Answer:
I would say about a billion because numbers can be put in any combination
Step-by-step explanation:
EXAMPLES:
012345678
023456781
034567812
045678912
123456780
234567801
345678012
456780123
567801234
678012345
780123456
801234567
123456789
234567891
345678912
456789123
567891234
678912345
789123456
891234567
912345678
There are 3,628,800 possible ways to create passwords .
What is permutation?Permutations are different ways of arranging objects in a definite order. It can also be expressed as the rearrangement of items in a linear order of an already ordered set.
The symbol [tex]P_{r} ^{n}[/tex] = [tex]\frac{n!}{(n-r)!}[/tex]
is used to denote the number of permutations of n distinct objects, taken r at a time.
According to the question
Website requires users to create a password consisting of digits only.
i.e Digits are:
0 , 1 , 2 , 3 , 4 , 5 , 6 , 7 , 7 , 8 , 9 = total 10 digits
no digit may be repeated and each password must be at least 9 digits.
i.e Digits taken at a time is 9 with no repetitions
Now ,
Applying permutation
[tex]P_{r} ^{n}[/tex] = [tex]\frac{n!}{(n-r)!}[/tex]
substituting the value
n = 10
r = 9
[tex]P_{9} ^{10}[/tex] = [tex]\frac{10!}{(10-9)!}[/tex]
[tex]P_{9} ^{10}[/tex] = 10!
= 3,628,800
Hence, There are 3,628,800 possible ways to create passwords .
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What is the average rate of change of h over the interval −6 ≤ x ≤ 3? Give an exact number.
Answer:
-1/9
Step-by-step explanation:
Solve using the Quadratic Formula
5x2-3x-7=0
A)
B)
C)
D)
Answer:
C) [tex]\displaystyle x=\frac{3 \pm \sqrt{149}}{10}[/tex]
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightAlgebra I
Standard Form: ax² + bx + c = 0Quadratic Formula: [tex]\displaystyle x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}[/tex]Step-by-step explanation:
Step 1: Define
Identify
5x² - 3x - 7 = 0
↓
a = 5, b = -3, c = -7
Step 2: Solve for x
Substitute in variables [Quadratic Formula]: [tex]\displaystyle x=\frac{3 \pm \sqrt{(-3)^2-4(5)(-7)}}{2(5)}[/tex][√Radical] Evaluate exponents: [tex]\displaystyle x=\frac{3 \pm \sqrt{9-4(5)(-7)}}{2(5)}[/tex][√Radical] Multiply: [tex]\displaystyle x=\frac{3 \pm \sqrt{9+140}}{2(5)}[/tex][√Radical] Add: [tex]\displaystyle x=\frac{3 \pm \sqrt{149}}{2(5)}[/tex][Fraction] Multiply: [tex]\displaystyle x=\frac{3 \pm \sqrt{149}}{10}[/tex]The number of employees in each industry in Seattle was recorded and rounded to the nearest
10 thousand. The results are displayed in the dot plot above. According to the dot plot, what is
the median number of employees, in thousands?
Answer:
20
Step-by-step explanation:
In the question, "35 is what percent of 40?" what is the 35?
Answer:
35 is the 'is' and 40 is the 'of'
Step-by-step explanation:
is/of = %/100
35/40 = x/100
cross-multiply to get:
40x = 3500
x = 3500/40
x = 87.5
Expand and combine like terms.
(4m^5) – 5m^6) (4m^5 + 5m^6) =
Answer:
[tex]16m^{10} -25m^{12}[/tex]
Step-by-step explanation:
hope this helps :)
The expand and combination like terms (4m^5) – 5m^6) (4m^5 + 5m^6) is -9m^12 + (16)m^10.
What is an equation?An equation is an expression that shows the relationship between two or more numbers and variables.
A mathematical equation is a statement with two equal sides and an equal sign in between. An equation is, for instance, 4 + 6 = 10. Both 4 + 6 and 10 can be seen on the left and right sides of the equal sign, respectively.
