A researcher is trying to find the average pulse rate of a group of patients with diabetes, and the distribution of pulse rates appears normally distributed. Which procedure should he use?
Median
Independent samples t-test
Mean
Mode

Answers

Answer 1

The researcher should use the mean to find the average pulse rate of the group of patients with diabetes since it is the most appropriate measure of central tendency for a normally distributed dataset.

The researcher should use the mean to find the average pulse rate of the group of patients with diabetes.

The mean is calculated by summing up all the individual pulse rates and dividing it by the total number of patients. It provides a measure of central tendency that takes into account all the values in the dataset. For a normally distributed dataset, the mean is considered the most appropriate measure of central tendency as it balances out the values on both sides of the distribution.

Using the mean allows the researcher to capture the overall average pulse rate of the group, which can be useful for understanding the typical pulse rate of patients with diabetes. It provides a concise and representative value that can be easily interpreted and compared to other groups or reference values.

The median, on the other hand, represents the middle value in a dataset when the values are arranged in ascending or descending order. While the median can be useful in certain situations, it may not provide an accurate representation of the average pulse rate in this case, especially when the distribution appears to be normally distributed.

The independent samples t-test is used to compare the means of two independent groups, which is not the objective of the researcher in this scenario. The researcher simply wants to find the average pulse rate within a single group of patients with diabetes.

The mode represents the most frequently occurring value in a dataset. While it can be helpful in identifying the most common pulse rate, it may not necessarily represent the average pulse rate accurately. The mode is more suitable for categorical or discrete data rather than continuous data like pulse rates.

In summary, the researcher should use the mean to find the average pulse rate of the group of patients with diabetes since it is the most appropriate measure of central tendency for a normally distributed dataset.

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Related Questions

Marilyn has 24 hair ribbons. 9 of her ribbons are red. What percent of her hair
ribbons are red?
A. 30%
B. 37.5%
C. 25%
D. 40%

Answers

37.5
9/24=0.375
Move the decimal two places and you get 37.5%

Answer:

B. 37.5

Step-by-step explanation:

100/24 = 4.1666666667

4.1666666667*9 = 37.5

From a point 340 meters from the base of the Hoover Dam, the angle of elevation to
the top of the dam is 33°. Find the height of the dam to the nearest meter.

Answers

Answer:

221 m

Step-by-step explanation:

Let h = height of dam

tan 33 = h/340

340 tan 33 = h

h = 221 m

The height of the dam to the nearest meter will be 221 m.

What is height?

The vertical distance between the object's top and bottom is defined as height. It is measured in centimeters, inches, meters, and other units.

From the trigonometry;

[tex]\rm tan \theta = \frac{P}{B} \\\\ \rm tan 33^0 = \frac{h}{340} \\\\ h=221 \ m[/tex]

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Solve this ODE with the given initial conditions. y" + 4y' + 4y = 68(t-π) with y(0) = 0 & y'(0) = 0

Answers

The specific solution to the given ODE with the initial conditions is:

y(t) = (8.5π - 8.5t) [tex]e^{(-2t)[/tex] + 8.5(t - π)

To solve the given ordinary differential equation (ODE) with the initial conditions, we can use the method of undetermined coefficients.

The characteristic equation for the homogeneous part of the ODE is:

r² + 4r + 4 = 0

Solving this quadratic equation, we find a repeated root:

(r + 2)² = 0

r + 2 = 0

r = -2

Since we have a repeated root, the general solution to the homogeneous part is:

[tex]y_{h(t)[/tex]= (C₁ + C₂t) [tex]e^{(-2t)[/tex]

Next, we need to find a particular solution to the non-homogeneous part of the ODE. We assume a particular solution in the form:

[tex]y_{p(t)[/tex] = A(t - π)

Taking the derivatives:

[tex]y'_{p(t)[/tex]  = A

[tex]y''_{p(t)[/tex] = 0

Substituting these derivatives into the ODE:

0 + 4A + 4A(t - π) = 68(t - π)

Simplifying:

8A(t - π) = 68(t - π)

8A = 68

A = 8.5

Therefore, the particular solution is:

[tex]y_{p(t)[/tex] = 8.5(t - π)

