A person invested
$
8
,
900
$8,900 in an account growing at a rate allowing the money to double every 7 years. How long, to the nearest tenth of a year would it take for the value of the account to reach
$
20
,
600
$20,600?

Answers

Answer 1

Answer:

8.5

Explanation:

A Person Invested $8,900$8,900 In An Account Growing At A Rate Allowing The Money To Double Every 7 Years.
Answer 2

To the nearest tenth of a year, it would take around 9.1 years when calculate compoundly for the account's worth to reach $20,600.

What is Compound interest?

A loan or investment's initial principal as well as any accrued interest from earlier periods are both taken into account when calculating compound interest.

To resolve this issue, we can apply the compound interest formula:

A = P(1 + r/n)nt

where:

A represents the balance of the account after t years.P stands for the initial outlay ($8,900 in this case).The annual interest rate is r, which is unknown.The number n determines how often interest is compounded each year (in this case, once every seven years because the value of the money doubles every seven years).The number of years is t.

When A = $20,600, we need to determine t. Since we are aware that the initial investment would double after seven years, we can use the following formula to determine the yearly interest rate:

2 = (1 + r/n)^(nt)

If n is 1/7 (since the investment twice once every 7 years), 2 is the factor by which the investment doubles, and t is an unknown.

When we simplify this equation, we obtain:

t log(1 + r/7) = log(2)

When we solve for r, we get:

r = 7[(2^(1/t))-1]

Now that we have P, r, n, and A, we can enter them into the compound interest formula to find t:

$20,600 = $8,900(1 + r/1)^(1t)

2.318 = (1 + r)^t = log (2.318) / log (one plus r)

t is equal to log(2.318)/log(1 + 7[(2(1/t))-1]).

We can iteratively solve for t using a calculator, beginning with a first guess of 7 years (because the investment doubles every 7 years):

r = 0.0998 and A = $17,800 for t = 7 years

r = 0.0909 and A = $19,397 for t = 8 years.

r = 0.0833 and A = $20,416 for t = 9 years.

r = 0.0823 and A = $20,601 (closest to $20,600) for t = 9.1 years

As a result, it would take the account's value to reach $20,600 in around 9.1 years (to the nearest tenth of a year).

Therefore, when calculated compoundly, it would take approximately 9.1 years for the account's value to reach $20,600, to the nearest tenth of a year.

Learn more about Compound interest, here:

https://brainly.com/question/18958915

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Answers

Answer:

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Answers

Answer:

F = 987600 N

Explanation:

Force Equation

F=ma

Newton's second law states that force is proportional to what is required for an object of constant mass to change its velocity. This is equal to that object's mass multiplied by its acceleration. We use Newtons, kilograms, and meters per second squared as our default units, although any appropriate units for mass (grams, ounces, etc.) or velocity (miles per hour per second, millimeters per second2, etc.) could certainly be used as well - the calculation is the same regardless.

Solve

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Newtons are derived units, equal to 1 kg-m/s². In other words, a single Newton is equal to the force needed to accelerate one kilogram one meter per second squared.

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Answer:

Friction can be minimized by using lubricants like oil and grease and by using ball bearing between machine parts. A substance that is introduced between two surfaces in contact, to reduce friction, is called a lubricant. Fluid friction can be minimized by giving suitable shapes to the objects moving in the fluids.

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hope it helps

Question 4
1 pts
If you have a voltage of 120 volts entering your house and a light bulb with
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Answers

Answer:

D. 75 watts

Explanation:

brainliest please? i've just answered 3 of your questions and they were all correct! :) i hope i helped!

Answer:

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Una caja con medicina es lanzada desde un avión localizado a una distancia vertical de 340 m por encima de un río. Si el avión lleva una velocidad horizontal de 70 m/s¿Qué distancia horizontal recorrerá la caja con medicina antes de caer al río?

Answers

Answer:

La distancia horizontal que recorrerá la caja con medicina antes de caer al río es 583.1 metros.

Explanation:

Una caja con medicina es lanzada desde un avión localizado a una distancia vertical de 340 m por encima de un río.  Este movimiento posee una composición en dos dimensiones: uno horizontal sin aceleración, y el otro vertical con aceleración constante debido a la gravedad.  Por lo que se trata de un movimiento rectilíneo uniforme (MRU) en su trayectoria horizontal o eje horizontal (es decir, su velocidad es constante) y un movimiento uniformemente variado (MRUV) en su trayectoria vertical o en el eje vertical (es decir, su aceleración es constante).

En este caso, son conocidos los datos, considerando el sistema de referencia de la imagen:

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En el caso del MRUV, la posición puede calcularse mediante la expresión:

Posición final= Posición inicial + Velocidad inicial*t + [tex]\frac{1}{2}[/tex]*a*t²

donde a es la aceleración y t el tiempo transcurrido.

En este caso, reemplazando los datos conocidos, teniendo en cuenta que el MRUV sucede en la trayectoria vertical y que la aceleración es el valor de la gravedad:

0 m= 340 m + 0 m/s*t + [tex]\frac{1}{2}[/tex]* (-9.8 m/s²)* t²

Resolviendo:

-340 m= [tex]\frac{1}{2}[/tex]* (-9.8 m/s²)* t²

[tex]\frac{-340 m}{\frac{1}{2} *(9.8\frac{m}{s^{2} } )} =t^{2}[/tex]

69.39 s²= t²

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La posición en MRU se obtiene mediante:

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Posición final= 583.1 m

La distancia horizontal que recorrerá la caja con medicina antes de caer al río es 583.1 metros.

Veremos que la distancia horizontal que recorre la caja es 583.1 metros.

¿Como encontrar la distanca horizontal recorrida?

Recordar que la velocidad vertical y horizontal son independientes.

Aqui, lo primero que debemos hacer es encontrar el tiempo que la caja tarda en llegar al suelo.

Para ello usamos la ecuación de movimiento vertical:

p(t) = (-4.9 m/s^2)*t^2 + v*t + h

Donde el primer termino representa la gravedad, el segundo la velocidad inicial (que es cero en este caso) y el tercero la altura inicial, que es 340m.

p(t) = (-4.9 m/s^2)*t^2 + 340m

La caja llegara al suelo cuando la función de arriba sea igual a cero:

(-4.9 m/s^2)*t^2 + 340m = 0

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Answers

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Answers

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Answer:

Explanation:

Coding is all about logic, since I do not have the actual problem from the website I will guide you on how to solve this.

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Answers

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