Don't call me square! While I have four right angles,
that term wouldn't be fair. While I have two parallel
sides, they both measure a different size. What shape
am I?

Answer:

Distributive property

Step-by-step explanation:

2(x+4)

We can write it as:-

=>2(x)+2(4)

=>2x+8

Answer:

the awnser is c the distributive proporties

Step-by-step explanation:

Answer:

The problem states that the answer cannot be a perfect square or have prime factors less than $50$. Therefore, the answer will be the product of at least two different primes greater than $50$. The two smallest primes greater than $50$ are $53$ and $59$. Multiplying these two primes, we obtain the number $3127$, which is also the smallest number on the list of answer choices. So we are done, and the answer is $\boxed{\textbf{(A)}\ 3127}$.

Step-by-step explanation:

Answer:

71

Step-by-step explanation:

I just did the AOPS question, you can see the attachment down below.

Hope this helped! :)

Answer:

its a distributive property..

Answer:

  95°

Step-by-step explanation:

  ∠SRW is a vertical angle with respect to the one marked 95°. As such, it will have the same measure: 95°.

  m∠SRW = 95°

Answer:

2a(x + 3y)

Step-by-step explanation:

2ax + 6ay

factor out a 2a

2a(x + 3y)

Answer:

a = [tex]\frac{11}{7}[/tex] ; b = [tex]\frac{6}{7}[/tex]

Step-by-step explanation:

[tex]\frac{3 + \sqrt{2}}{3 - \sqrt{2} } = a + b\sqrt{2} \\\\[/tex]

Rationalising [tex]\frac{3 + \sqrt{2}}{3 - \sqrt{2} }[/tex] gives :-

[tex]\frac{3 + \sqrt{2}}{3 - \sqrt{2} } = \frac{(3 + \sqrt{2})(3 + \sqrt{2})}{(3 - \sqrt{2})(3 + \sqrt{2}) } = \frac{(3 + \sqrt{2})^2}{3^2 - (\sqrt{2})^2 } = \frac{11 +6\sqrt{2} }{7}[/tex]

Comparing [tex]\frac{11 + 6\sqrt{2} }{7}[/tex] with [tex]a + b\sqrt{2}[/tex] gives

a = [tex]\frac{11}{7}[/tex] & b = [tex]\frac{6}{7}[/tex]

Answer:

[tex]\frac{11}{7}[/tex] + [tex]\frac{6}{7}[/tex] [tex]\sqrt{2}[/tex]

Step-by-step explanation:

Given

[tex]\frac{3+\sqrt{2} }{3-\sqrt{2} }[/tex]

Multiply the numerator/ denominator by the conjugate of the denominator.

The conjugate of 3 - [tex]\sqrt{2}[/tex] is 3 + [tex]\sqrt{2}[/tex] , thus

= [tex]\frac{(3+\sqrt{2})(3+\sqrt{2}) }{(3-\sqrt{2})(3+\sqrt{2}) }[/tex] ← expand numerator/ denominator using FOIL

= [tex]\frac{9+6\sqrt{2}+2 }{9-2}[/tex]

= [tex]\frac{11+6\sqrt{2} }{7}[/tex]

= [tex]\frac{11}{7}[/tex] + [tex]\frac{6}{7}[/tex] [tex]\sqrt{2}[/tex] ← in the form a + b[tex]\sqrt{2}[/tex]

with a = [tex]\frac{11}{7}[/tex] and b = [tex]\frac{6}{7}[/tex]

Answer:

9y+18

Step-by-step explanation:

Distribute the 9 to the terms in the parentheses.

9(y)+9(2)

9y+18

Answer:

1,3,5,15

1,2,11,22

1,2,17,34

1,3,5,9,15,45

1,2,5,10,25,50

Step-by-step explanation:

Hope it will help u

Answer:

A) 2.45 seconds

B)[tex]\begin{center}\begin{tabular}{ c c}\bold{Average Velocity} & \bold{Velocity at strike of water} \\ 39.18 & 78.4 \\ \end{tabular}\end{center}[/tex]

Step-by-step explanation:

Distance [tex]s[/tex] (in feet) from the top of cliff after [tex]t[/tex] seconds when a rock is dropped off the edge of a cliff is given as:

[tex]s(t)=16t^2[/tex]

Distance from the top of cliff to water = 96 ft

To find:

A) When will the rock strike the water

i.e. The time taken by the rock to travel the distance of 96 ft.

B) Table of Average Velocity and approximate velocity at which the rock strikes the water ?

Solution:

A) Given that distance traveled = 96 ft

To find the value of [tex]t[/tex]

Putting the value of [tex]s[/tex] in formula: [tex]s(t)=16t^2[/tex] to find [tex]t[/tex]:

[tex]96 = 16t^2\\\Rightarrow t^2=6\\\Rightarrow \bold{t = 2.45\ sec}[/tex]

B) The velocity at which the rock hits the water:

We need to differentiate [tex]s(t)[/tex] w.r.to [tex]t[/tex] in order to find the velocity at any instant.

