Graph the solution to the system
-x+y>2
X+2y>2

Answer:

Domain:(−∞,2)∪(2,∞),{x|x≠2}

Range:(−∞,0)∪(0,∞),{y|y≠0}

[tex]\text{Given that,}\\\\(x_1,y_1) = (-1,-2)~~ \text{and}~~ (x_2,y_2) = (-2,2)\\\\\text{Slope, m =} \dfrac{y_2-y_1}{x_2 -x_1} = \dfrac{2 -(-2)}{-2-(-1)} = \dfrac{2+2}{-2+1} = \dfrac{4}{-1} = -4[/tex]

Answer:

C7,3=7!( 3!)( 7−3)!= 7! I think tell me if I'm wrong?

Answer:

7C3 = 7! / (7 - 3)! 3! = 7 x 6 x 5 x 4! / 4!

[tex]\text{Given that,}\\\\f(x) = 3x +12, ~ ~ g(x) = 3x -1\\\\(f \circ g)(x)\\\\=f(g(x))\\\\=f(3x-1)\\\\=3(3x-1) +12\\\\=9x - 3 +12\\\\=9x +9\\\\=9(x+1)[/tex]

happy to you are you happy

Answer:

I beleive the missing value is -3

Step-by-step explanation:

if you plug -3 into the pink box it will give you the result of -5

(anyone is free to correct me)

Answer:

  10.25

Step-by-step explanation:

The slope of AC is given by the slope formula:

  m = (y2 -y1)/(x2 -x1)

  m = (-4 -1)/(3 -(-1)) = -5/4

Then the slope of CB is the opposite reciprocal, 4/5. The equation of line CB in point-slope form is ...

  y -k = m(x -h) . . . . . . line with slope m through point (h, k)

  y -(-4) = 4/5(x -3) . . . . line CB

When y = 1 (to match the y-value of A), then ...

  1 +4 = 4/5(x -3)

  5(5/4) = (x -3) . . . . . multiply by 5/4

  6.25 +3 = x = 9.25 . . . . add 3

Point B is (9.25, 1).

The length of the hypotenuse is ...

  9.25 -(-1) = 10.25

Answer:

d x 7 = 105

Step-by-step explanation:

Step-by-step explanation:

please, this is so easy !

so, please, burn this into your brain forever : the sum of all angles in a triangle is always (really, always) 180°.

so,

180 = 25 + 100 + A

A = 55°

ΔABC has: ∠CAB + ∠ABC + ∠ACB = 180°

so:  ∠CAB = 180° - ∠ABC - ∠ACB = 180° - 100° - 25° = 55°

ANSWER: ∠CAB = 55°

ok done. Thank to me :>

Answer:

i think its 195 but i am not for sure correct me if i am wrong

Step-by-step explanation:

-8 = m/3 + 2

Subtract 2 from both sides

-10 = m/3

Multiply both sides by 3

M = -30

Answer:

[tex]m=-30[/tex]

Step-by-step explanation:

[tex]-8=\frac{m}{3}+2[/tex] <-- Given equation

[tex]3(-8)=3(\frac{m}{3}+2)[/tex] <-- Step 1: Multiply both sides by 3 to eliminate the fraction

[tex]-24=m+6[/tex]

[tex]-24-6=m+6-6[/tex] <-- Step 2: Subtract both sides by 6 to isolate "m"

[tex]-30=m[/tex] <-- Final Solution

Answer:

g(x)= 1

Step-by-step explanation:

[tex]g(x) = \frac{1}{2} x - 4 \\g(10) = \frac{1}{2} (10) = 5 \\ 5 - 4 = 1[/tex]

Answer:

x=8

Step-by-step explanation:

x+x+5=x+x+x-3

2x+5=3x-3

Subtract 2x from both sides.

5=x-3

Add 3 to both sides.

