An athlete completes 1 laps around a track with a radius of 25 meters in 180 seconds. What is the magnitude of the athlete's tangential velocity?

Answers

Answer 1

Answer:

0.872m/s

Explanation:

Tangential velocity is given by the formula,

[tex]v= 2\pi r/ t[/tex]

In the question given,

radius= 25meters

time= 180secs

pie= 3.14

number of laps= 1

The magnitude of tangential velocity equals;

[tex]\frac{1lap* 2 *3.14 *25m}{180secs}[/tex]

v = 157m/180secs

Therefore, the magnitude of the tangential velocity

=0.872m/secs


Related Questions

1. The property of a material to absorb liquid like water is called
A non-porous
C. buoyancy
B. density
D. porosity
HELP ME PLEASE I MARK BRAINLIESTIF YOU ANSWER THIS♡​

Answers

Answer:

A hygroscopic substance is one that readily attracts water from its surroundings, through either absorption or adsorption.

Explanation:

A hygroscopic substance is one that readily attracts water from its surroundings, through either absorption or adsorption.

which of the following is a lever

Answers

Answer: the last one

Explanation: it pushes the lid off in a upward motion

Answer:

the last one

Explanation:

Can you mark me as BRAINLLIEST, PLEASE!!!!!!!!!!!!

(○’ω’○)          (ToT)  ↖(^ω^)↗  -_-z  ◑﹏◐  囧    ^O^  B-)

What happens to the sunlight that does not reach Earth’s surface?

Answers

It is absorbed, or can be reflected by clouds, gasses, dust. or is reflected off of Earths surface.

A drag racing vehicle travels from 0 to 100 mph in 5 seconds north. What is the acceleration?

Answers

Answer:

20 m/s^2

Explanation:

Use the formula Vf=Vi+at

Vf=100

Vi=0

a=?

t=5

Then solve for (a)

Brianna pushes a 20 kg box with a force of 50N to achieve an acceleration of 2.5 m/s/s. In order to push a 30
kg box at the same acceleration, how much force will Brianna need to apply? She applies _ N of force.

Answers

Answer:

She applies 75N of force

Explanation:

F=ma

50=20(2.5)

F=30(2.5)

F=75 N

8) a 20kg box is sliding across the ground. If the coefficient of friction is 0.5, how much friction will the box experience?

A 490 N
B 19.6 N
C 98 N
D 2 N

Answers

Answer:

STOP CHETING

Answer:

C is the answer to your question

Explanation:

Have a great day!!! :)

Steelhead trout migrate upriver to spawn. Occasionally they need to leap up small waterfalls to continue their journey. Fortunately, steelhead are remarkable jumpers, capable of leaving the water at a speed of 8.0 m/s. What is the maximum height that a steelhead can jump

Answers

Answer:

s = 3.26 m

Explanation:

Given that,

Water leaves at a speed of 8 m/s

We need to find the maximum height that steelhead can jump. Let it can jump to a height of h.

At maximum height, final speed is equal to 0. We can use third equation of motion to find the maximum height.

[tex]v^2-u^2=2as[/tex]

a = -g

[tex]-u^2=-2gs\\\\s=\dfrac{u^2}{2g}\\\\s=\dfrac{(8)^2}{2\times 9.8}\\\\=3.26\ m[/tex]

Hence, the maximum height is 3.26 m.

a 202 kg bumper car moving right at 8.50 m/s collides with a 355 kg car at rest. Find the total momentum of the system.

Answers

Explanation:It is given that,

Mass of bumper car, m₁ = 202 kg

Initial speed of the bumper car, u₁ = 8.5 m/s

Mass of the other car, m₂ = 355 kg

Initial velocity of the other car is 0 as it at rest, u₂ = 0

Final velocity of the other car after collision, v₂ = 5.8 m/s

Let p₁ is momentum of of 202 kg car, p₁ = m₁v₁

Using the conservation of linear momentum as :

p₁ = m₁v₁ = -342 kg-m/s

So, the momentum of the 202 kg car afterwards is 342 kg-m/s. Hence, this is the required solution.

