Answer:
1) Average velocities:
Given the magnitudes of 2 velocity vectors, in different time instants, the average velocity is defined as the difference of the 2 velocity magnitudes, in absolute value, divided by the interval of time occuring between the measurement of the velocity magnitudes.
2) Average acceleration
Given the magnitudes of 2 acceleration vectors, in different time instants, the average acceleration is defined as the difference of the 2 acceleration magnitudes, in absolute value, divided by the interval of time occuring between the measurement of the acceleration magnitudes.
As you see the definitions are pretty similar.
Note: I didn't copy-paste this answers from any other site.
Physical data is often used in the court system. In fact, police officers use radar to determine your speed when you are driving and admit that record in court if you are ever given a ticket. In one such instance, the police officer submitted data that goes against the claim of the driver, who is contesting his ticket in court. The police officer (who was stationary when he made the measure) claims that the driver was speeding at 44.7 m/s, but the driver claims he was only going 26.8 m/s (according to his speedometer). The speed limit was 60 mph. The driver argues that the radar gun must have been set incorrectly to record relative velocity. Is it possible that they are both telling the truth?
The driver is telling the truth, the radar gun must have been set incorrectly to record relative velocity.
The given parameters:
Speed of the driver observed by the stationary police officer, Vo = 44.7 m/sSpeed of the driver, V = 26.8 m/s.Speed limit = 60 mphThe speed limit of the driver in meter per second is calculated as follows;
[tex]= 60 \ \times \frac{miles}{hour} \times \frac{1609.34 \ m}{1 \ mile} \times \frac{1 \ hr}{3600 \ s}\\\\= 26.82 \ m/s[/tex]
From the speed limit, it is obvious that the driver's speed is within the limit. Thus, we can conclude that the driver is telling the truth, the radar gun must have been set incorrectly to record relative velocity.
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why efficiency of energy converters is less than 100%
The output work is always less than the input work because some of the input work is used to overcome friction.
A 0.5 kg rock is thrown straight downward off a cliff. If the rock only experience a gravitation force for 4.3 seconds, and ends with a downward velocity of 46.1 m/s, what was rock initial velocity? What is the gravitational force?
Answer:Answer:
See diagram for answers. The force and acceleration vectors are directed inwards towards the center of the circle and the velocity vector is directed tangent to the circle.
Explanation:
Help it multiple-choice 16 and 17 only
Answer:
16. c
17. d
Explanation:
16. Newton’s third law states that a force will always have an opposite but equal force as a reaction, so every force comes as a pair of action-reaction forces. For example, if you push on a book, the book also pushes on you.
17. If 1cm represents 15N, then 5cm must represent 15N*5=75N.
What is the main force that must be overcome in order to push an object along a horizontal surface. no silly answers
Answer:
Frictional force
Explanation:
The force that must be overcome in order to push an object along a horizontal surface is frictional force
If the force is more than frictional force the object moves
which statement is not correct about force.
A, force causes deformation
B, force xauses accleration
C, if there is no force, there is no motion
D, force emerges due to interaction.
Answer:
c
Explanation:
without force motion won't take place
what's some examples of inertial reference frames?
Answer:
Isolated spaceship, far, far away from the Earth, the Sun, the Milky Way Galaxy, and all other massive objects.
Explanation:
what color will a yellow banana appear when illuminated by yellow light
Answer:
A yellow banana reflects only yellow light,
Explanation:
2. A nutty professor leaves a history classroom and walks 10. meters north to a drinking fountain. Then, in a daze, she turns and walks 30. meters south to an art classroom. (draw vectors to scale to show your work)
(a) What is the professor’s total displacement from the classroom to the art classroom?
(b) What was the total distance she traveled?
