An airplane is flying south going 440 mph when it hits a crosswind going west at 35 mph, the resultant velocity of the airplane is approximately 439 mph southwest.
Hence, the correct option is B.
To find the resultant velocity of the airplane, we can use vector addition. The airplane's velocity in the south direction is 440 mph, and the crosswind's velocity in the west direction is 35 mph.
To find the resultant velocity, we can treat the velocities as vectors and add them together. Since the airplane is flying in the south direction and the crosswind is in the west direction, we can consider these vectors as negative in the corresponding directions.
Using the Pythagorean theorem, the magnitude of the resultant velocity can be calculated as follows
Resultant velocity = [tex]\sqrt{440^{2} }[/tex] + ([tex]-35^{2}[/tex]))
Resultant velocity = 439.66 mph
Since the resultant velocity is directed to the southwest, we can round the magnitude to the nearest mph and the direction to the nearest cardinal direction. Therefore, the resultant velocity of the airplane is approximately 439 mph southwest.
Hence, the correct option is B.
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determine the pressure drop per 100-m length of horizontal new 0.35-m-diameter cast iron water pipe when the average velocity is 2.9 m/s.
When the average velocity is 2.4 m/s, the horizontal 0.35 meter diameter cast iron water pipe experiences a pressure drop (P) of roughly 16457.14 kPa every 100 meters.
To determine the pressure drop per 100-meter length of a horizontal 0.35-meter diameter cast iron water pipe, we can use the Darcy-Weisbach equation. The equation is as follows:
[tex]\begin{equation}\Delta P = \frac{f \cdot \frac{L}{D} \cdot (\rho \cdot V^2)}{2}[/tex]
where ΔP is the pressure drop, f is the Darcy friction factor, L is the length of the pipe (100 meters in this case), D is the diameter of the pipe (0.35 meters), ρ is the density of water, and V is the average velocity of water.
To calculate the pressure drop, we need to determine the Darcy friction factor. For a rough cast iron pipe, we can estimate the friction factor to be around 0.02.
Using the given values and the estimated friction factor, the calculation becomes:
[tex]\begin{equation}\Delta P = \frac{0.02 \cdot \frac{100}{0.35} \cdot (\rho \cdot 2.4^2)}{2}[/tex]
Since the density of water (ρ) is approximately 1000 kg/m³, we can substitute this value and calculate the pressure drop:
ΔP = [tex]\frac{0.02 \times \frac{100}{0.35} \times 1000 \times 2.4^2}{2}[/tex]
Let's solve the expression to calculate the pressure drop (ΔP) in kilopascals (kPa):
ΔP = [tex]\frac{0.02 \times \frac{100}{0.35} \times 1000 \times 2.4^2}{2}[/tex]
First, let's simplify the expression:
ΔP = [tex]\frac{0.02 \times (285.714) \times (1000 \times 5.76)}{2}[/tex]
= 16457.14
Therefore, the pressure drop (ΔP) per 100-meter length of the horizontal 0.35-meter diameter cast iron water pipe, when the average velocity is 2.4 m/s, is approximately 16457.14 kPa.
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Complete question :
Determine the pressure drop per 100 -m length of horizontal new 0.35−m-diameter cast iron water pipe when the average velocity 2.4 m/s. Δp= kPa
It would not be economical to connect the houses to the National Grid.Give one reason why.
A series RLC circuit consists of a 100 Ω resistor, 0.15 H inductor, and a 30μF capacitor. It is attached to a 120V/60 Hz power line. Calculate: (a) the emf Srms (b) the phase angle φ, (c) the average power loss.
(a) The rms voltage is 120 V, and the frequency of the power line is 60 Hz. The circuit's impedance is calculated to be 100.075 Ω by combining the inductive and capacitive reactances.(b) tanφ = XL - XC /R where XL is the inductive reactance, XC is the capacitive reactance, and R is the resistance.(c) The average power loss is determined by calculating the average power absorbed by the resistor. By using the formula Pavg = ½Irms²R, the average power loss can be determined.
