A pizza parlor uses 42 tomatoes for each batch of tomato sauce. About how many batches of sauce can the pizza parlor make from its last shipment of 1,236 tomatoes?

Answers

Answer 1
Divide the total tomatoes in use by the average amount of tomatoes used in a single batch.

1,236/42 = 29.428 (about 29 batches can be made)

Related Questions

what is the ratio for 0.875?

Answers

i need more information to give you the correct answer on this. can you insert a picture or something?

The simplified ratio for 0.875 is 7:8 .

To express the ratio for 0.875, we need to convert the decimal value to a ratio form.

0.875 can be written as 875 / 1000 because the decimal value is equivalent to the fraction obtained by dividing the numerator by the denominator.

To simplify the fraction, we can divide both the numerator and denominator by their greatest common divisor, which is 125 in this case.

Dividing 875 and 1000 by 125, we get:

875 / 125 = 7

1000 / 125 = 8

So, the simplified ratio for 0.875 is 7:8 .

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Find all the missing sides and angles of this triangle.
A
7
B
70°
C

Answers

90+70= 160
Then 180-160=20
So angle A is 20

I need help with math.

Answers

Step-by-step explanation:

Circumference of a circle= 2πr

where r=6

and π=22/7

C=2πr

=2×22/7×6

=44/7×6

=264/7

=37.71cm

The approximation of 1 = integral cos(x3 + 10) dx using composite Simpson's rule with n= 3 is: When approximating Sof(x)dx using Romberg integration, R3,3 gives an approximation of order:

Answers

The approximation of the integral ∫cos(x³ + 10) dx using composite Simpson's rule with n = 3 is 0.126. When approximating the integral using Romberg integration, R₃,₃ gives an approximation of order h⁶.

To calculate the approximation using composite Simpson's rule, we divide the interval of integration into subintervals and apply Simpson's rule to each subinterval. The formula for Simpson's rule is:

S = h/3 * (f(x₀) + 4f(x₁) + 2f(x₂) + 4f(x₃) + ... + 2f(x_{n-2}) + 4f(x_{n-1}) + f(xₙ))

where h is the step size and n is the number of subintervals. In this case, we have n = 3, so we divide the interval into three equal subintervals, and the step size is h = (b - a) / n = (π - 0) / 3 = π/3.

Evaluating the function cos(x³ + 10) at the points x₀ = 0, x₁ = π/3, x₂ = 2π/3, and x₃ = π, we get:

f(x₀) = cos((0)³ + 10) = cos(10) ≈ -0.8391

f(x₁) = cos((π/3)³ + 10) = cos(π³/27 + 10) ≈ -0.4586

f(x₂) = cos((2π/3)³ + 10) = cos(8π³/27 + 10) ≈ -0.8391

f(x₃) = cos((π)³ + 10) = cos(π³ + 10) ≈ -0.3473

Using the Simpson's rule formula, we can now calculate the approximation:

S ≈ π/3 * (f(x₀) + 4f(x₁) + 2f(x₂) + 4f(x₃))

 ≈ π/3 * (-0.8391 + 4(-0.4586) + 2(-0.8391) + 4(-0.3473))

 ≈ 0.126

To calculate the order of approximation using Romberg integration, we use the formula:

Rₙ,ₖ = Rₙ₋₁,ₖ₋₁ + (Rₙ₋₁,ₖ₋₁ - Rₙ,ₖ₋₁) / (4ₖ - 1)

where Rₙ,ₖ represents the Romberg approximation at level n and column k. The order of approximation is determined by the highest power of h in the error term. In this case, we have R₃,₃, so the order is h⁶.

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How do I solve this problem. I have to find the missing side lengths and lease my sender as radicals in simplest form

Answers

Answer:

x = y = 2√2

Step-by-step explanation:

Find the diagram attached

To get the unknown side x and y, we need to use the SOH CAH TOA identity

Opposite side = x

Adjacent = y

Hypotenuse = 4

Sin theta = opposite/hypotenuse

sin 45 = x/4

x = 4 sin 45

x = 4 * 1/√2

x = 4 * 1/√2 * √2/√2

x = 4 * √2/√4

x = 4 * √2/2

x = 2√2

Similarly;

cos theta = adjacent/hypotenuse

cos 45 = y/4

y = 4cos45

y = 4 * 1/√2

y = 4 * 1/√2 * √2/√2

y = 4 * √2/√4

y = 4 * √2/2

y = 2√2

 what would be the equation of a line that passes through (3,-4) with slope 2/3

Answers

Answer:

y = 2/3x - 6

Step-by-step explanation:

