A pressure vessel has a design pressure of 50 bar. However the safety case for the chemical plant on which it is to be used requires that the pressure vessels have a 95% probability of surviving a pressure of 70 bar. Computer codes have generated an estimate of only 0.80 for the probability that any such pressure vessel, picked at random, will survive at 70 bar. However, they have also calculated that of the 20% of the pressure vessels that will not survive a pressure of 70 bar, 40% will fail under a pressure of 58 bar or less, while 80% will fail under a pressure of 65 bar or less. It is decided that an over-pressure test needs to be used to give reassurance on the behaviour of this particular pressure vessel. This test may be carried out at either 58 bar or 65 bar. The lower pressure test is considerably less difficult and cheaper to administer. (i) Suppose that you are brought in as a consultant. By calculating the probability of the pressure vessel being able to support the 70 bar maximum pressure if the over-pressure test is passed, advise on which over-pressure test should be administered.

Answer:

It will take her 15 weeks to have enough money for the computer.

Step-by-step explanation:

$1200 - $300 = $900

900 divided by 60 gives you 15

Therefor, it'll take Shirley 15 weeks to save $1200.

Answer:

7

Step-by-step explanation:

Answer:

Step-by-step explanation:

m<1 = 50

m<2 = 22

m<3 = 108

m<4 = 50

m<5 = 65

m<6 = 50

m<7 = 43

m<8 = 65

m<9 = 75

m<10 = 18

m<11 = 25

m<12 = 40

m<13 = 115

m<14 = 65

m15 = 115

Answer:

2x+9

Step-by-step explanation:

You have to combine like terms. 2x stays the same because there are no other like terms, but 5, 2, and 2 can be added together to make 9

We have proven that ΔWXY is similar to ΔWVZ using the ASA criterion.

We have,

To prove that ΔWXY is similar to ΔWVZ, we can use the ASA (Angle-Side-Angle) criterion.

Here are the steps of the proof:

Proof:

- Given: ΔWXY is isosceles with legs WX and WY; ΔWVZ is isosceles with legs WV and WZ.

Since ΔWXY is isosceles, we have WX ≅ WY. (Given)

Since ΔWVZ is isosceles, we have WV ≅ WZ. (Given)

We also know that ΔWXY and ΔWVZ share the common side segment WZ. (Common side)

Let's consider the angles: ∠WXY and ∠WVZ. Since ΔWXY is isosceles, we have ∠WXY ≅ ∠WYX. (Isosceles triangle property)

Similarly, since ΔWVZ is isosceles, we have ∠WVZ ≅ ∠WZV. (Isosceles triangle property)

Now, we have two pairs of congruent angles: ∠WXY ≅ ∠WYX and ∠WVZ ≅ ∠WZV.

We already know that WX ≅ WY and WV ≅ WZ.

By the ASA criterion, if two pairs of corresponding angles and the included side are congruent, then the triangles are similar.

Applying the ASA criterion, we conclude that ΔWXY ~ ΔWVZ. (Angle-Side-Angle)

Therefore,

We have proven that ΔWXY is similar to ΔWVZ using the ASA criterion.

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Answer:

2/3

Step-by-step explanation:

Answer:

Slope = -6

Step-by-step explanation:

The argument (arg) of the complex number z = (a + ai)(b + b/3i), where a and b are positive real numbers, is π/6 radians or 30 degrees.

To determine the argument (arg) of the complex number z = (a + ai)(b + b/3i), where a and b are positive real numbers, we can simplify the expression and find the argument without using a calculator.

First, expand the product (a + ai)(b + b/3i):

z = (a + ai)(b + b/3i)

 = ab + ab/3i + abi - ab/3

Combining like terms, we get:

z = (ab - ab/3) + (ab/3 + ab)i

 = (2ab/3) + (ab/3)i

Now, we have the complex number z in the form z = x + yi, where x = 2ab/3 and y = ab/3.

To compute the argument (arg) of z, we can use the definition of the argument as the angle θ between the positive real axis and the line connecting the origin to the complex number z in the complex plane.

Since a and b are positive real numbers, both x and y are positive.