(a) The emf Srms = 120 V and the frequency of the power line is 60 Hz, the impedance of the circuit is calculated as 100.075 Ω, by combining the inductive and capacitive reactances.(b) The phase angle φ = tan^-1((XL - XC)/R) where XL is the inductive reactance, XC is the capacitive reactance, and R is the resistance.(c) The average power loss can be calculated using the formula Pavg = ½Irms²R, where Irms is the current through the resistor, R is the resistance of the circuit. Thus, the average power loss can be found by substituting the values of the variables, i.e., Pavg = ½ (Vrms / Z)^2 × R where Vrms is the rms voltage and Z is the impedance.
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Imagine carefully weighing a metal can, leaving it out in the rain for weeks and weeks
until it was very rusted, and then carefully weighing it again. Would the can be heavier or lighter after it was rusted? Why?
Answer:
The can would be heavier.
Explanation:
The more rust is on the can, (Or object) the more it weights it down.
Answer:
The answer would be heavier, though it depends upon the type of metal. Rusting is essentially corrosion. Rust is often caused by a piece of metal getting soaked in water and then being exposed to oxygen. The rust will add more weight to the can so it becomes heavier.
The potential difference between the ends of a wire is 1.5 V, and it conducts 2.5 A of current. The length of the wire is 2.0 m. What is the resistance of the wire, and what is the magnitude of the electric field in the wire?
The resistance of the wire is 0.6 ohms. The magnitude of the electric field in the wire is 0.75 V/m.
To find the resistance of the wire, we can use Ohm's Law, which states that the resistance (R) is equal to the ratio of the potential difference (V) across a conductor to the current (I) flowing through it:
R = V / I
Given that the potential difference V is 1.5 V and the current I is 2.5 A, we can calculate the resistance:
R = 1.5 V / 2.5 A = 0.6 Ω
Therefore, the resistance of the wire is 0.6 ohms.
To find the magnitude of the electric field in the wire, we can use the relationship between the electric field (E), potential difference (V), and distance (d). For a uniform electric field in a straight wire, the electric field is given by:
E = V / d
Given that the potential difference V is 1.5 V and the length of the wire (distance) d is 2.0 m, we can calculate the magnitude of the electric field:
E = 1.5 V / 2.0 m = 0.75 V/m
Therefore, the magnitude of the electric field in the wire is 0.75 V/m.
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A 7.7 mW laser produces a narrow beam of light. How much energy is contained in a 1.0 m length of its beam? Please show step by step
The energy contained in a 1.0 m length of the beam from a 7.7 mW laser is 7.7 μJ (microjoules).
To calculate the energy contained in the length of the laser beam, we need to use the power of the laser and the formula:
Energy = Power × Time
However, we don't have the time information here. To proceed, we'll assume a continuous wave laser where the power remains constant over time.
Given:
Power of the laser = 7.7 mW (milliwatts)
Length of the beam = 1.0 m
First, we need to convert the power from milliwatts to watts:
7.7 mW = 7.7 × 10^(-3) W
Next, we can calculate the energy using the formula:
Energy = Power × Time
Since we assume a continuous wave laser, we can rearrange the formula as:
Energy = Power × Time = Power × (1 second)
Plugging in the values:
Energy = (7.7 × 10^(-3) W) × (1 second)
The time in this case is 1 second because we assume a continuous beam over that duration. Multiplying the power by 1 second doesn't change the value.
Finally, we can calculate the energy:
Energy = (7.7 × 10^(-3) W) × (1 second)
= 7.7 × 10^(-3) J (joules)
Since the joule is a relatively large unit, it's common to express small energy values in smaller units such as microjoules (μJ).
Converting from joules to microjoules:
1 J = 10^6 μJ
Therefore,
Energy = 7.7 × 10^(-3) J
= 7.7 × 10^(-3) × 10^6 μJ
= 7.7 × 10^(3) μJ
= 7.7 μJ
The energy contained in a 1.0 m length of the beam from a 7.7 mW laser is 7.7 μJ (microjoules).
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I will mark you brainlist!
What mythical creature do you think is possibly real, and not actually a myth? Why?
