To convert 1-butanol to pentlylamine, the reagents used are [tex]NaN_{3}[/tex], [tex]H_{2} O[/tex], and [tex]NH_{3}[/tex] (in excess), while to convert 1-butanol to dibutyl amine, the reagents used are [tex]SOCl_{2}[/tex] and Butylamine.
To convert 1-butanol to pentlylamine, the reagents would be:
a) [tex]NaN_{3}[/tex](Sodium azide) - to perform azide substitution
b) [tex]H_{2} O[/tex]- for hydrolysis of the azide group
c) [tex]NH_{3}[/tex](Ammonia) in excess - to carry out reductive amination
Therefore, the reagents used in the conversion of 1-butanol to pentlylamine would be a) [tex]NaN_{3}[/tex], b) [tex]H_{2} O[/tex], and c) [tex]NH_{3}[/tex](in excess).
To convert 1-butanol to dibutyl amine, the reagents would be:
a) [tex]SOCl_{2}[/tex](Thionyl chloride) - to perform a nucleophilic substitution
b) Butylamine - to react with the chloride group
Therefore, the reagents used in the conversion of 1-butanol to dibutyl amine would be: a) [tex]SOCl_{2}[/tex]and b) Butylamine.
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The elements C and Se have the same electronegativity value, 2.55. Which of the following claims about the compound that forms from C and Se is most likely to be true?
a. The compound is likely to be an ionic compound.
b. The compound is likely to be a covalent compound.
c. The compound is likely to be a metallic compound.
d. The compound is likely to be an organic compound.
Carbon (C) and Selenium (Se) having the same electronegativity value of 2.55 is likely to form a (b) covalent compound.
An electronegativity value is the measure of the ability of an atom to attract shared electrons towards itself when they are chemically bonded with another atom.
Brief Information about C and Se:
Carbon (C) - Carbon is the 6th element on the periodic table. It is a non-metallic element that can be found in all known life forms. Carbon has 4 valence electrons, and it can either lose or share electrons to attain a stable electron configuration.
Selenium (Se) - Selenium is a non-metal element that belongs to group 16 of the periodic table. It has 6 valence electrons, and it can either lose or share electrons to attain a stable electron configuration. It is not found in its elemental form in nature and it is found in trace amounts in soils, rocks, and water.
Based on the above information, the following claim about the compound that forms from C and Se is most likely to be true: Option b. The compound is likely to be a covalent compound.
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Identify the orbital containing the electron removed in each ionization. Enter a subshell designation, such as 3p or 5s.
a. 1st
b. 2nd
c. 3rd
The orbitals are;
a. 1st - 4s
b. 2nd - 4s
c. 3rd - 3d
What is the orbital from which the first, second and third electrons are removed from the transition elements?First, second, and third electrons from the 4s orbital are frequently removed from transition elements before any electrons from the 3d orbital. This is due to the fact that the energy levels of the 4s and 3d orbitals are quite similar and the energy level of the 4s orbital is marginally lower.
According to the Aufbau principle, electrons fill the lowest possible energy levels first in the electron configuration of transition elements before migrating to higher energy levels. As a result, electrons fill the 4s orbital first, followed by the 3d orbital, with the first two electrons.
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If a nuclear reactor were to have a meltdown, radioactive materials could escape in the form of gases from the reactor into the atmosphere and harm humans and the environment. One safety system that might be able to prevent such an escape is a:
A containment building.
hope this helpedddd
consider a thin film of of soapy water (n = 1.33) on plexiglas. since light is a wave, there are many thicknesses of this film that will result in constructive interference.
When light passes through a thin film of soapy water (n = 1.33) on plexiglass, there are several thicknesses of this film that will result in constructive interference.
Due to the light being a wave, it can create a constructive or destructive interference pattern.The thickness of the thin film of soapy water can be calculated by using the equation 2nt = mλ where n is the refractive index of the medium, t is the thickness of the film, m is the order of interference, and λ is the wavelength of the incident light.
If the thickness of the film satisfies the above equation, the light waves will interfere constructively, resulting in a bright spot.
The order of interference determines the location of the bright spot and is indicated by an integer value (m = 0, 1, 2, 3...).