Answer:

1717 kg*m/s

Explanation:

found it put it in on acellus and it was right

A rocket falls from the apogee (0 meters per second) until it hits the ground with a speed of 10 meters per second. Gravity pulled it down with an acceleration of 9.8m/s^2. The time during which the ball is in free fall is approximately what time?

Answers

Answer:

Approximately 1.02 seconds

Explanation:

Use the final velocity (vf) formula for a uniformly accelerated movement under "g" (acceleration of gravity):

[tex]v_f=v_i+g\,*\,t[/tex]

in our case:

[tex]10=0+9.8\,*\,t\\t=10/9.8\\t\approx 1.02\,\,sec[/tex]

Which term describes the force applied to an object multiplied by the time the force is applied

Answers

Answer:

Momentum

Explanation:

In order for an object's momentum to change,a force must be applied for a period of time

what instrument is used to measure volume by displacement

Answers

Volumes of liquids such as water can be readily measured in a graduated cylinder.

Does anyone knows this for physics?

Answers

The Answer: 12.5m/s2
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A projectile is fired horizontally from a height of 10 m above level ground. The projectile lands a horizontal distance of 15 m from where it was launched.
-Find the hang time for the projectile.
-Find the initial speed of a projectile.
-What are the x and y components of the projectile’s velocity the moment before it strikes the ground?
-At what speed will the projectile strike the ground?

Answers

Answer:

a)t  = 1,43 s

b) V = 10,49 m/s

c) V₀ₓ = 10,49 m/s   ;    V₀y = 14,01 m/s

d) Vf = 17,5 m/s

Explanation:

According to the problem statement

V₀ = V₀ₓ    and  V₀y = 0

And at the end of the movement t = ?  the distance y = 10 m

Therefore as

h = V₀y - (1/2)*g*t²

Vertical distance y = h = 10 = V₀y*t - 0,5 (-9,8)*t²

10 = 4,9*t²

t² = 10/4,9    ⇒  t² = 2,04 s

t  = 1,43 s

a) 1,43 s is the time of movement

b) V₀ = V₀ₓ        V₀y = 0     and  V₀ₓ = Vₓ     ( constant )

Just before touching the ground, the horizontal distance is

hd = 15 = Vₓ * t

Then  15 /1,43 = Vₓ = V₀ₓ

Vₓ = 10,49 m/s

Then initial speed is V = 10,49 m/s    since V₀y = 0

Vf² = Vₓ² + Vy²

Vyf = V₀y - g*t

Vyf =  0 - 9,8 *1,43

Vyf = - 14,01 m/s

And finally the speed when the projectile strike the ground is:

Vf² = Vₓ² + Vy²

Vf = √ (10,49)² + (14,01)²

Vf = 17,50 m/s

A block with mass m = 0.200 kg is placed against a compressed spring at the bottom of a ramp that is at an angle of 53.0∘ above the horizontal. The spring has 8.00 J of elastic potential energy stored in it. The spring is released, and the block moves up the incline. After the block has traveled a distance of 3.00 m, its speed is 4.00 m/s. Part A What is the magnitude of the friction force that the ramp exerts on the block while the block is moving? Express your answer with the appropriate units.

Answers

Answer:

[tex]0.566\; \rm N[/tex] (assuming that while the block is moving, the friction on the block is constant.)

Explanation:

The mechanical energy of a system is the sum of its:

elastic potential energy, gravitational potential energy, andkinetic energy.

Friction does work on the block as the block moves up the ramp. The amount of energy that the block-string system has lost would be equal in size to the work that friction has done on the block. The size of the friction on the block could thus be computed.

Before this block was released, the block-spring system has no kinetic energy because there was no movement. Assume that the system has no gravitational potential energy at that moment, either. The only type of mechanical energy in this system at that moment would be elastic potential energy: [tex]8\; \rm J[/tex] according to the question.