We are given that;
The equation=(4m^5) – 5m^6) (4m^5 + 5m^6)
Now,
To expand the expression, we need to multiply each term inside the first parentheses by each term inside the second parentheses. This gives us:
(4m^5 - 5m^6) (4m^5 + 5m^6) = 4m^5 * 4m^5 + 4m^5 * 5m^6 - 5m^6 * 4m^5 - 5m^6 * 5m^6
To simplify the expression, we need to use the exponent rule that a^b * a^c = a^(b + c) and combine the terms that have the same base and exponent. This gives us:
4m^5 * 4m^5 + 4m^5 * 5m^6 - 5m^6 * 4m^5 - 5m^6 * 5m^6 = 16m^(5 + 5) + 20m^(5 + 6) - 20m^(6 + 5) - 25m^(6 + 6)
To further simplify the expression, we need to add the exponents and simplify the coefficients. This gives us:
16m^(5 + 5) + 20m^(5 + 6) - 20m^(6 + 5) - 25m^(6 + 6) = 16m^10 + 20m^11 - 20m^11 - 25m^12
To combine like terms, we need to add or subtract the coefficients of the terms that have the same base and exponent. This gives us:
16m^10 + 20m^11 - 20m^11 - 25m^12 = (16 - 25)m^12 + (20 - 20)m^11 + (16)m^10
= -9m^12 + (0)m^11 + (16)m^10
= -9m^12 + (16)m^10
Therefore, the equation will be equal to -9m^12 + (16)m^10.
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Simplify.
Rewrite the expression in the form z”. Z5 • Z6
Answer:
Simplify.
Rewrite the expression in the form z”. Z5 • Z6Simplify.
Rewrite the expression in the form z”. Z5 • Z6
Answer:
Simplify.
Rewrite the expression in the form z”. Z5 • Z6Simplify.
Rewrite the expression in the form z”. Z5 • Z6
Find the measure of the missing angle
128°
Help plz
Answer:
52 degrees
Step-by-step explanation:
a line is 180 degrees so just subtract 128 from 180 which is 52
The Box-and-Whisker Plot represents the ages of 40 people who responded to a telephone survey.
Which statement is true about this data set?
A. About 50% of the respondents were at or between 40 and 67.5 years old.
B. The range of the data is 84 years.
C. The outlier is 28 years.
D. The mean is 51 years.
Answer:
'A' is true; theoretically, 50% of the data items reside between the first and third quartiles (40 and 67.5)
Step-by-step explanation:
Range is 84-28 which is 56
Median is 51
1.5 x Interquartile Range (IQR) = 1.5(67.5-40) which equals 41.25
Q1 is 40
Q1 - IQR = -1.25
Low outliers are below -1.25 - 41.25; there are not data items below -42
Answer:
'A' is true; theoretically, 50% of the data items reside between the first and third quartiles (40 and 67.5)
Step-by-step explanation:
Range is 84-28 which is 56
Median is 51
1.5 x Interquartile Range (IQR) = 1.5(67.5-40) which equals 41.25
Q1 is 40
Q1 - IQR = -1.25
Low outliers are below -1.25 - 41.25; there are not data items below -42
Classify this expression
Answer:
8.
[tex]8. - 1. - 44 [/tex]
9
PLEASE HELP IF POSSIBLE :)
Answer:
Step-by-step explanation:
Name the side that’s opposite to angle A. (Geometry)
1.) AB
2.) AC
3.) BC
Answer:
The answer gonna be A and C because their both is the same length
Answer:
BC
Step-by-step explanation:
The side opposite the right angle is called the hypotenuse. It is the largest side right angled triangle.If you stand at A in the triangle ABC, the side BC is opposite to you and the side BC is next to you. We therefore say that BC is the opposite side to angle A and AB is the adjacent side ti angle A.
Bacteria are taking over the kitchen sink. Right now, there are 375 microbes of bacteria. They double every hour.
Is the function describe above a growth or decay function?
Answer: The function described in this scenario above is a “Growth Function”
Have a nice day!
Find the measure of angle C
Answer:
ajnasnnanananandbabbabbansbansbz svabsvsb
The diagram shows a campground in the shape of a right triangle. You walk along a path from the camp office
at point c to your campsite at point D on a path that bisects the right angle C. Determine how far you are from
the picnic area at Point A to the nearest tenth of a meter.
