Answer:
c. 7.7 eV
Explanation:
The computation of the photon emitted is shown below:
Given that
From level 1 to level 3, the energy absorbed by electrons is 11.8eV
And, when from level 3 to level3, the energy released by electron is 4.1eV
So, from level 2 to level 1, the energy released is
= 11.8 - 4.1
= 7.7
= 7.7eV
Hence, the third option is correct
The same is to be considered
And, the other options are wrong
Which best describes her speed and velocity? (There are 60 seconds in 1 minute.) Her speed is 4.4 m/s, and her velocity is 0 m/s. Her speed is 1.1 m/s, and her velocity is 0 m/s. Her speed is 0 m/s, and her velocity is 2400 m/s. Her speed is 4.4 m/s, and her velocity is 4.4 m/s.
Answer:
A
Explanation:
Yw :)
Answer:
a
Explanation:
A sound level meter 6.0 m from a jet engine measures 110.0 dB. the sound power output of the jet engine , assuming uniform spherical spreading of the sound and neglecting absorption in the air is___W
dyed I don't it sorryvplss
Which of the following elements is more reactive than the
Answer:
you need to attach a picture so I can answer it
Where can you find most of earths freshwater
Answer:
HEY PLS LISTEN THERE IS A GUY GOING AROUND TELLING GIRLS TO JOIN HIS ZOOM ON BRAINLY AND MAKING ACCS AND STUFF TO MAKE PEOPLE JOIN HIS ZOOM.THE CODE IS 387 187 6280 HES A PEDXO AND TELLING GIRLS TO SHOW THERE BODIES TO HIM. SO PLEASE BE AWARE! COPY AND PASTE THIS TO SPREAD THE WORD!
Explanation:
HEY PLS LISTEN THERE IS A GUY GOING AROUND TELLING GIRLS TO JOIN HIS ZOOM ON BRAINLY AND MAKING ACCS AND STUFF TO MAKE PEOPLE JOIN HIS ZOOM.THE CODE IS 387 187 6280 HES A PEDXO AND TELLING GIRLS TO SHOW THERE BODIES TO HIM. SO PLEASE BE AWARE! COPY AND PASTE THIS TO SPREAD THE WORD!
Icecaps and Glaciers
Explanation:
Icecaps and Glaciers hold 68 percent of fresh water on earth :)
Different colors of light travel at greatly different speeds, even in the same medium.
True
False
Answer:
True
Explanation:
Different colors of light travel at greatly different speeds even in the same medium. This is what causes the dispersion of light through a prism.
In a vacuum, the speed of light is the same For other mediums, the speed of light depends on the properties of that medium. Light propagation depends on the medium it passes through because the photons of light interacts with the medium. The frequency of light remains the same in all medium but the speed and wavelength depends on the medium.Answer:Its false just took the test.
Explanation:
If the marshmallows represent the atoms in the substance, which change of state is Freida modeling Freida wants to model the way atoms move when a substance changes its state. To do this, Freida makes a pyramid of marshmallows. Then, she knocked down the pyramid causing the marshmallows to fall. O melting O freezing O condensation O deposition
Answer: Melting
Explanation:
When Frieda made a pyramid of marshmallows, she was representing the atoms in a solid substance as the atoms are clumped together and unable to move.
When she then knocks it down, she is showing the movement of atoms in a liquid substance as they are now freer than they were before. The process by which substances go from solid to liquid is melting.
Answer: Melting
Explanation: When Frieda made a pyramid of marshmallows, she was representing the atoms in a solid substance as the atoms are clumped together and unable to move.
When she then knocks it down, she is showing the movement of atoms in a liquid substance as they are now freer than they were before. The process by which substances go from solid to liquid is melting.
7. 100 Joules of work was done to move an object with a force of 15 N. How far did the
object move?
Answer:Distance=6.67 (rounded)
Explanation: Work = Force x Distance.
100 Joules of work= force of 15 N x Distance (?)
The work equation given above can be rearranged to find force or distance if the other variables are known:
Distance=Work / force
Distance=100Joules/15 N
Distance=6.67 (rounded)
By quadrupling the mass of the body hanging on the thread what will become the period of oscillation?
Well, the tension in the thread will probably quadruple, but the hanging body will continue to just hang there.
The question gives us no evidence that it is doing any oscillating, and there's no reason for it to start just because it suddenly got heavier.
