A solution is prepared by mixing 50.00 mL of 0.100 M HNO3 and 100.00 ml of 0.200 M Ca(NO3)2. Calculate the molarity of the nitrate ion in the final solution.

Answers

Answer 1
its 0.100 M HNO3 formula
Answer 2

A solution is prepared by mixing 50.00 mL of 0.100 M HNO3 and 100.00 ml of 0.200 M Ca(NO3)2. The molarity of the nitrate ion in the final solution is 0.1667 M.

What is molarity ?

The amount of a substance in a specific volume of solution is known as its molarity (M). The number of moles of a solute per liter of a solution is known as molarity. The molar concentration of a solution is another name for molarity.

Molarity (M), which is determined by dividing the solute's mass in moles by the volume of the solution in liters, is the most widely used unit to express solution concentration: liters of solution/moles of solute equals M. One liter of a solution with a 1.00 molar concentration (1.00 M) contains 1.00 moles of solute.

50.0 mL x 0.100 M

= 5.00 millimoles of HNO3

=0.00500 moles

100.0 mL x 0.200 M

= 20.0 millimoles of HNO3

=0.0200 moles

The whole solution has a volume of 150.0 mL

= 50.0+100.0

= 150

The whole solution contains 25.0 millimoles of HNO3

= 5.00+20.0

= 25

millimoles / mL = Molarity

25.0 / 150.0

= 0.1667 M

moles / Liters = Molarity

0.0250 / 0.1500

= 0.1667 M

Thus, The molarity of the nitrate ion in the final solution is 0.1667 M.

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Related Questions

If an atomic number of an element is 24, the number of protons the Atom has is

A. 24
B. 12
C. 189
D.51.996

Answers

Explanation:

i think the answer is A ........ hope this helps

If the Bunsen burner gave a luminous flame and some soot was deposited on
the tube, what effect would this situation have on the calculated % of oxygen ?​

Answers

Explanation:

If bunsen burner gave a luminous flame then there will deposition of soot at the bottom of the test tube which is actually pure carbon.

This deposition of soot actually depicts that there is incomplete combustion reaction that has taken place.

Also, the deposition of soot will provide a limited supply of oxygen to the reaction that has been calculated.

Therefore, in order to avoid any formation of soot it is advisable to adjust the burner flame till it produces a blue flame.

Which is a fossil fuel?
O A. Coal
O B. Biomass
O C. Geothermal
O D. Nuclear

Answers

Answer:

coal

Explanation:

fossil fuels are formed by natural process.

Coal is the fossil fuel. A is correct.

Fossil fuels are non renewable source of energy that means once they get finished we will not be able to use them. Hence it is very important for us to find an alternate like a renewable source of energy like sunlight so that we will not have to depend on these fossil fuels and will not have to tolerate the pollution happening by them as well.

Given options are-

A. Coal

B. Biomass

C. Geothermal

D. Nuclear

Therefore, Coal is the fossil fuel. A is correct.

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If only 0.225 g of Ca(OH)2 dissolves in enough water to give 0.100 L of aqueous solution at a given temperature, what is the Ksp value for calcium hydroxide at this temperature

Answers

Answer: The [tex]K_{sp}[/tex] value for calcium hydroxide at this temperature is [tex]1.08 \times 10^{-4}[/tex].

Explanation:

Given: Mass of [tex]Ca(OH)_{2}[/tex] = 0.225 g

Volume = 0.100 L

As moles is the mass of substance divided by its molar mass.

So, moles of [tex]Ca(OH)_{2}[/tex] (molar mass = 74 g/mol) is calculated as follows.

[tex]Moles = \frac{mass}{molar mass}\\= \frac{0.225 g}{74 g/mol}\\= 0.003 mol[/tex]

Molarity is the number of moles of substance present in a liter of solution.

Hence, molarity of given solution will be as follows.

[tex]Molarity = \frac{moles}{Volume (in L)}\\= \frac{0.003 mol}{0.1 L}\\= 0.03 M[/tex]

The equation for dissociation of  [tex]Ca(OH)_{2}[/tex] is as follows.

[tex]Ca(OH)_{2} \rightarrow Ca^{2+} + 2OH^{-}[/tex]

This means that [tex][Ca^{2+}] = 0.03[/tex] and [tex][OH^{-}] = 2 \times 0.03 = 0.06[/tex]. Hence, [tex]K_{sp}[/tex] value for this reaction is calculated as follows.

[tex]K_{sp} = [Ca^{2+}][OH^{-}]^{2}\\= (0.03) \times (0.06)^{2}\\= 1.08 \times 10^{-4}[/tex]

Thus, we can conclude that the [tex]K_{sp}[/tex] value for calcium hydroxide at this temperature is [tex]1.08 \times 10^{-4}[/tex].

How much energy is required to vaporize 2 kg of copper? Use the table below
and this equation: Q = mLvapor-

Answers

Answer:

9460 kj

Explanation:

just did it

Measure the initial temperature of the water to the nearest 0.1°C. Record in the data table.
Initial Temp. of Metal
Initial Temp. of water
Initial Temp. of Both

Subtract to find the temperature changes for the water and the metal

Water
Metal ​

Answers

The heat capacity of the metal is calculated using the formula:

Heat capacity = quantity of heat/(mass * temperature difference)

What is temperature?

The temperature of a substance is the degree of hotness or coldness of that substance.

Temperature difference between substances enables heat flow.

Heat flows from hot to cold bodies.

In the given experiment, to determine the heat capacity of a metal, the temperature difference is obtained by substracting the initial and final temperatures.

The heat capacity of the metal is then calculated using the formula:

Heat capacity = quantity of heat/mass * temperature difference

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1. How did the change of stress (adding or removing reactants or products) cause a shift in the equilibrium system of your solutions? Use data to support your answer. Make sure you discuss all four stress changes: a. Adding a reactant b. Adding a product c. Removing a reactant d. Removing a product

Answers

Answer:

If reactant or product is removed, the equilibrium shifts to make more reactant or product, respectively, to make up for the loss.

If the reactant or product is removed, the equilibrium shifts to make more reactant or product, to make up for the loss.

Choose the group that corresponds to each element.
Alkali Metal
Alkali earth metal
Halogen
Noble gas

Answers

The group corresponding to alkali metal, alkali earth metal, halogen, and noble gas is IA,IIA, 17, 18 group respectively.

Alkali metals have one outermost electron in their valence shell. They are kept under oil and are in the group IA of the periodic table.Alkaline earth metals have two outermost electrons in their valence shell. Examples are beryllium, magnesium, etc.Halogens have seven electrons in their outermost shells. They are in the periodic table in group 17 naming fluorine to iodine.Noble gas is the one that has fulfilled electronic configuration and doesn't react with any other compound.This is present in group 18 of periodic table.

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2) A 0.77 mg sample of nitrogen gas reacts with chlorine gas to form 6.61 mg of a nitrogen
chloride compound. What is the empirical formula of the nitrogen chloride compound?

Answers

Answer:

NCl₃

Explanation:

From the question given above, the following data were obtained:

Mass of nitrogen (N) = 0.77 mg

Mass of chlorine (Cl) = 6.61 mg

Empirical formula =?

The empirical formula of the compound can be obtained as follow:

N = 0.77 mg

Cl = 6.61 mg

Divide by their molar mass

N = 0.77 / 14 = 0.055

Cl = 6.61 / 35.5 = 0.186

Divide by the smallest

N = 0.055 / 0.055 = 1

Cl = 0.186 /0.055 = 3

Therefore, the empirical formula of the compound is NCl₃

In Atom, what is a heavier sub-atomic particle than the others and explain why​

Answers

The nucleons are havier in sub atomic particle like neutrons and protons.

fun fact i read in a book even 1cm³ of nucleons are around 2 million Kg which you can't pick up by hand even by machines like buldozer.

You need 520. mL of a 10. % (m/v) glucose solution. If you have a 25% (m/v) glucose solution on hand, how many milliliters do you need

Answers

Answer:

The answer is "208 mL".

Explanation:

[tex]C_1 = 25\% \ \frac{m}{v}\\\\C2 = 10\% \ \frac{m}{v}\\ \\V_1= 520\ \ mL\\\\V_2=?[/tex]

In dilutions of different concentration, its initial volume for glucose solution V1 can be obtained by using the following formula, i.e.

[tex]\to C_1V_1 = C_2V_2\\\\\to V_1 = \frac{C_2V_2}{C_1} \\\\= \frac{10 \times 520 }{ 25}\\\\ = 208 \ mL[/tex]

The solution of 520 mL [tex]10\%\ \ (\frac{m}{v})[/tex] final glucose solution thus requires 208 mL of glucose solution of [tex]25\%\ \ (\frac{m}{v})[/tex].  

Pea plants have green seeds only if a plant receives an allele for green seeds from each of its parents. What kind of allele produces green seeds in pea plants?

Your answer:


Hybrid

Dominant

Recessive

Mutated

Answers

Answer:If two heterozygous parents with a genotype of Yy are crossed, the possible combination of genotypes in their offspring would be YY, Yy, Yy, and yy. Therefore, the genotypic ratio of the offspring produced is 1:2:1.

Explanation:If two heterozygous parents with a genotype of Yy are crossed, the possible combination of genotypes in their offspring would be YY, Yy, Yy, and yy. Therefore, the genotypic ratio of the offspring produced is 1:2:1.

Please help, any and all is very much appreciated!

Answers

1. True
2. False
3. False
4. True
5. True
6. True
7. All of the above
8. According to their reactivity with other substances
9. Standard temp and pressure
10. Flush your eyes in the eye flush for 15-20 minutes

Which area of chemistry best links the use of titanium and plastics in artificial bone and joint replacements?

A) environmental chemistry
B) materials chemistry
C) agricultural chemistry
D) physical chemistry

Answers

Answer:I think it’s material chemistry

Explanation:

Answer:

Material chemistry.

Explanation:

Artificial bone and joint replacements is not environmental, it does not have anything to do with farming or such things, and physical chemistry has to do with chemical reactions which is not going on. This leaves materials chemistry.

If 23.6 mL of 0.200 M NaOH is required to neutralize 10.00 mL of a H3PO4 solution , what is the concentration of the phosphoric acid solution

Answers

Answer:

The correct answer is 0.157 M.

Explanation:

The chemical equation of the mentioned reaction is, 3NaOH + H₃PO₄ ⇄ Na₃PO₄ + 3H₂O The molarity of NaOH given is 0.2 M, the volume of NaOH given is 23.6 ml or 23.6 × 10⁻³ L. The moles of NaOH can be determined by using the formula, Moles of NaOH = Volume of NaOH × Molarity Moles of NaOH = 23.66 × 10⁻³ L × 0.2 M = 0.00472 moles Based on the reaction, 3 moles of NaOH needs 1 mole of H₃PO₄. So, 0.00472 moles of NaOH will require, 0.00472/3 = 0.0015733 moles.

The concentration or molarity of the H₃PO₄ will be, [H₃PO₄] = Moles of H3PO4/Volume of H₃PO₄ in liters (Volume of H₃PO₄ given is 10 ml of 10 × 10⁻³L) = 0.0015733 moles/ (10 × 10⁻³ L) = 0.157 M

what does litmus do when it is put into sodium hydroxide?
PLEASE ANSWER ME FAST PLEASE

Answers

Answer:

The red litmus turns to blue

Explanation:

Hope it helps

As the diagram model the processo se reproduction lomon) formand change formation Sexual reproduction results in a child that is different from its parents because

A. the child receives all of is genetic information from its mother

B. the child produces its own genetic information once it is formed

C. the child receives half of is genetic information from each parent

D. the child receives all of it's genetic information from it's father there ​

Answers

Answer:

The answer is C. the child receives half of is genetic information from each parent

Explanation:

hope this helps enjoy

Why is carbon used to date things that were once living?
A. Carbon is not toxic to living things.
B. The half-life of carbon depends on age.
C. The amount of carbon is easy to measure.
D. Living things take in carbon from food.

Answers

Answer:

a - carbon is not toxic to living things

Explanation:

The reason carbon dating works is that the fresh carbon-14 gets mixed in with the rest of the carbon in the atmosphere and, since it's chemically identical to regular carbon, gets worked into whatever is presently absorbing atmospheric carbon

) Dinitrogen Tetroxide partially decomposes according to the following equilibrium: N2O4 (g) 2NO2 (g) A 1.00-L flask is charged with 0.400 mol of N2O4. At equilibrium at 373 K, 0.0055 mol of N2O4 remains. Keq for this reaction is __________.

Answers

Answer: The value of [tex]K_{eq}[/tex] for this reaction is 1.578.

Explanation:

Given: Initial moles of [tex]N_{2}O_{4}[/tex] = 0.4 mol

Volume = 1.00 L

Therefore, initial concentration of [tex]N_{2}O_{4}[/tex] is calculated as follows.

[tex]Concentration = \frac{moles}{volume}\\= \frac{0.4}{1.0 L} mol\\= 0.4 M[/tex]

Now, ICE table for the given reaction equation is as follows.

                     [tex]N_{2}O_{4}(g) \rightleftharpoons 2NO_{2}[/tex]

Initial:               0.4               0

Change:           -x                +2x

Equib:  0.4 - x = 0.0055       2x

Hence, the value of x is calculated as follows.

0.4 - x = 0.0055

x = 0.4 - 0.0055

= 0.3945

Now, the [tex][NO_{2}][/tex] is calculated as follows.

2x = [tex][NO_{2}][/tex] = [tex]2 \times 0.3945 = 0.789[/tex]

Therefore, [tex]K_{eq}[/tex] for the given reaction is calculated as follows.

[tex]K_{eq} = \frac{[NO_{2}]^{2}}{[N_{2}O_{4}]}\\= \frac{(0.789)^{2}}{(0.3945)}\\= 1.578[/tex]

Thus, we can conclude that [tex]K_{eq}[/tex] for this reaction is 1.578.

Convert 2.0 micrometer to centimeters and to inches

Answers

Answer:

2x10⁻⁴cm and 7.9x10⁻⁵ inches

Explanation:

Micrometer, μm, is an unit of length. Could be related with another units of lenght as, for example:

1.0μm = 1x10⁻⁴cm

1.0μm = 3.93701x10⁻⁵ inches

That means, 2.0μm are:

2.0μm * (1x10⁻⁴cm / 1μm) = 2x10⁻⁴cm

And:

2.0μm * (3.93701x10⁻⁵ inches / 1μm) = 7.9x10⁻⁵ inches

Draw the major organic product(s) for the reaction. The starting material is a benzene ring with one substituent. The substituent is a nitrogen bonded to a hydrogen and a carbonyl that is bonded to a methyl group. THis reacts with tert butyl bromide and A l b r 3 to give the product.

Answers

Answer:

See Explanation

Explanation:

In electrophilic aromatic substitution, the benzene ring undergoes substitution when it is reacted with suitable electrophiles.

The products of electrophilic aromatic substitution depends on the substituents already present on the benzene ring. Some substituents activate the ring towards electrophilic substitution and direct the incoming electrophile to the ortho and para positions on the ring while some substituents deactivate the benzene ring towards electrophilic substitution and direct the incoming electrophlle to the meta position on the ring.

The amide substituent is moderately activating and is an ortho, para director hence the products shown in the mage attached to this answer.

(1.21 x 10^-3 + 1.3 x 10^-3) x 6.453 x 10^2 =

Answers

Answer:

1.61

Explanation:

How many moles of zinc are in 0.535 g ?*

Answers

Answer:

0.00818 moles

Explanation:

HELP PLS HELP i rlly need help omg

Answers

I think g (sorry if it’s wrong)

Each of the following models represents particles present before and after a
chemical reaction which correctly shows conservation of mass during a
reaction?

Answers

Answer:

D

Explanation:

According to the law of conservation of mass, matter can neither be created nor destroyed. The implication of this is that the total mass of reactants should be equal to the total mass of products.

There should be equal masses of reactants and products on both sides of the reaction equation. This most important condition is only satisfied by option D.

an organic compound that contains only carbon and hydrogen and a triple bond (all the other bonds are single bonds) is classified as:
a. alkane
b. alkene
c. alkyne
d. arene

Answers

Answer:

c. alkyne.

Explanation:

Hello there!

In this case, according to the attached file, it turns out possible for us to say that alkanes have only single-bonded carbon atoms, alkenes have two double-bonded carbon atoms and alkynes have two triple-bonded carbon atoms.

In such a way, according to the aforementioned definition, we infer that that an organic compound that contains only carbon and hydrogen and a triple bond (all the other bonds are single bonds) is classified as c. alkyne.

Regards!

Explain why the coefficients on the left side of the equation don’t necessarily equal the coefficients on the right side of the equation. Is this possible if mass is being conserved?

Answers

Answer:

Explanation:

Short answer: Yes.

The coefficients may not be conserved, but mass always has to be. Take this equation as an example

2 Mg3P2 ===>   6Mg + P4

There is a 2 on the left side and 6 and 1 on the right. I hope you mean that the coefficient 2 is not equal to 7.

But let's look a little closer. You have to look at the molecular structure of the left and right side.

2Mg3P2 has 6 Mgs and 4 Ps on the left side.

6Mg is on the right. They are free standing.

P4    has 1 molecule consisting of 4 Ps.

Everything balances.

This is a terrific question to be asking. You need to understand the internal balance numbers vs the molecular ones on the out side.

That sounds like a bit of gobbledygook and it takes a bit of study.

2 Mg3P2 means that Mg3P2 is written twice.

Mg3P2 ==> "3 Mg2+   +  2P3+   and there is another one written the same way.

Mg3P2 ==> "3 Mg2+   +  2P3+  

Limitations of Pearson rule

Answers

Hope this helps!!
Pearson correlation limitations
Limit: Coefficient values can range from +1 to -1, where +1 indicates a perfect positive relationship, -1 indicates a perfect negative relationship, and a 0 indicates no relationship exists..
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The law of partial pressures was developed by ___________.

Answers

Answer:

John Dalton

Explanation:

What caused carbon dioxide to decrease in the air (abiotic matter) of the biodome?

Answers

Answer:

As organisms release energy during cellular respiration, carbon dioxide is produced from the carbon in energy storage molecules. ... Carbon dioxide in the biodome decreased because decomposers decreased which means there was a decrease in cellular respiration overall.

Explanation:

Carbon dioxide is "a colorless, odorless gas that is present in the atmosphere and is formed when any fuel containing carbon is burned".

What is atmosphere?

Atmosphere is "a mixture of gases that includes about 78% nitrogen and 21% oxygen at Earth's surface".

What is fuel?

Fuel is "a substance which upon combustion produces a usable amount of energy".

When the population of decomposer decreased, the amount of carbon dioxide in the biodome decreased drastically. The carbon dioxide that used to be in the air (abiotic matter) is now in another part of the ecosystem and the carbon remained constant.

Hence, Carbon dioxide decreased in the air (abiotic matter) of the biodome.

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