What is the domain of f?
Stanley attempted to simplify the expression below.
−4●(2.5x−1.25)−3x
His work, step by step, is shown below.
Step 1: −4●{(2.5x+(−1.25)}−3x
Step 2:−10x+(−5)−3x
Step 3:−10x−3x+(−5)
Step 4: −13x−5
In which step did he make his first error simplifying the expression?
Write the expression using exponents.
43 . 43 . 43 . 43 . 43
Answer:
43⁵
Step-by-step explanation:
43 · 43 · 43 · 43 · 43 = 43⁵
11/3 as a decimal pls help
Answer:
3.7 rounded
Step-by-step explanation:
Just divide 11/3
Help If you know the answer plz!
Answer:
2
Step-by-step explanation:
Answer:
2t
Step-by-step explanation:
3t-t is the same as 3-1, so it equals 2t
3(2^2x+3)-5(2^x+2)-156=0
Answer: [tex]x=3.0206[/tex]
Step-by-step explanation:
Given
[tex]3(2^{2x}+3)-5(2^x+2)-156=0[/tex]
Replace [tex]2^x[/tex] by [tex]y[/tex]
We can write
[tex]\Rightarrow 3(y^2+3)-5(y+2)-156=0\\\Rightarrow 3y^2+9-5y-10-156=0\\\Rightarrow 3y^2-5y-157=0\\\\\Rightarrow y=\dfrac{5\pm \sqrt{25-4(3)(-157)}}{2\times 3}\\\\\Rightarrow y=\dfrac{5+43.69}{6}\\\\\Rightarrow y=8.115\\\Rightarrow 2^x=8.115\\\therefore \quad x=3.0206[/tex]
Find the area of a triangle with a height of 5 ft and a base of 4 ft.
Answer:
5 x 4 = 20, 20 divided by 2 ( x 1/2 ) = 10
Step-by-step explanation:
Formula area of a Triangle:
B(base) x H(height) x 1/2(basically just dividing by 2)
What is the area, in square units, of trapezoid AEDC shown below?
Area of this trapezoid is 264 unit²
What is the area of a trapezoid?Area: ½ x (sum of the lengths of the parallel sides) x perpendicular distance between parallel sides.
Given perpendicular distance as 12 and parallel sides as 20,24 units respectively.
Thus Area is (20+24 /2) ×12=264 units²
Hence, the Area of trapezoid is 264 unit²
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If the interest of a sum at 7.5% p.a in 4 years is Rs. 1050, find the sum
~Refer to the attachment for the solution.
[tex] \to \bf { Sum = 3500 } [/tex]
Rob's school is selling tickets to a spring musical. On the first day of ticket sales the school sold 3 adult tickets and 1 student ticket
for a total of $15. The school took in $69 on the second day by selling 9 adult tickets and 7 student tickets. What is the price each
of one adult ticket and one student ticket?
Answer:
Adult Tickets =$3
Student Tickets =$6
Step-by-step explanation:
3×3=9 9+6=15
9×3=27
7×6=42
27+42=67
Suppose f(x) = x^3 +3. Find the graph of f(2/3x)
Answer:
First, when we have a function f(x), an horizontal dilation of scale factor k, is written as:
g(x) = f(x/k)
Then f((2/3)*x) is an horizontal dilation of scale factor 3/2 of the function f(x).
(The graph will be a little bit wider than the graph of f(x))
Also, knowing that f(x) = x^3 + 3
Then:
f((2/3)*x) = ( (2/3)*x)^3 + 3
= (8/27)*x^3 + 3
And the graph of this function is shown below:
Please help. Image up top.
Answer:
6/5t + 4/15s - 3
Step-by-step explanation:
(-4/5t + 5/3s) + (-3 -7/5s + 2t)
You can only add like terms together so convert like terms to have the same denominator:
(-4/5t + 25/15s) + (-3 - 21/15s + 10/5t)
Get rid of the parentheses:
-4/5t + 25/15s - 3 - 21/15s + 10/5t
Combine like terms:
6/5t + 4/15s - 3
You take a bus from your neighborhood to your school. The express bus arrives at your neighborhood at a random time between 7:30 and 7:36 a.m. The local bus arrives at your neighborhood at a random time between 7:30 and 7:40 a.m. You arrive at the bus stop at 7:33 a.m. Find the probability that you missed both the express bus and the local bus. Express your answer as a fraction in simplest form.
