Ciara is swinging a 0.015 kg ball tied to a string around her head in a flat, horizontal circle. The radius of the circle is 0.50 m. It takes the ball 0.70 seconds to complete one full circle. Calculate the tension in the string and its direction that provides the centripetal force acting on the ball to keep it in the circular path. (3 points)

0.60 N, along the line tangent to the circle
0.015 N, along the line tangent to the circle
0.60 N, toward the center of the circle
0.015 N, toward the center of the circle

Answer:

60n would be the needed force

The force needed to push a box weighing 30 N up a ramp that has an ideal mechanical advantage of 3 is equal to 10 N.

The mechanical advantage can be described as the ratio of the input force to the output force. The mechanical advantage of any machine can be determined by the ratio of the forces involved to do the work.

The ratio of the resistance force to the effort is called the actual mechanical advantage which will be comparatively less. The efficiency of a machine is always determined by equating the ratio of its output to its input.

The efficiency of the machine is equal to the ratio of the actual mechanical advantage (M.A.) and theoretical mechanical advantage. Mechanical advantage can be defined as the force produced by a machine to the force applied to it.

Given the load = 30 N and the ideal mechanical advantage = 3

Mechanical advantage = Load/ Effort

Input force or effort = Load/ M.A.

Force = 30/3

Input Force = 10 N

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#SPJ2

Answer:

This appears to be the formula for the electrical force between 2 objects.

You need this constant to calculate the electrical force between 2 charged objects.

Note that k = (1 / 4 * π ∈0)

∈0 is called the permittivity constant and ∈0 = 8.85E-12 farad/m

k = ( 1 / (4 * 3.28 * 8.85E-12) = 8.99E9

This makes F reasonably easy to remember as

F = 9E9 Q1 * Q2 / R^2 Newtons for the electrical force between Q! and Q2 separated by R

Using Joules law

[tex]\\ \sf\Rrightarrow H=VIt[/tex]

[tex]\\ \sf\Rrightarrow H=5(2)(1)[/tex]

[tex]\\ \sf\Rrightarrow H=10Kwh[/tex]

1. • Here, force of gravity on the block = 20 N.

• Therefore, the normal force will also be the same, i.e., 20 N [According to Newton's Third Law, on every action, there is an equal and opposite reaction]

• The coefficient

[tex] u_{k} = 0.4[/tex]

• Force of friction =

[tex]u_{k} \times \: normal \: \: \: force \\ = 0.4 \times 20N \\ = 8N[/tex]

• Hence, the force of sliding friction between the block and the ground is 8 N.

• So, it is option c. 8 N

2. The answer is option d. continue in the same direction with no change in speed.

We know, force = mass × acceleration. When force is 0, then acceleration will also be 0 since mass cannot be 0. So, there will be no change in speed.

3. It is option b. force that is required to give a one kilogram object the acceleration of 1 m/s^2.

Newton is the SI unit of force. As mentioned earlier, force = mass × acceleration. The SI unit of mass and acceleration is Kg and m/s^2 respectively.

So, 1 N = 1 Kg × 1 m/s^2.

4. It is d. not zero.

Acceleration is the change in speed. So, if the force is zero, then acceleration will not occur.

5. Force = 2 N

Acceleration of the object A = 2 m/s^2.

Acceleration of the object B = 1 m/s^2.

Therefore, mass of the object A = 2 N ÷ 2 m/s^2 = 1 Kg

And, mass of the object B = 2 N ÷ 1 m/s^2 = 2 Kg

So, the mass of object B is greater than that of object A.

Hence, the answer is option c. Object B has more mass.

Hope you could get an idea from here.

Doubt clarification - use comment section.

The correct option is A: the force exerted on the wall by the sledgehammer is  - 1000 N

Newton's third law of motion states that for every action or force, there is an equal but oppositely directed force.

Force with which the sledgehammer hits the wall = 1000 N

Thus, the force exerted by the sledgehammer on the wall = -1000 N

Thus, the correct option is A: the force exerted on the wall by the sledgehammer is  - 1000 N

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Answer:

Explanation:

ello

The galaxy is 7200 km/s moving away from us.

A Hubble is a large telescope in space.

The question can be solved using the formula below

⇒ Formula

⇒ Where:

⇒ Given:

⇒ Substitute these values into equation 1

Hence, the galaxy is 7200 km/s moving away from us.

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Answer:

I hope this helps:)

Explanation:

good luck:)

Answer:

d. distance travelled

Explanation:

answer

Answer:

KE = 225000000 J

Explanation:

Answer:

10.954. from equation. KE=1/2m(v^2)

2KE=m(v^2) 6000=50(v^2) (v^2)=6000/50

(v^2)=120. square root for all v=10.954 m/s

Answer:

folk dancing is old music and ball room is young dancing

Answer:

Newton's universal law of gravitation predicts how mass can distort light, so we can apply Newton's law to determine the mass of the cluster. ... The lensing allows us to determine the orbital speeds of galaxies in the cluster, so that we can determine the mass of the cluster from the orbital velocity law.

Explanation:

Answer:

373.15 Kelvin

Explanation:

Boiling Point of water

= 100 degree Celsius

= (100 + 273.15) Kelvin

= 373.15 Kelvin

Gravitational Force

Explanation:-

The magma flows through the gap between the rocks which are stacked up on top of one another.