The argument (arg) of z can be determined as:

arg z = arctan(y/x)

      = arctan((ab/3) / (2ab/3))

      = arctan(1/2)

      = π/6

Therefore, without using a calculator, the argument (arg) of the complex number z = (a + ai)(b + b/3i) is π/6 radians or 30 degrees.

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Answer:

Step-by-step explanation:

Answer:

28

Step-by-step explanation:

The winning payout for the horse is $45

To determine the winning payout for the horse, you need to use the following formula:

Odds against winning: B / (A + B)

Betting amount: X Payout: X + (X * B / A)where A is the denominator of the odds and B is the numerator of the odds.

Here, the odds against winning are 2:7.

So, the denominator (A) is 7 and the numerator (B) is 2.

The betting amount is $35.

Plugging these values into the formula:

Payout = 35 + (35 * 2 / 7)

Payout = $45.

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Answer

use trigonometry to find both the answers.    

i have done the working out in the picture hope it helps...

Step-by-step explanation:

Answer:

Step-by-step explanation:

Dani has only 1/2 of a cup of baking mix. She needs 3/4 of a cup for one batch of muffins. Which solution method shows how much of a batch of muffins Dani can make?

Answer:

Any number less than greater than or equal to 18

Step-by-step explanation:

Answer:

The answer is m=1 , the slope is 1

Step-by-step explanation:

Answer:

[tex]\frac{n}{5} - 6[/tex]

Step-by-step explanation:

Quotient of a number and 5 means n/5

6 less than n/5 means n/5 - 6

Answer:

the product of a triple a number and 19

Step-by-step explanation:

but i'm not 100% sure so don't quote me

Answer:

y = -4

Step-by-step explanation:

dy/dx gives you slope

(-4)-(-4)/5-3 = 0/2  ----> slope = 0

y = mx+b

m = 0

y = 0x+b

y = b

as it says F(3) and F(5) = -4 b must be -4

so you end up with y = -4

Jasmine's Z-score is 2. The number of parks per capita in the city is [tex]1.38 * 10^-4[/tex] in scientific notation.

To calculate Jasmine's Z-score, we can use the formula:

Z = (X - μ) / σ

where X is the individual score (85), μ is the mean (76), and σ is the standard deviation (4.5).

Z = (85 - 76) / 4.5

Z = 9 / 4.5

Z = 2

Since Jasmine's Z-score is 2, this tells us that her score of 85 is 2 standard deviations to the right of the mean.

Now let's calculate the probability of randomly selecting a math exam with fewer than 15 questions using the mean of 20 and a standard deviation of 2.5.

To apply the empirical rule, we need to determine how many standard deviations 15 is away from the mean.

Z = (X - μ) / σ

Z = (15 - 20) / 2.5

Z = -5 / 2.5

Z = -2

Since 15 is 2 standard deviations to the left of the mean, we can use the empirical rule to estimate the probability.

According to the empirical rule:

The data is within one standard deviation of the mean for about 68% of the time.

The data is within 2 standard deviations of the mean for about 95% of the time.

99.7% of the data are contained within a 3 standard deviation range around the mean.

Since 15 is beyond 2 standard deviations to the left, the probability of randomly selecting a math exam with fewer than 15 questions would be very close to 0. In this case, we can assume it's effectively 0%.

Now let's calculate the number of parks per capita in the city with 890,000 people and 123 parks.

Number of parks per capita = Number of parks / Population

Number of parks per capita = 123 / 890,000

To write the answer in scientific notation, we can express 890,000 as 8.9 x 10^5:

Number of parks per capita =[tex]123 / (8.9 * 10^5)[/tex]

Calculating the result:

Number of parks per capita =[tex]1.38 * 10^-4[/tex]

Therefore, the number of parks per capita in the city is[tex]1.38 * 10^-4[/tex] in scientific notation.

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Answer:

$244.00

Step-by-step explanation:

- gave bank $100

- +6% of $100 per month

- 6% of $100 = $6 (earns $6 per month)

- twelve months in a year, so 12 x $6 = $72 per year

- $100 + $72 + $72 = $244

If Lacey wants to utilize her money to purchase a new bicycle in two years, she will spend $244 on the bike.