The question states that the ramp is [tex]53.0^\circ[/tex] above horizontal. Therefore, after the block has traveled [tex]3.00\; \rm m[/tex] (along the ramp,) the height of this block would have increased by [tex]\Delta h = 3.00\; \rm \sin\left(53^\circ\right) \approx 2.39591\; \rm m[/tex]. Calculate the corresponding gain in gravitational potential energy:

[tex]\begin{aligned}& m \cdot g \cdot \Delta h\\ &\approx 0.200\; \rm kg& \\\ &\quad\times 9.81\; \rm N \cdot kg^{-1} \\ &\quad \times 2.39591\; \rm m \\ &\approx 4.70077\; \rm J\end{aligned}[/tex].

On the other hand, the question states that the speed of the block ([tex]m = 0.200\; \rm kg[/tex]) at that moment is [tex]v = 4.00\; \rm m \cdot s^{-1}[/tex]. Calculate the corresponding kinetic energy:

[tex]\begin{aligned}& \frac{1}{2}\, m \cdot v^{2} = 1.6\; \rm J \end{aligned}[/tex].

Because the block was already released, there should be no elastic potential energy in the spring.

Hence, the mechanical of the block-spring system would be approximately [tex]4.70077\; \rm J+ 1.6\; \rm J \approx 6.30077\; \rm J[/tex].

Approximate the amount of mechanical energy that is lost:

[tex]8\; \rm J - 6.30077\; \rm J \approx 1.69923\; \rm J[/tex].

In other words, when applied over [tex]3\; \rm m[/tex], the friction on this block would do approximately [tex]1.69923\; \rm J[/tex] of work. Approximate the size of that friction:

[tex]\begin{aligned}F &= \frac{W}{s} \\ &\approx \frac{1.69923\; \rm J}{3.00\; \rm m}\approx 0.566\; \rm N\end{aligned}[/tex].

If 710-nm and 655-nm light passes through two slits 0.65 mm apart, how far apart are the second-order fringes for these two wavelengths on a screen 1.1 m away?

Answers

Answer:

Explanation:

Position of n the order fringe = n λ D / d

for n = 2

position = 2 λ D / d

λ = 710 nm , D = 1.1 m

d = .65 x 10⁻³

position 1 = 2 x 710 x 10⁻⁹ x 1.1 / .65 x 10⁻³

= 2403.07 x 10⁻⁶ m

= 2.403 x 10⁻³ m

= 2.403 mm .

For λ = 655 nm

position = 2 λ D / d

λ = 655 nm , D = 1.1 m

d = .65 x 10⁻³

position 2 = 2 x 655 x 10⁻⁹ x 1.1 / .65 x 10⁻³

= 2216.91 x 10⁻⁶ m

= 2.217 x 10⁻³ m

= 2.217 mm .

Difference between their position

= 2.403 - 2.217 = .186 mm .

initial velocity 10 m/s accelerates at 5 m/s for 2 seconds whats the final velocity

Answers

Answer:

The final velocity is 20 m/s.

Explanation:

Constant Acceleration Motion

It's a type of motion in which the velocity of an object changes by an equal amount in every equal period of time.

Being a the constant acceleration, vo the initial speed, and t the time, the final speed can be calculated as follows:

[tex]v_f=v_o+at[/tex]

The provided data is: vo=10 m/s, [tex]a=5\ m/s^2[/tex], t=2 s. The final velocity is:

[tex]v_f=10~m/s+5\ m/s^2\cdot 2\ s[/tex]

[tex]v_f=20\ m/s[/tex]

The final velocity is 20 m/s.

A rescue helicopter is lifting a man with 86 kg mass from a capsized boat by means of a cable and harness. What is the tension in the cable when the man is given an initial upward acceleration of 1.35 m/s2

Answers

The man is pulled upward by a net force of

F = (86 kg) (1.35 m/s²) = 116.1 N

The net force is comprised of the tension T in the cable and the man's weight W, such that

F = T - W = 116.1 N

T = (86 kg) (9.80 m/s²) + 116.1 N

T = 958.9 N ≈ 960 N

The driver of a car slams on the brakes when he sees a tree blocking the road. The car slows uniformly with acceleration of -5.05 m/s2 for 4.05 s, making straight skid marks 65.0 m long, all the way to the tree. With what speed does the car then strike the tree?