8=x

-hope it helps

Answer:

7.79

Step-by-step explanation:

in 30, 60, 90 triangle, hypotenuse is equal to "2x", shortest length is equal to "x" and second longest is equal to "x × square root of 3". hope this helps

Answer:

x-intercept(s):  (−1.9900717,  0)

y-intercept(s): (0, 52.5)

Step-by-step explanation:

To find the x-intercept, substitute in  [tex]0[/tex]  for  [tex]y[/tex]  and solve for  [tex]x[/tex]. To find the y-intercept, substitute in  [tex]0[/tex] for [tex]x[/tex] and solve for [tex]y[/tex] .

[tex]f(x)=y[/tex]

[tex](x)=x[/tex]

x-intercept

To find the x-intercept(s), substitute in  [tex]0[/tex]  for  [tex]y[/tex]  and solve for  [tex]x[/tex] .

[tex]f(x) = x ^ 3 - 8x ^ 2 + 17x - 10.5(x - 5[/tex]

[tex]=\bold{0}=x^3-8x^2+17x-10.5\left(x-5\right)[/tex]

[tex]=0\cdot \:10=x^3\cdot \:10-8x^2\cdot \:10+17x\cdot \:10-10.5\left(x-5\right)\cdot \:10[/tex]

[tex]=0=10x^3-80x^2+170x-105\left(x-5\right)[/tex]

[tex]=0=10x^3-80x^2+65x+525[/tex]

[tex]=10x^3-80x^2+65x+525=0[/tex]

[tex]=10x^2-99.90071\dots x+263.80959\dots \approx \:0[/tex]

[tex]\bold{x\approx \:-1.99007\dots}[/tex]

y-intercept

[tex]f(x) = x ^ 3 - 8x ^ 2 + 17x - 10.5(x - 5[/tex]

[tex]=y=\bold{0}^3-8(\bold{0})^2+17(\bold{0})-10.5\left(\bold{0}-5\right)[/tex]

[tex]=y=0-8\cdot \:0+17\left(0\right)-10.5\left(0-5\right)[/tex]

[tex]=y=0-8\cdot \:0+17\cdot \:0-10.5\left(0-5\right)[/tex]

[tex]=y=0-0+0-\left(-52.5\right)[/tex]

[tex]=0-0+0+52.5[/tex]

[tex]\bold{y=52.5}[/tex]

Answer:

[tex] \frac{1}{8} < \frac{2}{7} [/tex]

1/8 < 2/7

Answer: B

#CarryOnLearning

Answer:

5/12

Step-by-step explanation:

1/4 and 1/6 are fractions.

As we directly can't add fractions whenever denominators are different, so we will have to find out the Least common multiple of 4 and 6.

The LCM Of 4&6 will be 12, so we will write 12 instead of 4&6.

Now, 4*3=12, that is why we will have to multiply the numerator and denominator with 3.

1*3/4*3 = 3/12

Same thing applies to 1/6. In order to get 12 in the denominator we need to multiply 2 with numerator and denominator both.

1*2/6*2= 2/12

However, we have two new fractions with same denominator now, that is 3/12 and 2/12

We can directly add the numerators now, as we have the same denominator. So 3+2/12= 5/12 would be my final answer. (addition of like fractions)

5/12

Answer:

46 cards

Step-by-step explanation:

We can use a variable to represent the starting amount of cards: (x)

Keith bought 4 new cards: (+4)

His dog ate half of the collection: (x/2)

There are now 25 cards: (=25)

So we can use this expression to find the starting amount: (x+4)/2=25

Start by multiplying both sides by 2 to get rid of the (x/2).

Now subtract 4 from both sides to get rid of the (+4).

Finally, we know x= 46

Thus, Keith started with 46 cards.

Answer:

1) 3:8

2)5:7

3)4:5

4)1:3

5)2:3

6)11:18

Probabilities are used to determine the chances of events.

The given parameters:

[tex]n = 5[/tex] ---- the number of candy bars

[tex]p = 40\%[/tex] ---- the probability of selling a candy bar

(a) Name distributions

The distribution of X is represented as:

[tex]X \sim(r,p)[/tex]

Where:

[tex]r = 5[/tex]

[tex]p= \frac{5\times 40\%}{10}[/tex]

[tex]p= 0.2[/tex]

So, the name distribution of X is [tex]X \sim(r= 5,p = 0.2)[/tex]

(b) The probability that the last candy is sold at the 11th house

This means that:

[tex]n = 10[/tex] --- the number of previous houses

[tex]r = 4[/tex] --- the previous number of candies

[tex]p = 0.4[/tex] --- the given probability of selling a candy

The probability is calculated using:

[tex]P(x = n+1) = ^{n}C_r \times p^{r +1} \times (1 - p)^{n-r}[/tex]

This gives

[tex]P(x = 10+1) = ^{10}C_4 \times 0.4^{4 +1} \times (1 - 0.4)^{10-4}[/tex]

[tex]P(x = 11) = ^{10}C_4 \times 0.4^{5} \times (0.6)^6[/tex]

[tex]P(x = 11) = 210 \times 0.4^5 \times 0.6^6[/tex]

[tex]P(x = 11) = 0.1003290624[/tex]

Approximate

[tex]P(x = 11) = 0.1003[/tex]

Hence, the probability that the last candy is sold at the 11th house is 0.1003

(b) The probability he sells the candies on or before the 8th house

The probability is calculated using:

[tex]P(x \le 8) = P(5 \le x \le 8)[/tex]

This gives

[tex]P(x \le 8) = ^{10}C_5 \times 0.4^{6} \times (0.6)^5 + ^{10}C_6 \times 0.4^{7} \times (0.6)^4 + ^{10}C_7 \times 0.4^{8} \times (0.6)^3 +^{10}C_8 \times 0.4^{9} \times (0.6)^2[/tex]

[tex]P(x = 11) = 0.1737[/tex] ---- approximated

Hence, the probability he sells the candies on or before the 8th house is 0.1737

Read more about probabilities at:

https://brainly.com/question/251701

Answer:

whats the question, tell me it and i'll help you

Step-by-step explanation:

Answer:

[tex]\displaystyle m = 3[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Coordinate Planes

Slope Formula: [tex]\displaystyle m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

Step-by-step explanation:

Step 1: Define

Identify points.

Point (8, 1)

Point (11, 10)

Step 2: Find slope m

Simply plug in the 2 coordinates into the slope formula to find slope m.

Answer:

m=3

Step-by-step explanation:

Answer:

(a) 63               (b) 99

Step-by-step explanation:

(a)

length x 2 = 150

275-150=126/2= 63

(b)

8712/88= 99

Answer:

D

Step-by-step explanation:

Answer:

y = - [tex]\frac{10}{3}[/tex] x - 23

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (- 9, 7 ) and (x₂, y₂ ) = (- 6, - 3 )

m = [tex]\frac{-3-7}{-6-(-9)}[/tex] = [tex]\frac{-10}{-6+9}[/tex] = [tex]\frac{-10}{3}[/tex] = - [tex]\frac{10}{3}[/tex] , then

y = - [tex]\frac{10}{3}[/tex] x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (- 6, - 3 ) , then

- 3 = 20 + c ⇒ c = - 3 - 20 = - 23

y = - [tex]\frac{10}{3}[/tex] x - 23 ← equation of line

Answer:

y= -10x/3 + 1

Step-by-step explanation:

gradient of a line= (Y2-Y1)/(X2-X1)

= (-3-7)/[-6-(-9)]

=-10/3

equation of a line

(Y-Y1)/(X-X1)= gradient

(Y-7)/(X+9)= -10/3

3(Y-7)= -1d0(X+9)

3y-21= -10x -19

3y= -10x + 3

dividing both sides by 3

y= -10x/3 + 1

Answer:

20 is answer, hope it helps ypi

Answer:

(-3,1)

Step-by-step explanation:

2/2 x (-5,1)

Then the circle is (-3,1)

[tex]4(x-3)+3(2x-5)\\\\=4x -12 + 6x -15\\\\=10x - 27[/tex]