Use the slope intercept equation, y = mx + b

Plug in the slope and given point, then solve for b

y = mx + b

-4 = 2/3(3) + b

-4 = 2 + b

-6 = b

Plug in the slope and b into the equation

y = 2/3x - 6

So, the equation of the line is y = 2/3x - 6

Look at the triangle: A right angle triangle is shown with hypotenuse equal to 17 centimeters. An acute angle of the triangle is labeled as x degrees What is the value of cos x°? (1 point) 8 ÷ 17 17 ÷ 8 15 ÷ 17 8 ÷ 15 I can't put in the photo. So, description. h- 17cm o- 8cm a- 15cm. This is a right triangle btw. (this is 9th grade work)

Answers

Answer:

15 ÷ 17

Step-by-step explanation:

Since our hypotenuse side is 17 cm, our opposite side is 8 cm and our adjacent side is 15 cm. Since the acute angle is x degrees,

From trigonometric ratios, cosx° = adjacent/hypotenuse

= 15 cm/17 cm

= 15/17

= 15 ÷ 17

For which the value of f(x) = 2x^2 + 9 will be the same as g(x) = 3^x?

Answers

Answer:

For [tex]x = 3[/tex] the value of [tex]f(x) = 2\cdot x^{2}+9[/tex] will be the same of [tex]g(x) = 3^{x}[/tex].

Step-by-step explanation:

To determine for which value of [tex]x[/tex], we need to apply the following identity ([tex]f(x) = g(x)[/tex]) and solve numerically the resulting expression:

[tex]2\cdot x^{2}+9 = 3^{x}[/tex]

[tex]3^{x}-2\cdot x^{2}-9=0[/tex] (1)

A quick approach is using graphic tool and looking for the value of [tex]x[/tex] such that  [tex]3^{x}-2\cdot x^{2}-9=0[/tex]. The result of the analysis is included below in the attached image. We find the following result:

[tex]x = 3[/tex]

For [tex]x = 3[/tex] the value of [tex]f(x) = 2\cdot x^{2}+9[/tex] will be the same of [tex]g(x) = 3^{x}[/tex].


Determine whether true or false
(i) Let X be a random variable, then Cov (X,X) = VAR(X).
(ii) The mean and standard deviation of an exponential random
variable are equal.
(iii) The joint PDF fXY(x,y)

Answers

(i) True.

(ii) False.

The first statement is true.

It is a well-known fact that for any random variable X, the covariance of X with itself is equal to the variance of X. This can be easily shown by applying the definition of covariance and variance and using the fact that the correlation between X and X is always 1.

The second statement is false. The mean of an exponential random variable is equal to 1/λ, where λ is the rate parameter. On the other hand, the standard deviation of an exponential random variable is equal to 1/λ as well. These two values are not equal, unless λ=1. Therefore, the statement is false.

In summary, the first statement is true, while the second statement is false. The covariance of a random variable with itself is equal to its variance, but the mean and standard deviation of an exponential random variable are not equal unless λ=1.

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HELP ASAP PLZ!!! Question in picture!

Answers

Answer:YOUR ANSWER IS C

Step-by-step explanation:

Answer:

y=11/2x-10

20 character minimum

The amount of carbon-14 in an object is given by y = ae– 0.00012t where a is the initial amount of carbon and t is the age in years. A fossil bone contains 25% of its original carbon-14. What is the approximate age of the bone?

Answers

Answer:

The approximate age of the bone is approximately 11552 years.

Step-by-step explanation:

The current proportion of carbon-14 with respect to its original amount is defined by following formula:

[tex]\frac{y}{a} = e^{-0.00012\cdot t}[/tex] (1)

Where:

[tex]y[/tex] - Current amount of carbon-14, no unit.

[tex]a[/tex] - Initial amount of carbon-14, no unit.

[tex]t[/tex] - Time, in years.

If we know that [tex]\frac{y}{a} = 0.25[/tex], then the approximate age of the bone is:

[tex]t = -8333.333\cdot \ln \frac{y}{a}[/tex]

[tex]t\approx 11552.453\,yr[/tex]

The approximate age of the bone is approximately 11552 years.

