A cone has a height of 8 yards and a radius of 3 yards. What is its volume?

Use ​ ≈ 3.14 and round your answer to the nearest hundredth.

cubic yards
Submit

answer 7344012

percent *612000 =

(12:100)*612000 =

(12*612000):100 =

7344000:100 = 73440

Now we have: 12 percent of 612000 = 73440

Question: What is 12 percent of 612000?

Percentage solution with steps:

Step 1: Our output value is 612000.

Step 2: We represent the unknown value with $x$.

Step 3: From step 1 above,$612000=100\%$.

Step 4: Similarly, $x=12\%$.

Step 5: This results in a pair of simple equations:

$612000=100\%(1)$.

$x=12\%(2)$.

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

$\frac{612000}{x}=\frac{100\%}{12\%}$

Step 7: Again, the reciprocal of both sides gives

$\frac{x}{612000}=\frac{12}{100}$

$\Rightarrow x=73440$

Therefore, $12\%$ of $612000$ is $73440$

Answer:

31°

Step-by-step explanation:

As the opposing side and adjacent side of the angle x are given, we need to take the tan ratio of the angle.

=============================================================

Solving :

⇒ tan x° = 9/15

⇒ tan x° = 3/5

⇒ x = tan⁻¹ (0.6)

⇒ x = 31°

The size of the unknown angle "x"

We'll have to check which is the appropriate one from SOHCAHTOA.

In this question we'll have to use tan because opposite and adjacent is given.

[tex]\large\boxed{Formula: tan(A)= \frac{opp}{adj}}[/tex]

Substitute according to the formula.

[tex]tan \: x= \frac{9}{15}[/tex]

We'll have to use tan inverse.

[tex]x={tan}^{-1}(\frac{9}{15})[/tex]

[tex]x=30.96375653[/tex]

[tex]\large\boxed{x=31° }[/tex]

Hence, the size of the unknown angle "x" is 31°

let's firstly convert the mixed fractions to improper fractions and then get their difference.

[tex]\stackrel{mixed}{5\frac{3}{4}}\implies \cfrac{5\cdot 4+3}{4}\implies \stackrel{improper}{\cfrac{23}{4}} ~\hfill \stackrel{mixed}{1\frac{5}{8}}\implies \cfrac{1\cdot 8+5}{8}\implies \stackrel{improper}{\cfrac{13}{8}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{Saturday and Sunday}}{\cfrac{23}{4}}~~ - ~~\stackrel{Saturday~only}{\cfrac{13}{8}}\implies \cfrac{(2)23~~ - ~~(1)13}{\underset{\textit{using this LCD}}{8}}\implies \underset{Sunday~only}{\cfrac{33}{8}\implies 4\frac{1}{8}}[/tex]

Answer:

Check the attached image

Answer:

50.13

Step-by-step explanation:

We can easily find the area of our square, so to get that over with, 6*6=36. Now, for our circle, a full circle would be A=pi*r^2, but we only have half a circle. That means our equation will be A= 1/2(pi*r^2). We have our diameter, but we need our radius. Radius is just half the diameter, so 6/2=3. Now, we multiply. 3^3 is 9, and 9*3.14 is 28.26. All we have to do now is divide that by 2. If we do that, we get 14.13. The area of the semi-circle is 14.13. But we still have to add it to the area of the square, which will be our final step. 36+14.13=50.13, which is your area.

Hope this helps!

Answer:

55

Step-by-step explanation:

Answer: it suggests that this equation has no remainder and that the value of x is the factor.

Answer:

True

Step-by-step explanation:

8-2 (i+1) < 12 − 7i + 4i

Left side of the inequality:

8 - 2(i + 1)        distribute

8 - 2i - 2        simplify

(8 - 2) - 2i

6 - 2i

Right side of the inequality:

12 − 7i + 4i        simplify

12 − 3i

Combine:

6 - 2i < 12 − 3i

6 is less than 12

3i is less than 2i

leads to the assumption that the statement is true

Answer: 9

Step-by-step explanation:

By the geometric mean theorem, [tex]\frac{x}[6} =\frac{6}{4} \longrightarrow x=\left(\frac{6}{4} \right)(6)=\boxed{9}[/tex]

The domain of the function will be (-∞, ∞) and the range of the function will be (-∞, ∞).