A small lead ball, attached to a 1.75-m rope, is being whirled in a circle that lies in the vertical plane. The ball is whirled at a constant rate of three revolutions per second and is released on the upward part of the circular motion when it is 2.1 m above the ground. The ball travels straight upward. In the absence of air resistance, to what maximum height above the ground does the ball rise?
Answer:
h = 57.6 m
Explanation:
First, we find the linear speed of the ball while in circular motion:
v = rω
where,
v = linear speed of ball = ?
r = radius of circle = length of rope = 1.75 m
ω = angular speed = (3 rev/s)(2π rad/1 rev) = 18.84 rad/s
Therefore,
v = (1.75 m)(18.84 rad/s)
v = 32.98 m/s
Now, we apply the 3rd equation of motion on the ball, when it breaks:
2gh = Vf² - Vi²
where,
g = - 9.8 m/s² (negative sign due to upward motion)
h = height covered = ?
Vf = Final Velocity = 0 m/s (since, the ball finally stops at highest point for a moment)
Vi = Initial Velocity = 32.98 m/s
Therefore,
2(- 9.8 m/s²)h = (0 m/s)² - (32.98 m/s)²
h = ( - 1088.12 m²/s²)/( - 19.6 m/s²)
h = 55.5 m
since, the ball was initially at a height of 2.1 m from ground. So, the total height from ground, will now become:
h = 55.5 m + 2.1 m
h = 57.6 m
A bicycle travels at a velocity of 2.33 m/s, and has a displacement of -58.3 m. How much time did it take?
Answer:
The time will be: 25.02 seconds
Explanation:
Given
A bicycle travels at a velocity of 2.33 m/s.
i.e.
v = 2.33 m/sand
displacement = d = 58.3 mAs we know the formula to find the time
Time = Displacement/Velocity
= d/v
= 58.3/2.33
= 25.02 seconds
Therefore, the time will be: 25.02 seconds
What is the hydrostatic pressure at the bottom of a vessel in which water 30 cm high and gasoline 10 cm high have been poured? (density = 800)
Answer:
P = 3136 Pa
Explanation:
The formula to apply in this case is :
P= rho*g*d where;
rho = density = 800
g = acceleration due to gravity =9.8 m/s²
d= depth = 10+30 =40 cm = 0.4 m
P= hydrostatic pressure
P= 800 * 9.8 * 0.4
P = 3136 Pa
The table below shows the right ascensions of two stars at a location.
Name of star Right ascension
Star 1 2 hours
Star 2 4 hours 20 minutes
HELP ME PLS
What is the degree difference between the two stars that rise at the location?
20 degrees
30 degrees
35 degrees
60 degrees
Answer:
Star 1 2 hours
35
Explanation:
Answer:
the answer would be 35 degrees :))))
Explanation:
it was the correct on the quiz,,, good luckk :3!!
Which statements about our solar system are false?
Our solar system is made up of the Sun and other objects that orbit the Sun.
The Sun is the only star in our solar system.
Dwarf planets have several other bodies in their path orbiting the Sun just as they do.
The Kuiper Belt is between Uranus and Neptune.
A large number of irregularly shaped comets are located in a vast ring between the orbits of Mars and Jupiter.
Answer:
c
and d
Explanation:
Where does the name basketball come from?
Group of answer choices
ball and basket
round and ball
ball and net
basket and court
A 5 kg block is pulled along a horizontal surface by a 28N force to the right. Compute
the acceleration of the block if the surface is
a)
smooth,
b)
rough with a coefficient of kinetic friction of 0.23 between the block and the
surface.
[ 5.6ms 2,3.4ms]
(a) Without friction, Newton's second law tells us the net horizontal force is such that
28 N = (5 kg) a
a = (28 N) / (5 kg)
a = 5.6 m/s²
(b) With friction (magnitude f ), we get a net horizontal force such that
28 N - f = (5 kg) a
and a net vertical force such that
n - w = 0
since the block is only being pulled horizontally, where w is the weight of the block and n is the magnitude of the normal force. So
n = w = (5 kg) (9.8 m/s²)
n = 49 N
Friction is proportional to the normal force such that
f = µ n
We're given µ = 0.23, so
f = 0.23 (49 N)
f ≈ 11 N
Solve for a :
28 N - 11 N = (5 kg) a
a = (17 N) / (5 kg)
a = 3.4 m/s²
A car staring from rest accelerates at 12 m/s^2, what distance did it travel in 7 seconds? (Show work)
A child of mass m is released from rest at the top of a water slide,
at height h=8.8 m above the bottom of the slide. Assuming that the slide
is frictionless because of the water on it, find the child’s speed at the bottom of the slide
Answer:
From the concept of energy conservation, Ei=Ef
Explanation:
mgh=1/2mv^2
=> v=
\sqrt{2gh}2gh
=
\sqrt{2 \times 9.8 \times 8.8}2×9.8×8.8
=
\sqrt{172.28}172.28
=13.12m/s.
How do you think
the reactivity of aluminum compares
to the reactivity of other metals?
A more reactive metal will displace a less reactive metal from a compound. ... Because aluminum is more reactive than iron, it displaces iron from iron(III) oxide. The aluminum removes oxygen from the iron(III) oxide: iron is reduced.
A more reactive metal will displace a less reactive metal from a compound because aluminum is more reactive than iron, it displaces iron from iron(III) oxide.
What is compound?Compound has been combination of two or more than two different elements which are said to be chemically bond. So the compound has to be held by the chemical bond. A compound cannot be separate by the physical separation and after that the mixture you cannot be identified that it has compound or not.
Mixture has been combination of the two or more than different chemical elements which has not chemically bond. A mixture has been the physical combination of two or more elements in which the individual identities are remained and it also mixed by the solutions, suspension and colloids.
A compound cannot be separate by the physical separation and after that the mixture you cannot be identified that it has compound or not.Mixture has been combination of the two or more than different chemical elements which has not chemically bond.
Therefore, A more reactive metal will displace a less reactive metal from a compound because aluminum is more reactive than iron, it displaces iron from iron(III) oxide.
Learn more about compound here:
https://brainly.com/question/13516179
#SPJ1
What happens during free association? A person talks about a dream, making connections by openly talking. A therapist helps you learn empathy for others. You explore the role of the brain's functions in the dream. You discuss your feelings and analyze your emotions.
Answer:
You discuss your feelings and analyze your emotions.
Explanation:
During free association a therapist or psychoanalyst helps you discuss your feelings and analyze your emotions.
Free association allows patients to discuss their minds freely without any censorship. This helps people to communicate freely without placing any barrier on their free thought pattern. All the thoughts that comes to mind are encouraged to be expressed and spoken.Answer:
In traditional free association, a person in therapy is encouraged to verbalize or write all thoughts that come to mind. Free association is not a linear thought pattern. Rather, a person might produce an incoherent stream of words, such as dog, red, mother, and scoot. They may also jump randomly from one memory or emotion to another.
THE ANSWER IS B
PLEASE MARK BRANIEST
When light of frequency equal to 2.11 x 10^-15 s-1 shines on the surface of gold metal, the kinetic energy of ejected electrons is found to be 5.83 x 10^-19 J. What is the work function of gold?
Answer:
Work function, [tex]W=5.83\times 10^{-19}\ J[/tex]
Explanation:
Given that,
Frequency of light, [tex]f=2.11\times 10^{-15}\ Hz[/tex]
Kinetic energy of the ejected electrons, [tex]E_k=5.83\times 10^{-19}\ J[/tex]
We need to find the work function of the gold. Let it is W.
Using Einstein's photoelectric equation as follows :
[tex]W=hf-E_K\\\\W=6.63\times 10^{-34}\times 2.11\times 10^{-15}-5.83\times 10^{-19}\\\\W=-5.83\times 10^{-19}\ J[/tex]
So, the work function of gold is [tex]5.83\times 10^{-19}\ J[/tex].
Which refers to any disturbance that carries energy from one place to another through matter and space?
frequency
wave
hertz
pitch
Answer:
I think the answer is frequency
Answer:
wAvE
Explanation:
i have my ways
I
5. An electric field has a strength of 10.0 N/C at a distance of 1.00 m from an unknown charge. At
what distance from the charge does the electric field strength equal 2.50 N/C?
Answer:
The electric field strength is equal to 2.50 newtons per coulomb at a distance of 2 meters.
Explanation:
From Classic Electrostatic Theory, we find that electric field ([tex]E[/tex]), measured in newtons per coulomb, is defined by the following equation:
[tex]E = \frac{F}{q_{O}}[/tex] (1)
Where:
[tex]F[/tex] - Electrostatic force, measured in newtons.
[tex]q_{O}[/tex] - Electric charge, measured in coulombs.
In addition and supposing that phenomena occurs between particles, electrostatic force is modelled after the Coulomb's Law:
[tex]F = \frac{k\cdot q\cdot q_{O}}{r^{2}}[/tex] (2)
Where:
[tex]k[/tex] - Electromagnetic constant, measured in newton-square meters per square coulomb.
[tex]q[/tex], [tex]q_{O}[/tex] - Electric charges, measured in coulomb.
[tex]r[/tex] - Distance between particles, measured in meters.
By applying (2) in (1), we get the following definition of electric field:
[tex]E = \frac{k\cdot q}{r^{2}}[/tex] (3)
Then, we observe that electric field is inversely proportional to the square of the distance. The following relationship is therefore constructed:
[tex]\frac{E_{2}}{E_{1}} = \left(\frac{r_{1}}{r_{2}} \right)^{2}[/tex] (4)
If we know that [tex]E_{1} = 10\,\frac{N}{C}[/tex], [tex]E_{2} = 2.50\,\frac{N}{C}[/tex] and [tex]r_{1} = 1\,m[/tex], then the distance is:
[tex]\left(\frac{E_{2}}{E_{1}} \right)\cdot r_{2}^{2}= r_{1}^{2}[/tex]
[tex]r_{2}^{2}=\left(\frac{E_{1}}{E_{2}} \right)\cdot r_{1}^{2}[/tex]
[tex]r_{2} = r_{1}\cdot \sqrt{\frac{E_{1}}{E_{2}} }[/tex]
[tex]r_{2} = (1\,m)\cdot \sqrt{\frac{10\,\frac{N}{C} }{2.50\,\frac{N}{C} } }[/tex]
[tex]r_{2} = 2\,m[/tex]
The electric field strength is equal to 2.50 newtons per coulomb at a distance of 2 meters.
Explain why increasing the mass of a car affects how the car rolls down a ramp.
Answer:
Q1) Explain why increasing the mass of a car affects how the car rolls down a ramp
Ans1) Weight affects speed down the ramp but it's the mass that affects speed after a car leaves the ramp. Heavier cars have more momentum, so they travel further, given the same amount of friction
I need help lol .........
Answer:
a
Explanation:
The diagram shows a transverse wave at a particular instant. The wave is travelling to the right. The frequency of the wave is 12.5 Hz.
At the instant shown the displacement is zero at the point P.
What is the shortest time to elapse before the displacement is zero at point Q?
A 0.01s
B 0.03s
C 0.08s
D 0.10s
Answer:
0.03
Explanation:
do ghosts exist?!! and whats tye science behind it
Explanation:
ghost do exist and the science behind it is people have experienced paranormal activities
Answer: science has no evidence that ghosts are real
Explanation:
This story makes use of personification as one of the main figures of speech.
What is the frequency of a wave that has a wavelength of 2000 meters and is traveling at 20 m/s?
Answer:
freqiency=velocity/wavelength
ief=20/2000=0.01hz
Two pickup trucks each have a mass of 2,000 kg. The gravitational force between the trucks is 3.00 × 10-5 N. One pickup truck is then loaded with 1,000 kg of bricks. Which of the following would be the new gravitational force between the two trucks?
Answer:
New gravitational force would be: [tex]4.5\,\,\,10^{-5}\,\,\,N[/tex]
Explanation:
Recall the general form of the gravitational force between two objects of masses m1 and m2 separated a distance "d":
[tex]F_g=G\,\frac{m1\,*\, m2}{d^2}[/tex]
which for the 2000 kg trucks becomes:
[tex]F_g=G\,\frac{m1\,*\, m2}{d^2} \\3\,\,\,10^{-5}\,N=G\,\frac{2000\,*\, 2000}{d^2}[/tex]
when we add 1000 kg of bricks to one truck, we get the following unknown force (x) that we need to find:
[tex]F_g=G\,\frac{m1\,*\, m2}{d^2} \\x=G\,\frac{3000\,*\, 2000}{d^2}[/tex]
Now we divide term by term the last equation by the previous one, in order to cancel out common factors to both equation (G, d^2) and get the following equation:
[tex]\frac{x}{3\,\,\,10^{-5}} =\frac{3000}{2000} \\x=\frac{9}{2} \,10^{-5} =4.5\,\,\,10^{-5}\,\,\,N[/tex]
The fire department arrive to a fire in 210 seconds after leaving the fire station to the burning building which is 840m away. How fast did they travel?
Answer: The speed is 4 meters per second or 4 m/s.
Explanation:
First, we have the relationship:
Speed = Distance/Time.
In this case, we know that the fire department arrives to a fire in 210 seconds after leaving the fire station to the burning building which is 840m away, this means that:
Time = 210 seconds
Distance traveled in that time = 840m.
Then the speed is:
Speed = 840m/210s = 4 m/s.
The speed is 4 meters per second.