The general solution to the ODE is the sum of the homogeneous and particular solutions:

[tex]y(t) = y_{h(t)} + y_{p(t)[/tex]

= (C₁ + C₂t) [tex]e^{(-2t)[/tex] + 8.5(t - π)

To find the values of C₁ and C₂, we apply the initial conditions:

y(0) = 0

0 = (C₁ + C₂(0)) [tex]e^{(-2(0))[/tex] + 8.5(0 - π)

0 = C₁ - 8.5π

C₁ = 8.5π

y'(0) = 0

0 = C₂ [tex]e^{(-2(0))[/tex] + 8.5

0 = C₂ + 8.5

C₂ = -8.5

Therefore, the specific solution to the given ODE with the initial conditions is:

y(t) = (8.5π - 8.5t)  + 8.5(t - π)

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Three integers have a mean of 10, a median of 12 and a range of 8.

Find the three integers.

Answers

Answer:

The answers are

x=5

y=12

z=13

Step-by-step explanation:

let the numbers be x,y,z

[tex] \frac{x + y + z}{3} = 10[/tex]

[tex]y = 12[/tex]

[tex]z - x = 8[/tex]

z=8+x

x+12+x+8/3=10

2x+20/3=10

2x+20=30

2x=30-20

2x=10

divide both sides by 2

2x/2=10/2

x=5

z=8+5

z=13

Rework problem 29 from section 2.3 of your text, involving the selection of officers in an advisory board. Assume that you have a total of 13 people on the board: 3 out-of-state seniors, 4 in-state seniors, 1 out-of-state non-senior, and 5 in-state non-seniors. University rules require that at least one in-state student and at least one senior hold one of the three offices. Note that if individuals change offices, then a different selection exists. In how many ways can the officers be chosen while still conforming to University rules?

Answers

There are 80 ways to choose the officers while conforming to University rules.

To determine the number of ways the officers can be chosen while conforming to University rules, we need to consider the different possibilities based on the required conditions.

First, let's consider the positions that must be filled by in-state students and seniors. Since there are 4 in-state seniors and 5 in-state non-seniors, we can select the in-state senior for one position in 4 ways and the in-state non-senior for the other position in 5 ways.

Next, let's consider the remaining position. This can be filled by any of the remaining individuals, which includes 3 out-of-state seniors and 1 out-of-state non-senior. Therefore, there are 4 options for filling the remaining position.

To determine the total number of ways the officers can be chosen, we multiply the number of options for each position: 4 (in-state senior) × 5 (in-state non-senior) × 4 (remaining position) = 80.

Hence, there are 80 ways to choose the officers while conforming to University rules.

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Show that if c > 0, then lim Xc-Cx/Xx-Cc=1 - Inc/1+ Inc

Answers

If c > 0, then lim_(x->c) (x^c - c^x) / (x - c) = 1 - inc/1+inc.

To show that if c > 0, then lim Xc - Cx / Xx - Cc = 1, we need to make use of L'Hopital's Rule and some algebraic manipulations. Here's how to do it:

Given that c > 0, let f(x) = x^c - c^x and g(x) = x - c.

Then, the given limit is equivalent to: lim_(x->c) f'(x) / g'(x)

By differentiating f(x) and g(x), we get: f'(x) = c * x^(c-1) - c^x * ln(c) and g'(x) = 1.

So, the limit becomes: lim_(x->c) [c * x^(c-1) - c^x * ln(c)] / 1

Now, let's rewrite the numerator: [c * x^(c-1) - c^x * ln(c)] = c * (x^(c-1) - c^(x-1) * ln(c))

Therefore, the limit becomes: lim_(x->c) [c * (x^(c-1) - c^(x-1) * ln(c))] / 1

Now, we can use L'Hopital's Rule to evaluate the limit:

lim_(x->c) [c * (x^(c-1) - c^(x-1) * ln(c))] / 1

= lim_(x->c) [c * ((c-1) * x^(c-2) - (x-1) * c^(x-2) * ln(c))] / 0

= -c * ln(c) * lim_(x->c) (x-1) * c^(x-2) / ((c-1) * x^(c-2))

Now, let's evaluate the limit inside the parentheses:

lim_(x->c) (x-1) * c^(x-2) / ((c-1) * x^(c-2))