The gravity attracts the magma to do that.

Also the rocks are stacked because of the gravitational force between them

Hence Option D is correct

Hope it helps

Answer:

pls mark me as brainliest

Explanation:

last one

the answer is c, inherited traits are controlled by genes, which are found in chromosomes

Answer:

Large numbers might create fuse, be confusing and if you miss even one of the zeros it is a very big deal in a situation when you are making a spaceship. Hope this answers your questions :) Merry Christmas. Have fun.

Explanation:

2

Explanation:

for saving space in large numbers

and small numbers for multiplying easily

The answer is that the resultant force is the vector sum of the component forces. In your simple example, where the component forces (F1 and F2) are at right angles to one another, as illustrated below, then the resultant force (r) is given by:

[tex]r= \sqrt{(f_{1}) {}^{2} +( f_{2})^{2} + 2f_{1}f_{2}. cos \: Θ, } \\ where \\ \: Θ, = angle \: between \: f_{1} \: and \: f_{2} \\ r = \sqrt{(2) {}^{2} + (5) {}^{2} + 2 \times 2 \times 5 \times cos90 } \\ \sqrt{4 + 25} = \sqrt{29} = 5.385 \\ nearest \: hundred = 5.39[/tex]

Answer: 3N to the right

Explanation: 2N- 5N= 3N

did you end up getting the answer- im struggling

Answer:

I would think human error could cause differences like not pressing the stop watch on time.

Explanation:

Answer:

y-component = 45.75N

x-component = 0N

Explanation:

Answer:

I just put a random number for the work

Explanation:

I hope it is ok.

cut the square and make it a triangle

Hey there! I'll try to provide you with my best answer.

Answer: In a collision, the velocity change is always computed by subtracting the initial velocity value from the final velocity value. If an object is moving in one direction before a collision and rebounds or somehow changes direction, then its velocity after the collision has the opposite direction as before.

By using third law of equation of motion, the final velocity V of the rubber puck is 8.5 m/s

Given that a hockey player hits a rubber puck from one side of the rink to the other. The parameters given are:

mass m =  0.170 kg

initial speed u = 6 m/s.

Distance covered s = 61 m

To calculate how fast the puck is moving when it hits the far wall means we are to calculate final speed V

To do this, let us first calculate the kinetic energy at which the ball move.

K.E = 1/2m[tex]U^{2}[/tex]

K.E = 1/2 x 0.17 x [tex]6^{2}[/tex]

K.E = 3.06 J

The work done on the ball is equal to the kinetic energy. That is,

W = K.E

But work done = Force x distance

F x S = K.E

F x 61 = 3.06

F = 3.06/61

F = 0.05 N

From here, we can calculate the acceleration of the ball from Newton second law

F = ma

0.05 = 0.17a

a = 0.05/0.17

a = 0.3 m/[tex]s^{2}[/tex]

To calculate the final velocity, let us use third equation of motion.

[tex]V^{2}[/tex] = [tex]U^{2}[/tex] + 2as

[tex]V^{2}[/tex]  = [tex]6^{2}[/tex] + 2 x 0.3 x 61

[tex]V^{2}[/tex] = 36 + 36

[tex]V^{2}[/tex] = 72

V = [tex]\sqrt{72}[/tex]

V = 8.485 m/s

Therefore, the puck is moving at the rate of 8.5 m/s (approximately) when it hits the far wall.

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Answer:

1.1x10¹⁶ kg

Explanation:

Let m =  mass of asteroid y.

Because asteroid y has three times the mass of asteroid z, the mass of asteroid z is m/3.

Given:

F = 6.2x10⁸ N

d = 2100 km = 2.1x10⁶ m

Note that

G = 6.67408x10⁻¹¹ m³/(kg-s²)

The gravitational force between the asteroids is

F = (G*m*(m/3))/d² = (Gm²)/(3d²)

or

m² = (3Fd²)/G

    = [(3*(6.2x10⁸ N)*(2.1x10⁶ m)²]/(6.67408x10⁻¹¹ m³/(kg-s²))

   = 1.229x10³² kg²

m = 1.1086x10¹⁶ kg = 1.1x10¹⁶ kg (approx)

Answer:

Vertebrate zoology

Explanation:

Have a great day!

[tex]\text{Given that,}\\\\\text{Mass}~ m = 68 ~\text{g} = 68 \times 10^{-3}~ \text{kg}\\\\\text{Volume}~ V = 80 ~ \text{cm}^3 = 80 \times 10^{-6}~ \text{m}^3 = 8\times 10^{-5}~ \text{m}^3\\\\\\\text{Density} ~\rho = \dfrac mV = \dfrac{68\times 10^{-3}}{8 \times 10^{-5}} = 8.5 \times 10^2 = 850 ~ \text{kg}~\text{m}^{-3}[/tex]

Answer:

3m

Explanation:

I can't make a drawing right know, but it's all around vectors. First of all the ball travels down 5 meters, so we have a vector pointing down, then it is reflected and travels 2 meters up. You have to sum the vectors so you obtain that the distance traveled is: 5-2 meters = 3m