Examples of mythical creatures: Mermaids/Merman, Fairies/ Pixie, Nymphs, Dragons, Unicorn, Leprechauns, Werewolf, Loch Ness Monster, Sphinx, Centaur, Griffin, Yeti, Pegasus, Basilisk, Chimera, Ghoul, Imp, Gnome, Manticore, Troll, Bigfoot, Phoenix, Vampire etc.
You can choose one that is listed or not listed.
Explanation:
With most of our blue planet covered by water, it's little wonder that, centuries ago, the oceans were believed to hide mysterious creatures including sea serpents and mermaids. Merfolk (mermaids and mermen) are, of course, the marine version of half-human, half-animal legends that have captured human imagination for ages. One source, the "Arabian Nights," described mermaids as having "moon faces and hair like a woman's but their hands and feet were in their bellies and they had tails like fishes."
C.J.S. Thompson, a former curator at the Royal College of Surgeons of England, notes in his book "The Mystery and Lore of Monsters" that "Traditions concerning creatures half-human and half-fish in form have existed for thousands of years, and the Babylonian deity Era or Oannes, the Fish-god ... is usually depicted as having a bearded head with a crown and a body like a man, but from the waist downwards he has the shape of a fish." Greek mythology contains stories of the god Triton, the merman messenger of the sea, and several modern religions including Hinduism and Candomble (an Afro-Brazilian belief) worship mermaid goddesses to this day.
What happens to a digital signal sent using electromagnetic waves as it travels farther from its source?
A. The signal becomes weaker and more difficult to detect
B. The signal slows down and becomes distorted
C. The signal needs to be amplified before it can be detected
D. The digital signal changes to an analog signal.
Answer:
did you find the answer please answer back
Answer:a
Explanation:ap ex verified
) A 1.0kW kettle contains 500g of boiling waterCalculate the time needed to evaporate all the water
in the kettle (specific latent heat of vaporization2.26 MJ kg-1
Answer:
t = 1130 s = 18.83 min
Explanation:
First, we will calculate the energy required to evaporate 500 g of water:
[tex]E = mL[/tex]
where,
E = Energy Required for evaporation of water =?
m = mass of water = 500 g = 0.5 kg
L = Latent heat of vaporization of water = 2.26 MJ/kg = 2260 KJ/kg
Therefore,
[tex]E = (0.5\ kg)(2260\ KJ/kg)\\E = 1130\ KJ[/tex]
Now, we will calculate the time required:
[tex]P = \frac{W}{t}\\\\t = \frac{W}{P}[/tex]
where,
t = time = ?
P = Power of kettle = 1 KW
Therefore,
[tex]t = \frac{1130\ KJ}{1 KW}\\\\[/tex]
t = 1130 s = 18.83 min
A solenoid with an iron core is 25 cm long and is wrapped with 100 turns of wire. When the current through the solenoid is 10 A, the magnetic field inside it is 2.0 T. For this current, what is the permeability of the iron? If the current is turned off and then restored to 10 A, will the magnetic field necessarily return to 2.0 T?
The permeability of the iron is approximately 1.26 x 10^(-3) Tm/A. If the current through the solenoid is turned off and then restored to 10 A, the magnetic field inside the solenoid will not necessarily return to exactly 2.0 T.
The magnetic field inside a solenoid with an iron core can be calculated using the formula:
B = μ₀ * μᵣ * (N * I) / L
Where:
B is the magnetic field (2.0 T)
μ₀ is the permeability of free space (4π x 10^(-7) Tm/A)
μᵣ is the relative permeability of iron (unknown)
N is the number of turns of wire (100)
I is the current through the solenoid (10 A)
L is the length of the solenoid (25 cm = 0.25 m)
To find the relative permeability of iron (μᵣ), we rearrange the formula:
μᵣ = (B * L) / (μ₀ * N * I)
Plugging in the given values:
μᵣ = (2.0 T * 0.25 m) / (4π x 10^(-7) Tm/A * 100 * 10 A)
≈ 1.26 x 10^(-3) Tm/A
Therefore, the permeability of the iron is approximately 1.26 x 10^(-3) Tm/A.
