how do you get 14 divided by 9 as a decimal

Step-by-step explanation:

quarter circle means that you just find the are and then divide it by 4.

hence,

(3.14 × 8²) ÷ 4 = answer

the answer is 50.24 cm²

hope this helps.

Answer: 6.28

Step-by-step explanation: In order to get your answer, the equation that you need to do is 8 X 3.14 / 4 to get your answer.

The solution to the absolute value inequality is (-3,-2)

On the absolute value inequality, we have:

Interval = -3 to 2

The intervals are represented with open circles.

This means that -3 and 2 are exclusive of the values of the inequality.

So, we have:

-3 < x < 2

As an interval notation, we have:

(-3,-2)

Hence, the solution to the absolute value inequality is (-3,-2)

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Answer:

Q = 40.6°

Explanation:

Given three sides: 9.6, 8.1, 6.3

Use the cosine rule:

c² = a² + b² - 2ab cos(C)

Insert following variables:

6.3² = 9.6² + 8.1² - 2(9.6)(8.1) cos(Q)

39.69 = 157.77 - 155.52 cos(Q)

cos(Q) = -118.08/-155.52

cos(Q) = 41/54

Q = cos⁻¹(41/54) = 40.6°

Step-by-step explanation:

The wording is slightly confusing so I will just solve the equation.

2 (y + 6) = 4y

We expand the bracket

2y + 12 = 4y

We subtract 2y from both sides

12 = 2y

We divide both sides by 2

6 = y

Answer:

x = 11

Step-by-step explanation:

3/(3(2x-3)) = 2/(3x+5)

3(2x-3) = 6x - 9

3/(6x-9) = 2/(3x+5)

3(3x+5) = 2(6x-9)

9x + 15 = 12x - 18

12x - 9x = 15 + 18

3x = 33

x = 11

Answer:

[tex]\mathrm x= \dfrac{87}{10} \quad or \quad 8.7[/tex]

Explanation:

[tex]\longrightarrow \sf \dfrac{3}{4} (2x-3)=\:\dfrac{2}{3}\:x+5[/tex]

[tex]\longrightarrow \sf \dfrac{3}{2} x-\dfrac{9}{4} =\:\dfrac{2}{3}\:x+5[/tex]

[tex]\longrightarrow \sf \dfrac{3}{2} x-\dfrac{2}{3}x=5+\dfrac{9}{4}[/tex]

[tex]\longrightarrow \sf \dfrac{5}{6} x=\dfrac{29}{4}[/tex]

[tex]\longrightarrow \sf x=\dfrac{29(6)}{4(5)}[/tex]

[tex]\longrightarrow \sf x=\dfrac{87}{10} \quad or \quad 8.7[/tex]

Answer:

320 cents per pound

Step-by-step explanation:

so we do 9.60 divided by 3, which is 3.20. So, 3.20 for each pound. Now we need in cents. 3 dollars is 300 cents, plus another 20, so 320 cents. I hope this helped.

[tex]\begin{array}{ccll} feet&seconds\\ \cline{1-2} 19 & 1\\ 600& x \end{array} \implies \cfrac{19}{600}~~=~~\cfrac{1}{x} \\\\\\ 19x=600\implies x=\cfrac{600}{19}\implies \stackrel{\textit{about half a minute}}{x\approx 31.58~seconds}[/tex]

Answer:

  10/19 min ≈ 0.5263 min

Step-by-step explanation:

The woman's sprinting speed is given in feet per second, and we are asked for it in minutes per 600 feet. To find the time, we can use the relation ...

  time = distance / speed

Using the given numbers will give a time in seconds, so we need to do a units conversion to find the answer in minutes.

