How many milliliters of 0.100 M HClO4 solution are needed to neutralize 50.00 mL of 0.0832 M NaOH?

Answers

Answer 1
HClO4 +NaOH -----> NaClO4 + H2O
moles of NaOH = (0.0832 x 50 ) /1000= 4.16 x10^-3 moles
since the mole ratio of HClO4 to NaOH is 1:1 the moles of HClO4 is also 4.16 x 10^-3 moles

volume of HClO4 is therefore = moles/ molarity
that is 4.16 x 10^-3mol/ 0.167 mol/L= 0.0249L
multiply by 1000 to convert to ml
0.0249 x 1000= 24.9 ml
Answer 2

The milliliters of 0.100 M HClO4 solution are needed to neutralize 50.00 mL of 0.0832 M NaOH is 24.9 ml.

What is neutralization?

Neutralization is defined as a chemical reaction in which an acid and a base quantitatively react with one another. Because it determines how acidic or basic a solution is, a solution's pH is crucial. The interaction of H+ ions and OH- ions produces water in a neutralization reaction, which occurs when an acid and a base react to form water and a salt.

Since the mole ratio of HClO4 to NaOH is 1:1, the moles of HClO4 are equal to 4.16 x 10-3 moles.

The moles of NaOH are equal to (0.0832 x 50) /1000.

Therefore, the volume of HClO4 is equal to the moles/molarity, which is 4.16 x 10-3mol/ 0.167 mol/L= 0.0249L.

This amount is then multiplied by 1000 to get ml: 0.0249 x 1000 = 24.9 ml.

Thus, the milliliters of 0.100 M HClO4 solution are needed to neutralize 50.00 mL of 0.0832 M NaOH is 24.9 ml.

To learn more about neutralization, refer to the link below:

https://brainly.com/question/27891712

#SPJ2


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