The reason why soapy water forms a thin film on plexiglass is due to the adhesion and cohesive forces between the two.
The thickness of the film can be controlled by changing the concentration of soap in water or the angle of incidence of the light.
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The concentration of sugar in Coke is approximately 10%, or 100 ppt. If you drink
a single can of coke, which holds 355 ml, how much sugar have you consumed?
Answer:
35.5g of sugar
Explanation:
To solve this question we must assume the density of coke = Density of water = 1g/mL
Thus, in a single can of coke, the mass is 355g. Now, the 10% of this coke is sugar. That means the amount of sugar you are consuming is:
355g * (10/100) = 35.5g of sugar
10/100 = 10%
Question 19 (3 points)
If the density of the earth was 11.0 g/mL instead of its measured value of 5.51 g/mL, the force of gravity would
be twice what it is at sea level. If the earth's density was twice than its actual density, then in pounds per
square inch at sea level the earth's atmosphere in British units would be equal to:
a) 7.35 psi b) 14.7 psi c ) 29.4 psi d) 44.1 psl e) 98.8 psi
Answer:
c ) 29.4 psi
Explanation:
If the density of earth was twice than its actual density which is 5.51 g/mL, then at sea level the atmospheric pressure of earth in British units would be equal to 29.4 psi because increase of gravity, increase occurs in the atmospheric pressure. If we double the gravity of earth by double of the earth density, so the weight of that same mass of air will be double which leads to the doubling of the atmospheric pressure at the sea level.
How many moles is 80.0 g of calcium?
Answer:
Here we were given the weight of Ca as 80g
and the atomic mass of carbon is 40u(molar mass)
using the formula
n=W/Mwhere w is weight and m is molar mass
80/40
=2
therefore, there are 2 moles in 80g of calcium
What is the standard units of mass, length and time in the (a) CGS system (b) SI system
Explanation:
a. CGS system: centimetre as the unit of length, the gram as the unit of mass, and the second as the unit of time
b. SI system: metre as the unit of length, the kilogram as the unit of mass, and the second as the unit of time
Compute the percentage of error to the nearest tenth in the student’s calculation if the actual specific heat value for aluminum is 0.9J:g*C.
Complete Question:
1. A block of aluminum with a mass of 140 g is cooled from 98.4°C to 62.2°C with a release of 4817 J of heat. From these data, calculate the specific heat of aluminum.
a. Compute the percentage of error to the nearest tenth in the student's calculation if the actual specific heat value for aluminum is 0.9 J/g°C
Answer:
Percent error = 55.56 %
Explanation:
Given the following data;
Mass = 140 grams
Initial temperature = 62.2°C
Final temperature = 98.4°C
Quantity of heat = 4817 Joules.
To find the specific heat capacity;
Heat capacity is given by the formula;
[tex] Q = mcdt[/tex]
Where;
Q represents the heat capacity or quantity of heat. m represents the mass of an object. c represents the specific heat capacity of water. dt represents the change in temperature.dt = T2- T1
dt = 98.4 - 62.2
dt = 36.2°C
Making c the subject of formula, we have;
[tex] c = \frac {Q}{mdt} [/tex]
Substituting into the equation, we have;
[tex] c = \frac {4817}{140*36.2} [/tex]
[tex] c = \frac {4817}{5068} [/tex]
Specific heat capacity, = 0.95 J/g°C
b. To find the percentage error;
Given the following data;
Actual specific heat capacity = 0.9 J/g°C
Experimental specific heat capacity = 0.95 J/g°C
Percent error can be defined as a measure of the extent to which an experimental value differs from the theoretical value.
Mathematically, it is given by this expression;
[tex] Percent \; error = \frac {experimental \;value - actual \; value}{ actual \;value} *100[/tex]
Substituting into the formula, we have;
[tex] Percent \; error = \frac {0.95 - 0.9 }{ 0.9} *100[/tex]
[tex] Percent \; error = \frac {0.5}{0.9} *100[/tex]
[tex] Percent \; error = 0.5556 *100[/tex]
Percent error = 55.56 %
If a calorimeter used for an experiment had been made out of a heat-conducting material, such as metal, rather than styrofoam, a non-heat conducting metal, would the measured calorimeter constant be larger or smaller? Explain your answer.
If a calorimeter made of a heat-conducting material, such as metal, is used instead of a non-heat conducting material like Styrofoam, the measured calorimeter constant would be smaller. This is because a calorimeter made of a heat-conducting material would allow heat to be transferred more efficiently between the system being studied and the surroundings, resulting in less heat being absorbed by the calorimeter itself.
When conducting experiments involving heat transfer, a calorimeter is used to measure the heat exchanged. The calorimeter constant represents the amount of heat absorbed or released by the calorimeter for a given temperature change. A calorimeter made of a heat-conducting material, like metal, would conduct heat more effectively from the system to the surroundings. This means that a larger proportion of the heat generated by the system would be transferred away from the calorimeter, resulting in less heat being measured by the calorimeter itself. Consequently, the measured calorimeter constant would be smaller compared to using a non-heat conducting material like Styrofoam, where more heat would be retained within the calorimeter.
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Complete and balance the following redox equation in acidic solution using the smallest whole number coefficients. What is the coefficient of SnO₂ in the balanced equation? Sn + HNO₃ → SnO₂ +NO₂ +H₂O a. 2
b. 1
c. 4
d. 3
The coefficient of SnO₂ in the balanced equation is c. 4.
To balance the redox equation in acidic solution, we need to ensure that the number of atoms of each element and the total charge are balanced on both sides of the equation.
By assigning appropriate oxidation numbers to each element and considering the changes in oxidation states, the balanced equation is as follows:
Sn + 4HNO₃ → SnO₂ + 4NO₂ + 2H₂O
In the balanced equation, the coefficient of SnO₂ is 4, indicating that 4 molecules of SnO₂ are produced. This balanced coefficient ensures that the number of tin (Sn) atoms and oxygen (O) atoms are equal on both sides of the equation. Therefore, the correct answer is c. 4.
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Write the formula for Zn+2 (SO4)-2
Answer:
Zn2 + SO4 = Zn2(SO4)2
Explanation:
which of the following is true of carbon? select all that are correct. group of answer choices it can form a maximum of four covalent bonds with other elements. it can form a maximum of three covalent bonds with other elements. it is highly electronegative. it can form both polar and nonpolar bonds. it can only form polar molecules.
Based on the given options, the following statements are true of carbon: It can form a maximum of four covalent bonds with other elements and It can form both polar and nonpolar bonds.
Carbon is an element with atomic number 6, meaning it has six protons in its nucleus. It has four valence electrons, which are the electrons involved in bonding with other atoms.
Carbon's electron configuration allows it to form four covalent bonds by sharing its valence electrons with other atoms. This property is known as tetravalency and is a fundamental characteristic of carbon.
Additionally, carbon can form both polar and nonpolar bonds depending on the atoms it is bonded to and the electronegativity difference between them.
When carbon bonds with atoms of similar electronegativity, such as hydrogen, the bond is nonpolar because the electrons are shared equally. However, if carbon bonds with atoms of higher electronegativity, such as oxygen or nitrogen, the bond becomes polar due to the unequal sharing of electrons.
In summary, carbon can form a maximum of four covalent bonds with other elements due to its tetravalent nature. It is not highly electronegative itself but can form both polar and nonpolar bonds depending on the atoms it is bonded to. Therefore, the correct statements are:
It can form a maximum of four covalent bonds with other elements.
It can form both polar and nonpolar bonds.
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A 0.100 M oxalic acid, HO2CCO2H, solution is titrated with 0.100 M KOH. Calculate the pH when 25.00 mL of oxalic acid solution is titrated with 35.00 mL of NaOH. Ka1 = 5.4 × 10−2 and Ka2 = 5.42 × 10−5 for oxalic acid
A 0.100 M oxalic acid, HO₂CCO₂H, solution is titrated with 0.100 M KOH. Calculate the pH when 25.00 mL of oxalic acid solution is titrated with 35.00 mL of NaOH. Ka1 = 5.4 × 10−2 and Ka2 = 5.42 × 10−5 for oxalic acid is 1.94.
Oxalic acid is a dicarboxylic acid with the chemical formula HO₂CCO₂H, with a pKa1 of 1.25 and a pKa2 of 4.14. A titration is a process in which a solution of known concentration is added to a solution of unknown concentration until the equivalence point is reached.
The goal of a titration is to determine the concentration of the unknown solution. A 0.100 M oxalic acid solution is titrated with 0.100 M KOH. The pH is calculated when 25.00 mL of oxalic acid solution is titrated with 35.00 mL of NaOH. Ka1 = 5.4 × 10−2 and Ka2 = 5.42 × 10−5 for oxalic acid. Here is how to calculate the pH when 25.00 mL of oxalic acid solution is titrated with 35.00 mL of NaOH:
Step 1: Calculate the moles of oxalic acid
moles of oxalic acid = concentration x volume
moles of oxalic acid = 0.100 M x 0.025 L
moles of oxalic acid = 0.0025 mol
Step 2: Calculate the moles of NaOH
moles of NaOH = concentration x volume
moles of NaOH = 0.100 M x 0.035 L
moles of NaOH = 0.0035 mol
Step 3: Determine which species is in excess
0.0025 mol of oxalic acid reacts with 0.0025 mol of KOH
0.0010 mol of oxalic acid reacts with 0.0035 mol of KOH
0.0010 mol of oxalic acid is consumed in the reaction
The excess moles of NaOH = 0.0035 - 0.0010 = 0.0025 mol
Step 4: Calculate the concentration of the remaining OH- ions
Concentration of OH- ions = moles of OH- ions / volume
Concentration of OH- ions = 0.0025 mol / 0.060 L
Concentration of OH- ions = 0.0417 M
Step 5: Calculate the concentration of H+ ions
Ka1 = [H+][C₂O₄₂-]/[HC₂O₄-]
5.4 x 10^-2 = x^2 / (0.100 - x)
Assuming that x is much smaller than 0.100, x = [H+] = 0.115 M
Step 6: Calculate the pH
pH = -log[H+]
pH = -log(0.115)
pH = 1.94
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Select the correct answer.
What data points do we combine to make the integrated rate law?
a) initial concentration and time
B) concentration at some later time, time, and rate constant
C) initial concentration, concentration at some later time, and time
D) initial concentration, concentration at some later time, time, and rate constant
Answer:
b???
Explanation:
Answer:
Pretty sure it A.
Explanation:
I just thought that cause what exactly does 'some later time' mean?
Jack has a rock. The rock has a mass of 14g and a volume of 2cm3. What is the density of the rock?
Answer:
The density is 7 g/cm^3
Explanation:
The formula for density is p=m/V. Where p is the density, m is mass, and V is the volume. 14/2=7.
1. Why is the timing of tides predictable?
A. because winds are predictable
B. because the moon’s path is predictable
C. because ocean water density is predictable
D. because the sun’s movements are predictable
Answer:
Because the moon's path is predictable
Explanation:
The moon affects the tides
What happens as you decrease the temperature of a solution?
A.
The number of solute particles increases.
B.
The number of solute particles decreases.
C.
The rate of dissolution increases.
D.
The rate of dissolution decreases.
E.
The temperature has no effect on the rate of dissolution.
Answer:
D is the answer
Explanation:
3.4
Why is this cocktail not the perfect medication to treat infections by these
bacteria?
Answer:
many bacteria are resistant to penicillin and other β-lactam antibiotics - some bacteria have beta-lactamase enzymes and are able to break down the antibiotics - as a result, many drugs are combined with other drugs that are β-lactamase inhibitors.
Explanation:
Quizlet
Jet streams can cause warmer air temperatures on coastal land areas when
A. a cold jet stream occurs
B. a warm jet stream occurs
C. the tide changes direction
Jet streams can cause warmer air temperatures on coastal land areas when the tide changes direction.
What are jet streams?Jet streams are short bands of high wind that travel across the globe from west to east.
On earth, the location of the jet stream is in the latitude of the tropopause.
Two polar jet streams are present near the north and south poles.
Two subtropical jet streams are present, closer to the equator,
These make the Earth's four principal jet streams.
Thus, the correct option is C.
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Which are characteristics of all metals?
A
They are malleable, ductile, and conduct electricity.
B
They are malleable, ductile, and form ionic bonds.
C
They are ductile, inert, and conduct electricity.