If the current through the solenoid is turned off and then restored to 10 A, the magnetic field inside the solenoid will not necessarily return to exactly 2.0 T.
The relationship between the magnetic field and the current is given by the formula mentioned earlier, and it depends on the permeability of the iron.
If the permeability changes or if there are other factors affecting the magnetic field, the value may vary.
However, if the iron remains unchanged and no other factors significantly affect the magnetic field, it is reasonable to expect that the field will return close to 2.0 T when the current is restored.
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A longitudinal wave is observed. Exactly 6 crests are observed
to move past a given point in 9.1 s. Its wavelength is 2.4 m and
its frequency is 0.66 HZ. What is the speed of the wave?
a binary phase diagram indicates the phases of two elements (at least one of which is metallic) as a function of composition and temperature at atmospheric pressure? (a) true (b) false
The given statement '' A binary phase diagram indicates the phases of two elements (at least one of which is metallic) as a function of composition and temperature at atmospheric pressure '' is True.
A binary phase diagram is a graphical representation that shows the phases of two elements, at least one of which is metallic, as a function of composition and temperature at a specific pressure, typically atmospheric pressure.
The diagram displays different regions representing the stability of different phases (such as solid, liquid, and gas) as the composition and temperature of the system are varied. It is a valuable tool in understanding the behavior and phase transitions in binary systems.
Hence, The given statement '' A binary phase diagram indicates the phases of two elements (at least one of which is metallic) as a function of composition and temperature at atmospheric pressure '' is True.
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In Gay-Lussac's law, the pressure of a gas increases due to an increase in temperature because _____.
(a) the molecules strike the walls of the container less often.
(b) the molecules strike the walls of the container more often.
(c) the molecules get bigger.
(d) there is a decrease in the volume of the container.
(e) there is an increase in the number of gas particles.
Option (b) is the correct answer: the pressure of a gas increases due to an increase in temperature because the molecules strike the walls of the container more often.
Gay-Lussac's law, also known as the pressure law, states that the pressure of a gas is directly proportional to its temperature, assuming the volume and amount of gas remain constant. Therefore, an increase in temperature leads to an increase in pressure. The explanation for this phenomenon lies in the kinetic theory of gases.
According to the kinetic theory, the temperature of a gas is related to the average kinetic energy of its molecules. When the temperature increases, the average kinetic energy of the gas molecules also increases. As a result, the gas molecules move with higher velocities and collide more frequently with the walls of the container.
The frequency of molecular collisions with the container walls is directly related to the pressure exerted by the gas. When the gas molecules strike the walls more often due to increased kinetic energy, the pressure exerted by the gas increases.
Therefore, option (b) is the correct answer: the pressure of a gas increases due to an increase in temperature because the molecules strike the walls of the container more often.
An increase in temperature causes the pressure of a gas to increase because the gas molecules collide more frequently with the walls of the container, as explained by Gay-Lussac's law and the kinetic theory of gases.
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A lens produces a real imag eof a real object.
If lens 1 from part d were placed in exactly the same location as lens 2, would the image produced by lens 1 be larger or smaller than the image produced by lens 2?
If lens 1 from part d were placed in exactly the same location as lens 2, the image produced by lens 1 would be larger than the image produced by lens 2.
The reason is that the magnification produced by a lens depends on the ratio of the image distance to the object distance.
The larger the ratio, the larger the magnification.
Therefore, if lens 1 were placed in the same location as lens 2, it would produce a larger image because lens 1 has a shorter focal length and will bring the image closer to the lens than lens 2.
This will result in a larger image than that produced by lens 2.
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what is the magnifying power of an astronomical telescope using a reflecting mirror whose radius of curvature is 5.7 m and an eyepiece whose focal length is 2.9 cm ? follow the sign conventions.
We get: Magnifying Power = -(2.85 m / 0.029 m) ≈ -98.28. The magnifying power of an astronomical telescope can be calculated using the formula: Magnifying Power = -(fo/fe), where fo is the focal length of the objective (reflecting mirror) and fe is the focal length of the eyepiece.