The domain means all the possible values of x and the range means all the possible values of y.

The set of ordered pairs is given below.

{(-3, 2), (-2, 1), (-1,0), (0, -1)}

Then the line function will be

    y – 0 = [(– 1 – 0)/(0 + 1)] (x + 1)

          y = – x – 1

x + y + 1 = 0

Then the domain of the function will be (-∞, ∞) and the range of the function will be (-∞, ∞).

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Answer:

i = right angle

ii = obtuse angle

iii = straight angle

iv = obtuse angle

v = acute angle

Step-by-step explanation:

an acute angle is an angle less than 90 degrees

an obtuse angle is an angle more than 90 degrees

a right angle is an angle equivalent to 90 degrees (looks like two straight lines perpendicular)

a straight angle is an angle equivalent to 180 degrees (looks like a straight line)

a reflex angle is an angle greater than 180 degrees

so, ...

i = right angle

ii = obtuse angle

iii = straight angle

iv = obtuse angle

v = acute angle

Answer:

49 ÷ 66 × 100= x

Step-by-step explanation:

Answer:

Maria

Step-by-step explanation:

Marias suitcase is heavier as 1600 grams to kg is 1.6kg which is less than Marias suitcase which weighs 14kg hope this helps:)

The metaphor and its purpose from the excerpt from "On Beholding the Mountain" is "The heart's flame illustrates the intensity of the writer's emotion".

A metaphor is a figure of speech which is used to compare two things without using "like" or "as", by making the object of the metaphor take on the characteristic of the other thing.

It is also the use of a word or phrase to refer to something that it is not, invoking a direct similarity between the word or phrase used and the thing described but without the words like or as, which would imply a simile.

Therefore, the correct answer is option D; The heart's flame illustrates the intensity of the writer's emotion.

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Answer:

:

Step-by-step explanation:

Step-by-step explanation:

it is not important that the triangle is right-angled.

but the distance between each pair of points is calculated via Pythagoras

c² = a² + b²

with c being the Hypotenuse (baseline opposite of the 90° angle) = distance between the end points, and a and b are the legs (= the x and y coordinate differences of the 2 end points) of the virtual right-angled triangles between each pair of points.

so,

AB² = (6 - -3)² + (-4 - -4)² = 9² + 0² = 81

AB = 9 ft

BC² = (6 - 6)² + (8 - -4)² = 0² + 12² = 144

BC = 12 ft

and now for AC, which is because of the special case of how the main triangle is placed and oriented, the same calculation as with Pythagoras for the main right-angled triangle. but I keep showing you the point distance calculation, because this is what you will need in the future for more general triangle or other shapes calculations :

AC² = (6 - -3)² + (8 - - 4)² = 9² + 12² = 81 + 144 = 225

AC = 15 ft

so, Nasir will need

9 + 12 + 15 = 36 ft

of fencing.

Answer:

 B. 8.56

Explanation:

Given:

So using cosine rule:

[tex]\sf cos(x) = \dfrac{adjacent}{hypotenuse}[/tex]

[tex]\rightarrow \sf cos(50) = \dfrac{5.5}{x}[/tex]

[tex]\rightarrow \sf x= \dfrac{5.5}{cos(50) }[/tex]

[tex]\rightarrow \sf x= 8.56[/tex]

Answer:

61

Step-by-step explanation:

aₙ = a₁ + (n - 1)d

aₙ = 4 + (20 - 1)3

aₙ = 4 + (19)3

aₙ = 4 + 57

aₙ = 61

Answer:

10 and 4; and -8 and -5.

Answer:

hi the answer is c

Step-by-step explanation:

Answer:

  C, A, E, B, D

Step-by-step explanation:

The conversion relations between rectangular and polar coordinates can be used to find the polar coordinate equivalents. Those relations are ...

__

Using the expression for x, this is ...

  r·cos(θ) = 2

  r = 2/cos(θ) . . . . divide by cos(θ)

  r = 2·sec(θ) . . . . use the trig identity

__

From above, this becomes ...

  r² = 36

  r = 6 . . . . . . take the square root

__

From above, this becomes ...

  r² = 2·r·sin(θ)

  r = 2·sin(θ) . . . . . . divide by r

__

Using the above relations, this is ...

  r·cos(θ) = √3·r·sin(θ)

  1/√3 = sin(θ)/cos(θ) . . . . . . divide by √3·r·cos(θ)

  tan(θ) = 1/√3   ⇒   θ = arctan(1/√3)

  θ = π/6

__

From above, this is ...

  r·cos(θ) = r·sin(θ)

  1 = sin(θ)/cos(θ) = tan(θ) . . . . divide by r·cos(θ)

  θ = arctan(1)

  θ = π/4

_____

Additional comment

An equation of the form y = kx defines a line through the origin and through opposite quadrants of the Cartesian plane. Above, we found the equivalent polar equation to be θ = arctan(k). Using the principal branch of the arctangent function, this is the equation of a ray.

However, the tangent function is periodic with period π, so θ = arctan(k)+π is also an equivalent to the rectangular equation. It is the opposite ray, so forms the complete line when joined with the first ray.

The correct answer for the polar coordinates will be C, A, E, B, D

The polar coordinate system is a two-dimensional coordinate system in which a distance from a reference point and an angle from a reference direction identify each point on a plane. The pole is the reference point, and the polar axis is the ray from the pole in the reference direction.

The conversion relations between rectangular and polar coordinates can be used to find the polar coordinate equivalents. Those relations are ...

x = r·cos(θ)

y = r·sin(θ)

x² +y² = r²

x = 2

Using the expression for x, this is ...

r·cos(θ) = 2

r = 2/cos(θ) . . . . divide by cos(θ)

r = 2·sec(θ) . . . . use the trig identity

x²+y²=36

From above, this becomes ...

r² = 36

r = 6 . . . . . . take the square root

x²+y²=2y

From above, this becomes ...

r² = 2·r·sin(θ)

r = 2·sin(θ) . . . . . . divide by r

x=√3y

Using the above relations, this is ...

r·cos(θ) = √3·r·sin(θ)

1/√3 = sin(θ)/cos(θ) . . . . . . divide by √3·r·cos(θ)

tan(θ) = 1/√3   ⇒   θ = arctan(1/√3)

θ = π/6

x=y

From above, this is ...

r·cos(θ) = r·sin(θ)

1 = sin(θ)/cos(θ) = tan(θ) . . . . divide by r·cos(θ)

θ = arctan(1)

θ = π/4

However, the tangent function is periodic with period π, so θ = arctan(k)+π is also equivalent to the rectangular equation. It is the opposite ray, so forms the complete line when joined with the first ray.

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The graph which shows the function h(x) according to the task content is; Choice B.

It follows from the task content that the function h(x) = f(x)/4.

On this note, it follows that the values of h(x) in each case is one-fourth of the value of f(x).

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Answer:

Step-by-step explanation:

Ordered pairs

( 1 , -1 )

( 2 , -3 )

( 3 , -5 )

( 4 , -7 )

( 0 , 1 )

( -1 , 3)

( -2 , 5)

( -3 , 7)

Answer:

x-intercept = (0.5, 0)

y-intercept = (0, 1)

Step-by-step explanation:

x-intercept : where the line intersects the x-axis

y-intercept : where the line intersects the y-axis

Answer:

1. Reflection

2. G` will coincide with A, because having a reflection along with BC would mean G` directly goes on A.

3. GBC is congruent to triangle ABC because triangle GBC and triangle ABC have the same exact line measurements, and angles, and share a line.

Step-by-step explanation:

I don't know your notes on 6/3 so number 3 might not be 100% correct.

Answer:

Step-by-step explanation:

We want to identify a rigid transformation that maps congruent triangles to one-another, to explain the coincidence of corresponding parts, and to identify the theorems that show congruence.

__

Triangles GBC and ABC share side BC. Whatever rigid transformation we use will leave segment BC invariant. Translation and rotation do not do that. The only possible transformation that will leave BC invariant is reflection across line BC.