Total displacement:-
[tex]\\ \sf\Rrightarrow 10-30=20m[/tex]
Total distance
[tex]\\ \sf\Rrightarrow 10+30=40m[/tex]
19) Suppose a ball is thrown straight up and experiences no appreciable air resistance. What is its acceleration just before it reaches its highest point? A) zero B) slightly less than g C) exactly g D) slightly greater than g
Answer:
C)
Explanation: In freefall motion object always has gravity as its acceleration.
Which action will cause the tennis ball to move the farthest?
You gently hit the tennis ball.
You pull the tennis racket back and up and hit the ball hard as you swing down.
You hit the tennis ball from another side to change its direction.
You tap the tennis ball lightly.
Answer:
2nd option at the most
Explanation:
leave a thanks if helped
Elliot jumps up and down on a pogo stick. He weighs 600.N, and his pogo stick has a spring with spring constant 1100N/m. What is the height he will reach when he has gravitational potential energy 250J? m
From conservation of energy, the height he will reach when he has gravitational potential energy 250J is 0.42 meters approximately
The given weight of Elliot is 600 N
From conservation of energy, the total mechanical energy of Elliot must have been converted to elastic potential energy. Then, the elastic potential energy from the spring was later converted to maximum potential energy P.E of Elliot.
P.E = mgh
where mg = Weight = 600
To find the height Elliot will reach, substitute all necessary parameters into the equation above.
250 = 600h
Make h the subject of the formula
h = 250/600
h = 0.4167 meters
Therefore, the height he will reach when he has gravitational potential energy 250J is 0.42 meters approximately
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The normal force of a parked car on a level surface is 15,000 Newtons. What is the force of the car?
Answer:
The force of the car is 15000N.
Explanation:
The unit of force is Newtons (N), so based on the question, the force is 15000 Newtons.
The following data were collected during a short race between two friends. Velocity (m/s) 0 0.5 1 1.5 2 2 4 6 2 0 Time (s) 0 2 4 6 8 10 12 14 16 18 a) Describe the different sections of the graph. b) Determine the acceleration over the first eight seconds. c) Determine the maximum acceleration. d) Using the graph calculate the displacement: i) over the first eight seconds ii) the total race. e) Find the maximum velocity reached by the runner.
The characteristics of the kinematics allow to find the results for the questions about the movement of the body are:
a) we have four sections;
0 to 8 s The body is accelerating. 8 to 10 s The body goes at a constant speed, the acceleration is zero. 10 to 14 Body accelerating. 14 to 18 Body slowing down.b) The acceleration is the first 8 s is: a = 0.25 m / s²
c) The maximum acceleration is: a = 1 m / s²
d) The displacement is: i) d₁ = 8m, ii) [tex]d_{total}[/tex]= 16 m
e) maximum speed is: v = 6 m / s
Kinematics studies the movement of bodies by finding relationships between the position, speed and acceleration of bodies.
v = v₀ + a t
y = v₀ t + ½ a t²
where v and v₀ is the current and initial velocity, respectively, a is the acceleration and t is time.
In many circumstances graphs are made for their analysis, in a graph of speed versus time when we have a horizontal line the speed is constant, the acceleration is zero and in the case of a slope there is an acceleration, we have two cases:
Positive slope the body is accelerating and the speed is increasing. Negative slope the body is stopping, the speed decreases.
Let's answer the different questions about the system.
a) in the attached we have a graph of the velocity versus time, each section corresponds to a change in the slope of the graph, we have four sections;
0 to 8 s The body is accelerating. 8 to 10 s The body goes at a constant speed, the acceleration is zero. 10 to 14 Body accelerating. 14 to 18 Body slowing down.
b) The acceleration is the first 8 s
v = v₀ + a t
[tex]a = \frac{v-v_o}{\Delta t}[/tex]
[tex]a = \frac{2-0}{8-0}[/tex]
a = 0.25 m / s²
c) The maximum acceleration is when the slope is maximum.
[tex]a = \frac{6-2}{ 14-10}[/tex]
a = 1 m / s²
Therefore the acceleration is maximum in the section between 10 and 14 s
d) The total displacement is the sum of the displacements of each section.
