DUE SOON!! PLEASE HELP SO CONFUSED!!!!
ITS DUE IN AN HOUR!

DUE SOON!! PLEASE HELP SO CONFUSED!!!!ITS DUE IN AN HOUR!

Answers

Answer 1

Answer:

Step-by-step explanation:


Related Questions

Solve (z + 6)2 = 5
{−6±5‾√}

{6±5‾√}

{5‾√±−6}

{−6+5‾√,6−5‾√}

Answers

9514 1404 393

Answer:

  (a) -6±√5

Step-by-step explanation:

  (z +6)^2 = 5 . . . . . given

  z +6 = ±√5 . . . . .  take the square root

  z = -6 ±√5 . . . . . . subtract 6

help me please and answer correctly people answer wrong on purpose ​

Answers

Sorry for not answering your question but please I am telling you guys don’t fall for someone when they send you links here like this first person above me he send a link don’t press it y’all don’t this is really bad it makes your phone really bad

I pick a ball from a bag, replace it and then pick
another. I keep doing this until I have chosen 40 balls. If I picked out 12 yellow balls, estimate the probability of not picking out a yellow ball.

Answers

Answer:

It should be 50%

Step-by-step explanation:

It should be 50% because there are 12 yellow balls, so it should be 50%.

Hope it helps you

In a clothing store, 65% of the customers buy a shirt, 30% of the customers buy a pair of pants, and 20% of the customers buy both a shirt and a pair of pants. I’m f a customer is chosen at random, what is the probability that he or she buys a shirt or a pair of pants?

Answers

Answer:

The Answer will be (0.75)

A 33 gram sample of a substance that's
used for drug research has a k-value of
0.1124.

Find the substances half life and the round your answer to the nearest 10th

Answers

9514 1404 393

Answer:

  6.2

Step-by-step explanation:

We presume your "k-value" is the k in the exponential decay term ...

  e^(-kt) . . . where t is the number of time units

This is 1/2 when ...

  ln(1/2) = -kt

  t = ln(1/2)/(-k) = ln(2)/k

  t = 0.69315/0.1124 ≈ 6.2

The half life is about 6.2 time units.

This data shows the number of sit-ups done by 27 students in a gym class.
58 62 49 52 75 86 88 54 56 61 85 48 77 60
47 58 62 73 78 69 65 84 59 67 53 84 50
Which histogram represents the data?

Answers

Answer:

C

Step-by-step explanation:

None of the others have the correct data like C

What is the value of the angle marked with x?

Answers

Answer:

132

Step-by-step explanation: I'm not very sure tho

The table below is comparing level of education achieved to the rate of unemployment and the median weekly earnings in 2008. Based on the information provided, the unemployment rate decreases the most when moving between which two consecutive educational levels?

Answers

Answer:

"less than high school" and" high school graduate".

Answer:

The table below is comparing level of education achieved to the rate of unemployment and the median weekly earnings in 2008.  Based on the information provided, the unemployment rate decreases the most when moving between which two consecutive educational levels?

a.

“Less than high school” and “High School Graduate”  <<<<<<<CORRECT

b.

“High school graduate” and “Some college, no degree”

c.

“Associate degree” and “Bachelor’s degree”

d.

“Professional degree” and “Doctoral degree”

 

Step-by-step explanation:

Edge2021

Find the slope of the line (2,6) and (-2,-4)

Answers

10/8
Hope this helped

what is the measure of A, in degrees, in the figure shown?

Answers

Answer:

[tex]12.7[/tex]

Step-by-step explanation:

[tex]180 - 167.3 = 12.7 \\ < angle \: on\: a \: stright \: line \: is \: 180[/tex]

Let {u1,u2,u3} be an orthonormal basis for an inner product space V. If

v=au1+bu2+cu3
is so that ∥v∥=42, v is orthogonal to u3, and ⟨v,u2⟩=−42, find the possible values for a, b, and c.