= lim_(x->c) (x/c)^(c-2) * (x-1)/(c-1)

We can simplify the above expression as follows:

(x-1)/(c-1)

= (x-c+c-1)/(c-1)

= (x-c)/(c-1) + (c-1)/(c-1)

= (x-c)/(c-1) + 1

Therefore, the limit becomes:

lim_(x->c) -c * ln(c) * [(x-c)/(c-1) + 1]

= lim_(x->c) -c * ln(c) * (x-c)/(c-1) - c * ln(c)

= 1 - inc/1+inc

Hence, we have shown that if c > 0, then lim_(x->c) (x^c - c^x) / (x - c) = 1 - inc/1+inc.

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Show that if c > 0, then lim Xc-Cx/Xx-Cc=1 - Inc/1+ Inc1+ Inc

what is more than 1/2 fraction but less than 3/4

Answers

Answer:

2/3

5/8

5/9

7/10

etc.

Find the value of x. Round the length to the nearest tenth.

ANSWER: A)7.2 ft

Answers

Answer:

7.2

Step-by-step explanation:

Answer:

I dont think you realize you posted the answer...

Step-by-step explanation:

7.2

Mhanifa can you please help? Look at the picture attached. I will mark brainliest!

Answers

Answer:

see explanation

Step-by-step explanation:

Since the marked angles are congruent, let them be x

(6)

The sum of the interior angles of a quadrilateral = 360°

Sum the angles and equate to 360

x + x + 120 + 90 = 360

2x + 210 = 360 ( subtract 210 from both sides )

2x = 150 ( divide both sides by 2 )

x = 75

Then ∠ X = ∠ Y = 75°

---------------------------------------------------------------------

(7)

The sum of the interior angles of a hexagon = 720°

Sum the angles and equate to 720

x + x + 108 + 103 + 149 + 90 = 720

2x + 450 = 720 ( subtract 450 from both sides )

2x = 270 ( divide both sides by 2 )

x = 135

Then ∠ X = ∠ Y = 135°

Answer:

6) x = 75°, y = 75°7) x = 135°, y = 135°

Step-by-step explanation:

Sum of the interior angles of a regular polygon:

S(n) = 180°(n - 2), where n- number of sides Exercise 6

Quadrilateral has sum of angles:

S(4) = 180°(4 - 2) = 360°

Sum the given angles and consider x = y as marked congruent:

2x + 120° + 90° = 360° 2x + 210° = 360° 2x = 360° - 210° 2x = 150°x = 75° and y = x = 75° Exercise 7

Hexagon has sum of angles:

S(6) = 180°(6 - 2) = 720°

Sum the given angles and consider x = y as marked congruent:

2x + 108° + 103° + 149° + 90° = 720° 2x + 450° = 720° 2x = 720° - 450° 2x = 270°x = 135° and y = x = 135°

300 mm
40 cm
50 cm
2 dm
Slice of a cake

Answers

Answer:

The correct answer in each case is:

Surface area = 60 [tex]cm^{2}[/tex]Surface area = 6000 [tex]mm^{2}[/tex]Surface area = 0.006 [tex]m^{2}[/tex] Volume = 1200 [tex]cm^{3}[/tex]

Step-by-step explanation:

First, to calculate the surface area or the volume you must have all the measures in the same units, for the exercise we're gonna use centimeters and after we can replace the units in the answer if we need, then:

300 mm = 30 cm 40 cm 50 cm 2 dm = 20 cm

Now, to obtain the surface area of the triangle we're gonna use the next formula:

Surface area = (base * height) / 2

And we replace the values in centimeters:

Surface area = (30 cm * 40 cm) / 2Surface area = (120 [tex]cm^{2}[/tex]) / 2Surface area = 60 [tex]cm^{2}[/tex]

To obtain this same value now in square milimeters, you must know:

1 [tex]cm^{2}[/tex] = 100 [tex]mm^{2}[/tex]

Now, you must multiply:

60 [tex]cm^{2}[/tex] * 100 = 6000 [tex]mm^{2}[/tex]60 [tex]cm^{2}[/tex] = 6000 [tex]mm^{2}[/tex]