[tex]s'(t) =\dfrac{d}{dt}s(t) = \dfrac{d}{dt}(16t^2)\\\Rightarrow v = 2\times 16t^{(2-1)}\\\Rightarrow v = 32t[/tex]

The time taken to reach the water is 2.45 seconds.

Putting [tex]t[/tex] = 2.45 seconds to find the velocity:

[tex]v = 32\times 2.45 = 78.4\ ft/sec[/tex]

Average velocity is given as total distance traveled and total time taken.

[tex]\text{Average Velocity = }\dfrac{\text{Total Distance traveled}}{\text{Total Time Taken}}[/tex]

[tex]\text{Average Velocity = }\dfrac{96}{2.45}\\\text{Average Velocity = 39.18\ ft/s}[/tex]

[tex]\begin{center}\begin{tabular}{ c c}\bold{Average Velocity} & \bold{Velocity at strike of water} \\ 39.18 & 78.4 \\ \end{tabular}\end{center}[/tex]

Answer: x=22

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

Step 2: Add 9/2 to both sides.

Step 3: Multiply both sides by 4/3.

Answer:

Step-by-step explanation:

x -  9 = 17

x = 26

the answer is D

Answer:

i can't see that

Step-by-step explanation:

plzz sent me a clear photo

Answer:

1. 1

2. 1  ⋅  10 ^24

3. 1000000000

4. 1

5. 1  ⋅  10 ^20

6. 1  ⋅  10 ^30

7. 1  ⋅  10 ^27

8. 10000

9. 0.01

10. 0.0001

11. 0.1

Hopefully these are right, I simplified all of the problems...sorry if they are wrong

Step-by-step explanation:

Answer:

90

Step-by-step explanation:

15*6=90...

[tex]( {5}^{2} - 1) \div 6 = [/tex]

[tex](25 - 1) \div 6 = [/tex]

[tex]24 \div 6 = 4[/tex]

Note:

Do the square first, and then you do mathematic operation between the parentheses. And, then do the

mathematic operation in the outside of parentheses.

Thank you.

Answer:

Step-by-step explanation:

[tex]\left(5^2-1\right)\div \:6\\\\\mathrm{Follow\:the\:PEMDAS\:order\:of\:operations}\\\\\mathrm{Calculate\:within\:parentheses}\:\left(5^2-1\right)\::\quad 24\\=24\div \:6\\\\\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:24\div \:6\:\\:\quad 4[/tex]

Answer:

see the work pictured please

Answer:

The part that is shaded is 5/14

Step-by-step explanation:

The total circle is 1

1/2 + 1/7 + x = 1  where x is the shaded area

Multiply each side by 14 to get rid of the fractions

14(1/2 + 1/7 + x) = 1*14

7 + 2 + 14x = 14

9+14x = 14

Subtract 9 from each side

14x = 5

Divide by 14

x = 5/14

The part that is shaded is 5/14

Answer:

A.    [tex] x > \dfrac{7}{3} [/tex]

Step-by-step explanation:

[tex] 8(\dfrac{1}{2} x - \dfrac{1}{4}) > 12 - 2x [/tex]

Distribute the 8 on the left side.

[tex] 4x - 2 > 12 - 2x [/tex]

Add 2x to both sides. Add 2 to both sides.

[tex] 6x > 14 [/tex]

Divide both sides by 6.

[tex] x > \dfrac{14}{6} [/tex]

Reduce 14/6 by dividing the numerator and denominator by 2.

[tex] x > \dfrac{7}{3} [/tex]

Answer:

its \text{L}Lstart text, L, end text

Step-by-step explanation:

The sorting of the dataset and the information from the five number summary, which includes the three quartiles and the minimum and maximum values indicates that we get;

1. 2.8, 4, 4.3, 6, 7.5, 8.5, 9, 11.6, 12, 12.1

2. The interquartile range is; 7.745

The five number summary includes the first, second and third quartiles, Q₁, Q₂, and Q₃, and maximum and minimum values of the dataset, which serves to describe the characteristics of the data.

here, we have,

1. The sorted data from least to greatest can be presented as follows;

2.8, 4, 4.3, 6, 7.5, 8.5, 9, 11.6, 12, 12.1

Therefore, the original data in the question is already sorted from least to the greatest

2. The interquartile range, IQR, is the the difference between the third quartile, Q₃, and the first quartiles, Q₁, of the data.