D
They are noble, ductile, and form ionic bonds.
Answer:
A. They are malleable, ductile, and conduct electricity.
Explanation:
Answer:
a
Explanation:
Consider the four weak bases listed below. Which would primarily exist as a cation in an aqueous solution with pH = 9? a) only aniline, Kb = 4.0 x 10-10, pKa = 4.60 b) only caffeine, Kb = 1.4 x 10-4, pKg = 10.1 c) none will be cationic d) only quinine, Kb = 3.3 x 10-6, pKa = 8.52 e) only morphine, Kb = 1.6 x 10-6, pkg = 8.20 f) all will be cationic
When an aqueous solution has a pH value of 9, the solution is basic. It is important to note that weak bases behave like weak acids, producing their corresponding conjugate acid in the presence of water.
When a base interacts with water, it accepts a hydrogen ion to form the conjugate acid of the base. This conjugate acid can either exist in solution as a neutral species, as an anion, or as a cation. An anion is formed when a strong acid reacts with a weak base and displaces the weak base's conjugate base. Consider the four weak bases listed below. Which would primarily exist as a cation in an aqueous solution with pH = 9?
a) Aniline with Kb = 4.0 x 10-10 and pKa = 4.60
Aniline is a weak base that will primarily exist in a cationic state in an aqueous solution with a pH of 9. Aniline's Kb value is small, indicating that it is a weak base. Aniline's conjugate acid is NH2+, which is a weak acid.
b) Caffeine with Kb = 1.4 x 10-4 and pKg = 10.1
Caffeine is a weak base that will primarily exist in an anionic state in an aqueous solution with a pH of 9. Caffeine has a Kb value that is relatively large, indicating that it is a weak base. The conjugate acid of caffeine is H+, which is a strong acid.
c) None of the above weak bases will be cationic in solution.
d) Quinine with Kb = 3.3 x 10-6 and pKa = 8.52
Quinine is a weak base that will primarily exist in a cationic state in an aqueous solution with a pH of 9. Quinine has a Kb value that is small, indicating that it is a weak base. The conjugate acid of quinine is NH+2, which is a weak acid.
e) Morphine with Kb = 1.6 x 10-6 and pkg = 8.20
Morphine is a weak base that will primarily exist in a cationic state in an aqueous solution with a pH of 9. Morphine has a Kb value that is small, indicating that it is a weak base. The conjugate acid of morphine is NH+2, which is a weak acid.
f) All weak bases will not be cationic in solution.
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A 0.5 kg arrow was shot at a target. The arrow accelerated at 200 m/s2. What was
the net force on the arrow to the nearest newton?
Record your answer and be sure to use the correct place value.
Answer: I think 100?
Explanation:
It’s asking for the net FORCE! And the formula to find force is to multiply the mass by the acceleration which would be in this case 0.5x200 which would be 100
2.50 Kilojoule (2.5 Kj) is the same amount of energy in calories?
A) 598 cal.
B) 2720 cal.
C) 0.598 cal.
D) 105 cal.
2.50 Kilojoule (2.5 Kj) is the same amount of energy in calories as (A) 598 cal.
To convert kilojoules (Kj) to calories, you can use the conversion factor of 1 kilocalorie (kcal) = 4.184 kilojoules (Kj).
Here, 2.50 Kilojoules (2.5 Kj) is the amount of energy, we can convert it to calories as follows:
2.50 Kj * (1 kcal / 4.184 Kj) = 0.598 kcal
Since 1 kilocalorie (kcal) is equal to 1000 calories (cal), we can further convert:
0.598 kcal * 1000 cal/kcal = 598 cal
Therefore, the same amount of energy as 2.50 Kilojoules (2.5 Kj) is 598 calories.
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The table gives the concentrations of C2H4O(g)C2H4O(g) as a function of time at a certain temperature for the reaction shown.
C2H4O(g)⟶CH4(g)+CO(g)C2H4O(g)⟶CH4(g)+CO(g)
Verify that this is a first-order reaction by plotting ln[C2H4O]ln[C2H4O] versus time and determining the value of the rate constant.
[C2H4O] (M)Time (min)0.08600.000.046558.00.035583.00.0274107.00.0174150.0
_____________min^-1 ?
The required answer for the value of the rate constant, k, is 0.009 min-1.