Given that the radius of curvature of the reflecting mirror is 5.7 m, the focal length can be determined using the relation: Focal Length = Radius of Curvature / 2. So, the focal length of the objective is 5.7 m / 2 = 2.85 m.
Converting the focal length of the eyepiece to meters, we have 2.9 cm = 0.029 m.
Substituting the values into the magnifying power formula, we get: Magnifying Power = -(2.85 m / 0.029 m) ≈ -98.28
The negative sign indicates an inverted image, and the magnitude of the magnifying power suggests that the image appears 98.28 times larger than the object.
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a 17.0-n force stretches a wire 0.650 cm. (a) what force will stretch a similar piece of wire 1.87 cm? (b) a force of 21.3 n is applied to a similar piece of wire. how far will it stretch?
(a) To find the force that will stretch a similar piece of wire to 1.87 cm, we can use the concept of Hooke's Law. Hooke's Law states that the force required to stretch or compress a spring (or wire) is directly proportional to the displacement or change in length.
Given that the original force is 17.0 N and it stretches the wire by 0.650 cm, we can set up a proportion to find the force required for a 1.87 cm stretch.
Let F1 be the original force, x1 be the original displacement, F2 be the unknown force, and x2 be the desired displacement. The proportion can be expressed as:
F1 / x1 = F2 / x2
Substituting the given values, we have:
17.0 N / 0.650 cm = F2 / 1.87 cm
Now we can solve for F2:
F2 = (17.0 N / 0.650 cm) * 1.87 cm
F2 ≈ 48.8 N
Therefore, a force of approximately 48.8 N will stretch a similar piece of wire to 1.87 cm.
(b) To determine how far a similar piece of wire will stretch when a force of 21.3 N is applied, we can use Hooke's Law again.
Using the same variables as before, the proportion can be set up as:
F1 / x1 = F2 / x2
Substituting the given values:
17.0 N / 0.650 cm = 21.3 N / x2
Solving for x2:
x2 = (21.3 N / 17.0 N) * 0.650 cm
x2 ≈ 0.815 cm
Therefore, a force of 21.3 N will cause the wire to stretch approximately 0.815 cm.
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Students push a swing with a hard push and a soft push. Each time the students count how many time the swing moves back and forth before stopping. What variable is tested in this investigation?
a. differences in pushes and pulls
b. force of the push
c. number of time the swing moves
d. distance the swing moves
a piece of 14-gauge copper wire (meaning that it has a diameter of 1.63mm) has a resistance of 0.128 . the resistivity of copper is . what must be the length of the wire?
The length of the copper wire must be approximately 44.2 meters for it to have a resistance of 0.128 ohms, assuming a 14-gauge wire with a diameter of 1.63 mm and using the resistivity of copper.
To find the length of the wire, we can use Ohm's Law, which states that the resistance (R) is equal to the product of the resistivity (ρ), the length (L), and the cross-sectional area (A) of the wire, divided by the diameter (d) of the wire squared.
The formula can be written as:
R = ρ * (L / A)
Resistance (R) = 0.128 ohms
Resistivity of copper (ρ) = (1.68 × 10^-8) ohm-meter (at 20°C)
Diameter (d) = 1.63 mm = 0.00163 meters (converted from millimeters to meters)
We need to find the length (L) of the wire.
To calculate the cross-sectional area (A) of the wire, we can use the formula for the area of a circle:
A = π * (d/2)^2
Plugging in the values, we have:
A = 3.14159 * (0.00163 / 2)^2
A ≈ 2.08 x 10^-6 square meters
Rearranging Ohm's Law to solve for the length (L), we get:
L = (R * A) / ρ
Substituting the given values:
L = (0.128 * 2.08 x 10^-6) / (1.68 x 10^-8)
L ≈ 44.2 meters
The length of the copper wire must be approximately 44.2 meters for it to have a resistance of 0.128 ohms, assuming a 14-gauge wire with a diameter of 1.63 mm and using the resistivity of copper.
