Classify each polynomial according to its degree and type. Look at the screenshot below!

Answer:

a<-12

Step-by-step explanation:

Three selected options are as follows:

Distance is a numerical measurement of how far apart objects or points are. In Physics or everyday usage, distance may refer to a physical length or an estimation based on other criteria.

Here, put the values in option substitute  in given equation D(t)

Option 1: At t = 0 hour,

              D (0) = 300 X 0 + 125 = 125 ≠ 300    Option Incorrect

Option 2 : At t = 2 hours,

                D(2) = 300 X 2 + 125 = 725  Option Correct.

Option 3: At t = 2.5 hours,

               D(2.5) = 875  Option Incorrect

Option 4: At t = 3 hours,

               D(3) = 875 Option Correct

Option 5: At t = 6 hours,

                D(6) = 75 X 6 + 612.5 = 450 + 612.5

                        = 1062.5 miles  Option Correct

Thus, Option two, four and five are correct.

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The amount received by Ahmed is 168 gm.

The ratio is defined as the comparison of two quantities of the same units that indicates how much of one quantity is present in the other quantity. Ratios can be classified into two types. One is part to part ratio and the other is part to whole ratio.

Here, let the amount received by Ahmed be 7x

          and amount received by Babar be 3x

       Total amount of sweets = 240 gm

Now, according to question,

           7x + 3x = 240

              10x = 240

               x = 240/10

              x = 24

Thus, the amount received by Ahmed is 7 X 24 = 168 gm and amount received by Babar = 3 X 24 = 72 gm.

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because the x values are identical the radius would be found by subtracting the y values.

6-2 = 4

the radius is 4

Answer: 78.09

Step-by-step explanation:

Seventy-eight is the whole number, so it goes to the left of the decimal point 78.09

Nine-hundredths is decimal, it goes two places to the right of the decimal point because it's hundredths 78.09

Answer:

11.94 %

Step-by-step explanation:

Compound interest formula     FV = PV e^(it)    i = decimal interest per year  

                                                                             t = time   FV = future value

2600 = 1000e^(i * 8)

  solve for i = 11.94 %

The probability that the lunch combo will have an ham sandwich is 3 / 7.

Probability simply means possibility. It describes how likely an event will occur or happen.

Mathematically,

probability = number of favourable outcome to A / total number of possible outcome

Therefore,

probability that a lunch combo will include a ham sandwich = 6 / 14 = 3 / 7

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The area of the Triangle PQR which is in the circle,  is given as 784.25. See the computation below.

Mathematically speaking, a circle is a 2-dimensional shape whose boundaries are round and are equidistant from a fixed center.

The area of ΔPQR is given as ((√3)/4) x QR²

= (√3)/4) x (6√2 - 2√6)²

= 0.43301270189 x  (8.48528137424 x 4.89897948557)²

=  0.43301270189 x 1728

Area of ΔPQR = 784.25

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The height of the pile is 150.7 mm, and the volume is V = 6,830,477.5 mm³.

We know that each paper is 0.55mm thick, then if we pile 274 of these, the height of the pile will be:

H = 0.55mm*274 = 150.7mm

Now we want to get the volume of the pile of paper. Remember that for a rectangular prism of height H, width W, and length L, the volume is:

V = H*W*L

In this case, we have:

Then the volume is:

V = (150.7mm)*(185 mm)*(245 mm) = 6,830,477.5 mm³

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Answer:

function

Step-by-step explanation:

no repeated domain means its a function

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Answer:

The point will be plotted on Y axis

Answer:

120 = L+2W

LW =area.

to maximize area with given fencing that would make Width = 30 feet and length = 60

A= LW = (120-2W)W = 120W -2W^2

A' = 120-4W =0

W = 30

L=120-2(30) = 60 feet

W by L is 30 by 60 feet for max area

Answer:

6

Step-by-step explanation:

[tex]f(a)=a^4-2a^3 -10a^2 -7a \\\\f(-2) = (-2)^4-2(-2)^3 -10(-2)^2 -7(-2)\\\\~~~~~~~~~=16-2(-8)-10(4)+14\\\\~~~~~~~~~=30+16-40\\\\~~~~~~~~~=46-40\\\\~~~~~~~~~=6[/tex]

Answer:

C 33.52 cm³

Step-by-step explanation:

Here, we have Radius(r)=2(Given)

Volume = 4/3 πr³

= 4/3 · 22/7 · 2³

= 33.5238

Round to the nearest tenth:
C 33.52 cm³

Answer:

A

Step-by-step explanation:

Consider the left triangle within the big triangle.

Identity :

sin θ = opposite side / hypotenuse

=============================================================

Taking the sine value of the angle to find h :

⇒ sin37° = h/6

⇒ h = 6sin37°

Opposite 37 is h

Angle opposite 6 is 90

Sine rule:

h/sin37 = 6/sin90

xsin37

h = 6 x sin37/ sin90

h = 3.6108....

h = 3.6 to 1dp

A) 6xsin37= 3.6108...

B) 10xsin37 =6.018...

C) 6x 10 xsin37 = 36.108...

D) 10 x 6 x sin37 = 36.108...

Thus, answer is A

Hope this helps!

The length of the other leg of the right triangle will be 13.86 cm.

The complete question is given below.

The triangle BCD ​ is a right triangle. The length of the hypotenuse is 19 centimeters. The length of one of the legs is 13 centimeters.

What is the length of the other leg?

The Pythagoras theorem states that the sum of two squares equals the squared of the longest side.

The Pythagoras theorem formula is given as

H² = P² + B²

Let the unknown sides be x. Then we have,

19² = 13² + x²

361 = 169 + x²

 x² = 361 – 169

 x² = 192

  x = 13.856 ≈ 13.86 cm

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Explanation:

Given Inequalities:

(i) 3x + 8y ≤ 480

(ii) y - x ≤ 20

For first inequality:

(a) y intercept: (0, 60)

(b) x intercept: (160, 0)

For second inequality:

(a) y intercept: (0, 20)

(b) x intercept: (-20, 0)

The point (40, 40) falls between these two inequalities.

By finding the scale factor of the model, we will see that the area is 561,600 square feet.

On the model, the length is 13 inches, and the actual length is 780 ft, then the scale factor is:

k = (780ft)/(13 in) = 60 ft/in

This means that each inch in the model is equal to 60ft in the actual plot of land.

Then the width is:

W = (12in)*( 60 ft/in) =  720 ft

And the area is the product between length and width, so we have:

A = (780ft)*(720ft) = 561,600 ft²

Then the correct option is D.

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Answer:

h(4)=17

Step-by-step explanation:

h(g(x)), h(x)= 2x+9; g(x)=4

2(4)+9= 8+9=17

The Sine or Sinθ in a right-angle triangle is the ratio of its perpendicular to its Hypotenuse. The correct option is B.

The Sine or Sinθ in a right-angle triangle is the ratio of its perpendicular to its Hypotenuse. it is given as,

Sin(θ) = Perpendicular/Hypotenuse

where,

θ is the angle,

Perpendicular is the side of the triangle opposite to the angle θ,

The hypotenuse is the longest side of the triangle.

In the ΔGEF, the value of Sin(E) is,

Sin(E) = GF/GE

In the ΔDEF, the value of Sin(E) is,

Sin(E) = FD/FE

Hence, the correct option is B.

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Answer:

Hold its nose

Step-by-step explanation:

You can actually de-scent a skunk if it is the powerful defensive odor you are referring to. When you have a skunk de-scented, they are no longer able to spray, and at this point they are now similar to having a pet cat or dog; lovable and highly desire affection and attention from their owners.

Answer:

(4,-3)

Step-by-step explanation:

The scale factor is 1/3. So, multiply the numbers by 1/3.

12*1/3 is 4.

-9*1/3 is -3.

The new coordinates are (4,-3).

Answer:

(x-7)

Step-by-step explanation:

(1/6)*(x-7)= (1/6)x-(7/6)

Answer:27?

Step-by-step explanation:

So since there needs to be 3 1/3ds in each cup you just multiply 3x9=27

The ratio of a : b : c in its simplest form is 5 : 12 : 30 respectively

So,

a / b = 1/6

b/c = 2/5

1/6 + 2/5

=(5 + 12) /30

a : b and b : c

= 5/30 and 12/30

Therefore,

a : b : c = 5 : 12 : 30

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The value of the car after three years is £6936

The initial value of the car is given as:

Value =  £12000

When the value depreciates by 20% after the first year, the new value of the car is:

New =  £12000 * (1 - 20%)

Evaluate

New =  £9600

When the value depreciates by 15% after the second year, the new value of the car is:

New =  £9600* (1 - 15%)

Evaluate

New =  £8160

When the value depreciates by 15% after the third year, the new value of the car is:

New =  £8160 * (1 - 15%)

Evaluate

New =  £6936

Hence, the value of the car after three years is £6936

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Maintain the same constraints on edge capacity, skew symmetry, and flow conservation in the ordinary maximum-flow problem on a flow network of comparable size.

A flow network is a directed graph with each edge having a capacity and each edge receiving a flow, according to graph theory. The amount of flow on an edge must not exceed the edge's capacity.

Let's suppose the network flow is given by;

G = (V, E)

With edge capacity:

c: E → R

And vertex capacity:

d: V → R

Maintain the same constraints on edge capacity, skew symmetry, and flow conservation.

Consider the new stipulation: for each:

v ∈V

So,

[tex]\rm \sum_{u \in v } \{ f(u,v)|f(u,v) > 0 \} \leq d(v)[/tex]

Thus, if maintain the same constraints on edge capacity, skew symmetry, and flow conservation the ordinary maximum-flow problem on a flow network of comparable size.

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Answer:

40

Step-by-step explanation:

14 = 35% of x

35% = 0.35

So lets make an equation and solve for x:

14 = 0.35x

x = 14÷0.35

x = 40

To check our answer let's put it back into the question :

35% of 40 = 14

10% = 4 , 30% = 12 , 5% = 2

35% = 12+2 = 14 ✅

Hope this helped and have a good day