Based on the scatterplot, what is the best prediction of the amount of $ in sales when the temperature is at 21°C?​

Answer:

292.6

Step-by-step explanation:

Answer: store b because you can get more ground beat.

Step-by-step explanation:

Step-by-step explanation:

Two t-shirts that are(31.80) plus a hat(6.20) cost £38.00.

which means that one t-shirt costs £15.90 :)

Answer:

n(E) = 6

Step-by-step explanation:

That's to say that there are 6 five-digit numbers with 7 in the first place and 8 in the last place, using the digits 2, 3, 4, 7 and 8. Therefore n(E) = 6.

Answer:

true

Step-by-step explanation:

[tex]\mathfrak{ x ^ { 2 } + b x - 4 = 0} [/tex]

[tex]\mathfrak{bx-4=-x^{2} } [/tex]

[tex]\mathfrak{bx=-x^{2}+4 } [/tex]

[tex]\mathfrak{xb=4-x^{2} } [/tex]

[tex]\mathfrak{\frac{xb}{x}=\frac{4-x^{2}}{x} } [/tex]

[tex]\mathfrak{ b=\frac{4-x^{2}}{x} } [/tex]

[tex]\mathfrak{b=-x+\frac{4}{x} } [/tex]

AnSwEr

[tex]\boxed{\mathfrak{b=-x+\frac{4}{x},x\neq 0 } }[/tex]

 ღ ꪑ꠸᥅ꫀꪊ

Jake's Argument is correct, adding zero (0) to an addend does not change a sum.

Addend is number which is added to another number.

For example:

y + 5 = 8

where;

Adding zero (0) to an addend does not change a sum. An example is present below;

5 + 3 = 8

add zero (0) to 3 and check if the final result will change;

5 + (3 + 0) = 5 + 3 = 8

Thus, Jake's Argument is correct, adding zero (0) to an addend does not change a sum.

Learn more about addend number here: https://brainly.com/question/654494

Answer:

Step-by-step explanation:

[tex]x - 0.20x \: = 1480[/tex]

[tex]0.8x = 1480[/tex]

[tex]x = 1480 \div 0.8[/tex]

I'm not sure if this is correct, but I got this

Last year’s computer models are discounted 20%. If a computer is on sale for $1,480, what is the original price of the computer rounded to the nearest dollar?

20% = 0.2

1,480 x 0.2 = 296

1,480 + 296 = 1,776

Answer: 1,776

Again, I don't know if this is correct, so don't be 100% sure with my response.

Answer:

4 burgers

Step-by-step explanation:

four burgers

If you're making the patties yourself (to save money or because you love making burgers), assume four burgers per pound of meat

Answer:

this is do confusing I do not understand

Answer:

A. 511; 6

Step-by-step explanation:

The margin of error would be [tex]\pm\frac{517-505}{2}=\pm\frac{12}{2}=\pm 6[/tex]

The sample mean would be [tex]505+6=511[/tex] (or [tex]517-6=511[/tex])

Answer:

I feel like something is wrong with the equation but the answer is a = 3

Step-by-step explanation:

a + 3a - 3 = 6 + 3 = 9

--> 4a = 12 --> a = 3

So basically what you have to do is first identify all of the sides or angles that equal eachother then you can see if you did a side side and side in a row etc, like 44 would be SAS because the vertical angles would be inbetween the two sides. 46 would be SSS because after you make the line in the middle for reflexive property you can see that there are three sides in a row. If this didnt help i recommend looking on Khan Academy

Answer:

the answer is number 1 !!

• correct me if I'm wrong

Answer:

-5.

Step-by-step explanation:

5 + -5 = 0, so i's -5.

150−28w

i think i dont know

Answer:

70% right, 30% wrong

Step-by-step explanation:

3 is 30% of 10

Answer:

55.56%

Step-by-step explanation:

55/99=.5555555...