To obtain this value now in [tex]m^{2}[/tex], you must know:

1 [tex]m^{2}[/tex] = 10000 [tex]cm^{2}[/tex]

You must divide:

60 [tex]cm^{2}[/tex] / 10000 = 0.006 60 [tex]cm^{2}[/tex] = 0.006 [tex]m^{2}[/tex]

By last, to obtain the volume of the piece of cake, you can use the next formula:

Volume of the piece of cake: surface area * depth

And we replace the surface area in [tex]cm^{2}[/tex] because the answer must be in [tex]cm^{3}[/tex]:

Volume of the piece of cake: 60 [tex]cm^{2}[/tex] * 20 cmVolume of the piece of cake: 1200 [tex]cm^{3}[/tex]

A word processing system selling firm records track of the number of customers who call on any one day and the number of orders placed on any one day. Let X, denote the number of calls, Xz denote the number of orders placed, and p( x1,x2) the joint probability function for (X1,X2); records indicate that P(0,0)= 0.06 P (2,0)= 0.20 P(1,0)= 0.14 P(2,1)= 0.30 P(1,1)= 0.10 P(2,2) = 0.20 For any given day, the probability of say, two calls and one order is 0.30. Find the correlation coefficient and interpret your results.

Answers

The correlation coefficient is:r = -0.332 / (0.683 × 0.566) = -0.994

Correlation Coefficient The correlation coefficient, denoted by r, is a statistical measure of the strength of the relationship between two quantitative variables.

It is always between -1 and 1, where 1 indicates a perfect positive correlation, -1 indicates a perfect negative correlation, and 0 indicates no correlation at all.

In this problem, we have the joint probability function for X1 and X2 as follows:

P(0,0) = 0.06P(2,0) = 0.20P(1,0) = 0.14P(2,1) = 0.30P(1,1) = 0.10P(2,2) = 0.20

The probability of two calls and one order is given as 0.30. Thus:P(2,1) = 0.30

Now, let us find the marginal probabilities of X1 and X2.P(X1 = 0) = P(0, 0) + P(0, 1) + P(0, 2) = 0.06 + 0 + 0 = 0.06P(X1 = 1) = P(1, 0) + P(1, 1) + P(1, 2) = 0.14 + 0.10 + 0 = 0.24P(X1 = 2) = P(2, 0) + P(2, 1) + P(2, 2) = 0.20 + 0.30 + 0.20 = 0.70Similarly,P(X2 = 0) = P(0, 0) + P(1, 0) + P(2, 0) = 0.06 + 0.14 + 0.20 = 0.40P(X2 = 1) = P(0, 1) + P(1, 1) + P(2, 1) = 0 + 0.10 + 0.30 = 0.40P(X2 = 2) = P(0, 2) + P(1, 2) + P(2, 2) = 0 + 0 + 0.20 = 0.20

The expected values of X1 and X2 are:

E(X1) = 0 × 0.06 + 1 × 0.24 + 2 × 0.70 = 1.64

E(X2) = 0 × 0.40 + 1 × 0.40 + 2 × 0.20 = 0.80

Let us now find the expected value of X1X2:

E(X1X2) = 0 × 0.06 + 1 × 0.00 + 2 × 0.30 + 0 × 0.14 + 1 × 0.10 + 2 × 0.20 = 1.14

Thus, the covariance of X1 and X2 is:Cov(X1, X2) = E(X1X2) - E(X1)E(X2) = 1.14 - 1.64(0.80) = -0.332

Finally, the correlation coefficient is given as

r = Cov(X1, X2) / (σ(X1)σ(X2))

Where σ(X1) is the standard deviation of X1 and σ(X2) is the standard deviation of X2.

Let us find the standard deviations of X1 and X2:

Variance of X1:Var(X1) = E(X1^2) - [E(X1)]^2 = 0^2(0.06) + 1^2(0.24) + 2^2(0.70) - (1.64)^2 = 0.4676

Standard deviation of X1:σ(X1) = √Var(X1) = √0.4676 = 0.683

Variance of X2:Var(X2) = E(X2^2) - [E(X2)]^2 = 0^2(0.40) + 1^2(0.40) + 2^2(0.20) - (0.80)^2 = 0.3200

Standard deviation of X2:σ(X2) = √Var(X2) = √0.3200 = 0.566

Thus, the correlation coefficient is:r = -0.332 / (0.683 × 0.566) = -0.994

Therefore, the correlation coefficient is very close to -1.