Explanation: For verifying if the reaction is first order, the graph of ln [C2H4O] versus time will be plotted.The given data can be used for calculating the ln [C2H4O] as given below:ln [C2H4O] = ln [0.0860] = -2.45ln [C2H4O] = ln [0.0465] = -3.06ln [C2H4O] = ln [0.0355] = -3.33ln [C2H4O] = ln [0.0274] = -3.60ln [C2H4O] = ln [0.0174] = -4.05Now, we will plot a graph between ln [C2H4O] and time on a sheet of paper or in excel. From the graph, we will get a straight line The graph obtained is a straight line which confirms that the given reaction is first order.
To determine the value of rate constant, k, we will use the formula:ln [C2H4O] = -kt + ln [C2H4O]0Where,[C2H4O] = Concentration of ethylene oxide at time t [C2H4O]0 = Initial concentration of ethylene oxide at t = 0 k = Rate constant of the reaction t = Time period of the reactionNow, we will use the given data to determine the value of k:ln [0.0860] = -k × 0 + ln [0.0860] => k = 0ln [0.0465] = -k × 8 + ln [0.0860]=> k = 0.012ln [0.0355] = -k × 3 + ln [0.0860]=> k = 0.008ln [0.0274] = -k × 7 + ln [0.0860]=> k = 0.010ln [0.0174] = -k × 50 + ln [0.0860]=> k = 0.009Thus, the value of the rate constant, k, is 0.009 min-1.
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HELPHELPHELPHELPHELPHELPHELP
Answer:
C
Explanation:
increasing T (knowledge of direct proportion and Inverse proportion)
(PLS HELP ASAP <3)
a sample of oxygen gas occupies 600mL when the pressure is 900 mmHg, what is the pressure if the volume is increased to 800 mL
Answer:
675 mmHgExplanation:
The new pressure can be found by using the formula for Boyle's law which is
[tex]P_1V_1 = P_2V_2[/tex]
Since we're finding the new pressure
[tex]P_2 = \frac{P_1V_1}{V_2} \\[/tex]
We have
[tex]P_2 = \frac{900 \times 600}{800} = \frac{540000}{800} \\ = 675[/tex]
We have the final answer as
675 mmHgHope this helps you
The percent yield for the reaction in which 15.6g of aluminum hydroxide is reacted in excess hydrogen chloride gas is 92.5%. What is the actual yield of aluminum chlorine?
Answer:
24.6 g
Explanation:
which step in glycolysis involves the process where direct substrate phosphorylation occurs? (a) 3- phosphoglycerate to phosphoenolpyruvate (b) 1,3, bisphosphoglycerate to 3-phosphoglycerate and phosphoenolpyruvate to pyruvate (c) fructose-6-phosphate to fructose1,6-bisphosphate (d) 3- phosphoglycerate to 2-phosphoglycerate and phosphoenolpyruvate to pyruvate
The correct option is (b) 1,3, bisphosphoglycerate to 3-phosphoglycerate and phosphoenolpyruvate to pyruvate is the step in glycolysis involves the process where direct substrate phosphorylation occurs.What is glycolysis?Glycolysis is the metabolic pathway that breaks down glucose to pyruvate.
The glycolytic pathway converts glucose into two molecules of pyruvate and yields two ATP and two NADH molecules for each glucose molecule that enters the process.The series of reactions of glycolysis are divided into two main phases: an energy-investment phase, in which energy is consumed, and an energy-payoff phase, in which ATP is created. The first energy-investment phase is phosphorylation of glucose into glucose-6-phosphate, which is followed by phosphorylation of fructose-6-phosphate into fructose-1,6-bisphosphate.The direct substrate phosphorylation is the process where a substrate or molecule is phosphorylated via the transfer of a high-energy phosphate molecule directly from a phosphorylated intermediate (substrate-level phosphorylation).1,3-bisphosphoglycerate to 3-phosphoglycerate and phosphoenolpyruvate to pyruvate are steps in glycolysis that involve the process where direct substrate phosphorylation occurs.
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Minerals are formed by which process? O magma cooling O fault lines moving O metamorphosis O sedimentation