Compare the probability that a student will pass the test in the morning with
the probability that a student will pass the test in the afternoon. Draw a
conclusion based on your results.
A. P(pass morning) = 0.24
P(pass afternoon) = 0.41
Conclusion: A student taking the test in the morning has a greater
chance of passing it than a student taking it in the afternoon
O B. P(pass morning) = 0.24
P(pass | afternoon) = 0.41
Conclusion: A student taking the test in the afternoon has a
greater chance of passing it than a student taking it in the
morning.
O c. P(pass morning) = 0.48
P(pass | afternoon) = 0.82
Conclusion: A student taking the test in the afternoon has a
greater chance of passing it than a student taking it in the
morning.
D. P(pass morning) = 0.48
P(pass afternoon) = 0.82
Conclusion: A student taking the test in the morning has a greater
chance of passing it than a student taking it in the afternoon.

Answers

Answer: C

Step-by-step explanation:

just took the quiz

The conclusion based on the statement would be option C. Conclusion: A student taking the test in the afternoon has a greater chance of passing it than a student taking it in the morning.

What is the probability?

Probability refers to a possibility that deals with the occurrence of random events.

The probability of all the events occurring need to be 1.

We need to Compare the probability that a student will pass the test in the morning with the probability that a student will pass the test in the afternoon.

The conclusion based on the statement would be;

C. P(pass morning) = 0.48

P(pass | afternoon) = 0.82

Conclusion: A student taking the test in the afternoon has a greater chance of passing it than a student taking it in the morning.

Therefore, the correct option is C.

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Please show me step by step how to do this

Answers

Answer:

You know that the beginning salary is $32,000, and it is raised by $1,000 per year.

a) We want to find a recursive relation, let's try to find a pattern:

S₁ = salary on the first year =  $32,000

S₂ = salary on the second year = $32,000 + $1,000 = $33,000

S₃ = salary on the third year = $33,000 + $1,000 = $34,000

and so on.

We already can see that the recursive relation is: "the salary of the previous year plus $1,000", this can be written as:

Sₙ = Sₙ₋₁ + $1,000

Such that S₁ = $32,000

b) Your salary in the fifth year is S₅

Let's construct it:

S₃ = $34,000

S₄ = $34,000 + $1,000 = $35,000

S₅ = $35,000 + $1,000 = $36,000

Your salary on the fifth year is $36,000

c) When we have a recursive relation like:

Aₙ = Aₙ₋₁ + d

The sum of the first N elements is given by:

Sum(N) = N*(2*A₁ + (N - 1)*d)/2

Then the sum of your salary for the first 20 years is:

S(20) = 20*(2*$32,000 + (20 - 1)*$1,000)/2

S(20) = $830,000

Find the area of the following
triangle:
5 cm
10 cm
A= [?] cm?

Answers

Answer:

25

Step-by-step explanation:

A=1/2×b×h

A=1/2×5cm×10cm

A=25cm

Which expression is equivalent to the following expression? -4 (5x - 6)

1.) -20x - 24
2.) -20x + 24
3.) -20x + 6
4.) -20x - 6

Answers

Step-by-step explanation:

2.) -20× + 24

maaf kalo salah

Find the missing side lengths. Leave your answers as radicals in simplest form

Answers

Answer:

i think the answer is c but im not sure sorry if im wrong

Step-by-step explanation:

please help easy math!! 8th grade math Storypromblem answer number 9

Answers

Answer: Chris's Gym pays $2.75

Step-by-step explanation:

So i was glancing at this question wondering how I was gonna figure it out then flipped it upside down in my head and figred out what I was missing

So basically we know that Tyrell pays $2.00 for court reservations

Chris on the other hand according to the table pays $52.75 for court reservation in addition to his monthly fee. Now we have to find out how much is just the court fee. So if we look at the next box I realized that a second court recomendation costs $55.5 and I realized that to find the court reservation costs I needed to subtract so 55.5-52.755= 2.75 which means Chis has a monthly costs of 50 and pays $2.75 for a court holding

jada says she can write an equivalent fraction with a denominator of 100 by multiplying 5 by 5, then writing the number of hundredths as a decimal ​

Answers

It’s going to be 845.64 and 2.52

A woman bought a bag of rice for 5,700 naira and in three weeks later,she could only buy 3/4 of a bag for 5,700 find the percentage increase​

Answers

That’s a lot of rice

Test the claim that the proportion of people who own cats is significantly different than 90% at the 0.02 significance level.
The null and alternative hypothesis would be:
H0:μ≥0.9H0:μ≥0.9
H1:μ<0.9H1:μ<0.9
H0:p=0.9H0:p=0.9
H1:p≠0.9H1:p≠0.9
H0:μ=0.9H0:μ=0.9
H1:μ≠0.9H1:μ≠0.9
H0:p≥0.9H0:p≥0.9
H1:p<0.9H1:p<0.9
H0:μ≤0.9H0:μ≤0.9
H1:μ>0.9H1:μ>0.9
H0:p≤0.9H0:p≤0.9
H1:p>0.9H1:p>0.9
The test is:
left-tailed
right-tailed
two-tailed
Based on a sample of 500 people, 82% owned cats
The p-value is:__________ (to 2 decimals)
Based on this we:
Fail to reject the null hypothesis
Reject the null hypothesis

Answers

The null and alternative hypotheses for testing the claim that the proportion of people who own cats is significantly different from 90% at the 0.02 significance level are:

H0: p = 0.9 (proportion of cat owners is 90%)

H1: p ≠ 0.9 (proportion of cat owners is not equal to 90%)

Based on a sample of 500 people, where 82% owned cats, we can conduct a hypothesis test to determine the p-value at the 0.02 significance level. The p-value is the probability of obtaining a sample proportion as extreme as the observed proportion (82%) assuming the null hypothesis is true.

The p-value for this test is the probability of observing a sample proportion as different from 90% as 82%. Since the p-value is not provided in the question, it needs to be calculated based on the sample data and the assumed null distribution.

If the p-value is less than 0.02, we would reject the null hypothesis and conclude that the proportion of cat owners is significantly different from 90%. However, if the p-value is greater than or equal to 0.02, we would fail to reject the null hypothesis and conclude that there is not enough evidence to suggest a significant difference in the proportion of cat owners from 90%.

Without the calculated p-value, we cannot make a definitive conclusion about rejecting or failing to reject the null hypothesis.


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Suppose you measured a boiling temperature (in Cº) for a liquid 6 times and observed. the following results:
Sample mean: 101.82, sample variance (biased): 0.81
a. You are given that σ^2 = 1.2 for the population distribution. What is the confidence interval for the mean at 95% confidence level?
b. Assuming σ is unknown, what is the confidence interval for the population mean at 95% confidence level?
Please round your answers to 2 decimal digits.

Answers

The confidence interval for the mean at 95% confidence level with the variance known and unknown are (101.17, 102.47), (101.06, 102.58) respectively

A.)

Known Variance

Confidence interval is related by the formula:

CI = μ ± t * s * √(1/n)

Where :

μ = population mean

t = critical value for the confidence level

s = sample standard deviation

n = sample size

The critical value for a 95% confidence level is 1.96.

C.I = 101.82 ± 1.96 * 0.81 * √(1/6)

C.I = 101.82 ± 0.648

C.I = (101.172, 102.468)

Hence, the confidence interval is (101.17, 102.47)

B.)

Assuming variance is Unknown

We use the t-distribition; The critical value at 95% confidence and (6-1) degree of freedom = 2.306

CI = μ ± t * s * √(1/n)

C.I = 101.82 ± 2.306 * 0.81 * √(1/6)

C.I = 101.82 ± 0.763

C.I = 101.057, 102.583

Hence, the confidence interval is (101.06, 102.58)

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Which equation is equivalent to 3 = 87 ÷ h? A. 3 = (87 ÷ h) – 9 B. 3 × 9 = (87 ÷ h) ÷ 9 C. 3 + 9 = (87 ÷ h) + 9 D. 3 – 9 = (87 ÷ h)

Answers

Answer:

3= (87÷h)

Step-by-step explanation:

The question is to pick among the option the solutions that will be equal to 3= (87÷h)

Therefore the most suitable and correct option is

3×9= (87÷h)÷9

27= (87÷h)÷9

Divide by 9

3= (87÷h)

Hence the answer is 3=(87÷h)

Consider the function f(x)=6x+5
(A) find it’s average rate of change by changing x=1 to x=5

Answers

Answer: I really don’t know

Step-by-step explanation: I need help with this as well. I’m really sorry if you were looking for a real answer

Q10.
Prove algebraically that the recurring decimal 0.178 can be written as the fraction 59/330

Answers

Answer:

bbv

Step-by-step explanation:

Recurring decimal is decimal representation of a number whose digits are periodic and infinite. Proved algebraically that the recurring decimal 0.178 can be written as the fraction 59/330 below.