Answer:
[tex]\frac{3}{20}[/tex] probability that you missed both the express bus and the local bus.
Step-by-step explanation:
Uniform distribution:
An uniform distribution has two bounds, a and b.
The probability of getting a value lower than x is:
[tex]P(X < x) = \frac{x - a}{x - b}[/tex]
The express bus arrives at your neighborhood at a random time between 7:30 and 7:36 a.m.
6 minutes, so [tex]a = 0, b = 6[/tex]
You arrive at 7:33, so if x < 3, you lose the express bus:
[tex]P_E = P(X < 3) = \frac{3 - 0}{6 - 0} = \frac{3}{6} = \frac{1}{2}[/tex]
The local bus arrives at your neighborhood at a random time between 7:30 and 7:40 a.m.
10 minutes, so [tex]a = 0, b = 10[/tex]
[tex]P_B = P(X < 3) = \frac{3 - 0}{10 - 0} = \frac{3}{10}[/tex]
Find the probability that you missed both the express bus and the local bus.
[tex]p = P_E*P_B = \frac{1}{2}*\frac{3}{10} = \frac{3}{20}[/tex]
[tex]\frac{3}{20}[/tex] probability that you missed both the express bus and the local bus.
The probability that you missed both the express bus and the local bus is 3/20
The individual probability of a uniform distribution is calculated as:
[tex]P(X < x) = \frac{x - a}{b - a}[/tex]
For the express bus
At 7:30 am, a = 0
At 7:36 am, b = 6
You arrived at 7:33 am; this means that:
x = 3
For you to miss the express bus, it means that the express bus left before 7:33 am.
i.e. x < 3
So, the probability that you miss the express bus is:
[tex]P(X < 3) = \frac{3 - 0}{6 - 0}[/tex]
[tex]P(X < 3) = \frac{3}{6}[/tex]
[tex]P(X_E < 3) = \frac{1}{2}[/tex]
For the local bus
At 7:30 am, a = 0
At 7:40 am, b = 10
You arrived at 7:33 am; this means that:
x = 3
For you to miss the local bus, it means that the local bus left before 7:33 am.
i.e. x < 3
So, the probability that you miss the local bus is:
[tex]P(X < 3) = \frac{3 - 0}{10 - 0}[/tex]
[tex]P(X_L < 3) = \frac{3}{10}[/tex]
So, the probability that you miss both bus is:
[tex]P(Both) = P(X_E < 3) * P(X_L < 3)[/tex]
This gives
[tex]P(Both) = \frac 12 * \frac 3{10}[/tex]
[tex]P(Both) = \frac 3{20}[/tex]
Hence, the probability that you missed both the express bus and the local bus is 3/20
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I NEED THIS QUICK no links !!!!! (math)
answer: the answer is c
Find the measure of the arc indicated. Assume that lines which appear tangent are tangent.
Answer:
Minor Arc AC = 360 - 235 = 125°
[tex]mABC = \frac{Major \ arc - Minor \ arc}{2} = \frac{235 - 125}{2} = \frac{110}{2} = 55[/tex]
A survey of 125 freshmen business students at a local university produced the results listed below. How many students took history and math, but not music? 30 took history; 32 took math; 33 took music; 14 took history but not math; 9 took math and music; 13 took history and music; 2 took all three
Answer:
Total Number of students taking Math and History and not music are 68.
Number of students who took both math and history at the same time is 6.
Step-by-step explanation:
History = 30
Math = 32
Music= 33
Math and Music= 9
History and Music= 13
History and Music and Math = 2
History but not math = 14
We have to find students taking history and math but not music.
Total number of students = 125
From the figure number of students taking Math and History and not music are
=30+6+32= 68
Number of students who took both math and history at the same time is 6.