IQR = Q₃ - Q₁

The dataset indicates that we get;

The number of datapoints in the dataset, n = 10

The first quartile = The (N + 1)/4 percentile value

First quartile, Q₁ = (10 + 1)/4 × 10 = The 2.75th value

The 2.75th value is the value 0.75 = 3/4 larger than the 2nd value, which can be found as follows;

Q₁ = The 2.75th value = 4 + (4.3 - 4) × (3/4)  = 4.225

The third quartile, Q₃ = The (N + 1) × (3/40th value, therefore;

Q₃ = The (10 + 1) × (3/4)th value = The 8.25th value (The value 0.25th more than the 8th value )

Q₃ = 11.6 + (12 - 11.6) × 0.25 = 11.7

The interquartile range, IQR = 11.7 - 4.225 = 7.475

The interquartile range = 7.475

Learn more on the interquartile range of a dataset here: brainly.com/question/13119591

#SPJ7

Complete question:

The following data points represent the volume of gas in each race car driver's tank (in liters).

Answer 2 questions about the data set.

1. Sort the data from least to greatest.

2.8

4

4.3

6

7.5

8.5

9

11.6

12

12.1

2. Find the interquartile range (IQR) of the data set.

L

The alternate interior angle theorem states that when two parallel lines are cut by a transversal, the resulting alternate interior angles are congruent.

This means that [tex]6x-8=5x+14[/tex]

[tex]x=22[/tex]

Hope this helps. 頑張って!

Answer:

the mistake is the addition sign. When a number is next to a parenthesis it means multiplication

Answer:

106 or 4x+18  

Step-by-step explanation:

Since Ray QR is a bisector you can determine that PRQ and QRS are equal angles (def. of a bisector). Then, what I chose to do is graph them and find where they intercept which was 22. We now know 22 is x so we can substitute it into the equation and solve to deterine that our answer is 106.

Answer:

V = πr²(h/3)

Step-by-step explanation:

83.74 = πr²(5/3)

R = 4.00 in

Diamater = 2r = 2 x 4.00 = 8 inches

Answer:

The answer is

Step-by-step explanation:

To find the volume in liter we must first find the volume in cm³

Since the container is cubic

Volume = l³

where l is the length of one side

From the question

l = 50.0 cm

Volume = 50³

= 125000 cm³

Next we use the conversion

1cm³ = 0.001 L

If 1 cm³ = 0.001 L

Then 125,000 cm³ = 125,000 × 0.001 L

We have the final answer as

Hope this helps you

Using the volume of a cube, and conversion of units, it is found that the volume of the cube is of 125 liters.

---------------------

The volume of a cube of side s is given by:

[tex]V = s^3[/tex]

---------------------

Thus, the volume, in cubic centimetres, is given by:

[tex]V = 50^3 = 125000[/tex]

---------------------

Then:

[tex]\frac{125000}{1000} = 125[/tex]

The volume of the cube is of 125 liters.

A similar problem is given at https://brainly.com/question/23514867

Answer:

x =1.28571428571

Step-by-step explanation:

6x + 2y = -10

y = -4x - 8

6x + 2(4x - 8) = -10

6x + 8x - 8 = -10

14x - 8 = 10

(we put together the like terms)

14x = 10 + 8

14x = 18

x =  [tex]\frac{18}{14}[/tex]

x = 1.28571428571

Answer:

jacki did not subtract 8 minus 12 properly.8 minus 12 equals -4

Answer:

its c

Step-by-step explanation:

on edunuity

Answer:

the answer is -12-(-3)

Step-by-step explanation:

The expression equivalent to -18-(-9) is -12-(-3)

An expression in maths is a sentence with a minimum of two numbers or variables and at least one maths operation.

Given is an expression, -18-(-9), we are given to find the expression equivalent to it,

-18-(-9) = -18+9 = -9

1) -18+2 = -16 (not equivalent)

2) -12-(-3) = -12+3 = -9

Therefore, we see, the value of expressions -12-(-3) and -18-(-9) are equivalent,

Hence, the expression equivalent to -18-(-9) is -12-(-3)

For more references on expressions, click;

https://brainly.com/question/14083225

#SPJ2

Answer:

[tex] \huge{ \fbox{ \sf{7x - 20}}}[/tex]

Step-by-step explanation:

[tex] \star{ \sf{ \: 5(3x - 4) - 8x}}[/tex]

[tex] \text{Step \: 1 \: : Distribute \: 5 \: through \: the \: parentheses}[/tex]

[tex] \mapsto{ \sf{5 \times 3x - 5 \times 4 - 8x}}[/tex]

[tex] \mapsto{ \sf{15x - 20 - 8x}}[/tex]

[tex] \text{Step \: 2 \: : Collect \: like \: terms}[/tex]

[tex] \sf{Like \: terms \: are \: those \: which \: have \: the \: same \: base.}[/tex]

[tex] \mapsto{ \sf{15x - 8x - 20}}[/tex]

[tex] \mapsto{ \boxed{\sf{7x - 20}}}[/tex]

[tex] \sf{Hope \: i \: helped!}[/tex]

[tex] \sf{Best \: regards!!}[/tex]

~[tex] \rm{TheAnimeGirl}[/tex]

Answer:

B-LearnCenter charges a higher membership fee but a lower rate per class.

Step-by-step explanation:

Answer:B-learning for ever

Step-by-step explanation:

Answer:

I think its 0.89

Step-by-step explanation: