Determine the slope and y-intercept of each linear function below y=x/3-1

Answers

Answer 1

Answer:

Slope= 1/3

y-int: -1

Step-by-step explanation:


Related Questions

3 cm
.
.
5 cm
If the base is halved and the height is quadrupled, then which of the following statements
about its area will be true?

Answers

Answer:

I think 7

Step-by-step explanation:

if the moon is purple then what toothpaste do u use on your but

A trader buys 30 shirts for #x each. He sells
them all for #y each. What is his profit​

Answers

if he buys 30 for x amount and sells them for y then you would take y and subtract 30x and your left with the answer = y-30x.


Find the sum of the following arithmetic series:
(a) 6-5-16 - .... -115 (b) 21
(c) 13 + 6 -1 - .... -106
Find the sum of the first 500 odd numbers.

Answers

Answer:

12345678910

Step-by-step explanation:

CHARRRRRRRRR joke lang bestie

Which type of sequence is shown? 5, 10, 15, 20, 25, . . .

geometric
both arithmetic and geometric
arithmetic
neither arithmetic nor geometric

Answers

Answer:

Arithmetic Sequence

Step-by-step explanation:

In Arithmetic sequence each term increases by adding/subtracting some constant k. This is in contrast to a geometric sequence where each term increases by dividing/multiplying some constant k.

Arithmetic sequence.

1. A waste management service attempts to design routes so that each of their trucks pick-up on average four tons of garbage or less. A garbage collector believes, however, that he averages picking up more than four tons of garbage per day and decides to perform a hypothesis test. If the hypothesis test is performed at a 5% significance level and the resulting p-value is 0.04. Your conclusion should be:

2. It has been determined with 95% confidence that the proportion of on-line students at NYU who live in Brooklyn is between 0.73 and 0.77. Determine the sample proportion of on-line NYU students who live in Brooklyn.
3. Assume a normal distribution and use a hypothesis test to test the given claim.

According to city reports, it was found that the mean age of the prison population in the city was 26 years. Marc wants to test the claim that the mean age of the prison population in his city is less than 26 years. He obtains a random sample of 25 prisoners, and finds a mean age of 24.4 years and a standard deviation of 9.2 years. At a significance level of 0.05, what should his conclusion be?

Answers

Answer:

1.-Then we p-value indicates that we are in the rejection region we reject H₀

We support the claim of the garbage collector the average picking up more than 4 tn of garbage

2.- p  = 75 %

3.-3.-t(s) is in the rejection region we accept H₀ we have not evidence to support Marc´s claim

Step-by-step explanation:

1.- If p-value is 0,04   and significance level α = 5 %  or  α = 0,05 then p-value < α

Test hypothesis should be    ( x the average of garbage)      

Null hypothesis          H₀           x = 4 Tn

Alternative Hypothesis     Hₐ    x  > 4 Tn

Then  alternative hypothesis suggests a one tail-test to the right  and

p-value <  0,05

Then we p-value indicates that we are in the rejection region we reject H₀

We support the claim of the garbage collector the average picking up more than 4 tn of garbage

2.- As we are dealing with a normal distribution the CI  95 % is symmetrical with respect to the mean, therefore the proportion of student living in Brooklyn is:  

(0,73 + 0,77) /2

p = 0,75     p  = 75 %

Test hypothesis:

Null Hypothesis            H₀            μ    =  26

Alternative Hypothesis      Hₐ      μ   <  26

Alternative hypothesis tells us the test is a one-tail test to the left

Sample size   n = 25

Sample mean   μ  =  24,4

Sample Standard deviation  =  9,2

We assume normal distribution, and as n < 30 we use t-student table

with  24 degree of freedom

Significance level is 0,05  and df = 24  we find t (c)  in t- student table

t(c) = 1,7109      test to the left   t(c) = -1,7109

To calculate  t(s)

t(s)  =  (  24,4 - 26 ) / 9,2 / √25

t(s) =  - 1,6 * 5 / 9,2

t(s) = - 0,87

Comparing t(s)  and t(c) we have

t(s) > t(c)

t(s) is in the rejection region we accept H₀ we have not evidence to support Marc´s claim

Given the triangle below, what is m angle A, rounded to nearest tenth.

Answers

Answer:

D.82.8°

Step-by-step explanation:

Hope it helps

Have a great day

Giving brainliest!!!!!

Answers

Answer: V = 434cm³

6 x 10 x 5 = 300
4/3 x π x r x 4³ = 268.08257310633

268.08257310633 + 300 = 434.041286553

Answer:

434 [tex]cm^3[/tex]

Step-by-step explanation:

volume of bottom: 6 x 10 x 5 = 300 [tex]cm^3[/tex]

volume of top:

[tex]V = (\frac{4}{3}\pi r^3)/2\\\\= (\frac{4}{3}\pi(4)^3)/2\\[/tex]

≈ 134.041 [tex]cm^3[/tex]

300 + 134.041 = 434.041

they want to the nearest tenth, so it would just be 434.0

Plsssss help it is khan academy!!!

Answers

The inequality is in the direction of the arrow
The arrow is like this <——— so the inequality is <
It is an open circle so that means -1 is not included
x<-1
Or choice A

4 * (3.4+2)-(56 divided by 7)= 13.6, please give an explanation to this problem!!

Answers

Answer:

[tex]=13.6[/tex]

Step-by-step explanation:

[tex]\mathrm{Remove\:parentheses}:\quad \left(a\right)=a[/tex]

[tex]=4\left(3.4+2\right)-\frac{56}{7}[/tex]

[tex]=21.6-8[/tex]

[tex]\mathrm{Subtract\:the\:numbers:}\:21.6-8=13.6[/tex]

[tex]=13.6[/tex]

mong 500 marriage license applications chosen at random in a givenyear, there were 48 in which the woman was at least one year older than the man, and among400 marriage license applications chosen at random six years later, there were 68 in which thewoman was at least one year older than the man. Construct a 99% confidence interval for thedifference between the corresponding true proportions of marriage license applications in whichthe woman was at least one year older than the man. Interpret the CI in the context of theproblem.

Answers

Answer:

CI 99% = (  0,022  ;  0,126 )

Step-by-step explanation:

First sample  

n₁  = 500

x₁  = 48

p₁ = x₁ / n₁   =  48 / 500      p₁  =  0,096      p₁  = 9,6 %

Second sample

n₂  = 400

x₂  = 68

p₂ = x₂ / n₂   =  68 / 400      p₂  =  0,17       p₂  = 17 %

CI = 99 %    significance level α = 1 %     α  = 0,01

z(c)  for α = 0,01  is from z- table    z(c) = 2,325

CI  =  ( p₂ - p₁ ) ±  z(c) *√ p*q* ( 1/n₁  +  1 / n₂ )

Where

p₂  -  p₁  =  0,17 - 0,096 = 0,074

p = ( x₁ + x₂ )  / n₁ + n₂

p =  ( 48  +  68  ) /( 500 + 400)

p = 116/ 900     p = 0,1288     and   q = 1 - p     q  = 0,8712

z(c) *√ p*q* ( 1/n₁  +  1 / n₂ ) = 2,325 * √ 0,1288*0,8712 ( 1 / 500 + 1/ 400)

2,235 * 0,02247

z(c) *√ p*q* ( 1/n₁  +  1 / n₂ ) = 0,052

Then

CI 99 %  =  0,074  ±  0,052

CI 99% = (  0,022  ;  0,126 )

The difference between the groups shows that the proportion in the second group was bigger than in the first group.

The CI in the context of the problem is  CI 99% = (  0,022  ;  0,126 )

What will be the Solution of This problem?

Given first sample is  

n₁  = 500

x₁  = 48

  [tex]P_{1} =\dfrac{X_{1} }{n_{1} }[/tex]      [tex]P_{1} =\dfrac{48}{500}[/tex]      

p₁  =  0,096      p₁  = 9,6 %

Given second sample

n₂  = 400

x₂  = 68

[tex]P_{2} =\dfrac{X_{2} }{n_{2} }[/tex]      [tex]P_{2} =\dfrac{68}{400}[/tex]        

p₂  =  0,17       p₂  = 17 %

Since given CI = 99 %    so significance level  α = 1 %     α  = 0,01

From Z-Table  z(c)  for α= 0,01  is = 2,325

CI  =   [tex](P_{2} -P_{1}[/tex]   ±    [tex]Z(c)\sqrt[2]{p\times q} (\dfrac{1}{n_{1} } +\dfrac{1}{n_{2} } )[/tex]  

Where

p₂  -  p₁  =  0,17 - 0,096 = 0,074

[tex]P= \dfrac{X_{1} +X_{2} }{n_{1}+n_{2} }[/tex]

[tex]P=\dfrac{48+68}{500+400}[/tex]

[tex]P=\dfrac{116}{900}[/tex]

p = 0,1288     and   q = 1 - p     q  = 0,8712

[tex]Z(c)\sqrt[2]{p\times q} (\dfrac{1}{n_{1} } +\dfrac{1}{n_{2} } )[/tex]  [tex]2325\times\sqrt[2]{0.1288\times 0.8712} (\dfrac{1}{500_{} } +\dfrac{1}{400_{} } )[/tex]

  [tex]Z(c)\sqrt[2]{p\times q} (\dfrac{1}{n_{1} } +\dfrac{1}{n_{2} } )=0.052[/tex]

Then

CI 99 %  =  0,074  ±  0,052

CI 99% = (  0,022  ;  0,126 )

Hence the difference between the groups shows that the proportion in the second group was bigger than in the first group.

To know more about Chi square follow

https://brainly.com/question/4543358

Which graph represents the solution set of the system y ≤ x2 – 1 and x > y2 – 6?

Answers

The fourth option is indeed correct on Edge 2021.

The graph that represents the system of nonlinear inequalities is graph (a)

The nonlinear inequalities are given as:

[tex]y \le x^2 - 1[/tex]

[tex]x > y^2 - 6[/tex]

Rewrite the above nonlinear inequalities as:

[tex]y - x^2 \le - 1[/tex]

[tex]x -y^2 > -6[/tex]

[tex]y - x^2 \le - 1[/tex] means that the inequality has a solid line, and the outside part is shaded

[tex]x -y^2 > -6[/tex] means that the inequality has a dotted line, and the inner part is shaded

So, the graph that represents the system of nonlinear inequalities is graph (a)

Read more about the system of nonlinear inequalities at:

https://brainly.com/question/9248293

please help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answers

Answer:

√11 = 3.31....

option 1. Irrational: √11 = 3.3

Answer:

Irrational [tex]\sqrt{11}[/tex] = 3.3

Step-by-step explanation:

Have a nice day!! :)

Help me out pls, i’m new to this whole hypotenuse thing

Answers

Answer:

x = 6.5

Step-by-step explanation:

Reference angle = 54°

Length of Side opposite to 54° = x

Hypotenuse = 8 cm

Recall: SOHCAHTOA.

Apply SOH:

Sin 54 = Opp/Hyp

Sin 54 = x/8

x = 8*sin 54

x = 6.47213595 ≈ 6.5 cm (nearest tenth)

18 out of 20 to percentage

Answers

Answer:

90%

Step-by-step explanation:

That would be 90% as it is equivalent to 9/10 or 90/100

For every 16 mango trees in the orchard, there are 8 coconut trees. If there are 1320 trees. How many trees of each kind are there?
SHOW PROCESS PO pa help po need ko po ngayon:(
I BRAINLIEST ko po yung tamang sagot :( ​

Answers

Answer:

let's say coconut trees is X is there from mango trees will be 2X

Step-by-step explanation:

2x+x=1320

3x=1320

divide both sides by three

3x/3=1320/3

x=440(coconut)

2x=880(mango)

What's another name for qualitative variables?

Answers

Answer:

A qualitative variable, also called a categorical variable, is a variable that isn't numerical.

A qualitative variable, also called a categorical variable, is a variable that isn't numerical. It describes data that fits into categories.

A sample of 1300 computer chips revealed that 50% of the chips do not fail in the first 1000 hours of their use. The company's promotional literature states that 47% of the chips do not fail in the first 1000 hours of their use. The quality control manager wants to test the claim that the actual percentage that do not fail is different from the stated percentage. Make the decision to reject or fail to reject the null hypothesis at the 0.01 level.

Answers

Answer:

The pvalue of the test is 0.03 > 0.01, which means that we fail to reject the null hypothesis at the 0.01 level.

Step-by-step explanation:

The company's promotional literature states that 47% of the chips do not fail in the first 1000 hours of their use. The quality control manager wants to test the claim that the actual percentage that do not fail is different from the stated percentage.

This means that at the null hypothesis we test that the proportion is 47% = 0.47, that is:

[tex]H_0: p = 0.47[/tex]

And at the alternate hypothesis, we test that the proportion is different from 47%, that is:

[tex]H_a: p \neq 0.47[/tex]

The test statistic is:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, [tex]\sigma[/tex] is the standard deviation and n is the size of the sample.

47% is tested at the null hypothesis:

This means that [tex]\mu = 0.47, \sigma = \sqrt{0.47*0.53}[/tex]

A sample of 1300 computer chips revealed that 50% of the chips do not fail in the first 1000 hours of their use.

This means that [tex]n = 1300, X = 0.5[/tex]

Value of the test statistic:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

[tex]z = \frac{0.5 - 0.47}{\frac{\sqrt{0.47*0.53}}{\sqrt{1300}}}[/tex]

[tex]z = 2.17[/tex]

Pvalue of the test and decision:

The pvalue of the test is the probability that the proportion differs from 0.47 by at least 0.5 - 0.47 = 0.03, which is P(|Z| > 2.17), which is 2 multiplied by the pvalue of Z = -2.17

Z = -2.17 has a pvalue of 0.015

2*0.015 = 0.03

The pvalue of the test is 0.03 > 0.01, which means that we fail to reject the null hypothesis at the 0.01 level.

Which set of numbers is in DESCENDING order?
* 1 point
WILL GIVE BRANLIEST
55, -8, -2, -282

55, -2, -8, -282

-282, -8, -2, 55

-282, 55, -8, -2

Answers

C) -282, -8, -2, 55
Answer ^

6=24(x+1)^2 what is the answer simplified

Answers

Answer:

hi can i fu k u

Step-by-step explanation:

The answer is:

-0.5, -1.5

PLSS HELPPPPPPPPPPPP​

Answers

Answer:

c Melindas account will have about 5.40 more than olivia's account

Step-by-step explanation:

the peremeter of a square is 16 inches what is the lenth of each side

Answers

Answer:If the figure is a square with a perimeter of 16 inches, then each side of the square is 4 inchest in length.

Step-by-step explanation:

Answer:

The length of each side is 4 inches.

Step-by-step explanation:

Since the shape is a square, all sides are equal so you do 16÷4 since there are 4 sides to get your answer of 4 inches.

The quadrilateral shown is a rectangle. What is m∠ZVY?
A) 39°
B) 59°
C) 61°
D) 119°

Answers

Answer: hey bro i can solve this for you but you need to show the quadrilateral. without it i can't solve it.

Step-by-step explanation:

Leslie is installing blue carpet that will cover the entire floor of a room.
What is the area, in square feet, of the room Leslie will cover with blue
carpet?
I need it step by step please

Answers

Answer:

392 ft²

Step-by-step explanation:

The composite figure can be divided into a rectangle, 2 triangles and a square

Area of rectangle = Length * width

Area of rectangle = 21 feets * 14 feets = 294 feet²

Area of triangle = 0.5 * base * height

Area of triangle = 0.5 * 7 * 7 = 24.5

AREA of square = a² = 7² = 49 feets²

Total area :

294 feets + (2 * 24.5) feets² + 49 feets²

294 + 49 + 49 = 392 ft²

The average of an electrician's hourly wage and a plumber's hourly wage is $33. One day a contractor hires an electrician for 7hr of work and the plumber for 4hr of work and pays a total of $396 in wages. Find the hourly wage for the electrician and for the plumber.