__

  time = distance/speed

  time = (600 ft) / (19 ft/s) = (600/19) s

Converting the units gives ...

  time = (600/19) s × (1 min)/(60 s) = (600·1)/(19·60) min

The time it takes the woman to sprint 600 feet will be ...

  time = 600/(19·60) min = 10/19 min ≈ 0.5263 min

[tex]f(x) = 3(x+5)\\\\f(a+2) = 3(a+2 +5) \\\\~~~~~~~~~~~~=3(a+7)\\\\~~~~~~~~~~~~=3a+21[/tex]

By weighted average, we need 75 liters of 24 % iodine solution and 25 liters of 40 % iodine solution to obtain 100 liters of 28 % iodine solution.

Physically speaking, concentration is equal to the amount of solute divided by the volume of solution. We have two solutions with same solute and different concentration and can find the right proportion between the 24 % solution and the 40 % solution by concept of weighted average:

x · 24 + (1 - x) · 40 = 28

40 - 16 · x = 28

16 · x = 40 - 28

16 · x = 12

x = 3/4

By weighted average, we need 75 liters of 24 % iodine solution and 25 liters of 40 % iodine solution to obtain 100 liters of 28 % iodine solution.

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We are given the equation for the height of the arrow. If you graph it, you see that it's a parabola and that the arrow kinda peaks and then falls back down. Another way of thinking about this problem is that you're looking for the time when the height is 0. You can see on the graph that there are two times that h=0. The first is obviously at t=0, when the arrow hasn't left the ground yet. The second is what we're looking for, when the arrow reaches the ground.

To solve this, let's set h=0. So 0=40t-5t^2. If you factor this, you get 5t(8-t) = 0. Continuing that leads to 5t=0 where t=0 which we already knew, and 8-t=0 where t=8. So that second time is when the arrow is back on the ground. Therefore your answer is 8 sec.

Considering the given function, the ordered pair (5,8) means that the signed up for 5 weeks of yoga classes and 8 weeks of kickboxing classes.

The function that represents the relationship between the number x of yoga classes that Donovan signs up for and the number y of kickboxing classes is given by:

8x + 12y = 136.

Hence the ordered pair (5,8) means that the signed up for 5 weeks of yoga classes and 8 weeks of kickboxing classes.

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Answer: (8, -4)

Step-by-step explanation:

-5x - 3y = -28
  x + 2y = 0

1. Multiply both sides of the bottom system by 5 to cancel the x out

   5(x+2y=0)

   5x + 10y = 0

2. rewrite

   -5x - 3y = -28

    5x + 10y = 0

3. add

   0x + 7y = -28

4. divide by 7

   7y = -28

5. y = -4

6. plug in -4 for y in one of the original equations

   x + 2(-4) = 0

7. simplify

   x = 8

9. solution is

   (8, -4)

Answer:

[tex]0.95*10^8[/tex]

Step-by-step explanation:

Hello!

Rules for scientific notation format:

[tex]\bold{0.95*10^8}[/tex]

There is a multiplication to a power of 10, but the other factor is less than 1.

This is NOT in Scientific Notation.

All the other options have a multiplication operation to a power of 10, and all the other factors are above 1 and less than 10.

Answer:

B) [tex]8\sqrt[4]{4}[/tex]

Step-by-step explanation:

[tex](2^{8} *2^{6} )^\frac{1}{4} = (2^{8+6} )^\frac{1}{4} =(2^{14} )^\frac{1}{4} =2^{\frac{7}{2} }=\sqrt{2^{7} } =2^{3} \sqrt{2} =8\sqrt{2} = 8\sqrt[4]{2^{2} } = 8\sqrt[4]{4}[/tex]

Answer:

the measure of each angle is 75degrees

Answer: 1.125 pounds of blueberries or  [tex]1 \frac{1}{8}[/tex] or [tex]\frac{9}{8}[/tex]

Step-by-step explanation:

Since she will eat it for 9 days, just multiply or add the pounds.

The average rates of change of f(x) and their corresponding intervals are given as:

Interval          Rate of Change

[-5, -1]                 -8

[-4, -1]                 -7

[-3, 1]                  -4

[-2, 1]                  -3.