Answer:

The answer is A. 116 square cm

Step-by-step explanation:

Answer:

g) [tex]u^{4}\cdot v^{-1}\cdot z^{3}[/tex], h) [tex]\frac{(x+4)\cdot (x+2)}{3\cdot (x-5)}[/tex]

Step-by-step explanation:

We proceed to solve each equation by algebraic means:

g) [tex]\frac{u^{5}\cdot v}{z}\div \frac{u\cdot v^{2}}{z^{4}}[/tex]

1) [tex]\frac{u^{5}\cdot v}{z}\div \frac{u\cdot v^{2}}{z^{4}}[/tex] Given

2) [tex]\frac{\frac{u^{5}\cdot v}{z} }{\frac{u\cdot v^{2}}{z^{4}} }[/tex] Definition of division

3) [tex]\frac{u^{5}\cdot v\cdot z^{4}}{u\cdot v^{2}\cdot z}[/tex]   [tex]\frac{\frac{a}{b} }{\frac{c}{d} } = \frac{a\cdot d}{b\cdot c}[/tex]

4) [tex]\left(\frac{u^{5}}{u} \right)\cdot \left(\frac{v}{v^{2}} \right)\cdot \left(\frac{z^{4}}{z} \right)[/tex]  Associative property

5) [tex]u^{4}\cdot v^{-1}\cdot z^{3}[/tex]   [tex]\frac{a^{m}}{a^{n}} = a^{m-n}[/tex]/Result

h) [tex]\frac{x^{2}-16}{x^{2}-10\cdot x + 25} \div \frac{3\cdot x - 12}{x^{2}-3\cdot x -10}[/tex]

1) [tex]\frac{x^{2}-16}{x^{2}-10\cdot x + 25} \div \frac{3\cdot x - 12}{x^{2}-3\cdot x -10}[/tex] Given

2) [tex]\frac{\frac{x^{2}-16}{x^{2}-10\cdot x+25} }{\frac{3\cdot x - 12}{x^{2}-3\cdot x - 10} }[/tex] Definition of division

3) [tex]\frac{(x^{2}-16)\cdot (x^{2}-3\cdot x -10)}{(x^{2}-10\cdot x + 25)\cdot (3\cdot x - 12)}[/tex]  [tex]\frac{\frac{a}{b} }{\frac{c}{d} } = \frac{a\cdot d}{b\cdot c}[/tex]

4) [tex]\frac{(x+4)\cdot (x-4)\cdot (x-5)\cdot (x+2)}{3\cdot (x-5)^{2}\cdot (x-4) }[/tex] Factorization/Distributive property

5) [tex]\left(\frac{1}{3} \right)\cdot (x+4)\cdot (x+2)\cdot \left(\frac{x-4}{x-4} \right)\cdot \left[\frac{x-5}{(x-5)^{2}} \right][/tex] Modulative and commutative properties/Associative property

6) [tex]\frac{(x+4)\cdot (x+2)}{3\cdot (x-5)}[/tex]  [tex]\frac{a^{m}}{a^{n}} = a^{m-n}[/tex]/[tex]\frac{a}{b}\times \frac{c}{d} = \frac{a\cdot c}{b\cdot d}[/tex]/Definition of division/Result

Answer:

median = 5

range = 2

mean = 11

Step-by-step explanation:

We need to determine whether the test is for the population proportion, mean, or standard deviation, and what distribution should be applied for the critical value.

a) This test is for the population mean since we are comparing the sample mean to a hypothesized population mean. To find the critical value, we apply the t-distribution since the population standard deviation is un known, and we are working with a sample.

b) The test statistic for comparing means is calculated using the formula:

t = (sample mean - hypothesized mean) / (sample standard deviation / √sample size).