Given information;

Given number in the decimal form is [tex]0. 1 \overline 7 \overline 8[/tex]

Suppose the number is equal to the x,

[tex]x=0. 1 \overline 7 \overline 8[/tex]

Recurring decimal

Recurring decimal is decimal representation of a number whose digits are periodic and infinite.

As the number 78 is the recurring number. Thus the recurring number can be written as,

[tex]x=0.1787878.....[/tex]                      .......equation 1.

Suppose this is equation number 1.

Multiply the above equation with 100 both the sides,

[tex]100\times x=100\times0. 1 787878....[/tex]

[tex]100x=100\times0.1787878...[/tex]

[tex]100x=17.87878...[/tex]

Subtract the above equation from equation number 1. Thus,

[tex]\begin{aligned}\ 100x-x&=17.87878-0.1787878\\ 99x&=17.7\\ \end[/tex]

Solve for x ,

[tex]x=\dfrac{17.7}{99} [/tex]

Multiply with 10 in both numerator and denominator,

[tex]x=\dfrac{177}{990} \\ x=\dfrac{59}{330} \\[/tex]

Hence proved algebraically that the recurring decimal 0.178 can be written as the fraction 59/330

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the perimeter of the triangle is ___ units.

Answers

Answer:

29 units

Step-by-step explanation:

12 + 12 + 5

29

plzz hurryyyy its for my mathhhh classss

Answers

Answer:

A

Step-by-step explanation:

4x+2 = 10

=> 2x+2 = 10-2x

Which of the numbers listed below are solutions to the equation?
Check all that apply.
x2 = 49
A. -7
B. 14
C. 24.5
D. 7
E. -14
F. 2401

Answers

C. 24.5 is the only answer that adds up to 49.

y=-3x + 4
y = 3x - 2
What solution does this system have? How do you
know? Justify(explain).

Answers

Use substitution
Set them equal to each other
-3x + 4 = 3x - 2
Solve the equation
4 = 6x - 2
6x = 6, x = 1
Plug in 1 for any equation to find y
Y = -3(1) + 4
Y = -3 + 4, y = 1
Solution: x = 1, y = 1

Questions (a,b), 1 (a,b)

Answers

a )

First of all we need to find the value of x ,

because the angles are written in terms of the variable x .

______________________________________

Let's find the value of x :

STV angle & SUV angle have same measure because both of them are the front angle of SV arc .

[tex]STV angle \: = SUV angle \: \: = \frac{SV \: arc}{2} \\ [/tex]

So :

[tex]3x - 5 = 2x + 15[/tex]

Add sides 5

[tex]3x - 5 + 5 = 2x + 15 + 5[/tex]

[tex]3x = 2x + 20[/tex]

Subtract sides minus 2x

[tex]3x - 2x = 2x + 20 - 2x[/tex]

Collect like terms

[tex]x = 2x - 2x + 20[/tex]

[tex]x = 20[/tex]

Thus the measure of angle T equals :

[tex]measure \: of \: angle \: T = 3x - 5 \\ [/tex]

Now just need to put the value of x which we found :

[tex]measure \: of \: angle \: T \: = 3 \times (20) - 5 \\ [/tex]

[tex]measure \: of \: angle \: T \: = 60 - 5[/tex]

[tex]measure \: of \: angle \: T \: = 55°[/tex]

♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡

b )

angle S & angle V are also have same measure because they both are the front angles to the TU arc .

And we need to find the value of x again in this part exactly like we did for a .

[tex]angle \: \: S = angle \: \: V[/tex]

As the question told :

[tex]angle \: \: S = 3x[/tex]

and ,

[tex]angle \: \: V = x + 16[/tex]

Thus :

[tex]3x = x + 16[/tex]

Subtract sides minus x

[tex]3x - x = x + 16 - x[/tex]

Collect like terms

[tex]2x = x - x + 16[/tex]

[tex]2x = 16[/tex]

Divide sides by 2

[tex] \frac{2x}{2} = \frac{16}{2} \\ [/tex]

Simplification

[tex]x = 8[/tex]

So ;

[tex]measure \: \: of \: \: angle \: \: S = 3x[/tex]

[tex]measure \: \: of \: \: angle \: \: S = 3(8)[/tex]

[tex]measure \: \: of \: \: angle \: \: S = 24°[/tex]

And we're done.

18,8. Assuming the tree shown below is perpendicular to the base distance, use trigonometry
to calculate its height to 1 decimal place. Dimensions are in feet.
I
32°
150

Answers

Answer:

x = 93.7ft or x = 94ft

Step-by-step explanation:

Hope that helps :)

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