Calculate the value of Key in the following reaction if the equilibrium concentrations are
[H2S] -0.25 M, (H2) - 0.88 M, [S2] -0.44M.
2 H2Sig) = 2 H2(g) + S218)

Answers

Answer 1

Answer:

The value of the equilibrium constant Kc is 5.45

Explanation:

The "Law of Mass Action" states:

"For a reversible reaction in chemical equilibrium at a given temperature, it is true that the product of the concentrations of the products raised to the stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients is a constant."

This constant was called the equilibrium constant. For a reaction:

aA + bB ⇄ cC + dD

the equilibrium constant Kc is:

[tex]Kc=\frac{[C]^{c} *[D]^{d} }{[A]^{a} *[B]^{b} }[/tex]

In this case, the balanced reaction is:

2 H₂S → 2 H₂ + S₂

So, the equilibrium constant Kc is:

[tex]Kc=\frac{[H_{2} ]^{2} *[S_{2} ] }{[H_{2} S]^{2} }[/tex]

The equilibrium concentrations are

[H₂S] =0.25 M[H₂]= 0.88 M[S₂]= 0.44M

Replacing in the definition of equilibrium constant:

[tex]Kc=\frac{(0.88 M)^{2} *0.44 M }{(0.25 M)^{2} }[/tex]

Solving:

Kc= 5.45

The value of the equilibrium constant Kc is 5.45


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Answers

Answer:

the number of moles of the gas is 0.00174 mol.

Explanation:

Given;

temperature of the, T = 300 K

volume of the gas, V = 1.45 L

Pressure of the gas, P = 3.0 kPa

The number of moles of the gas is calculated using Ideal gas equation, as follows;

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Answers

Answer:

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Explanation:

At standard temperature and pressure, temperature of a system = 273K, and pressure= 1atm

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From Gay-Lussac's law which expressed that at constant volume, pressure of a particular mass of gas is directly proportional to temperature . It can be expressed as

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T1= initial temperature

P2= final pressure

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Substitute the values we have

P2= (1 atm × 248.15K)/273.15

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Answers

Answer:

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Explanation:

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Answer:

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Hello there!

In this case, according to the definition of molarity in terms of the moles of solute divided by the volume of the solution, it is possible for us to write:

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