Substituting the given values, we have:

t = (750 - 745) / (30 / √225) = 5 / 2 = 2.5.

c) To find the p-value, we compare the absolute value of the test statistic to the critical value associated with the significance level. Since the significance level α is not specified, we cannot directly calculate the p-value without knowing the critical value or α.

d) Without the critical value or the specific significance level, we cannot determine the conclusion of the test. The conclusion is drawn by comparing the p-value to the significance level α. If the p-value is less than α, we reject the null hypothesis, and if the p-value is greater than α, we fail to reject the null hypothesis.

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Answer:

The answer is 3,100

Step-by-step explanation:

If you subtract the 8,500 from his parents and his football scholarship you get 4,900 and then take the 1,800 from his saved money, You get what he still needs, which is 3,100.

Random samples of size 50 are taken from this population, and the number of fully vaccinated individuals in each sample, represented by the variable X, follows an approximately binomial distribution with n = 50 and p = 0.727.

(a) Using the binomial formulas, the mean (μ) of X is calculated as np, which is 50 * 0.727 = 36.4, rounded to the nearest tenth. The standard deviation (σ) is given by the square root of np(1-p), which becomes √(50 * 0.727 * 0.273) ≈ 4.1.(b) To determine the values within 3 sigma of the mean, we calculate 3 times the standard deviation (3σ) and find the range around the mean: 36.4 ± 3 * 4.1, resulting in the range of approximately 24.1 to 48.7. Therefore, the common numbers of fully vaccinated people expected in samples of this size, given the 72.7% vaccination rate, would fall within this range.(c) By using appropriate commands on a calculator or technology, the following probabilities can be determined:

The probability of one sample having exactly 35 fully vaccinated people is obtained from the binomial distribution as P(X = 35), which can be calculated using the binompdf command.

The value of P(X ≤ 25) can be found using the binomcdf command, representing the probability of having 25 or fewer fully vaccinated people in a sample. The probabilities should be reported to four decimal places for accuracy.

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Answer:

(4x+5y=7

y=3x+9

4x+5(3x+9)=7

4x+15x+45=7

19x=7-45

19x= -38

19×/19=-38/19

x= -2

whlie y=3x+9

y=3(-2)+9

y= -6+9

y=3 end solution

x= -2,y= 3

The constant c that produces a solution satisfying the initial condition y(6) = 4 is c = 24.

To find the constant c that satisfies the given equation and the initial condition, we need to substitute the function y = x² + (c/x²) into the differential equation and solve for c. The given equation is xy' * 2y = 4x².

First, we differentiate y with respect to x to find y',

y = x² + (c/x²)

y' = 2x - (2c/x³)

Now we substitute y and y' into the differential equation,

xy' * 2y = 4x²

x(2x - (2c/x³)) * 2(x² + (c/x²)) = 4x²

Simplifying,

2x³ - 2cx + 4c = 4x²

Rearranging,

2x³ - 4x² - 2cx + 4c = 0

Now we substitute x = 6 and y = 4 (from the initial condition y(6) = 4) into the equation,

2(6)³ - 4(6)² - 2(6)c + 4c = 0

432 - 144 - 12c + 4c = 0

288 - 8c = 0

8c = 288

c = 36

Therefore, the constant c that produces a solution satisfying the initial condition y(6) = 4 is c = 36.

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Answer:

One Chilly Night, Elijah Was Sleeping but Then Woke Up. He Realized It Was 45 Degrees According To the AC Monitor, So He Changed it To 70 Degrees But The Monitor Broke And Changed to -6 DEGREES!!

Step-by-step explanation:

A situation that can be represented by the integer - 6 was envisaged.

An integer is a whole number (not a fractional number) that can be positive, negative, or zero.

One day maths teacher decided to take a random test

There were 16 questions each of 4 marks and 1 mark deduction for each wrong answer, with no penalties for non-attempt.

David was so good at guessing. He guessed all the 16 answers out of which 2 were correct and 14 were incorrect.

So, the total marks that David got = 4(2)-1(14) = 8-14 =-6

Thus, a situation that can be represented by the integer - 6 was envisaged.

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Answer:

y = 2

Step-by-step explanation:

y = x

x = 2

Plug in the given value.

y = (2)

This is already simplified.

Therefore, when x = 2, y = 2.

Hope this helps!

Answer:

Your answer would be A

Step-by-step explanation: