metabolism.

5. A stretched spring in a pinball machine has elastic potential energy and can move the steel ball when released.

6. When a crane swings a wrecking ball up to a certain height, it gains more potential energy and has the ability to crash through buildings.

7. A set of double "A" batteries in a remote control car possess chemical potential energy which can supply electricity to run the car.

happy to help!

from: Otaku Kun ^^

Answer:

Aerobic physical activity is better for the cardiovascular system than it is for strength endurance, while anaerobic physical activity is better at building strength endurance than it is at increasing cardiorespiratory fitness.

Therefore true

Answer:

C. Its velocity is perpendicular to its acceleration

Explanation:

Because acceleration is always perpendicular to the velocity when the velocity will change direction without change it's magnitude

Answer:

less precise than

Explanation:

Answer:

less precise than

Explanation:

its right on edge2020

Answer:

  Q_total = 2 10⁻⁶ C

Explanation:

Let's apply the conditions of static equilibrium to this case, in the adjoint we can see a diagram of the forces.

X axis

    Tₓ - Fe = 0

    Tₓ = Fe

Y axis  

    [tex]T_{y}[/tex] - W = 0

    T_{y} = W

Let's use trigonometry to find the stress components, the angle is measured with respect to the vertical

    sin 10 = Tₓ / T

    cos 10 = T_{y} / T

    Tₓ = T sin 10

    T_{y} = T cos 10

we substitute

    T sin 10 = Fe

    T cos 10 = W

     T = mg / cos10

     T = 0.120 9.8 / cos 10

     T = 1,194 N

     Fe = 1,194 sin 10

     Fe = 0.2073 N

the electric force is

     F = k q₁q₂ / r²

in this case, as the cans touch, they have the same charge and the distance r is searched for by trigonometry

     sin 10 = y / L

     y = L sin 10

     y = 0.30 sin 10

     y = 0.052 m

this is the distance from the vertical to one can the distance between the two cans is

     y_total = 2y

     y_totlal = 2  0.052 = 0.104 m

     Fe = F = k q² / r²

     q = √ (F r² / k)

       q = √ (0.2073 0.104²/9 10⁹) = √ (24.913 10⁻¹⁴)

       q = 4.99 10⁻⁷ C

This is the charge of a can, as the transfer is carried out by contact, the flannel transfers half of its charge to the cans and these when separating face one keeps half of the transferred charge, therefore the total charge of the flannel is

     Q_total = 4 q

     Q_total = 19.97 10⁻⁷ C

     Q_total = 2 10⁻⁶ C

Answer:

[tex]s=6.86m/s^2[/tex]

Explanation:

Hello,

In this case, considering that the acceleration is computed as follows:

[tex]a=\frac{v_{final}-v_{initial}}{t}[/tex]

Whereas the final velocity is 28.82 m/s, the initial one is 0 m/s and the time is 4.2 s. Thus, the acceleration turns out:

[tex]a=\frac{28.82m/s-0m/s}{4.2s}\\ \\s=6.86m/s^2[/tex]

Regards.

Answer:Compared to other pathogens, such as bacteria, viruses are minuscule. And because they have none of the hallmarks of living things — a metabolism or the ability to reproduce on their own, for example — they are harder to target with drugs.

Explanation:

Answer:

Explanation:

The mass balance is an application of conservation of mass, to the analysis of physical system. This is given in an equation form as

Input = Output + Accumulation

The conservation law that is used in this analysis of the system actually depends on the context of the problem. Nevertheless, they all revolve around conservation of mass. By conservation of mass, I mean that the fact that matter cannot disappear or be created spontaneously.

Speed=distance/time.

7.74mins=464.4secs.

72.1=distance/464.4.

distance=464.4×7.21.

=3348.324m.

Answer:

1.78 m/s

Explanation:

Distance to putt = 8 m

Distance the ball stops to the putt = 1.5 m

therefore distance traveled by the ball = 8 - 1.5 = 6.5 m

The ball stops at this point 1.5 m from the putt, therefore its final velocity at this point = 0 m/s

the ball was struck with an initial velocity of 1.6 m/s

Using the equation

[tex]v^2[/tex] = [tex]u^2[/tex] + 2as

where v is the final velocity of the ball = 0 m/s

u is the initial speed of the ball = 1.6 m/s

a is the acceleration of the grass

s is the distance the ball travels = 6.5 m

substituting values, we have

[tex]0^2[/tex] = [tex]1.6^2[/tex] + 2(a x 6.5)

0 = 2.56 + 13a

13a = -2.56

a = -2.56/13 = -0.197 m/s^2

If this acceleration of the grass is assumed to be constant, then to the initial speed needed to make the putt will be calculated from

[tex]v^2[/tex] = [tex]u^2[/tex] + 2as

where

v is the final speed at the putt = 0 m/s

u is the initial speed with which the ball is struck = ?

a is the acceleration of the grass = -0.197 m/s^2

s is the distance to the putt = 8 m

substituting values, we have

[tex]0^2[/tex] = [tex]u^2[/tex] + 2(-0.197 x 8)

0 = [tex]u^2[/tex] - 3.152

[tex]u^2[/tex] = 3.152

u = [tex]\sqrt{3.152}[/tex] = 1.78 m/s

Answer:

q = -2.19 x 10⁻⁵ C

Explanation:

Given;

mass of the particle, m = 1.5 g = 0.0015 kg

magnitude of electric field, E = 670 N/C

Electric field is given by;

[tex]E = \frac{F}{q}[/tex]

where;

q is the magnitude of the

f is the force of the charge

f = mg

[tex]E = \frac{F}{q}\\\\E = \frac{mg}{q}\\\\q = \frac{mg}{E}\\\\q = \frac{0.0015*9.8}{670} \\\\q = 2.19*10^{-5} \ C[/tex]

Since the electric field is acting downward, the force on the charge must be acting upward. Therefore, the charge must be negative

q = -2.19 x 10⁻⁵ C

Answer:

6.705555556 m/s

Explanation:

60.35 divide by 9

Answer:

85.12 μAmp

Explanation:

The battery power output = 17.15 Amp-hr

If the battery is to last 23 years, we have to calculate how many hours there are in 23 years

in one year there are 24 hours x 365 day = 8760 hrs

in 23 years there are 23 x 8760 = 201480 hours

maximum current to be drawn from the battery = (17.15 Amp-hr) ÷ (201480 hours) = 85.12 x 10^-6 Amp = 85.12 μA