Answers

• ||v|| = 42, which is to say

||v||² = 〈v, v

…  = 〈a u₁ + b u₂ + c u₃, a u₁ + b u₂ + c u₃〉

… = a ² 〈u₁, u₁〉 + b ² 〈u₂, u₂〉 + c ² 〈u₃, u₃〉 + 2(abu₁, u₂〉 + acu₁, u₃〉 + bcu₂, u₃〉)

… = a ² ||u₁||² + b ² ||u₂||² + c ² ||u₃||²

[since each vector in the basis for V is orthogonal to any other vector in the basis, and 〈x, x〉 = ||x||² for any vector x ]

42² = a ² + b ² + c ²

[since each vector in the basis has unit length]

42 = √(a ² + b ² + c ²)

• v is orthogonal to u₃, so 〈v, u₃〉 = 0. Expanding v gives the relation

v, u₃〉 = 〈a u₁ + b u₂ + c u₃, u₃〉

… = au₁, u₃〉 + bu₂, u₃〉 + cu₃, u₃〉

… = c ||u₃||²

… = c

which gives c = 0, and so

42 = √(a ² + b ²)

• Lastly, 〈v, u₂〉 = -42, which means

v, u₂〉 = 〈a u₁ + b u₂ + c u₃, u₂〉

… = au₁, u₂〉 + bu₂, u₂〉 + cu₃, u₂〉

… = b ||u₂||²

… = b

so that b = -42. Then

42 = √(a ² + (-42)²)   →   a = 0

So we have a = 0, b = -42, and c = 0.

The required values are, [tex]a=0,b=-42 ,c=0[/tex]

Given,

[tex]v=au_1+bu_2+cu_3[/tex]

[tex]\left\| V\right\|=42[/tex]

Computation:

Since, [tex]v[/tex] is orthogonal to [tex]u_3[/tex] then we have,

[tex]\left<v,u_3 \right> =0\\\left< v,u_2\right> =-42[/tex]

Then,

[tex]\left\| V\right\|^2=\left<v,v \right>\\=\left<au_1+bu_2+cu_3,au_1+bu_2+cu_3 \right>\\=a_2\left\|u_1 \right\|^2+b_2\left\|u_2 \right\|^2+c_2\left\|u_3 \right\|^2\\=a^2+b^2+c^2\\=a^2+b^2+c^2=42^2[/tex]

As we know,

[tex]a=\left<v_1u_1 \right>\\b=\left< v_1u_2\right>= -42\\c=\left<v_1u_3 \right> =0[/tex]

[tex]a_2+b_2+c_2=42\\a=0[/tex]

Learn More:https://brainly.com/question/13152748

Solve this expression: (2-i)(-3+i)

Answers

Answer:

-5+5i

Step-by-step explanation:

Answer:

D on edge

Step-by-step explanation:

-5+5i

Joseph and Molly each have coin collections. Joseph starts with 15 coins in his collection and adds 25 coins each month. Molly starts with 25 coins in her collection and adds 25 coins each month. How many coins would Joseph have after 3 months?

Answers

Answer:

Joseph has 90 coins after 3 months

Step-by-step explanation:

Joseph: 25x + 15

Molly: 25x + 25

x = 3

Joseph: 25(3) + 15  =  90

Solve for x.
Enter the solutions from least to greatest.
(2x + 4)(3x − 2) = 0
lesser x =
greater x =

Answers

Answer:

lesser x = -2, greater x = 2/3

Step-by-step explanation:

(2x+4)= 0 ---> bring 4 to the other side

2x=-4 ----> divide by 2 on both sides

x= -4/2 = -2 ----> simplify

(3x-2)= 0 ----> bring the 2 to the other side

3x=2 ----> divide by three on both sides

x=2/3

hope this helps!

The Table shows the relationship and speeds between a cheetah and a line. What is the missing value in the table?

Cheetah (miles per hour)
7 14 ? 28 35

Lion (miles per hour)
5 10 15 20 25

A. 19
B. 21
C. 23
D. 25


Please help ASAP!!

Answers

B because the lions you count by 5 and the cheetahs you count by 7 14+7= 21

Janae solved the equation 3.67 = c − 2.13 , and found the value for c. Janae's solution was c =1.54 Do you agree or disagree with her solution. Explain. Show your work. plzzz help me ill give yo a brainlyiest

Answers

Answer:

Solution;

given equation : 3.67 = c - 2.13

On solving equation, we get

c = 3.67 +2.13

c = 5.8

Hence, Janae solution is incorrect. So I disagree.

Answer: No because the answer is c =5.8 or 5.80

Step-by-step explanation:

Add 2.13 to both sides. 3.67 + 2.13 = 5.80


Hey y’all answers in the picture ABC or D. Plz help

Answers

Answer:

D

Step-by-step explanation:

Lets use the the chart. The (5,9) if the 5 was doubled that it would equal to 10. Now you subract 1 from it making it 9.

