How many moles are in 12 liters of Cl2?

Answers

Answer 1

Answer:

[tex]\boxed {\boxed {\sf 0.54 \ mol \ Cl_2}}[/tex]

Explanation:

A mole is any quantity of a substance that contains 6.02 × 10²³ particles. At standard temperature and pressure, or STP, 1 mole of as is equal to 22.4 liters. This is true for any gas, regardless of the specific kind.

Although it is not specified, we can assume this gas is at STP. Let's set up a ratio using this information: 22.4 L/mol

[tex]\frac {22.4 \ L \ Cl_2}{1 \ mol \ Cl_2}[/tex]

Multiply by the given number of liters: 12

[tex]12 \ L \ Cl_2 *\frac {22.4 \ L \ Cl_2}{1 \ mol \ Cl_2}[/tex]

Flip the ratio so the liters of chlorine cancel.

[tex]12 \ L \ Cl_2 * \frac {1 \ mol \ Cl_2}{22.4 \ L \ Cl_2}[/tex]

[tex]12 * \frac {1 \ mol \ Cl_2}{22.4 }[/tex]

[tex]\frac {12}{22.4 } \ mol \ Cl_2[/tex]

[tex]0.53571428571 \ mol \ Cl_2[/tex]

The original measurement of liters has 2 significant figures, so our answer must have the same.

For the number we found, that is the hundredth place.

0.53571428571

The 5 in the thousandth place tells us to round the 3 up to a 4.

[tex]0.54 \ mol \ Cl_2[/tex]

12 liters of chlorine gas at STP is approximately 0.54 moles of chlorine gas.


Related Questions

____________ are traits characteristics or features of an organism that are passed from parent to offspring

Answers

Answer:

Heredity, also called inheritance or biological inheritance, is the passing on of traits from parents to their offspring; either through asexual reproduction or sexual reproduction, the offspring cells or organisms acquire the genetic information of their parents.

Explanation:

Plss markk mee brainlistt

A canister of neon contains 4.8x1024 atoms of the gas. How many moles of neon are present in the canister?

Answers

Answer:

7.97 moles of neon are present in the canister.

Explanation:

Avogadro's constant or "Avogadro's number" is the number of constituent particles found in the amount of substance in one mole.

In other words, Avogadro's number is the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number applies to any substance.

So, you can apply the following rule of three: if 6.023*10²³ atoms are present in 1 mole, 4.8*10²⁴ atoms are present in how many moles?

[tex]amount of moles=\frac{4.8*10^{24}atoms*1 mole }{6.023*10^{23}atoms}[/tex]

amount of moles= 7.97 moles

7.97 moles of neon are present in the canister.

place the following in order of increasing standard molar entropy. n2o4 (g) no (g) no2 (g)

Answers

The standard molar entropy of no₂ is 240.0 J/(mol.K).Therefore, the order of increasing standard molar entropy of the given gases is n₂o₄ (g) < no (g) < no₂ (g).

Entropy is the measure of disorder in a system. It is a thermodynamic property that depends on the degree of randomness in the molecules of a substance. The unit of entropy is Joules per Kelvin. In general, the entropy of a substance increases with an increase in temperature.

This is because at higher temperatures, the molecules of a substance have more kinetic energy and can move more freely, leading to an increase in the number of possible arrangements of molecules, which increases entropy.

Increasing Standard Molar Entropy Order n₂o₄ (g) < no (g) < no₂ (g)The standard molar entropy (S°) is the entropy of one mole of a substance at standard temperature and pressure (STP). In the order of increasing standard molar entropy, the gases listed are as follows: n₂o₄ (g) has the least entropy because it is a relatively heavy and rigid molecule. It has fewer possible arrangements of molecules, which results in a lower entropy.

The standard molar entropy of n₂o₄ is 304.3 J/(mol.K).no (g) has more entropy than n₂o₄ because it is a lighter molecule that is more mobile. It has more possible arrangements of molecules, leading to higher entropy.