Answers

Answer:

Electrician = 44

Plumber = 22

Step-by-step explanation:

Let :

Electrician Hourly wage = x

Plumber's hourly wage = y

Average = 33

(x + y ) /2 = 33

x + y = 66 - - - - (1)

7x + 4y = 396 - - - (2)

From (1)

x = 66 - y

Put x = 66 - y in (2)

7(66-y) + 4y = 396

462 - 7y + 4y = 396

-3y = - 66

y = 22

x = 66 - 22

x = 44

Electrician = 44

Plumber = 22

what is the value of x?

Answers

2x+2=3x-52
2x-3x=-52-2
-x=-54
x=54

Find the slope of the line.
Please Help

Answers

the slope should be y=3x

Question 3 (Fill-In-The-Blank Worth 3 points) (04.04) Point R is at (2, 1.2) and Point T is at (2, 2.5) on a coordinate grid. The distance between the two points is such as 8.2.) (Input numbers and decimal point only, Answer for Blank 1:​

Answers

9514 1404 393

Answer:

  1.3

Step-by-step explanation:

The two points are on the same vertical line, so the distance between them is the distance between their y-coordinates:

  2.5 -1.2 = 1.3

The distance between the two points is 1.3 units.

What is the volume of the solid generated when the region in the first quadrant bounded by the graph of y=x^3, the x-axis, and the vertical line x=2 is revolved about the x-axis?
Show work.

A
[tex]4[/tex]
B
[tex] \frac{128}{7} [/tex]
C
[tex]4\pi[/tex]
D
[tex] \frac{128\pi}{7} [/tex]

Answers

Answer:

The first thing we need to do is to find the area bounded by:

y = x^3

y = 0

between:

x = 0 and x = 2

This is the integral of the given function between x = 0 and x = 2, written as:

[tex]\int\limits^2_0 {x^3} \, dx = \frac{2^4}{4} - \frac{0^4}{4} = 2^2 = 4[/tex]

This means that the area of the bounded region is 4 square units.

Now, if we do a full rotation around the x-axis, the volume generated will be equal to the area that we obtained times 2*pi units.

The volume is:

V = (4 square units)*(2*pi units) = 8*pi cubic units.

(Notice that no option coincides with this, there may be a mistake in the options)

Enter the measure of YVZ in degrees

Answers

Answer:

(3x+5)+(2x) = 90

5x + 5 = 90

5x = 85

x = 17

YVZ = 3×17 +5

=56°

Yeah the answer is just had the same question 56

Need help!! algebra!!!

Part A: The area of a square is (4a2 − 20a + 25) square units. Determine the length of each side of the square by factoring the area expression completely. Show your work. (5 points)

Part B: The area of a rectangle is (9a2 − 16b2) square units. Determine the dimensions of the rectangle by factoring the area expression completely. Show your work. (5 points)

Answers

Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:

Part A

we have to solve the associated equation

4a^2 - 20a + 25 = 0

first of all we have to find the delta/4

Δ/4 = (b/2)^2 - ac  where a is the term that multiply a^2, b is the term that multiply a and c is the therm without the variable

Δ/4 = (-10)^2 -100 = 100-100 = 0

the delta is equal to 0 that is mean that the equation has two coincident solutions, that can be find thanks to this formula

a1,a2 = -b/2/a = 10/4 = 5/2

now we can factorize the trinomial in this way:

4(a-5/2)(a-5/2)

4[(2a-5)/2][(2a-5)/2]

(2a-5)(2a-5)

the side of the square is 2a-5

Part B

the area of the rectangle is expressed as difference by two squares, so it can be rewritten as

(3a+4b)(3a-4b)

so the dimension of the rectangle are

3a+4b and 3a-4b

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