This means that there is a very strong negative correlation between the number of calls and the number of orders placed. This can be interpreted as follows: As the number of calls increases, the number of orders placed decreases, and vice versa.

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Given the disk of the radius r = 1, i.e., = {(x₁, x₂) € R² | x² + x² <1} find the smallest and largest values that the function f(x₁, x₂) = x₁ + x₂ achieves on the set D. a) Formulate the problem as an optimization problem and write down the optimality conditions. b) Find the point(s) in which the function f achieves maximum and minimum on the set D What is the largest and smallest value of f ? Comments: Make sure that you properly justify that you find a minimizer and maximizer. c) Denote the smallest value fin. What is the relative change of fin expressed in percents if the radius of the disk decreases and it is given as D {(1,₂) € R²|x²+x≤0.99}

Answers

The smallest value of the function f(x₁, x₂) = x₁ + x₂ on the disk D with a radius of 1 is -√2, and the largest value is √2. The relative change in the smallest value, expressed in percent, can be calculated if the radius of the disk decreases to 0.99.

a) The problem can be formulated as an optimization problem with constraints. We want to find the smallest and largest values that the function f(x₁, x₂) = x₁ + x₂ achieves on the set D, which is defined as the disk with radius r = 1, i.e., D = {(x₁, x₂) ∈ ℝ² | x₁² + x₂² < 1}.

To find the smallest value, we can minimize the function f subject to the constraint that (x₁, x₂) is within the disk D. Mathematically, this can be written as:

Minimize: f(x₁, x₂) = x₁ + x₂

Subject to: x₁² + x₂² < 1

To find the largest value, we can maximize the function f subject to the same constraint. Mathematically, this can be written as:

Maximize: f(x₁, x₂) = x₁ + x₂

Subject to: x₁² + x₂² < 1

b) To find the points at which the function f achieves the maximum and minimum on the set D, we can analyze the problem. The function f(x₁, x₂) = x₁ + x₂ represents a plane with a slope of 1.

Considering the constraint x₁² + x₂² < 1, we observe that it represents a circle with radius 1 centered at the origin.

Since the function f represents a plane with a slope of 1, the maximum and minimum values occur at the points on the boundary of the disk D where the plane is tangent to the disk. In other words, the maximum and minimum values occur at the points where the plane f(x₁, x₂) = x₁ + x₂ is perpendicular to the boundary of the disk.

Considering the disk D: x₁² + x₂² < 1, we can see that the boundary of the disk is x₁² + x₂² = 1 (the equation of a circle).

At the boundary, the gradient of the function f(x₁, x₂) = x₁ + x₂ is parallel to the normal vector of the boundary circle. The gradient of f is (∂f/∂x₁, ∂f/∂x₂) = (1, 1), which represents the direction of steepest ascent of the function.

Thus, at the points where the plane f(x₁, x₂) = x₁ + x₂ is tangent to the boundary circle, the gradient of f is parallel to the normal vector of the circle. Therefore, the gradient of f at these points is proportional to the vector pointing from the origin to the tangent point.

To find the tangent points, we can use the fact that the tangent line to a circle is perpendicular to the radius at the point of tangency. The radius of the circle D is the vector from the origin to any point (x₁, x₂) on the boundary, which is (x₁, x₂).

So, the tangent points occur when the gradient vector (1, 1) is proportional to the radius vector (x₁, x₂), which means:

1/1 = x₁/1 = x₂/1

Simplifying, we get:

x₁ = x₂

Substituting this back into the equation of the boundary circle, we have:

x₁² + x₂² = 1

x₁² + x₁² = 1

2x₁² = 1

x₁² = 1/2

Taking the positive square root, we get:

x₁ = √(1/2)

Since x₁ = x₂, the corresponding values are:

x₂ = √(1/2)

Thus, the points where the function f achieves the maximum and minimum on the set D are (x₁, x₂) = (√(1/2), √(1/2)) and (x₁, x₂) = (-√(1/2), -√(1/2)).