The standard molar entropy of no is 210.6 J/(mol.K).no₂ (g) has the highest entropy because it is the lightest and most mobile molecule of the three gases. It has the most possible arrangements of molecules, leading to the highest entropy. The standard molar entropy of no₂ is 240.0 J/(mol.K).

Therefore, the order of increasing standard molar entropy of the given gases is n₂o₄ (g) < no (g) < no₂ (g).

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Se midió el pH de una muestra del agua de lluvia en la ciudad de México, y se obtuvo un valor de 3.5 Calcula la [H+] en dicha muestra.

Answers

Answer:

[tex][H^+]=3.16x10^{-4}M[/tex]

Explanation:

¡Hola!

En este caso, dado que el pH de una solución se entiende como el potencial de los iones hidrógeno en la misma, es posible recordar la ecuación que se usa para calcularlo:

[tex]pH=-log([H^+])[/tex]

De este modo, al conocer el pH, se resuelve para la concentración de iones hidrógeno como se muestra a continuación:

[tex][H^+]=10^{-pH}[/tex]

Así, reemplazamos el pH para obtener:

[tex][H^+]=10^{-3.5}=3.16x10^{-4}M[/tex]

¡Saludos!

When a 0.3546 g of vanadium metal is heated in air, it reacts with oxygen to achieve a
final mass of 0.6330 g. Calculate the empirical formula of this vanadium oxide

Answers

Answer:

V2O5 is the empirical formula of vanadium oxide

Explanation:

The molecular mass of Vanadium is  50.949 g/mol

Number of moles of vanadium = 0.3456 g/50.949 g/mol = 0.00696 moles

The molecular mass of Oxygen is 16.0 g/mol

Number of moles of Oxygen = (0.6330 – 0.354) g/16 g/mol = 0.0174 moles

Emperical formula  

V (0.00696 moles/0.00696 moles) O (0.0174 moles /0.00696 moles)

V 1 O2.5

Multiply by two get a whole number  

V2 O5

27 which statement about members of a homologous series is true ? a) they are all constitutional isomers. b) they are always hydrocarbons. c) each differs from its nearest neighbors by 14 amu. d) they may also be classified as tautomers.

Answers

The statement about members of a homologous series that is true is that they differ from their nearest neighbors by 14 amu (c).

A homologous series is a group of compounds with a similar general formula, chemical properties, and a constant increment in molecular structure. As a result, each member varies from the previous by a constant unit, which is often a CH2 group.Each member of the homologous series is classified as either a tautomer or a constitutional isomer. Constitutional isomers, also known as structural isomers, are compounds with the same molecular formula but different structural arrangements. Isomers of tautomers are structural isomers that interconvert by a simple chemical reaction. As a result, the formula and composition of tautomers are the same, but they differ in the distribution of their valence electrons and bonding patterns.Members of a homologous series may or may not be hydrocarbons, and they are not always constitutional isomers. Therefore, statement (a) and statement (b) are both incorrect. Statement (d) is also incorrect because tautomers cannot be classified as members of a homologous series. However, statement (c) is correct because members of a homologous series differ from their nearest neighbors by a constant increment in molecular structure, which is usually 14 amu. Therefore, the correct answer is C.

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please helpp: All things that are acidic will eventually produce ___ in an aqueous solution?​

Answers

Answer:

Protons / H+ ions

Explanation:

The acids are compounds with a pH range between 1-7, while the base has a pH range of 7-14. Acids produce hydrogen ions or protons in the solution.

What is pH?

The pH can be defined as the hydrogen ion concentration in the solution. The higher the proton concentration in the solution, the lower will be the pH.

The pH of 7 has an equal number of hydrogen and hydroxide ions contributing to the neutral pH. The alkaline pH is contributed by the hydroxide ion concentration.

The acids fall at the lower pH range with a high hydrogen ion concentration. Thus, acids produce hydrogen ions or protons in the aqueous solution.