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a muon is traveling at 0.996 cc . what is its momentum? (the mass of such a muon at rest in the laboratory is 207 times the electron mass.)
What is its kinetic energy?
The momentum of the muon traveling at 0.996c can be calculated using the relativistic momentum equation, and its kinetic energy is (1/0.089389 - 1) × (207 × [tex]m_e[/tex]) × c².
To calculate the momentum of a muon traveling at 0.996c, we can use the relativistic momentum equation:
p = m × v / √(1 - (v/c)²),
where p is the momentum, m is the mass, v is the velocity, and c is the speed of light.
Given that the mass of the muon at rest in the laboratory is 207 times the electron mass, we can denote the mass of the muon as m = 207 × [tex]m_e[/tex], where [tex]m_e[/tex] is the mass of an electron.
Let's substitute the values into the equation:
p = (207 × [tex]m_e[/tex]) × (0.996c) / √(1 - (0.996c/c)²)
= (207 × [tex]m_e[/tex]) × (0.996c) / √(1 - 0.996²)
= (207 × [tex]m_e[/tex]) × (0.996c) / √(1 - 0.992016)
= (207 × [tex]m_e[/tex]) × (0.996c) / √(0.007984)
= (207 × [tex]m_e[/tex]) × (0.996c) / 0.089389
Now, to calculate the kinetic energy (KE) of the muon, we can use the equation:
KE = (γ - 1) × m × c²,
where γ is the Lorentz factor given by γ = 1 / √(1 - (v/c)²).
Substituting the values:
γ = 1 / √(1 - (0.996c/c²))
= 1 / √(1 - 0.996²)
= 1 / √(1 - 0.992016)
= 1 / √(0.007984)
= 1 / 0.089389
KE = (1/0.089389 - 1) × (207 × [tex]m_e[/tex]) × c²
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A 4000 V equipotential surface is 26.0 cm farther from a positively charged particle than the 5000 V equipotential surface. What is the charge on the particle?
The charge on the positively charged particle is approximately 4.08 x 10^-6 C.
To find the charge on the particle, we can use the relationship between potential difference (V), charge (Q), and distance (r) given by the equation V = kQ/r, where k is the electrostatic constant.
Let's assume the distance between the positively charged particle and the 5000 V equipotential surface is r1 and the distance between the particle and the 4000 V equipotential surface is r2. We are given that r2 is 26.0 cm (or 0.26 m) farther than r1.
Using the equation for potential difference, we can write the following equations:
5000 = kQ/r1
4000 = kQ/r2
Dividing the two equations, we get:
5000/4000 = r2/r1
Simplifying, we find:
r2 = (5/4) * r1
Since r2 is 0.26 m farther than r1, we can write:
r2 = r1 + 0.26
Substituting the expression for r2 in terms of r1 into the above equation, we get:
r1 + 0.26 = (5/4) * r1
Simplifying, we find:
r1 = 0.52 m
Now, substituting this value of r1 into the equation 5000 = kQ/r1, we can solve for the charge Q:
Q = (5000 * r1) / k
Substituting the values of r1 and k (8.99 x 10^9 Nm²/C²), we find:
Q = (5000 * 0.52) / (8.99 x 10^9)
Q ≈ 4.08 x 10^-6 C
Therefore, the charge on the positively charged particle is approximately 4.08 x 10^-6 C.
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A force is applied to the rim of a disk that can rotate like amerry-go-round, so as to change its angular velocity. Its initialand final angular velocities, respectively, for four situationsare: (a) -3 rad/s, 7 rad/s; (b) 3 rad/s, 7 rad/s; (c) -3 rad/s, -7rad/s; (d) 3 rad/s, -7 rad/s. Rank the situations according to thework done by the torque due to the force, greatest first (use onlythe symbols > or =, for example, a>d=b>c).
The ranking of the work done by the torque is a > b > c > d.
What is the work done by the torque?The work done by the torque is equal to the change in rotational kinetic energy of the body.