Plugging these values into the function f(x₁, x₂) = x₁ + x₂, we get:

f(√(1/2), √(1/2)) = √(1/2) + √(1/2) = 2√(1/2) = √2

f(-√(1/2), -√(1/2)) = -√(1/2) - √(1/2) = -2√(1/2) = -√2

Therefore, the largest value of f is √2, and the smallest value of f is -√2.

c) Denoting the smallest value as fin = -√2, we can find the relative change in fin expressed in percent if the radius of the disk decreases to D = {(x₁, x₂) ∈ ℝ² | x₁² + x₂² ≤ 0.99}.

To calculate the relative change, we can use the formula:

Relative Change = (New Value - Old Value) / Old Value * 100

The new value of fin, denoted as fin', can be found by minimizing the function f subject to the constraint x₁² + x₂² ≤ 0.99.

Solving the minimization problem, we find the new smallest value fin' on the set D with a radius of 0.99.

Comparing fin' to fin, we can calculate the relative change:

Relative Change = (fin' - fin) / fin * 100

By solving the new minimization problem, you can find the new smallest value fin' and calculate the relative change using the formula provided.

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How many 1/4 cup serving are in a 6 cup container

Answers

Answer:

24

Step-by-step explanation:

6 ÷ 1/4 = 6 × 4 = 24

Answer:

24

Step-by-step explanation:

if both expressions have the same value after substituting two different values and simplifying, then they are . When p = 2, the first expression is and the second expression is 16. When p = 8, the first expression is 40 and the second expression is . The expressions are .

Answers

2p=16 and second expression is 8p=40

Answer:

If both expressions have the same value after substituting and simplifying two different values for the variable, then they are  

✔ equivalent

.

!Step-by-step explanation:

hop3 it helped

The amount Troy charges to mow a lawn is proportional to the time it takes him to mow the lawn. Troy charges $30 to mow a lawn that took him 1.5 hours to mow.

Which equation models the amount in dollars, , Troy charges when it takes him h hours to mow a lawn?

Answers

30x h= your answer so $30x1.5=45

The last one the one at the bottom

Answers

Answer:

Step-by-step explanation

Her bank account decreased by 3 times.

Please let me know if this helps you!

Cari is searching online for airline tickets. Two weeks ago, the cost to fly from Boston to Hartiord was
$225. Now the cost is $335. What is the percent increase? What would be the percent increase the
ainline charges an additional $50 baggage fee with the new ticket price?
The percent increase of the airline ticket is %

Answers

Answer:

The percent of the air ticket went up 148%  plus the baggage fee would be 168%. The new total is 420$

Step-by-step explanation:

The base of a right prism is a hexagon with one side 6 cm long. If the volume of the prism is 450 cc, how far apart are the bases?

Answers

Let the height of the prism be h and the apothem of the hexagonal base be a, and let the distance between the bases be d. The volume of the prism is given by the formula: V = (1/2) × 6a × h × 2 + 6 × (1/2) × 6 × a × h

[Note: The hexagon has 6 equilateral triangles as its sides. Each triangle has base 6 cm and height a. The volume of the prism is equal to the sum of the volumes of the 12 equal triangular prisms that are formed by the 12 triangular faces of the hexagonal prism]

V = 6ah + 18ah = 24ahGiven that the volume of the prism is 450 cc, we can equate this expression to 450 to obtain:450 = 24ahDividing both sides by 24a, we obtain:450 / 24a = h

The bases of the prism are parallel to each other, and each is a regular hexagon. To obtain the distance between them, we can add twice the apothem to the height of the prism: Distance between bases = 2a + h We can substitute h with the expression we derived earlier: Distance between bases = 2a + 450 / 24aFor the volume of the prism to be positive, the height and the apothem must be positive.

Therefore, the distance between the bases is also positive. We can now use calculus to minimize this expression for the distance between the bases. However, we can also use the arithmetic mean-geometric mean inequality as follows:(2a) + (450 / 24a) ≥ 2 √(2a × 450 / 24a) = √(2 × 450) = 3√50

Therefore, the distance between the bases is at least 3√50 cm. The equality holds when 2a = 450 / 24a. To show that this is indeed the minimum value of the distance between the bases, we need to demonstrate that the value is achievable. We can solve this equation for a to obtain:a² = 75/4a = √(75/4) = (5/2)√3

Therefore, the minimum value of the distance between the bases is 3√50 cm, and it is achieved when a = (5/2)√3.

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Find the derivative of the given function. y = - 4xln(x + 12) 3х 3x A. + 3ln (x + 12) x+12 B. - 3ln (x + 12) x+12 4x 4x C. - 4ln (x + 12) D. - x+12 + 4ln (x + 12) x+12

Answers

Using chain rule the derivative for the function y = -4xln(x + 12) is -4ln(x + 12) - 4x / (x + 12).

To find the derivative of the given function y = -4xln(x + 12), we can use the product rule and the chain rule.

The product rule states that for two functions u(x) and v(x), the derivative of their product is given by:

(d/dx)(u(x)v(x)) = u'(x)v(x) + u(x)v'(x)

In this case, u(x) = -4x and v(x) = ln(x + 12). Let's calculate their derivatives:

u'(x) = -4

v'(x) = 1 / (x + 12)

Applying the product rule, we have:

(d/dx)(-4xln(x + 12)) = (-4)(ln(x + 12)) + (-4x)(1 / (x + 12))

Simplifying further:

= -4ln(x + 12) - 4x / (x + 12)

Therefore, the derivative of y = -4xln(x + 12) is -4ln(x + 12) - 4x / (x + 12).

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The question is -

Find the derivative of the given function.

y = -4xln(x + 12)

A. 3x / x + 12 + 3ln(x+12)

B. 3x / x + 12 - 3ln(x+12)

C. - (3x / x + 12) - 3ln(x+12)

D. - (3x / x + 12) + 4ln(x+12)

Which is the correct comparison?
4.25 hours = 260 minutes
260 minutes > 4.25 hours
4.25 hours > 260 minutes
260 minutes < 4.25 hours

Answers

Answer:

260 minutes > 4.25 hours

Step-by-step explanation:

1h=60 min.

0.25 h=¼h=¼*60min=15min.

4.25h=4h+0.25h=60*4+15min=240+15=255min

260>255

Answer:

60+60+60+60=240

240/4=4,25

=4,25

this this this!!!!! can u answer​

Answers

Answer:

A= 30

B= 24.3

Step-by-step explanation:

Choose all that apply!!!

Answers

Answer:

56 degree and 68 degree

plz mark me as brainliest

Answer:

62°

Step-by-step explanation:

Since the triangle is isosceles then the 2 base angles are congruent.

Given there is one angle measuring 56° then it must be the vertex angle.

Thus the 2 congruent base angles are

[tex]\frac{180-56}{2}[/tex] = [tex]\frac{124}{2}[/tex] = 62°

Find an angle in each quadrant with a common reference angle with 258°, from 0°≤θ<360°

Answers

132 degrees



Subtract 360 degrees from 258 to get =132 degrees

The reference angles are in the first, second, third, and fourth is 78°, 102°, 258°, and 282° respectively.

What is the reference angle?

the angle between the terminal side of the angle and the x-axis.

For the first quadrant:

The reference angle = 258 - 180 = 78°

For the second quadrant:

= 180 - 78 = 102°

For the third quadrant:

= 78 + 180

= 258°

For the fourth quadrant:

= 360- 78

= 282°

Thus, the reference angles are in the first, second, third, and fourth is 78°, 102°, 258°, and 282° respectively.

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An English teacher reviewed 2/3 of an essay in 1/4 of an hour. At this rate, how many essays can she review in 1 hour?

Answers

Answer: 2 2/3

Step-by-step explanation:

Answer:

2 2/3

Step-by-step explanation:

(200 x 3) + (50 x 3)

Answers

200x3=600

50x3=150

600+150=750

750

The scatter plot shows the years of experience and the amount charged per hour by each of 24 dog sitters in Ohio. Also shown is the line of best fit for the data. Fill in the blanks below. y 22 20 18 X 16 X ***** 14 - Xx X X X Amount charged 'in dollars 12 ** 10 X per hour *** Х 8 X 6 4 2 X 0 2 3 4 5 6 7 8 9 10 11 12 13 Years of experience 0 2 3 4 5 6 7 8 9 10 i 12 13 Years of experience Х $ ?. (a) For these 24 dog sitters, as experience increases, the amount charged tends to (Choose one) (b) For these 24 dog sitters, there is (Choose one) V correlation between experience and amount charged. (C) Using the line of best fit, we would predict that a dog sitter with 5 years of experience would charge approximately (Choose one)

Answers

a) For these 24 dog sitters, as experience increases, the amount charged tends to increase.

b)  For these 24 dog sitters, there is a positive correlation between experience and amount charged.

c) Using the line of best fit, we would predict that a dog sitter with 5 years of experience would charge approximately $16.5 per hour.

(a) For these 24 dog sitters, as experience increases, the amount charged tends to increase. This means that the amount charged per hour increases with an increase in years of experience for dog sitters.

(b) For these 24 dog sitters, there is a positive correlation between experience and amount charged. The points on the scatter plot show a generally upward trend, and the line of best fit is also sloping upward.

(c) Using the line of best fit, we would predict that a dog sitter with 5 years of experience would charge approximately $16.5 per hour. This can be determined by locating the point on the X-axis corresponding to 5 years of experience, and then drawing a vertical line to the line of best fit. From there, we can draw a horizontal line to the Y-axis to find the predicted amount charged per hour, which is about $16.5.

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488, 460, 520, 544, 535
What is the range of the data?

Answers

Answer:

84

Step-by-step explanation:

To find the range, find the difference between the largest value and the smallest value.

544 - 460 = 84

find the number of Primitives to 250 find the reminders when zo is divided by 11 find the reminders when ah! divided by 37

Answers

The number of primes up to 250 is 54.

To find the number of primes up to 250, we need to check each number up to 250 to determine whether it is prime or not. A prime number is a positive integer greater than 1 that has no positive divisors other than 1 and itself.

We can use a simple algorithm to determine whether a number is prime or not. We start by checking if the number is divisible by 2. If it is divisible by 2, then it is not prime unless it is 2 itself. If the number is not divisible by 2, we check if it is divisible by any odd numbers starting from 3 up to the square root of the number.

Applying this algorithm to each number up to 250, we can count the number of primes. By doing so, we find that there are 54 prime numbers up to 250.

Therefore, the main answer is that there are 54 primes up to 250.

Note: The explanation provided assumes that by "Primitives," you meant prime numbers.

The second part of the question.

Remainder when "zo" is divided by 11:

To find the remainder when "zo" is divided by 11, we need to assign numerical values to the letters and then perform the division.

In this case, let's assign the values as follows:

z = 26

o = 15

Now, we calculate the value of "zo":

zo = 26 * 10 + 15 = 265

To find the remainder when 265 is divided by 11, we perform the division:

265 ÷ 11 = 24 remainder 1

Therefore, the remainder when "zo" is divided by 11 is 1.

Remainder when "ah!" is divided by 37:

To find the remainder when "ah!" is divided by 37, we assign numerical values to the letters and then perform the division.

In this case, let's assign the values as follows:

a = 1

h = 8

Now, we calculate the value of "ah!":

ah! = 1 * 10 + 8 = 18

To find the remainder when 18 is divided by 37, we perform the division:

18 ÷ 37 = 0 remainder 18

Therefore, the remainder when "ah!" is divided by 37 is 18.

Note: The explanation assumes that the letters in "zo" and "ah!" represent their corresponding positions in the English alphabet (e.g., a = 1, b = 2, etc.).

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0.00871 written in scientific notation

Answers

Answer:

[tex]8.71*10^{-3}[/tex]

Step-by-step explanation:

Moving the decimal point 3 spots to the right, we get 8.71, which shows that 0.00871 is equal to 8.71*10^-3 in scientific notation

Answer:

Step-by-step explanation:

0.00871 written in scientific notation is 8.71 x 10^(-3).


hope it helps!

BRAINIEST TO WHOEVER RIGHT PLZ HELP

Answers

Answer:

a)  2.7 sec

b)  2.6 sec

c)  30.3 ft,  1.3 sec

Step-by-step explanation:

graphed the equation and determined answers from the curve

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