Find the answer in m/s.

Answers

Answer:

656.5 m/s

Explanation:

V = ? U = 0 m/s a = 5.05 m/s2 S = 65.0 m

V = u + 2as

V = 0 + 2× 5.05 × 65

V = 656.5 m/s

Need help fast it’s on forces!

Answers

i think the answer is h if am wrong am sorry

Explanation:

turns into _____ energy (when plants convert into food)

Answers

Answer:

its called photosynthesis  

Explanation:

when plants turn food into energy.  Photosynthesis is a process used by plants and other organisms to convert light energy into chemical energy and stored in the form of starch which can be used later.

Answer:

The answer would be photosynthesis

Explanation:

In this case plants convert light energy (1) into chemical energy, (in molecular bonds), through a process known as photosynthesis. Most of this energy is stored in compounds called carbohydrates. The plants convert a tiny amount of the light they receive into food energy. :)

A ball is thrown off a cliff at a speed of 10 m/s in a horizontally direction. The ball reaches the ground 1.5 seconds. If the ball is launched a second time at the same speed from a second higher cliff, which of the following is true?
A. The ball takes a longer time and lands further away from the foot of the cliff.
B. The ball takes longer to hit the ground, but lands at the same distance from the foot of the cliff.
C. The ball takes the same time lands at the same distance from the foot of the cliff.
D. The ball falls further away from the foot of the cliff, but takes the same time.

Answers

i am pretty sure it is d

What is the formula for electrical power?
A. P = IV/R
B. P = IVR
C. P = IR
D. P = IV

Correct answer is D!

Answers

the Forrest answer is D

Electrical power can be defined as the product of Voltage and current. Thus, P = IV. Hence, Option D is the correct answer.

What is Power?As we study Electric power, the electric current to the another form of energy.The SI unit of power is the watt or one joule per second.Electric power can be calculated as current times voltage. Electrical energy used by equals the power of the appliances and its  multiplied by the amount of time and the appliance is used.

Thus, the formula for electric power,

P = IV watt

Where,

P - Power (Watt)

I - Current (Ampere)

V - Voltage (volts)

Power can be also known as the mechanical power equation.Also, the power dissipated energy can also be found with the equation.

Electrical power can be defined as the product of Voltage and current. Thus, P = IV. Hence, Option D is the correct answer.

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A particle executes simple harmonic motion with an amplitude of 2.00 cm. At what positions does its speed equal one fourth of its maximum speed?

Answers

Answer:

The positions are  0.0194 m  and - 0.0194 m.

Explanation:

Given;

amplitude of the simple harmonic motion, A = 2.0 cm = 0.02 m

speed of simple harmonic motion is given as;

[tex]v = \omega \sqrt{A^2-x^2}[/tex]

the maximum speed of the simple harmonic motion is given as;

[tex]v_{max} = \omega A[/tex]

when the speed equal one fourth of its maximum speed

[tex]v =\frac{v_{max}}{4}[/tex]

[tex]\omega\sqrt{A^2-x^2} = \frac{\omega A}{4} \\\\\sqrt{A^2-x^2}= \frac{A}{4}\\\\A^2-x^2 = \frac{A^2}{16} \\\\x^2 = A^2 - \frac{A^2}{16} \\\\x^2 = \frac{16A^2 - A^2}{16} \\\\x^2 = \frac{15A^2}{16} \\\\x= \sqrt{\frac{15A^2}{16} } \\\\x = \sqrt{\frac{15(0.02)^2}{16} }\\\\x = 0.0194 \ m \ \ or\ - 0.0194 \ m[/tex]

Thus, the positions are  0.0194 m and - 0.0194 m.

The positions where the speed equals 1/4 of its maximum speed is mathematically given as

[tex]x \pm 0.0194[/tex]

What positions does its speed equal one-fourth of its maximum speed?