Mathematically, the formula for torque is given as;
τ = r.F sinθ = Iα
where;
r is the radius of the force actionF is the applied forceI is the moment of inertiaα is the angular accelerationThe formula for angular acceleration is given as;
α = Δω / Δt
where;
Δω is the change in angular speedΔt is the change in time of motionThus, the greater the change in angular speed, the greater the work done by the applied torque.
(a) Δω = 7 rad/s - (-3 rad/s) = 10 rad/s
(b) Δω = 7 rad/s - 3 rad/s = 4 rad/s
(c) Δω = -7 rad/s - (-3 rad/s) = -4 rad/s
(d) Δω = -7 rad/s - 3 rad/s = -10 rad/s
The ranking, a > b > c > d
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A luminous object moves along the optical axis of a concave spherical mirror. If the object approaches the mirror and its focal point, where does the image of the object move? a. It moves perpendicular to the optical axis b. Towards the mirror c. Away from the mirror d. It does not move at all
The image of the object moves towards the mirror as the object approaches the mirror and its focal point.
When an object moves along the optical axis of a concave spherical mirror and approaches the mirror's focal point, the image formed by the mirror undergoes a change in position. This change is characterized by the image moving towards the mirror.
In a concave mirror, the focal point is located on the same side as the object, but at a distance determined by the mirror's curvature. As the object moves closer to the focal point, the reflected rays converge and the image position changes. The image moves towards the mirror as a result.
To understand this phenomenon, we can consider the ray diagram for a concave mirror. As the object approaches the focal point, the rays of light from different points on the object converge towards the focal point after reflection. This convergence leads to the image moving towards the mirror.
When a luminous object moves along the optical axis of a concave spherical mirror and approaches the mirror's focal point, the image of the object moves towards the mirror. This is due to the convergence of reflected rays as the object approaches the focal point, resulting in a change in the image position.
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An object's inertia is its tendency to maintain contact:
1.) Mass.
2.) Position.
3.) Acceleration.
4.) Velocity.
hello! it is velocity.
i say this because, Inertia is the tendency of an object to resist changes in its state of motion. ... The state of motion of an object is defined by its velocity - the speed with a direction.
In an L-R-C series circuit, the resistance is 500 ohms, the inductance is 0.380 henrys, and the capacitance is 2.00×10−2 microfarads.
Part A
What is the resonance angular frequency ω0 of the circuit?
Express your answer in radians per second to three significant figures.
Part B
The capacitor can withstand a peak voltage of 570 volts. If the voltage source operates at the resonance frequency, what maximum voltage amplitude Vmax can the source have if the maximum capacitor voltage is not exceeded?
Express your answer in volts to three significant figures.
The resonance angular frequency (ω0) of the circuit is approximately 3615 radians per second. The maximum voltage amplitude (Vmax) that the source can have without exceeding the maximum capacitor voltage is 570 volts.
Part A:
The resonance angular frequency ω0 of the circuit can be calculated using the formula:
ω0 = 1 / √(LC)
Inductance (L) = 0.380 H
Capacitance (C) = 2.00×10^(-2) μF = 2.00×10^(-8) F
Converting the capacitance to farads:
C = 2.00×10^(-8) F
Plugging the values into the formula, we get:
ω0 = 1 / √(0.380 * 2.00×10^(-8))
= 1 / √(7.6×10^(-9))
= 1 / (2.76×10^(-4))
≈ 3615 rad/s
Therefore, the resonance angular frequency ω0 of the circuit is approximately 3615 radians per second.
Part B:
To determine the maximum voltage amplitude Vmax that the source can have without exceeding the maximum capacitor voltage, we need to consider the relationship between the voltage across the capacitor (Vc) and the voltage across the source (Vs) in an L-R-C series circuit.
At resonance, the voltage across the capacitor (Vc) is maximum, and the voltage across the inductor (VL) and resistor (VR) is minimum.
In this case, the maximum voltage across the capacitor is equal to the maximum voltage across the source.
Peak voltage withstand by the capacitor = 570 V
Therefore, the maximum voltage amplitude (Vmax) that the source can have without exceeding the maximum capacitor voltage is 570 V.
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Is your increase in gravitational potential energy the same in both cases? When Climbing a mountain on a zigzag path and on a straight path
Answer:
The increase in gravitational potential energy is the same in both cases
Explanation:
It is easier to climb a mountain in a zigzag way rather than climbing on a straight line but since the distance is the same ( vertical height ) , mass and gravity is the same. Hence the increase in gravitational potential energy is the same in both cases.
gravitational potential energy = mgh ( same in both cases )
m = mass
g = acceleration due to gravity
h = distance ( vertical height )
describe atmospheric pressure and water pressure
Answer:
The difference is that water is an incompressible fluid — its density is almost constant as the pressure changes — while air is a compressible fluid — its density changes with pressure. ... Atmospheric pressure is the pressure exerted on a surface by the weight of the atmosphere (a compressible fluid) above it
Explanation:
change some words
6)which types of telescopes will be able to detect flux from objects if the telescopes are located on earth? use figure 5.6 for guidance. bold the correct answers.
The types of telescopes that will be able to detect flux from objects when located on Earth include optical telescopes, radio telescopes, and infrared telescopes.
Optical Telescopes: Optical telescopes are specifically designed to gather and focus visible light, enabling the detection of flux from astronomical objects. They come in two main types: refracting telescopes, which use lenses to gather and focus light, and reflecting telescopes, which use mirrors to capture and direct light to a detector or eyepiece.
Radio Telescopes: Radio telescopes detect and analyze radio waves emitted by astronomical objects. They are designed to capture a wide range of radio frequencies and are crucial for studying celestial sources that emit primarily in the radio part of the electromagnetic spectrum. By analyzing the received signals, astronomers can study phenomena such as pulsars, quasars, and cosmic microwave background radiation.
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Which of the following statements about zoroastrianism is false?
A. The people of Persia were allowed to freely accept it or not accept it; itwas not imposed upon them
B. Both Ahurda Mazda, and Angra Mainyu are considered gods
C. It was characterized by the Great Creator and the Destructive Forces
D. It was named after its founder Zoroaster
The false statement about Zoroastrianism is both Ahurda Mazda and Angra Mainyu are considered gods. In Zoroastrianism, Ahura Mazda is considered the supreme deity and the embodiment of good, while Angra Mainyu (also known as Ahriman) represents the embodiment of evil and is not considered a god.
Zoroastrianism is an ancient Iranian religion founded by the prophet Zoroaster (or Zarathustra). It originated in Persia (modern-day Iran) and played a significant role in the development of Persian culture and civilization. Zoroastrianism promotes the belief in the existence of one supreme deity, Ahura Mazda, who represents goodness, truth, and light. The religion also recognizes the presence of destructive forces, personified by Angra Mainyu, representing evil and darkness. Zoroastrianism emphasizes the eternal struggle between these opposing forces and the importance of choosing good over evil. The faith does not impose itself on individuals but allows people to freely accept or reject its teachings.
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what is a waves frequency
Answer:
the number of times the crest of a wave hits a certain point
the more waves, the higher the frequency
Explanation:
Which of the following is NOT correct for a simple magnifying glass?
a) The image is virtual.
b) The object is closer to the lens than the focal point.
c) The image is erect.
d) The lens is diverging.
e) The image is larger than the object.
The option that is NOT correct for a simple magnifying glass is:
d) The lens is diverging.
Determine what is the simple magnifying glass?A simple magnifying glass consists of a converging lens, not a diverging lens. The purpose of a magnifying glass is to create a magnified virtual image of an object.
When an object is placed closer to the converging lens than its focal point, a virtual and erect image is formed on the opposite side of the lens.
This image appears larger than the object and is located at a distance farther away from the lens than the object itself. The converging lens bends the light rays in such a way that they appear to diverge from a point behind the lens, creating a virtual image.
Therefore, the statement that the lens is diverging is incorrect for a simple magnifying glass.
To clarify further, a diverging lens would cause the light rays to spread out, resulting in a diminished, virtual image. A converging lens, on the other hand, causes the light rays to converge, allowing for magnification and the formation of a virtual image.
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