Step 1 - See Table Attached

Step 2 - State the formula for rate of change

The formula for rate of change is given as:
= [change in f(x)] / [change in x]

a) For interval [5, -1] ⇒

Rate of Change - [ f(1) - f(-5) ] / [-1 - (-5)]  

= [-1 - 35] / [-1+5]

= -36 / 4

= - 8

b) For interval [-4, -1] ⇒

rate of change = [ f(-1) - f(-4) ] / [ -1 - (-4) ]

= [3 - 24] / [-1 + 4]

= -21/3

= - 7

c) interval [-3,1] ⇒

rate of change = [ f(1) - f(-3) ] / [ 1 - (-3) ]

= [-1 - 15] / [1 + 3]

= -16/4

= - 4

d) interval [-2,1] ⇒

rate of change = [f (1) - f(-2)] / [1 - (-2)]

= [ -1 - 8] / [1 + 2]

= -9/3

= -3

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Answer: 674 ft

Step-by-step explanation:

[tex]\tan 12^{\circ}=\frac{y}{1315} \\ \\ 1315\tan 12^{\circ}=y[/tex]

[tex]\tan 8^{\circ}=\frac{y}{x+1315} \\ \\ (x+1315)\tan 8^{\circ}=y \\ \\ (x+1315)\tan 8^{\circ}=1315 \tan12^{\circ} \\ \\ x \tan 8^{\circ}+1315 \tan 8^{\circ}=1315 \tan 12^{\circ} \\ \\ x \tan 8^{\circ}=1315 \tan 12^{\circ}-1315 \tan 8^{\circ} \\ \\ x=\frac{1315 \tan 12^{\circ}-1315 \tan 8^{\circ}}{\tan 8^{\circ}} \approx \boxed{674 \text{ ft}}[/tex]

The number of each type of coin that Joan has are; 16 dimes and 3 quarters

We are told that Joan has a total of 19 coins.

Now, the worth of the coins is $2.35

Let dimes be d and let quarters be q. Thus;

10d + 25q = 235

d + q = 19

Substitute d = 19 - q in the 1st equation to get;

10(19 - q) + 25q = 235

190 - 10q + 25q = 235

15q = 45

q = 45/15

q = 3

Thus;

d = 19 - 3

d = 16

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The conversion of 120 sq. inches is equivalent to 0.09264 sq. yd.

Conversion is the process of changing the value of one form to another for example inches to millimeters, or liters to gallons.

Here, we know that,

    1 square inches = 0.000772 sq yd

we have 120 sq. inches

so, 120 sq. inches = 120 X 0.000772 sq yd

                              = 0.09264 sq. yd.

Thus, the conversion of 120 sq. inches is equivalent to 0.09264 sq. yd.

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The average value of f over the region D is 243/4

To answer the question, we need to know what the average value of a function is

The average value of a function f(x) over an interval [a,b] is given by

[tex]\frac{1}{b - a} \int\limits^b_a {f(x)} \, dx[/tex]

Now, given that we require the average value of f(x,y) = 3xy over the region D where D is the triangle with vertices (0, 0), (1, 0), and (1, 9).

x is intergrated from x = 0 to 1 and the interval is [0,1] and y is integrated from y = 0 to y = 9

So, [tex]\frac{1}{b - a} \int\limits^b_a {f(x,y)} \, dA = \frac{1}{1 - 0} \int\limits^1_0 \int\limits^9_0 {3xy} \, dxdy \\= \frac{3}{1} \int\limits^1_0 {x} \,dx\int\limits^9_0 {y} \,dy\\ = \frac{3}{1} [\frac{x^{2} }{2} ]^{1}_{0}[\frac{y^{2} }{2} ]^{9}_{0} \\= 3[\frac{1^{2} }{2} - \frac{0^{2}}{2} ] [\frac{9^{2} }{2} - \frac{0^{2}}{2} ] \\= 3[\frac{1}{2} - 0 ][\frac{81}{2} - 0 ]\\= \frac{81}{2} X3 X \frac{1}{2} \\= \frac{243}{4}[/tex]

So, the average value of f over the region D is 243/4

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The numbers that can be pulled based on the probability of the calls will be 90, 110, and 50.

From the information given, the bag has 9 blue cubes, 11 red cubes, and 5 green cubes and when one draws a cube and replace it in the bag 250 times, the number of blue balls that can be gotten will be:

= 9/(9+ 11 + 5) × 250

= 9/25 × 250

= 90

The number of red balls that can be gotten will be:

= 11/25 × 250

= 110

The number of green balls that can be gotten will be:

= 5/25 × 250

= 50

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Answer:

See below ~

Step-by-step explanation:

Classifying the triangles by sides and angles :

Triangle ABC

⇒ By Sides : Scalene (All sides are unequal)

⇒ By Angles : Right (There is a right angle = 90°)

============================================================

Triangle GHI

⇒ By Sides : Isosceles (2 sides are equal)

⇒ By Angles : Obtuse (One angle is greater than 90°)

============================================================

Triangle DEF

⇒ By Sides : Equilateral (All sides are equal)

⇒ By Angles : Acute (All angles are less than 90°)

The length of the curve will be given by the definite integral

[tex]\displaystyle \int_0^1 \sqrt{\left(\frac{dx}{dt}\right)^2 + \left(\frac{dy}{dt}\right)^2} \, dt[/tex]

From the given parametric equations, we get derivatives

[tex]x(t) = 3t^2 + 5 \implies \dfrac{dx}{dt} = 6t[/tex]

[tex]y(t) = 2t^3 + 5 \implies \dfrac{dy}{dt} = 6t^2[/tex]

Then the arc length integral becomes

[tex]\displaystyle \int_0^1 \sqrt{\left(6t\right)^2 + \left(6t^2\right)^2} \, dt = \int_0^1 \sqrt{36t^2 + 36t^4} \, dt \\\\ = \int_0^1 6|t| \sqrt{1 + t^2} \, dt[/tex]

Since 0 ≤ t ≤ 1, we have |t| = t, so

[tex]\displaystyle \int_0^1 6|t| \sqrt{1 + t^2} \, dt = 6 \int_0^1 t \sqrt{1 + t^2} \, dt[/tex]

For the remaining integral, substitute [tex]u = 1 + t^2[/tex] and [tex]du = 2t \, dt[/tex]. Then

[tex]\displaystyle 6 \int_0^1 t \sqrt{1 + t^2} \, dt = 3 \int_1^2 \sqrt{u} \, du \\\\ = 3\times \frac23 u^{3/2} \bigg|_{u=1}^2 \\\\ = 2 \left(2^{3/2} - 1^{3/2}\right) = 2^{5/2} - 2 = \boxed{4\sqrt2-2}[/tex]

The measures of BC will be 100°. Option D is correct.

It is a point locus drawn equidistant from the center. The radius of the circle is the distance from the center to the circumference.

The angle at the center is twice as large as the angle at the perimeter.

BC = 2 ×∠CDB

BC=2×50°

BC= 100°

Hence option D is correct.

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Answer:

z = 1/4

Step-by-step explanation:

See attached image

Answer:

z = 5

Step-by-step explanation:

simplify

5/(z-25) first

turning it into

((0 - 3/z) + 7/4z) - 5/(z - 25) = 0

then simplify 7/4z

((0 - 3/z) + 7/4z) - 5/(z-25) = 0

when the fractions denominator is 0 then the numerator must be 0

turning the equation into

-25  *  (z - 5)  = 0

solve

-25   =  0

something that is not zero cannot equal zero.

z - 5 = 0

5 - 5 = 0

z = 5

hope this helps:)

Answer:

Architects use geometry to study and divide space as well as draft detailed building plans. Builders and engineers rely on geometric principles to create structures safely. Designers apply geometry (along with color and scale) to make the aesthetically pleasing spaces inside. Applying geometry in design is unavoidable.