[tex]d_{total } = d_1 +d_2 + d_3 +d_4[/tex]
We look for every displacement.
d₁ = v₀ + ½ a₁ Δt²
d₁ = 0 + ½ 0.25 8²
d₁ = 8 m
In the second section the velocity is constant
d₂ = v₂ Δt₂
d₂ = 2 (10-8)
d₂ = 4 m
The third section.
d₃ = v₀ + ½ a t²
d₃ = 2 + ½ 1 (14-10) ²
d₃ = 10 m
The distance of the fourth section.
we look for acceleration
a₄ = [tex]\frac{v-v_o}{\Delta t}[/tex]
a₄ = [tex]\frac{0-6}{18-14}[/tex]
a₄ = -1.5 m / s²
d₄ = 6 + ½ (-1.5) (1814) ²
d₄ = -6 m
The total displacement is;
[tex]d_{total}[/tex] = 8 + 4 + 10 -6
[tex]d_{total}[/tex] = 16 m
e) The maximum speed is the highest point in the graph of speed versus time that in the attachment we can see corresponds to
v = 6 m / s
In conclusion using the characteristics of kinematics we can find the results for the questions about the motion of bodies are:
a) we have four sections;
0 to 8 s The body is accelerating. 8 to 10 s The body goes at a constant speed, the acceleration is zero. 10 to 14 Body accelerating. 14 to 18 Body slowing down.b) The acceleration is the first 8 s is: a = 0.25 m / s²
c) The maximum acceleration is: a = 1 m / s²
d) The displacement is: i) d₁ = 8m, ii) [tex]d_{total}[/tex]= 16 m
e) maximum speed is: v = 6 m / s
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anyone to help with this question
Answer:
i can
Explanation:
i know what's the answer
The Doppler technique for planet detection has found Earth-like planets around nearby Sun-like stars. (True or False) ____________________
Answer: false
Explanation:
what are two variables that are always in every experiment?
the independent variable and the dependent variable.
Student 1 lifts a box with a force of 500 N and sets it on a tabletop 1.2 m high. Student 2 pushes an identical box up a 5 m ramp from the floor to the top of the same table. Which student did the MOST work?
The student who did the most work is student 2 with 2500 Joules.
Given the following data:
Force 1 = 500 NewtonDistance 1 = 1.2 meterForce 2 = 500 NewtonDistance 2 = 5 meterTo determine which of the students did the most work:
Mathematically, the work done by an object is given by the formula;
[tex]Work\;done = Force \times distance[/tex]
For student 1:
[tex]Work\;done = 500 \times 1.2[/tex]
Work done = 600 Joules
For student 2:
[tex]Work\;done = 500 \times 5[/tex]
Work done = 2500 Joules.
Therefore, the student who did the most work is student 2 with 2500 Joules.
Read more: Read more: brainly.com/question/13818347
Answer:student 2 did the most work
Explanation:student 2 did more work because he pushed it up 5 m instead of 1.2.
how to find velocity with constant acceleration
Answer:
velocity = distance / time
example:
if a body moves "20" meters in "2" seconds
, then it's velocity = 20/2 = "10m/s"
What is the mass of an object that has a weight of 110N ?
Answer:
The mass of the object is 11.2 Kg.
Hope you could get an idea from here.
Doubt clarification - use comment section.
The mass of an object that has a weight of 110 N is 11.2kg.
What is Weight?The weight of an object is defined as the force that acts on the object due to gravity. It is a vector quantity in some cases such as when the force of gravity acts on an object but it is also a scalar quantity where the force of gravity has a magnitude.
Weight is the gravitational force of attraction on an object due to the presence of another heavy object, such as the Earth or the Moon. It is expressed by multiplying the mass by the gravitational acceleration.
In above case,
Weight (W) = 110 N
Acceleration due to gravity (g) = 9.8 m/s^2
Let the mass of the object be m.
By using the formula,
W = mg,
[tex]110 N = 9.8 m/s^2 *m\\m = 110 N/ 9.8 m/s^2[/tex]
so, m = 11.2 Kg
Thus, the mass of an object that has a weight of 110 N is 11.2kg.
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The average distance between the Earth and the Moon is 384,000,000 meters. What is the distance in kilometers?
Answer:
384000
Explanation:
it would be 384000 in km
What event will produce the greatest increase in the gravitational force between the two masses?
Question 5 options:
Doubling the distance between the masses
Reducing the small mass by half
Doubling the large mass
Reducing the distance between the masses by half
Answer:
Doubling the large mass
Explanation:
Doubling the destance bewteen the masses will simply make the gravitational force weaker
same with every answer exce
Event will produce the greatest increase in the gravitational force between the two masses is Doubling the large mass.
What is force?
A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
Gravitational force is directly proportional to product of mass and inversely proportional to product of distance between them. So, on increasing heaver mass greatest increase in the gravitational force.
Event will produce the greatest increase in the gravitational force between the two masses is Doubling the large mass.
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Which of the following devices can be red to produce both transverse and
longitudinal waves?
1o) a string
(b) a ripple tank
(c) a helical spring (Slinky (d) a tuning fork
Answer:
Slinky is the correct answer.
Assuming a current is flowing, what increases the strength of the magnetic field of a coiled electrical wire? Select all that apply. Straightening the wire changing the direction of the current flow adding more coils to the wire placing a metal bar within the coils stopping the current.
The strength of the magnetic field is increased by adding more coils to the wire and placing a metal bar within the coils.
The given problem is based on the concept and fundamentals of the magnetic strength in a current-carrying coil of wire. The current-carrying wire in a coiled form is known as Solenoid.
And the mathematical expression for the magnetic field in a solenoid is,[[tex]B = \dfrac{\mu_{0} \times N \times i}{L}[/tex]
Here,
B is the strength of the magnetic field.
[tex]\mu_{0}[/tex] is the magnetic permeability of free space.
N is the number of coils.
The strength of the magnetic field will increase by increasing the number of coils and placing the metallic slab (it will increase magnetic permeability) within the coils.
Thus, we can conclude that the strength of the magnetic field is increased by adding more coils to the wire and placing a metal bar within the coils.
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Answer:
C
Explanation:
The engine of a 2400 kg car applies a force of 740 N to make the car accelerate. Calculate the
acceleration of the car.
Answer:
0.31 m/s²Explanation:
The acceleration of an object given only it's mass and the force acting on it can be found by using the formula
[tex]a = \frac{f}{m} \\ [/tex]
f is the force
m is the mass in kg
From the question
m = 2400 kg
f = 740 N
We have
[tex]a = \frac{740}{2400} = \frac{74}{240} \\ = 0.308333...[/tex]
We have the final answer as
0.31 m/s²Hope this helps you
Record your observations. Include the data table you created for the lab and a graph based on the data table. Type your answer here:
To create a graph of the data you collected during the lab, first, organize the data, then select the best type of graph, and finally create the graph.
One of the steps you need to complete after an experiment is to graph your results. This implies organizing the data and creating a diagram to visually represent your findings.
These are the steps you can follow to complete this task:
Organize the data: The first thing you need to do is to understand what were the main factors for example if your experiment measured temperature changes this is the main factor you need to consider. Then try to organize this data in a chart so you can visualize it.Select the type of graph: There are different types of graphs such as:Bar graph.Pie chart.Scatter plot.Among others.Each of these graphs focuses on specific types of data, and therefore you need to select the one that best fits the data you collected.
Create the graph: Finally, you can create the graph to do this, there are programs like excel that help you create the graph only by entering the data.Learn more about graphs in: https://brainly.com/question/16192791
4. In not less than 150 words, write your substantial insights on what you have learned in the past modules in relevance to what is happening now.