Question Parameters:

an amplitude of 2.00 cm.

Generally, the equation for the speed of simple harmonic motion  is mathematically given as

[tex]v = w \sqrt{A^2-x^2}\\\\v=\frac{wA}{4}[/tex]

Therefore

[tex]w \sqrt{A^2-x^2}=\frac{wA}{4}\\\\x^2=A^2-A^2/16\\\\x=\sqrt{\frac{15A^2}{16}}[/tex]

[tex]x \pm 0.0194[/tex]

In conclusion, the positions are

[tex]x \pm 0.0194[/tex]

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Answer this question: Is math really important to giving science power? (remember the 5 Ws and the H)

Answers

i don’t really understand what you are asking but i believe that math is important to giving science power without math it’s wouldn’t really be a thing yk but i don’t i understood what’s your asking ?

A mover slides a refrigerator weighing 650 N at a constant velocity across the floor a distance of 8.1 m. The force of friction between the refrigerator and the floor is 230 N. How much work has been performed by the mover on the refrigerator?​

Answers

Given :

A mover slides a refrigerator weighing 650 N at a constant velocity across the floor a distance of 8.1 m.

The force of friction between the refrigerator and the floor is 230 N.

To Find :

How much work has been performed by the mover on the refrigerator.

Solution :

Since, refrigerator is moving with constant velocity.

So, force applied by the mover is also 230 N ( equal to force of friction ).

Now, work done in order to move the refrigerator is  :

[tex]W = Force\times distance\\\\W = 230 \times 8.1\ N\ m\\\\W = 1863\ N\ m[/tex]

Hence, this is the required solution.

The diagram shows an electromagnet made with copper wire, a steel nail,
and a 1.5 V battery. Which action could cause this electromagnet to be
stronger?

A. Replace the steel nail with a plastic straw.

B. Replace the battery with a 6 V battery.

C. Reduce the number of coils of wire wrapped around the nail.

D. Reverse the direction of the battery in the circuit.

Correct answer is B!

Answers

The correct answer is b

Answer:B

Explanation: i took the test and i got it right

in the case shown below, the 1 kg rock rides on a horizontal disk that rotates at constant speed 5m/s

Answers

Answer:25 N

Explanation:

in the case shown below, the 1 kg rock rides on a horizontal disk that rotates at constant speed 5m/s is 25N

what is speed ?

Speed is the ratio of distance with respect to the time in which the distance was covered. Speed is a scalar quantity as it does not have magnitude only have direction

The formula of speed can be represented as s=d/t, Where, s is the speed in m.s-1, d is the distance traveled in m, t is the time taken in s

Uniform speed is defined when the object covers equal distance at equal time intervals, variable speed is defined as when the object covers a different distance at equal intervals of times.

Average speed is defined as the total distance travelled by an object to the total time taken by the object.

Instantaneous speed is defined as when the object is move with variable speed, then the speed at any instant of time is known as instantaneous speed.

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A horse has a momentum of 1200 kg·m/s. If the horse has a mass of 313 kg, what is the speed of the horse?

Answers

Answer:

3.83 m/s

Explanation:

The speed of the horse can be found by using the formula

[tex]v = \frac{p}{m} \\ [/tex]

p is the momentum

m is the mass

From the question we have

[tex]v = \frac{1200}{313} \\ = 3.83386..[/tex]

We have the final answer as

3.83 m/s

Hope this helps you

The fact that our preconceived ideas contribute to our ability to process new information best illustrates the importance of: the serial position effect. O repression iconic memory . semantic encoding . retroactive interference .

Answers

Answer:

It’s a

Explanation:

Don’t actually put that i needed the points mb

____ is the ability to course change in matter

Answers

Answer:

i don't know the correct answer

but this is what i found on web

Explanation:

Changes of state are physical changes in matter. They are reversible changes that do not change matter's chemical makeup or chemical properties. Processes involved in changes of state include melting, freezing, sublimation, deposition, condensation, and evaporation. Energy is always involved in changes of state.

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