Watch help
In APQR, PR is extended through point R to point S,
m_QRS = (4x – 15)°, m_RPQ = (x + 1), and
mZPQR = (x - 2)°. Find mZRPQ.

Answers

Answer:

m∠RPQ = 8°

Step-by-step explanation:

m∠QRS = 4x - 15

m∠RPQ = x + 1

m∠PQR = x - 2

m∠QRS is exterior angle and m∠RPQ and m∠PQr are opposite interior angles to m∠QRS

m∠QRS = m∠RPQ + m∠PQR      {Exterior angle property of triangle}

4x - 15 = x +1 + x - 2

4x - 15 = x + x + 1-2          {Combine like terms}

4x - 15 = 2x - 1        {Subtract 2x from both sides}

4x - 2x - 15 = - 1

2x - 15 = - 1                  {Add 15 to both sides}

2x = -1 + 15

2x = 14          {Divide both sides by 2}

x = 14/2

x = 7

m∠RPQ = x + 1 = 7 + 1 = 8°

Answer: x+1 =(7)+1=8

Step-by-step explanation:

Find x if these are similar

Answers

Answer:

C) 28

Step-by-step explanation:

RSTV = WXYZ

WX = x

[tex]\frac{RS}{VR} =\frac{WX}{ZW} \\\\\frac{7}{3} =\frac{x}{12} \\\\3x=84\\x=28[/tex]

HURRY! What is the circumference of the circle below? Use 3.14 for π.

Answers

Answer:

2.14 divided by 5 x 2 is the ansewer

Step-by-step explanation:

Suppose 60% of a large group of animals is infected with a particular disease. What is the probability that at least 2 animals are infected in a sample of size 5?
0.0870
0.3174
0.913
0.6826​

Answers

Answer:

0.6826

Step-by-step explanation:

Probabilities are used to determine the chances of events.

The probability that at least 2 animals are infected is (c) 0.913

The proportion of the animal infected is given as:

[tex]p =60\%[/tex]

The probability is then calculated using the following binomial equation

[tex]P(x) = ^nC_xp^x(1-p)^{n-x}[/tex]

In this case,

[tex]n = 2[/tex]

To calculate the probability that at least 2 animals are infected, we start by calculating the probability that not up to 2 animals are infected.

So, we have:

[tex]P(x<2) =P(0) + P(1)[/tex]

This gives

[tex]P(x<2) = ^5C_0 \times (60\%)^0 \times (1-60\%)^{5-0}+ ^5C_1 \times (60\%)^1 \times (1-60\%)^{5-1}[/tex]

Simplify

[tex]P(x<2) = 1 \times (60\%)^0 \times (40\%)^{5}+ 5 \times (60\%) \times (40\%)^{4}[/tex]

[tex]P(x<2) = 0.08704[/tex]

Using the complement rule, we have:

[tex]P(x \ge 2) = 1 - P(x<2)[/tex]

So, we have:

[tex]P(x \ge 2) = 1 - 0.08704[/tex]

[tex]P(x \ge 2) = 0.91296[/tex]

Approximate

[tex]P(x \ge 2) = 0.913[/tex]

Hence, the probability is (c) 0.913

Read more about probabilities at:

https://brainly.com/question/251701

Space shuttle Challengerexploded because of O-ring failure shortly after it was launched. O-ring damage and temperature at time of launch for the 23 space shuttle flights that preceded the Challenger. The data is reproduced below.
Flights with O-ring damage 43 57 58 63 70 70 75
Flights with no O-ring damage 66 67 67 67 68 69 70 70 72 73 75 76 76 78 79 81
Is the mean launch temperature for flights with O-ring damage significantly less than for flights with no O-ring damage? Use 5% level of significance.

Answers

Solution :

The null and the alternate hypothesis can be stated as :

Null hypothesis

[tex]$H_0:\mu_1 \geq \mu_2$[/tex]

Alternate hypothesis

[tex]$H_a:\mu_1 \leq \mu_2$[/tex]

We known;

[tex]$\overline x_1=\frac{\sum_{i=1}^n X_i}{n_1}$[/tex]

   [tex]$=\frac{43+....+75}{7}$[/tex]

   = 62.286

[tex]$\overline x_2=\frac{\sum_{i=1}^n X_i}{n_2}$[/tex]

   [tex]$=\frac{66+....+81}{16}$[/tex]