.55555...*100=55.555...%

55.56%

Answer:

the perimeter of the figure is 27.4 mi

Step-by-step explanation:

rectangle perimeter = 6+6+6 = 18

half circle perimeter = 1/2 2πr = 3.14 × 3 = 9.42

the perimeter of the figure is 18+9.42 = 27.42 --> 27.4 mi

Answer:

D

Step-by-step explanation:

Pluck in the values, we have:

4.5/2.4 - 6 = 20/2 = 10

Answer: The blue dot's value on the number line is 1.

Step-by-step explanation: Each two-skip interval from -7 to -3 is a skip of 4. Therefore, -3 skipped two times is -3 + 4, which equals 1, therefore the blue dot's value on the number line is 1.

Answer:

D: {-2, 0, 2}

R: {-1, 1, 3

Answer:

10.5

Step-by-step explanation:

A=a+b

2h=2+5

2·3=10.5

Answer:

solution given:

let's see only in a right-angled triangle Δ ACD.

AC=3 units

AD=5 units

since Δ ACD is a right-angled triangle. It satisfies Pythagoras law

[tex]AD^{2}=AC^{2}+CD^{2}[/tex]

25=9+[tex]CD^2[/tex]

[tex]CD^2[/tex]=25-9=16

[tex]CD=\sqrt{16} =4 units[/tex]

Now

Area of rectangle Δ ACD=[tex]\frac{1}{2} CD*AC=\frac{1}{2}*4*3=6\: square \:units[/tex]

similarly,

[tex]\frac{1}{2} AD*CE=6\: square \:units\\ 5*CE=6*2\\CE=\frac{12}{5}=2.4 units[/tex]

since AB=CE=2.4 units

Δ ACE is a right-angled triangle. It satisfies Pythagoras law.

[tex]AC^{2}=AE^{2}+CE^{2}\\3^2=AE^2+2.4^2\\9-5.76=AE^2\\AE and BC=\sqrt{1.24} =1.11 units[/tex]

now

area of trapezoid=area ofΔACD+Area of ΔABC

=6+[tex]\frac{1}{2}AB*BC=6+\frac{1}{2}*2.4*1.11=6+1.33 =7.33\: square \:units[/tex]

Step-by-step explanation:

a) If f(y) is a probability density function, then both f(y) ≥ 0 for all y in its support, and the integral of f(y) over its entire support should be 1. eˣ > 0 for all real x, so the first condition is met. We have

[tex]\displaystyle \int_{-\infty}^\infty f(y) \, dy = \frac14 \int_0^\infty e^{-\frac y4} \, dy = -\left(\lim_{y\to\infty}e^{-\frac y4} - e^0\right) = \boxed{1}[/tex]

so both conditions are met and f(y) is indeed a PDF.

b) The probability P(Y > 4) is given by the integral,

[tex]\displaystyle \int_{-\infty}^4 f(y) \, dy = \frac14 \int_0^4 e^{-\frac y4} \, dy = -\left(e^{-1} - e^0\right) = \frac{e - 1}{e} \approx \boxed{0.632}[/tex]

c) The mean is given by the integral,

[tex]\displaystyle \int_{-\infty}^\infty y f(y) \, dy = \frac14 \int_0^\infty y e^{-\frac y4} \, dy[/tex]

Integrate by parts, with

[tex]u = y \implies du = dy[/tex]

[tex]dv = e^{-\frac y4} \, dy \implies v = -4 e^{-\frac y4}[/tex]

Then

[tex]\displaystyle \int_{-\infty}^\infty y f(y) \, dy = \frac14 \left(\left(\lim_{y\to\infty}\left(-4y e^{-\frac y4}\right) - \left(-4\cdot0\cdot e^0\right)\right) + 4 \int_0^\infty e^{-\frac y4} \, dy\right)[/tex]

[tex]\displaystyle \cdots = \int_0^\infty e^{-\frac y4} \, dy[/tex]

[tex]\displaystyle \cdots = -4 \left(\lim_{y\to\infty} e^{-\frac y4} - e^0\right) = \boxed{4}[/tex]