Aziza has a triangle with two sides measuring 11 in. and 15 in. She claims that the third side can be any length as long as
it is greater than 4 in. Which statement about Aziza's claim is correct?
O Aziza's claim is not correct. The third side must be between 4 in. and 26 in.
O Aziza's claim is not correct. The third side can be any length less than 26 in.
O Aziza's claim is not correct. The third side can be any length.
O Aziza's claim is not correct. The third side must create a scalene triangle.

Answer:

When you run a regression, calculating and plotting residuals help you understand and improve your regression model. In this post, we describe the fitted vs residuals plot, which allows us to detect several types of violations in the linear regression assumptions. You may also be interested in qq plots, scale location plots, or the residuals vs leverage plot.

Step-by-step explanation:

Step-by-step explanation:

tan(x) = sin(x)/cos(x) = 3/4

in the trigonometric triangle sin(x) and cos(x) are the legs, and the radius is the Hypotenuse, the baseline (opposite of the 90° angle).

so, we can use Pythagoras to find the radius.

c² = a² + b²

with c being the Hypotenuse, a and b being the legs.

let's stay integer.

if sin(x) is equivalent to 3, and cos(x) to 4, then what is the radius ?

3² + 4² = c²

9 + 16 = c²

25 = c²

c = radius = 5

so,

3 = sin(x) × 5

4 = cos(x) × 5

sin(x) = 3/5 = 0.6

cos(x) = 4/5 = 0.8

The value of sin x is 3/5 and the value of cos x is 4/5.

What are trigonometry ratios?

The trigonometric functions in mathematics are real functions that connect the right-angled triangle's angle to the ratios of its two side lengths. They are extensively employed in all fields of geometry-related study, including geodesy, solid mechanics, celestial mechanics, and many others.

Given that tan x = 3/4.

The tangent of an angle is the ratio of height to the base of the right triangle.

Here the height of the triangle is 3 and the base is 4.

According to the Pythagorean theorem, the square of the hypotenuse is equal to the sum of the square of the base and height.

Thus,

hypotenuse = √(3² + 4²)

hypotenuse = 5.

The sine of an angle is the ratio of height to the hypotenuse.

Sin x = Height/ hypotenuse

sin x = 3/5

The cosine of an angle is the ratio of the base to the hypotenuse.

cos x = base/ hypotenuse

cos x = 4/5

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The radius of the sphere of surface area 320 cm² is 5.04 cm.

A radius is defined as half of a diameter. The unit of radius is meter.

To calculate the radius of the sphere, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the radius of the sphere is 5.04 cm.

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The function h is defined, for all real numbers h(-3) = -1/2 , h(2) = -2 and h(4) = -4.

What is a function ?

When it comes to arithmetic, a function is represented as a rule that produces a different result for each input x. Mathematicians refer to functions as mapping or transformations.

The given function,

h(x) =  -1/2 x^2 + 4 if x≠ 2

                 -2         if x=2

So, h(-3) = -1/2 (-3)^2 + 4

             = - 9/2 + 4

             = -1/2

     h(2) = -2 ( given )

     h(4) = -1/2 (4)^2 + 4

            = -8 + 4

            = -4 .

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Answer:

30

Step-by-step explanation:

not sure might be wrong lol soz

Part (a)

Given data table.

[tex]\begin{array}{|c|c|} \cline{1-2}t & T\\\cline{1-2}0 & 81\\\cline{1-2}5 & 69\\\cline{1-2}10 & 60.5\\\cline{1-2}15 & 54.2\\\cline{1-2}20 & 49.3\\\cline{1-2}25 & 45.4\\\cline{1-2}30 & 42.6\\\cline{1-2}\end{array}[/tex]

where,

It's unfortunate that T is used twice for these variables. It might cause some confusion.

This is what happens when we subtract 24 from each temperature.

[tex]\begin{array}{|c|c|} \cline{1-2}t & T-24\\\cline{1-2}0 & 57\\\cline{1-2}5 & 45\\\cline{1-2}10 & 36.5\\\cline{1-2}15 & 30.2\\\cline{1-2}20 & 25.3\\\cline{1-2}25 & 21.4\\\cline{1-2}30 & 18.6\\\cline{1-2}\end{array}[/tex]

The graph of each set of points is shown in figure A. I used GeoGebra to make the graph.

The first set of data points are in red. The second set in blue. Notice the set of blue points is the result of shifting the red points 24 units down.

The green exponential model is also shown as the curve through the set of red points.

The green regression exponential model doesn't go through each point perfectly. Rather it tries to get as close as possible.

To go from

T-24 = 54.4(0.964)^t

to

T = 54.4(0.964)^t + 24

we simply add 24 to both sides. This means there isn't much to show in terms of steps when solving for T.

=======================================================

Part (b)

Use spreadsheet technology or something like GeoGebra to generate this data table.

[tex]\begin{array}{|c|c|} \cline{1-2}t & ln(T-24)\\\cline{1-2}0 & 4.043051\\\cline{1-2}5 & 3.806662\\\cline{1-2}10 & 3.597312\\\cline{1-2}15 & 3.407842\\\cline{1-2}20 & 3.230804\\\cline{1-2}25 & 3.063391\\\cline{1-2}30 & 2.923162\\\cline{1-2}\end{array}[/tex]

The values in the 2nd column are approximate.

Then plot each of those points on the same xy grid. Use technology of your choice to determine the regression line is roughly

y = -0.03723x + 3.99739

So we can say

ln(T-24) = -0.03723t + 3.99739

the right hand side fits the format at + b where

both of which are approximate.

Then,

e^(ln(T-24)) = e^(at+b)

T-24 = e^(at+b)

T-24 = e^(-0.03723t + 3.99739)

T-24 = e^(-0.03723t)*e^(3.99739)

T-24 = e^(-0.03723t)*54.45583

T-24 = 54.45583*e^(-0.03723t)

T = 54.45583*e^(-0.03723t) + 24

T = 54.456*e^(-0.037t) + 24

Let's verify that this is equivalent to the model found in part (a).

T = 54.456*e^(-0.037t) + 24

T = 54.456*(e^(-0.037))^t + 24

T = 54.456*(0.963676)^t + 24

T = 54.5*(0.964)^t + 24

which is very close to the model mentioned in part (a). There's some slight rounding error. That's to be expected in problems like this.

-----------------------------

Answer: T = 54.456*e^(-0.037t) + 24

See figure B for the graph. Like with the other regression curve, this straight line doesn't go through all of the points. It tries to get as close as possible.

=======================================================

Part (c)

Refer to the 2nd table mentioned in part (a).

We'll apply the reciprocal to each item in the column labeled T-24.

For instance, the item 57 becomes 1/57 = 0.017544 approximately.

This is what the data table looks like:

[tex]\begin{array}{|c|c|} \cline{1-2}t & 1/(T-24)\\\cline{1-2}0 & 0.017544\\\cline{1-2}5 & 0.022222\\\cline{1-2}10 & 0.027397\\\cline{1-2}15 & 0.033113\\\cline{1-2}20 & 0.039526\\\cline{1-2}25 & 0.046729\\\cline{1-2}30 & 0.053763\\\cline{1-2}\end{array}[/tex]

The values in the 2nd column are approximate.

The set of points and regression line are shown in figure C1. This line does not go through all of the points. Like with the others, it tries to get as close as possible to each point.

Use technology to determine the equation of the regression line is approximately:

y = 0.00121x + 0.01613

Which tells us that

1/(T-24) = 0.00121t + 0.01613

Let's solve for uppercase T.

1/(T-24) = 0.00121t + 0.01613

T-24 = 1/(0.00121t + 0.01613)

T = 1/(0.00121t + 0.01613) + 24

T = 1/(0.0012t + 0.0161) + 24

which is the approximate final answer.

Figure C2 shown below represents the original data points (t, T) in red. The blue curve is y = 1/(0.0012x+0.0161)+24, which is the rational regression curve we just found. This curve tries its best to get as close as possible to each red point.

Compare the regression curves of figure A and figure C2. We have a very close tie in terms of which curve does a better job of fitting the original data.

Answer:

Area = 5π/2 in^2

Perimeter = 3π + 2 in

Step-by-step explanation:

A=area of a circle.   P=Perimeter of a circle

F=Area of first semi-circle

T=Area of Figure

Solve for Area:

A=πr^2

F=A/2

A=π(2)^2  ==> solve for A

A=4π

F=(4π)/2
F=2π   ==> this is for the first semi-circle

S=Area of second semi-circle

S=(πr^2)/2

S=(π(2/2)^2)/2  ==> the radius is half the diameter, and the diameter is 2 in

S=(π(1)^2)/2

S=π/2

T=F+S  ==> The total area is the area of both semi-circles

T=2π + π/2  ==> plugin 2π for F and π/2 for S

T = 4π/2 + π/2  ==> common denominators

T = 5π/2 in^2

Now solve for perimeter

P = 2πr.

q = perimeter of first semi-circle

q = P/2

q = 2πr/2

q = 2π(2)/2  ==> plugin 2 for r

q = 2π

R = Perimeter of second semi-circle

R = 2π(1)/2  ==> we calculated that the radius of the semi-circle is half of the

                          radius of the first semi-circle

R = 2π/2  ==> simplify

R = π

Also, add in side length DC into the perimeter as it is part of the perimeter.

E = Entire perimeter of figure

E = q + R + DC

E = 2π + π + 2

E = 3π + 2 in

the test type and relevant statistic, which will depend on the data and the hypothesis being tested.

Step 1 - g. calculate test statistic

Step 2 - b. write claim symbolically

Step 3 - c. compare p-value to alpha

Step 4 - d. reject or fail to reject null

Step 5 - e. write null and alternative hypotheses

Step 6 - f. write conclusion

Step 7 - a. calculate p-value

Step 8 - h. identify test type and relevant statistic

Step 1: Calculate the test statistic, which is a numerical measure of how likely the data is under the null hypothesis.

Step 2: Write the claim symbolically, which is a statement of what you are attempting to prove.

Step 3: Compare the p-value to the alpha level, which is the significance level of the test.

Step 4: Reject or fail to reject the null hypothesis, depending on whether or not the p-value is less than the alpha level.

Step 5: Write the null and alternative hypotheses, which are statements that describe the data and are used to test a hypothesis.

Step 6: Write a conclusion, which is a statement about the data based on the results of the test.

Step 7: Calculate the p-value, which is the probability of obtaining a result as extreme or more extreme than what was observed in the data, given that the null hypothesis is true.

Step 8: Identify the test type and relevant statistic, which will depend on the data and the hypothesis being tested.

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The reason behind this is that when the negative root goes from the RHS to LHS, its sign gets converted, and it appears like (x + 4).

A 2nd equation in x is known as a quadratic function. Ax2 + bx + c = 0 is the quadratic equations in standard form, wherein there a and b are the coefficient, x is the constant, and c is the constant.

The presence of a non-zero component in the coefficient of x2 (a ≠ 0) is the first prerequisite for an expression to be a quadratic equation.

As per the given information in the question,

The root obtained is -4 or,

We can also write this thing as,

x = -4

So, when -4  will come to the LHS the sign will be converted to positive, and then it can be written as (x + 4).

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Step-by-step explanation:

the slope-intercept form is in general

y = ax + b

a being the slope, b being the y-intercept (the y-value when x = 0).

the slope is the ratio (y coordinate difference / x coordinate difference) when going from one point on the line to another.

we got 2 points identified, so, let's use them.

(2, 44) and (5, 80)

x changes by +3 (from 2 to 5).

y changes by +36 (from 44 to 80).

the slope is +36/+3 = 12.

so, we got "a" for our equation. to get "b" we need to use the coordinates of one of the given points as x and y.

I usually use the one with the smaller numbers.

here : (2, 44).

44 = 12×2 + b = 24 + b

b = 44 - 24 = 20

our equation is

y = 12x + 20

Theresa should take her 7th dose at 9:00 AM on Friday.

What are arithmetic operations?

Arithmetic operations is a branch of mathematics that studies numbers and the operations on numbers that are useful in all other branches of mathematics. It consists primarily of operations like addition, subtraction, multiplication, and division.

we have,

The doctor told her to take a dose of 4.8 ml every 12 hours for 7 days.

If Theresa took her first dose at 9:00 AM on Monday,

Simply add 12 hours every time up to the 7th dose,

First dose  ----> 9:00 AM on Monday,

Second dose  ----> 9:00 PM on Monday,

Third dose  ----> 9:00 AM on Tuesday,

Fourth dose  ----> 9:00 PM on Tuesday,

Fifth dose  ----> 9:00 AM on Thursday,

Sixth dose  ----> 9:00 PM on Thursday,

Seventh dose  ----> 9:00 AM on Friday,

Hence, Theresa should take her 7th dose at 9:00 AM on Friday.

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Taking two count variables, say count3 and count5, to store the count of numbers divisible by 3 and 5 respectively.

Iterate over the range [1, N] using a variable, say i, and perform the following steps:

If the value of count3 and count5, print “FizzBuzz”.

If the value of count3 is equal to 3, print “Fizz”.

If the value of count5 is equal to 5, print “Buzz”.

If none of the above conditions match, then print i.

In a typical coding challenge during an interview, candidates are asked to create a solution that prints integers from 1 to N, designating any integers that are divisible by 3 as "Fizz," any integers that are divisible by 5 as "Buzz," and any integers that are both divisible by 3 and 5 as "FizzBuzz." Good coding practises can be reinforced by knowing how to solve it.

// C++ program for the above approach

#include <bits/stdc++.h>

using namespace std;

// Function to generate FizzBuzz sequence

void fizzBuzz(int N)

{

// Stores count of multiples

// of 3 and 5 respectively

int count3 = 0;

int count5 = 0;

// Iterate from 1 to N

for (int i = 1; i <= N; i++) {

// Increment count3 by 1

count3++;

// Increment count5 by 1

count5++;

// Initialize a boolean variable

// to check if none of the

// condition matches

bool flag = false;

// Check if the value of count3

// is equal to 3

if (count3 == 3) {

cout << "Fizz";

// Reset count3 to 0, and

// set flag as True

count3 = 0;

flag = true;

}

// Check if the value of count5

// is equal to 5

if (count5 == 5) {

cout << "Buzz";

// Reset count5 to 0, and

// set flag as True

count5 = 0;

flag = true;

}

// If none of the condition matches

if (!flag) {

cout << i;

}

cout << " ";

}

}

// Driver Code

int main()

{

int N = 15;

fizzBuzz(N);

return 0;

}

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The solution to the systems are (1, 1), (-3, -1), (1, -2), (2, -1), (7, -1) and (-2, 2)

System 1

In this case, the system of equations is given as

y = -3x + 4

y = 3x - 2

Next, we plot the graph of the system of equations

In this case, the point of intersection of the equations represent the solution to the system

From the graph, the lines intersect at (1, 1)

So, the solution is (1, 1)

System 2

In this case, the system of equations is given as

y = x + 2

x = -3

Next, we plot the graph of the system of equations

In this case, the point of intersection of the equations represent the solution to the system

From the graph, the lines intersect at (-3, -1)

So, the solution is (-3, -1)

System 3

In this case, the system of equations is given as

4x + y = 2

x - y = 3

Next, we plot the graph of the system of equations

In this case, the point of intersection of the equations represent the solution to the system

From the graph, the lines intersect at (1, -2)

So, the solution is (1, -2)

System 4

We have

y = 4x - 9

y = x - 3

Substitute y = 4x - 9 in y = x - 3

4x - 9 = x - 3

Evaluate the like terms

3x = 6

So, we have

x = 2

Recall that:

y = x - 3

So, we have

y = 2 - 3

y = -1

So, the solution is (2, -1)

System 5

We have

x + 7y = 0

2x - 8y = 22

Make x the subject in x + 7y = 0

x = -7y

Substitute x = -7y in 2x - 8y = 22

-14y - 8y = 22

Evaluate the like terms

-22y = 22

So, we have

y = -1

Recall that:

x = -7y

So, we have

x = -7(-1)

x = 7

So, the solution is (7, -1)

System 6

We have

-7x + 2y = 18

6x + 6y = 0

Make x the subject in 6x + 6y = 0

x = -y

Substitute x = -y in -7x + 2y = 18

7y + 2y = 18

Evaluate the like terms

9y = 18

So, we have

y = 2

Recall that:

x = -y

So, we have

x = -2

So, the solution is (-2, 2)

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The solution to the equation 125x³ - 27 = 0 is (5x−3)(25x ^2 +15x+9)

An equation is a mathematical expression that contains an equals symbol. Equations often contain algebra. Algebra is used in mathematics when you do not know the exact number in a calculationsolving the equation 125x³ - 27 = 0 by grouping

Rewriting 125x^ 3 −27 as (5x) ^3 −3³

The difference of cubes can be factored using the rule:: a ^3 −b^ 3 =(a−b)(a^ 2 +ab+b^ 2 )

Polynomial 25x^ 2 +15x+9 is not factored since it does not have any rational roots.

Hence, (5x−3)(25x ^2 +15x+9)

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The Answers to the Question are solved below.

A number's cube root is the factor that we multiply three times to get that number.

The symbol for cube root is 3 ​cube root of, end cube root(∛) .

Given:

1. [tex]5^{-2[/tex]

Using Exponents

[tex]a^{-m[/tex] = 1 / [tex]a^m[/tex]

So,  [tex]5^{-2[/tex] = 1/5² = 1/25.

2. z+ 5= 12

z= 12-5

z= 7

3. Pythagorean triplet: m²-1, 2m, m²+1

2m= 6

m=3

and, m²-1 = 9-1= 8

and, m²+1 = 9+1= 10

3. Cube root of 64 = ∛64= ∛(4 x 4 x 4)= 4

4. 4z+ 3= 6+ 2z

2z = 3

z= 3/2

5. a- b+ ab, b- c + bc, c- a +ac

Adding: (a- b+ ab) + (b- c + bc) + (c- a +ac)

= ab+ bc+ ac

6. -1 x -2/5

= 2/5

The Multiplicative inverse = -5/2

7. y+3 = 10

y=7

8. 10³= 10 x 10 x 10= 1000

9. [tex]3^{-2[/tex]

= 1/3²

= 1/9

10. Volume = Base Area x height

900 = 180 h

h= 900/180

h = 5

11. 16 as sum of 4 add number

= 1 + 3 + 5 + 7

12. 78 x 82

(80- 2)(80+ 2)

= 80² - 2²

= 6400 - 4

= 6396

13. 2/3 x 100

= 200/3 %

14. (ab- bc)+ (bc - ca)  + (ca- ab)

= [tex](-4)^5[/tex]  ÷ [tex](-4)^8[/tex]

= [tex](-4)^{5-8}[/tex]

= [tex](-4)^{-3[/tex]

15. 4p² - 9q²

= (2p)² - (3q)²

= (2p - 3q) (2p + 3q)

16. 2y-1 = 14- y

3y= 15

y= 5

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Based on the information provided, a linear model is not appropriate for summarizing the relationship between home size and sale price because of the random scatter of points in the residual plot. In a linear model, the residuals should be randomly distributed around a mean of zero, without any discernible pattern. However, the residual plot shown in the question indicates that the residuals are randomly scattered throughout the graph, which suggests that a linear model may not be the best way to summarize the relationship between the variables. Therefore, a linear model is not appropriate for this data.

Answer:

Not Appropriate

Step-by-step explanation:

Based on the information provided in the problem, it appears that a linear model is not appropriate for summarizing the relationship between home size and sale price. This is because the residual plot shows a random scatter of points, which suggests that there is not a strong linear relationship between these variables. Furthermore, the scatterplot of home price versus home size shows a line with a positive slope, which indicates that there is some relationship between these variables, but it is not necessarily a linear relationship. In this situation, it would be more appropriate to use a non-linear model to summarize the relationship between home size and sale price.

Answer:

[tex] \huge{ \boxed{x = 3}}[/tex]

Step-by-step explanation:

[tex] {x}^{2} - 6x + 9 = 0[/tex]

Using the quadratic formula that's,

[tex] \bold{x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}} \\ [/tex]

Comparing the equation to the general form of a quadratic equation ( ax² + bx + c), we have.

[tex]a = 1 \\ b = - 6 \\ c = 9[/tex]

Substituting the values into the formula we have.

[tex]x = \frac{- ( -6) \pm \sqrt{( - {6})^{2} - 4(1)(9) } }{2(1)} \\ x = \frac{6 \pm \sqrt{36 - 36} }{2} \\ x = \frac{ 6 \pm\sqrt{0} }{2} \\ x = \frac{6}{2} \: \: \: \: \: \\ \\ x = 3 \: \: \: \: \: \: \: \: \: \: \: \: \: [/tex]

We have the final answer as

Answer:

7x+7y siuuuuuuuuuuuuuuuuu

Answer:

$47.48

Step-by-step explanation:

Let x = the amount owed Sept.

x + x - 2.23 = 292.43  Combine like terms

2x -2.23 = 292.43  Add 2.23 to both sides

2x - 2.23 + 2.23 = 292.43 + 2.23

2x = 294.66  Divide both sides by 2

[tex]\frac{2x}{2}[/tex] = [tex]\frac{294.66}{2}[/tex]

x = 147.33 this is the bill for September

Oct. 147.33 -2.23 = 145.10 This is the Bill for Oct.

Total:

147.33 + 145.10 = 292.43

292.43 ÷ 3 = 97.48  This is what each will owe rounded to the nearest penny.

Answer:

-----------------------------------

Given:

Distribute and simplify it to get  equivalent expression:

This is matching the last option.

Mark can travel a distance of 110 km on 1000 worth of gas.

The operations that we use in daily life are problems like adding, subtracting adding multiple times, and dividing things are called Mathematical operations.  

The four basic mathematical operations are

1. Adding, 2. Subtracting, 3. Multiplication, and 4. Division.

Here in this problem, we use Multiplication and Division to solve the

Here we have

Mark car can travel 22 km per liter of gas costs 200 per liter  

Here we need to find how many kilometers can mark travel on 1000 worth of gas

Given the cost of 1 liter of gas = 200 Rs

=> Amount gas that can be worth 1000 = 1000/200 = 5 liter  

Given Mark can travel 22 km with 1 liter

The distance can be travel with 5 liters = 5 × 22 = 110 km

Therefore,

Mark can travel a distance of 110 km on 1000 worth of gas.

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Answer:

Below

Step-by-step explanation:

2x-y = 20

2x + y = 48       add the two equations to get

4x = 68

x = 17    <==== use this value in either equation to calculate y = 14

The median is 43 g. By using median formula and by simple observation method we can find median of the given data.Hence median is 43 g.

The middle number ,by ordering all data points and picking out the one in the middle.Arrange the all values from lowest to highest.Then we can find easily.Median is also type of average which is used to find centre value.

There are the following formula we use to find median.

Median= (n+1)th/2  terms (if n is odd)

Where n is the number of observations.

So,if n is even then we use

Median= (n/2)th  terms

if number of term is even,then the median is the simple average of the middle two numbers.  

So we can find median by two methods

median= n/2 -th term

median =6/2 -th term

median = 3-th term

Hence our third term is 43 g so our median will be 43 g.

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Answer:

a = 8

b = 2

c = 48

Step-by-step explanation:

3 cups of flour is needed to make 24 servings.

3:24

Simplify. First, divide 3 from both sides of the ratio.

(3)/3 : (24)/3

1:8

Next, solve for b. You multiply 2 to 8 to get 16. Next, multiply 2 to 1

1 x 2 = b = 2

Finally, multiply 8 to 6 to get c.

8 x 6 = c = 48

~

The probability that at most 195 of those purchases are paid with a credit or debit card i.e P(X ≤ 195 ) is 0.9625..

We have given that,

Sample size , n=250

Sample proportion, p= 73.2% = 0.732

np = 183

n(1-p) = 67

both np & n(1-p) values are greater than 5, So normal approximation is applicable

mean, µ = np = 183

std. dev, σ = √np(1-p) =√250×0.732 ×(1-0.732) =7.0031

we have to calculate probability that at most 195 of those purchases are paid with a credit or debit card i.e P(X ≤ 195 )

= P( X < 195.5 )

= P((x - µ) / σ < (195.5 -183)/ 7.0031)

= P( Z < 1.78 )

= 0.9625

Required probability using Excel function ,

Excel command: =NORM.S.DIST(z,1)

= Norm.S.DIST(1.78,1)

= 0.9625

Hence, required probability is 0.9625..

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The expression to the scenario it's represent is as follows:

The price of a USB memory stick selling at 21% discount off it marked price(m) → 0.21m

The price of Cd that sells for 21%  more than the amount (m) needed to manufacture the CD → 1.21m.

The final value of painting after the initial value, m increases by 2 / 5 → 7 / 5 m.

The total number of markers Nancy have if she gives away 2 / 5 of her m markers to Amy → 3 / 5 m

An algebraic expression is made up of variables and constants, along with algebraic operations like subtraction, addition, multiplication and division.

Therefore, let's match the algebraic expression with the scenario.

The price of a USB memory stick selling at 21% discount off it marked price(m).

Hence, the expression is 21% of m = 21 / 100 m = 0.21m

The price of Cd that sells for 21%  more than the amount (m) needed to manufacture the CD.

Hence, the expression is 21%m + m  = 0.21m + m = 1.21m.

The final value of painting after the initial value, m increases by 2 / 5.

Hence, the expression is 2 / 5 m + m = 7 / 5 m.

The total number of markers Nancy have if she gives away 2 / 5 of her m markers to Amy.

Hence, the expression is m - 2 / 5 m = 3 / 5 m.

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Answer:

1

Step-by-step explanation:

The possible value for the side length of the plot of land is 46 meters.

Area is a measurement of the size of a two-dimensional space or shape. It can be measured in square feet, square meters, and other units of measurement. Area is often used to measure the size of a room, a garden, a piece of land, and many other objects. In mathematics, area is a concept used to calculate the size of a shape or figure. It is calculated by multiplying the length of a shape by its width. Area can also refer to the total amount of space a shape takes up, such as the area of a circle or triangle.
The area of a square is calculated by multiplying the length of one of its sides by itself. Therefore, the side length of Abby's plot of land can be calculated by taking the square root of the area. The square root of 2200 is 46.89, and of 2400 is 48.98. Therefore, the possible side lengths of Abby's plot of land are 46 meters and 48 meters.
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This is a SAS situation, only one triangle is possible. Then the correct option is C.

The polygonal shape of a triangle has a number of sides and three independent variables. Angles in the triangle add up to 180 °.

In triangle ΔABC, the angle ∠A is 22°. And the measure of the side BC is 18.9 cm and the measure of the side AC is 15.1 cm.

To fix a triangle, the known dimensions of the triangle should be three which one must be a side.

This is a SAS circumstance, just a single triangle is conceivable. Then the right choice is C.

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The slope and y-intercept, or the points, should be used to graph the line.  Slope: 3 y-intercept: (0, 1 )

g ( x ) = − 3 x − 1

Create an equation using the function.

y = − 3 x − 1

Calculate the slope and y-intercept using the slope-intercept form.

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In the slope-intercept form, y = m x + b denotes the slope and the y-intercept, respectively.

y = m x + b

With the use of the formula y = m x + b, determine the values of m and b.

m = − 3 b = − 1

m is the line's slope, and is the value of the y-intercept.

B. Slope: 3 Y-intercept: (0, 1 )

Two points are all that are required to graph any line. To determine the associated y values, enter two x values into the equation.

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Assign the x and y values to a table.

x     y

0   − 1

1    − 4

The slope and y-intercept, or the points, should be used to graph the line.

Slope: 3 y-intercept: (0, 1 )

x        y

0        1

1         4.

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