   = 72.125

[tex]$s_1^2=\frac{\sum_{i=1}^n(X_i- \overline X_1)^2}{n_1-1}$[/tex]

    [tex]$=\frac{(43-65.5)^2+....+(75-65.5)^2}{7-1}$[/tex]

   = 116.571

[tex]$s_2^2=\frac{\sum_{i=1}^n(X_i- \overline X_2)^2}{n_2-1}$[/tex]

    [tex]$=\frac{(66-72.13)^2+....+(81-72.13)^2}{16-1}$[/tex]

   = 23.45

Therefore, calculating the test statics :

[tex]$t=\frac{\overline x_1 - \overline x_2}{\sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}}}$[/tex]

[tex]$t=\frac{62.29-72.125}{\sqrt{\frac{116.571}{7}+\frac{23.45}{16}}}$[/tex]

[tex]$t=\frac{-9.839}{4.2566}$[/tex]

 = -2.312

Now calculating the P-value for the test as follows :

P=T.DIST(t, df)

[tex]$df=\frac{\left(\frac{s_1^2}{n_1}+\frac{s^2_2}{n_2}\right)^2}{\frac{1}{n_1-1}\left(\frac{s^2_X}{n_1}\right)^2+\frac{1}{n_2-1}\left(\frac{s^2_Y}{n_2}\right)^2}$[/tex]

[tex]$df=\frac{\left(\frac{116.571}{7}+\frac{23.45}{16}\right)^2}{\frac{1}{7-1}\left(\frac{116.571}{7}\right)^2+\frac{1}{16-1}\left(\frac{23.45}{16}\right)^2}$[/tex]

    [tex]$=\frac{328.2868}{46.36395}$[/tex]

   [tex]$\approx 7$[/tex]

P=T.DIST(t, df)

 =T.DIST(-2.31, 7)

 = 0.0270

Thus, the [tex]$\text{P-value}$[/tex] of the test is P = 0.0270 is [tex]$\text{less}$[/tex] than the level of significance [tex]$\alpha= 0.05$[/tex]. Hence the researcher can reject the null hypothesis.

Conclusion: The mean launch temperature for the flights with O ring damages less than that for the flights with no O rings.

the probability that a student takes spanish is 70%. The probability that a student takes spanish and they are a freshman is 30% what is the probability that a randomly selected student is a freshman given that he/she takes spanish

Answers

30%....................................

Answer:  At Kennedy Middle School, the probability that a student takes Technology and Spanish is 0.087. The probability that a student takes Technology is 0.68

Step-by-step explanation: u divide

HELP MEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE

Answers

Answer:

6/13

Step-by-step explanation:

6/13 is the right answer. Goodluck



Determine which point is part of the solution set to the following
system of inequalities: f(x) < x + 4; f(x) > - X-3; and f(x) < 5.
(0,0)
(-60)
(-3, 4)
(4,6)

Answers

I think 4,6
I had a test similar I’m not the best at it though hope this helps tho

I need help please fast .................

Answers

Answer:

I have no idea what sohcahtoa is but:

tan 50.1° = x/5

1.196 = x/5

multiply both sides of the equation by 5:

x = 5.98

please someone answer this

Answers

Answer:

option 2.

the others are simultaneous equations in two unknowns but 7x-2y have the same value and the value can't be two different things at once

In the triangle below,
x = [ ? ] cm. Round to the
nearest tenth.
15 cm
х
350
9.00
y

Answers

Answer:

x=8.6

Step-by-step explanation:

x=8.6

Aiden calculated that their family used 20% of their monthly income for food, and 15% of the money spent on food was spent on snacks. If they spent $45 on snacks, what is their monthly income?

Answers

Answer:

There monthly income is 300$

Need help with this question.

Answers

9514 1404 393

Answer:

  643.72 m²

Step-by-step explanation:

The area is the sum of the areas of the parts. The figure can be divided into a triangle and a semicircle.

The formula for the area of the triangle is ...

  A = 1/2bh

For the given base of 28 m and height of 24 m, the area is ...

  A = 1/2(28 m)(24 m) = 336 m²

__

The area of a semicircle is given by the formula ...

  A = (π/8)d² . . . . for diameter d

The given diameter is 28 m, so the area is about ...

  A = (3.14/8)(28 m)² = 307.72 m²

__

Then the total area of the figure is ...

   total area = triangle area + semicircle area

   total area = 336 m² +307.72 m² = 643.72 m²

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