__

In part 3, we show ∆GBC ≅ ∆ABC. That means vertices A and G are corresponding vertices. When we map the congruent figures onto each other, corresponding parts are coincident. That is, vertex G' (the image of vertex G) will coincide with vertex A.

__

The markings on the figure show the corresponding parts to be ...

And the reflexive property of congruence tells us BC corresponds to itself:

There are four available congruence theorems applicable to triangles that are not right triangles

We don't know which of these are in your notes, but we do know that all of them can be used. AAS can be used with two different sides. SAS can be used with two different angles.

SSS

  Corresponding sides are listed above. Here, we list them again:

  AB and GB; AC and GC; BC and BC

SAS

  One use is with AB, BC, and angle ABC corresponding to GB, BC, and angle GBC.

  Another use is with BA, AC, and angle BAC corresponding to BG, GC, and angle BGC.

ASA

  Angles CAB and CBA, side AB corresponding to angles CGB and CBG, side GB.

AAS

  One use is with angles CBA and CAB, side CB corresponding to angles CBG and CGB, side CB.

  Another use is with angles CBA and CAB, side CA corresponding to angles CBG and CGB, side CG.

A total of 720 tickets were sold for the school play. They were either adult tickets or student tickets is mathematically given as

Generally, the equation for a sold tickets is mathematically given as

S=x+72

Therefore

x+x+72=772

2x+72=772

2x=772-72

x=350

In conclusion, tickets sold was

x=350

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Answer:

(10, 14)

Step-by-step explanation:

Hello there!

Given such a problem, we have been told to use substitution method to solve it.

To cut it short, substitution refers to replacing a variable with a value.

Here is a way to solve this problem even in future:

Back to our problem,

y = 2x - 6, x = 10

Substitute x into equation y = 2x - 6

y = 2(10) - 6

= 20 - 6

= 14

. ° . x = 10, y = 14

Variables in terms of x and y

(x, y) = (10,14) ✓

This is our answer.

I hope this helps.

Have a nice studies.

The type of variation between the speed and time is inverse.

The equation is r = d / t

The number of miles travelled is 102 miles.

When the speed a person is driving at increases, the time it takes to travel would decrease. On the hand,  speed a person is driving at decreases, the time it takes to travel would increase. This means that there is an inverse relationship.

The equation that represents an inverse relationship is

r = d / t

Where d is the distance

Distance = t x r

51 x 2 = 102 miles

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Answer:

B

Step-by-step explanation:

6% of her salary is  .06 * 50000 = 3000  <===== matched 100%

   from 6- 12% is another 3000 <=====matched 50% =  1500

3000 + 1500 = 4500 dollars matched

(she put in 6000 and her employer put in 4500 = 10500 total)

Answer:

[tex] \frac{4}{9} [/tex]

Step-by-step explanation:

[tex]( \frac{16 {}^{ \frac{1}{2} } }{81 { }^{ \frac{1}{2} } }) \\ ( \frac{ {4}^{2 \times \frac{1}{2} } }{9^{2 \times \frac{1}{2} } }) \\ ( \frac{4^{1} }{9 ^{1} } ) \\ \frac{4}{9} [/tex]

[tex]: \: \implies \: \sf{ \bigg( \dfrac{4 {}^{2} }{9 {}^{2} } \bigg) } {}^{ \frac{1}{2} } \\ \\ : \: \implies \: \sf{ \bigg( \dfrac{4 {}^{ \: 2 \times \frac{1}{2} } }{9 {}^{ \: 2 \times \frac{1}{2} } } \bigg) } \\ \\ : \: \implies \: \sf{ \bigg( \dfrac{4 {}^{ \: \cancel2 \times \frac{1}{ \cancel2} } }{9 {}^{ \: \cancel2 \times \frac{1}{ \cancel2} } } \bigg) } \\ \\ : \: \implies \: \sf{ \bigg( \dfrac{4 {}^{ \: 1 }}{9 {}^{ \: 1 } } \bigg) } \\ \\ : \: \implies \: \red{\bf{ \bigg( \dfrac{4 }{9 } \bigg) } }[/tex]