Answer:
“I think it’s about putting yourself in the students’ shoes and seeing how a first-time student, maybe someone who hasn’t even taken chemistry before, is looking at it.”
—Valerie Taraborelli, undergraduate chemistry student, University of Arizona1
“In some ways, I think the people who are the most successful as teachers are the ones who are able to remember what it was like being uncertain and not knowing. When you become an expert, things are easy. So the idea is to try and see where [students] are coming from and why they’ve developed this misconception and what you can do to specifically address it.”
—Dee Silverthorn, biology professor, University of Texas2
Hope this helps !!An automobile with a mass of 1250 kg accelerates at a rate of 4 m/sec2 in the forward direction. What is the net force acting on the automobile?
[tex]\large{\underline{\underline{\maltese{\pink{\pmb{\sf{ \; Question \; :- }}}}}}}[/tex]
An automobile with a mass of 1250 kg accelerates at a rate of 4 m/sec² in the forward direction. What is the net force acting on the automobile?
_________________________________________
[tex]\large{\underline{\underline{\maltese{\green{\pmb{\sf{ \; Given\; :- }}}}}}}[/tex]
➢ Mass of the automobile = 1250 kg➢ Acceleration of the body = 4m/sec²_________________________________________
[tex]\large{\underline{\underline{\maltese{\orange{\pmb{\sf{ \; To \: Find \; :- }}}}}}}[/tex]
Net force acting on the automobile = ?_________________________________________
[tex]\large{\underline{\underline{ \bigstar{{\pmb{\sf{ \; Concept \: and \: Formula \: Used \; :- }}}}}}}[/tex]
➯ Force is defined as the product of the mass of the body and its acceleration.
[tex] \bigstar \: \small{ \fbox {\textsf {\textbf{F = ma}}}}[/tex]
Where :
F = Force m = Mass of the bodya = acceleration due to gravity[tex]\large{\underline{\underline{ \bigstar{{\pmb{\sf{ \; Substituting \: the\: Given\: Values :- }}}}}}}[/tex]
[tex]⇝ \: \: \small \textsf {\textbf{ F = (1250 × 4) N }}[/tex]
[tex]⇝ \: \: \small \textsf {\textbf{ F = 5000 N }}[/tex]
[tex]\large{\underline{\underline{ \bigstar{{\pmb{\sf{ \; Therefore \; :- }}}}}}}[/tex]
❝ The net force acting on the automobile is 5000 N. ❞
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Situation You are going through a very rough time. You feel so down that you need someone to talk to you send a text message to your friend asking her if she could come over to make you feel better. You friend gives you a call then tells you she will be there in 20 minutes. You are so happy to see her, you give her a big hug. then pour your heart out. After crying to her for a good 30 minutes. she gives some comforting words. You finally say that you feel so much better. Your mend then says. "That's good to know. Now we're done, could we settle my expenses for this - 20 pesos for the phone call, 35 pesos for the tricycle nde going to your place, 20 pesos for all the tissue paper you drew from my tissue pack, and 10 pesos for the time I lost to working productively because had to come here. Thanks." What would be your reaction to your friend after she says this? Fourreaction
Answer:
she is your bestfriend so she should always be there for you as long as you are there for them but be like omg im so sorry.
Explanation:
wow tea is pouring
An EMT raceway contains two 3-phase, 480-volt branch circuits. What minimum size THHN branch circuit conductor is required for one of the circuits when it supplies a noncontinuous load of 27 kW?
Answer:8 AWG
Explanation: 6 current carrying conductors with 2 - 3 phase branch circuits. Divide 27000 by (480v × 1.732 or square root of 3) and you get 32.46 amps. Now using the code book, divide 32.46 by the adjustment factor of 6 CCC's which is .8 and you get 40.61 amps. Now go to Table 310.16 in the 2020 NEC book and you'll see that in the 90° column that 40.61 amps is above #10 AWG so you size up to #8 AWG.