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0.39 moles of a gas fill a 5.0 l container that connects to a balloon through a closed valve. if the valve is opened an pressure remains the same, what would be the total number of moles of gas needed in order to inflate the balloon by 1.5

Answers

Answer: 5.39

Explanation: you are adding the balloon's volume and the container's volume

I need help...well honestly I don't wanna do it so can someone help because this is just confusing....I don't need any citing or whatever just give me a short explication of how Denver is mile high....thank youuu...​

Answers

Answer: Denver is named after James W. Denver, a governor of the Kansas Territory. It is nicknamed the Mile High City because its official elevation is exactly one mile (5280 feet or 1609.344 meters) above sea level.

. A saturated solution of AgCl is treated with solid NaCl until the [CH] is 0.27 M. What will be the resulting (Ag'in solution? Enter your answer in scientific notation. L T * 10-10 ] What percent of Agt remains in solution at this point?

Answers

The percent of Ag+ remaining in solution is 0.0158 %.

The concentration of the Cl- ion in the solution is increased by adding more NaCl to it. The solubility product of AgCl is Ksp = [Ag+][Cl-]2. When the solution contains 0.27 M Cl-, AgCl will dissolve until it reaches its solubility limit.The solubility of AgCl at 25°C is 1.3 x 10-5 M (0.000013 M) and its solubility product (Ksp) at the same temperature is 1.8 x 10-10. Therefore, the concentration of [Ag+] in the saturated AgCl solution is: 1.3 x 10-5 MThus, when 0.27 M Cl- is added to the solution, AgCl will dissolve to reach a final [Ag+] of: Ksp = [Ag+][Cl-]2[Ag+] = (Ksp/[Cl-]2) = (1.8 x 10-10)/(0.27)2 = 2.06 x 10-9 MThe amount of Ag+ in solution at this point is: [Ag+] = 2.06 x 10-9 M = 2.06 x 10-3 %AgCl dissolved = (2.06 x 10-9 M)/(1.3 x 10-5 M) x 100 = 0.0158 %Hence, the resulting [Ag+] is 2.06 × 10-9 M. The percent of Ag+ remaining in solution is 0.0158 %.

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how many grams is 4.2 moles HCL​

Answers

≈153.14 grams. Sine one mole of HCL is ≈36 grams. Just multiple 4.2 by 36.

If you were traveling from Earth to Neptune in a spaceship, what would
you see between Mars and Jupiter?

Imposters
little green men
Pluto
the asteroid belt

Answers

Answer:

I believe it would be Asteroid Belt

Explanation:

little green men and imposters seem very unlikely, and Pluto is definetely not between earth and Jupiter

Answer:

the asteroid belt

Explanation:

it orbits between mars and jupiter

Which of the following usually occurs when a molecule dissolves in water?
a. The covalent bonds in the molecule break.
b. The covalent bonds in water break.
c. Covalent bonds between the molecule and water form.
d. Covalent bonds between several of the molecules form.
e. Hydrogen bonds form between the molecule and water.

Answers

Answer:

e. Hydrogen bonds form between the molecule and water.

Explanation:

When a molecule dissolves in water, it is typically because the molecule has polar or charged regions that can interact with the polar water molecules. Water is a highly polar molecule due to its bent shape and the presence of electronegative oxygen atoms. As a result, it forms hydrogen bonds with other water molecules and with other polar or charged substances.

When a molecule dissolves in water, the water molecules surround the individual molecules and interact with them through hydrogen bonding. The positively charged hydrogen atoms of water form hydrogen bonds with negatively charged regions of the dissolved molecule, such as oxygen or nitrogen atoms, or with partially negative regions due to uneven distribution of electron density. This interaction between the water molecules and the dissolved molecule is what allows the molecule to become dispersed and solvated in the water, forming a homogeneous mixture.

It's important to note that during the dissolution process, the covalent bonds within both the water molecules and the dissolved molecule generally remain intact. Dissolving in water does not typically involve breaking the covalent bonds within the molecule or the water molecule. Instead, it involves the formation of hydrogen bonds between the solvent (water) and solute (dissolved molecule).

Identify which redox reactions occur spontaneously in the forward direction.
Check all that apply.
2Ag+(aq)+Ni(s)→2Ag(s)+Ni2+(aq)
2Cr(s)+3Pb2+(aq)→2Cr3+(aq)+3Pb(s)
Ca2+(aq)+Zn(s)→Ca(s)+Zn2+(aq)
Sn(s)+Mn2+(aq)→Sn2+(aq)+Mn(s)

Answers

The redox reactions that occur spontaneously in the forward direction are:

2Ag+(aq) + Ni(s) → 2Ag(s) + Ni2+(aq)

Ca2+(aq) + Zn(s) → Ca(s) + Zn2+(aq)

Among the given redox reactions, the ones that occur spontaneously in the forward direction are: 2Ag+(aq) + Ni(s) → 2Ag(s) + Ni2+(aq) and Ca2+(aq) + Zn(s) → Ca(s) + Zn2+(aq). These reactions occur because the reduction potentials of Ag+ and Ca2+ are higher than those of Ni2+ and Zn2+, respectively. As a result, Ag+ and Ca2+ are reduced, while Ni and Zn are oxidized. The other two reactions, 2Cr(s) + 3Pb2+(aq) → 2Cr3+(aq) + 3Pb(s) and Sn(s) + Mn2+(aq) → Sn2+(aq) + Mn(s), do not occur spontaneously in the forward direction due to the lower reduction potentials of the species being reduced.

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Use data from Appendix C in the textbook to calculate the equilibrium constant, K, at 298 K for each of the following reactions.
ONE significant figure!!!!
H2(g)+I2(g)←−→2HI(g)
C2H5OH(g)←−→C2H4(g)+H2O(g)
3C2H2(g)←−→C6H6(g)

Answers

We can say that the equilibrium constant, K, can be calculated at 298 K for each of the following reactions using the data given in Appendix C of the textbook.

The equilibrium constant, K, can be calculated at 298 K for each of the following reactions using the data given in Appendix C of the textbook as follows: Equation: H2(g)+I2(g)↔2HI(g). At equilibrium: [H2] = [I2] = 0.0100 M, and [HI] = 0.0938 M∴ Kc = [HI]2[H2][I2]⇒Kc = (0.0938)2/(0.0100)2= 87.56. Equation: C2H5OH(g)↔C2H4(g)+H2O(g). At equilibrium: [C2H5OH] = 1.00 M, and [C2H4] = [H2O] = 0.0158 M∴ Kc = [C2H4][H2O]/[C2H5OH]⇒Kc = (0.0158)2/1.00= 0.000249. Equation: 3C2H2(g)↔C6H6(g)At equilibrium: [C2H2] = 0.101 M, and [C6H6] = 0.052 M∴ Kc = [C6H6]/[C2H2]3⇒Kc = 0.052/(0.101)3= 0.542

The equilibrium constant (K) is calculated using the formula shown below: Kc = [Products]/[Reactants]For example, for the reaction H2(g)+I2(g)↔2HI(g), the equilibrium constant (K) is calculated as follows: Kc = [HI]2[H2][I2]/[Reactants]. In this reaction, at equilibrium, the concentrations of hydrogen, iodine, and hydrogen iodide are [H2] = [I2] = 0.0100 M and [HI] = 0.0938 M. Therefore, Kc = (0.0938)2/(0.0100)2= 87.56.

Similarly, for the reaction C2H5OH(g)↔C2H4(g)+H2O(g), the equilibrium constant (K) is calculated as follows: Kc = [C2H4][H2O]/[C2H5OH] . In this reaction, at equilibrium, the concentrations of ethyl alcohol, ethylene, and water are [C2H5OH] = 1.00 M, [C2H4] = [H2O] = 0.0158 M. Therefore, Kc = (0.0158)2/1.00= 0.000249Similarly, for the reaction 3C2H2(g)↔C6H6(g), the equilibrium constant (K) is calculated as follows: Kc = [C6H6]/[C2H2]3. In this reaction, at equilibrium, the concentrations of acetylene and benzene are [C2H2] = 0.101 M and [C6H6] = 0.052 M.

Therefore, Kc = 0.052/(0.101)3= 0.542. Hence, the equilibrium constant (K) is calculated at 298 K for each of the given reactions.

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Select the correct statement that corresponds to the second law of thermodynamics. (a) The standard Gibbs free energy change, ΔG°, can be calculated from Gibbs free energies of formation, ΔGf° (b) The entropy of a perfect crystal of any pure substance approaches zero, as the temperature approaches absolute zero (0 K) (c) The entropy change for a reaction, DS°C, can be calculated from the standard molar entropies of the reactants and products (d) ΔE universe - ΔE system + ΔEsurroundings = 0 (e) In any spontaneous process, ΔS universe - ΔS system + ΔSsurroundings > 0

Answers

The correct statement (e) captures the fundamental principle of the second law of thermodynamics, emphasizing the tendency of entropy to increase in spontaneous processes, leading to a positive net entropy change of the universe.

The second law of thermodynamics is a fundamental principle that describes the behavior of energy and entropy in physical systems. It can be stated in various ways, but the correct statement corresponding to the second law is: In any spontaneous process, ΔS universe - ΔS system + ΔS surroundings > 0.

This statement captures the essence of the second law, which is that the entropy of an isolated system tends to increase over time. The entropy change of the universe (ΔS universe) is the net change in entropy of the system and its surroundings. For a spontaneous process, where the system undergoes a change without external intervention, the total entropy change of the universe must be greater than zero.

The entropy change of the system (ΔS system) and the entropy change of the surroundings (ΔS surroundings) may have opposite signs, but their magnitudes must be such that the net entropy change of the universe is positive. This reflects the irreversibility of natural processes, where entropy tends to increase and energy becomes more dispersed. The correct statement (e) captures the fundamental principle of the second law of thermodynamics, emphasizing the tendency of entropy to increase in spontaneous processes, leading to a positive net entropy change of the universe.

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what are the two components of a solution

Answers

The components of a solution are solute and solvent

part a which substance is the oxidizing agent in the reaction below? fe(co)5 (l) 2hi (g) → fe(co)4i2 (s) co (g) h2(g)

Answers

Answer : The substance that acts as the oxidizing agent in the reaction:Fe(CO)5(l) + 2HI(g) → Fe(CO)4I2(s) + CO(g) + H2(g)is HI, or hydrogen iodide.

Explanation : In this reaction, HI acts as an oxidizing agent and Fe(CO)5(l) acts as a reducing agent.What is an oxidizing agent?An oxidizing agent is a substance that oxidizes or causes oxidation in another compound by transferring electrons to that compound. In the process, the oxidizing agent itself gets reduced.Oxidizing agents are chemicals that accept electrons from other substances. They are generally characterized by their ability to oxidize another substance, which is why they are sometimes referred to as electron acceptors.

Examples of oxidizing agents include hydrogen peroxide, potassium permanganate, and sodium hypochlorite.

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How much water needs to be added
to 55 mL of 3.0 M stock solution to
produce a .75 M solution?

Answers

Answer:

165 ml

Explanation:

We are given;

Initial volume; V_a = 55 ml

Initial molarity; M_a = 3 M

Molarity of desired solution; M_b = 0.75 M

Volume of desired solution; V_b = (55 + x) ml

Where x is the volume of water to be added.

To solve for V_b, we will use the equation ;

M_a•V_a = M_b•V_b

V_b = (M_a•V_a)/M_b

V_b = (3 × 55)/0.75

V_b = 220 mL

Thus;

(55 + x) = 220

x = 220 - 55

x = 165 mL

Answer:

gotta concert mL to L

3.0=mol/0.055( you multiply morality and liter)

0.165 mol

you divide the mole by the other given molarity

0.165/0.75= 0.22 L

0.22 *1000= 220 mL

Explanation:

The population size of panda

bears increases dramatically

The

population will decrease because

Answers

Answer:

it will decrease because there will not be food for all of them and there is very little space for them now so if there is more they will start to fight

Explanation:

there is very little habitat left for panda bears so if there population increases the food and space with be filed

Hello! jamilialves888

I'm glad you asked my name is ✰Tobie✰

And I will help you understand why the population of ⚝pandas ⚝

is decreasing .

-Your answer :βy Tobie

≛So why are pandas going extinct?

One of the main cause is due to the destruction of their own habitat

Since china is a country that is constantly growing their own homes are slowly   being destroyed Since their habitats are becoming destroyed it forces them to live in small unhabitable area .

≛This leads to another problem.....

If they are forced to live in a small area there will be less food...

Since there is a shortage of food that will leave the panda's to slowly starve to death since pandas only eat bamboo they could never be able to live anywhere else....Another reason panda's are going extinct is because they are being hunted for their fur.

ex·tinct

/ikˈstiNG(k)t/

_____________

It means that the species does not exist anymore and

are no longer in existence

Hope this helps!

                                                                                             -Tobie <3

ʕ •ᴥ•ʔ

Which statements are true regarding the following spontaneous reaction? CHOOSE ALL CORRECT ANSWERS; there may be more than one correct answer. Mg(s) + CoSO4(aq) ? MgSO4(aq) + Co(s)
Co is oxidized
O is reduced
S is oxidized
S is reduced
This is not a redox reaction.
O is oxidized
Co is reduced
Mg is reduced
Mg is oxidized

Answers

Mg is reduced to Mg2+.Hence, the correct option is Mg is oxidized, Co is reduced, and Co is oxidized

In the given reaction, Mg(s) + CoSO4(aq) ⟶ MgSO4(aq) + Co(s), the true statements regarding the given spontaneous reaction are: Mg is oxidized.Co is reduced.Co is oxidized. The reduction half-reaction of the given reaction is Co2+ + 2e− ⟶ Co. The oxidation half-reaction of the given reaction is Mg ⟶ Mg2+ + 2e−.The oxidation number of Co changes from +2 in CoSO4(aq) to 0 in Co(s), therefore, Co is oxidized in the given reaction. The oxidation number of Mg changes from 0 in Mg(s) to +2 in MgSO4(aq), therefore, Mg is oxidized in the given reaction. Therefore, Mg is reduced to Mg2+.Hence, the correct option is Mg is oxidized, Co is reduced, and Co is oxidized. The explanation of each of the true statements is already given above.

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T/F A reaction which is endothermic and has an overall increase in entropy is spontaneous only at high T

Answers

"A reaction which is endothermic and has an overall increase in entropy is spontaneous only at high T" is incorrect.

"A reaction which is endothermic and has an overall increase in entropy is spontaneous only at high T" is false.A spontaneous process occurs naturally and without any assistance. The rate of the process does not affect its spontaneity; instead, spontaneity is determined by the change in free energy that occurs during the reaction.A reaction is spontaneous if the Gibbs free energy of the reaction is negative (∆G < 0). Gibbs free energy is calculated using the equation: ∆G = ∆H - T∆S, where ∆H is the enthalpy change, T is the temperature, and ∆S is the entropy change of the reaction.A reaction that is endothermic (∆H > 0) and has an increase in entropy (∆S > 0) can be spontaneous at any temperature if the free energy change is negative. As a result, the given statement "A reaction which is endothermic and has an overall increase in entropy is spontaneous only at high T" is incorrect.

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A sample of gas has a volume of 2.50 L at 236 kPa and 75.0 °C. What
is the pressure (in atm) of the gas if it expands to 3.75 L at 25.0 °C?

Answers

If a sample of gas has a volume of 2.50 L at 236 kPa and 75.0 °C, the pressure 1.18 atm is required.

Only ideal gas is subject to the ideal gas law; vanderwaal gas is not. Here, Boyle's and Charles' gas laws are combined. As a result, the new gas pressure is 1.18 atm.

The relation between Pressure, volume, and temperature can be given as:

PV = nRT

In which:

P = pressure of  gas

V= volume of gas

n =number of moles of gas

T =temperature of gas

R = Gas constant

= 0.0821 L.atm/K.mol

Combining Boyle's and Charles' gas law

P₁V₁/T₁ = P₂V₂/T₂

{ (5.28atm) (2.50 L)} ÷348 K ={ (P2) (3.75 L)} ÷298 K

P₂ =1.18 atm

Thus, the new pressure of gas is 1.18 atm when the temperature is changed to 348K and volume is increased to 3.75 L.

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Which element is oxidized in the reaction below?
Fe(CO)5 (l) + 2HI (g) →Fe(CO)4I2 (s) + CO (g) + H2(g)
The answer is Fe...but I'm messing up on setting up my oxidationcharges. Can someone clearly explain how to do this?

Answers

The element that is oxidized in the reaction Fe(CO)5 (l) + 2HI (g) → Fe(CO)4I2 (s) + CO (g) + H2(g) is iron (Fe). When determining the oxidation state of iron (Fe), we use the rule that the oxidation state of a monatomic ion is equal to its charge.

The oxidation state of Fe in Fe(CO)5 is zero. In Fe(CO)4I2, the oxidation state of Fe is +2. So, Fe is oxidized in the reaction.Balancing the redox reaction:Fe(CO)5 (l) + 2HI (g) → Fe(CO)4I2 (s) + CO (g) + H2(g)The oxidation half-reaction is:Fe(CO)5 (l) → Fe(CO)4I2 (s) + I- (aq)The reduction half-reaction is:2H+ (aq) + 2e- → H2 (g)By adding both half-reactions, the balanced redox reaction is:Fe(CO)5 (l) + 2HI (g) → Fe(CO)4I2 (s) + CO (g) + H2(g)The oxidation half-reaction shows that iron (Fe) has lost electrons, thereby being oxidized.

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if the initial concentration of ab is 0.260 m , and the reaction mixture initially contains no products, what are the concentrations of a and b after 80 s

Answers

The concentration of A and B after 80 s  if the initial concentration of ab is 0.260 m, and the reaction mixture initially contains no products is 0.0091 M.

To find the concentrations of A and B after 80 s, we must write the kinetic data is given as follows for the reaction:

AB ⟶ A + B

Initial rate of the reaction is 1.62 x 10⁻³ mol/L/s

Order of reaction for AB is first order (n = 1). Now, using the first-order rate equation, the concentration of AB at time t, [AB]t can be calculated as follows:

ln [AB]0/[AB]t = k

tHere, [AB]0 is the initial concentration of AB, [AB]t is the concentration of AB at time t, k is the rate constant, and t is the time interval.

To determine the rate constant, we can use the initial rate of reaction.

Initial rate, ri = k[AB]n

Here, n is the order of reaction.

So, k = ri/[AB]n

Substituting the given values:

ri = 1.62 x 10⁻³ mol/L/s[AB]0

= 0.260 mk = ri/[AB]n

= 1.62 x 10⁻³ mol/L/s / (0.260 m)1

= 6.23 s-1

Now, we can use the rate constant to determine the concentration of AB at 80 seconds:

ln [AB]0/[AB]80 = kt

Here, k = 6.23 s-1, [AB]0 = 0.260 m, and t = 80 s.

Substituting the values:

ln (0.260 m)/[AB]80

= (6.23 s-1) (80 s)[AB]80

= [AB]0 e-kt

= (0.260 m) e-(6.23 s-1) (80 s)

= 0.0091 m

Now, since the stoichiometry of the reaction is 1:1, the concentration of A and B will be equal to each other. Therefore, [A]80 = [B]80 = 0.0091 m.

Thus, the final concentrations of A and B are 0.0091 M after 80 seconds.

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22 Determine the molar mass of an unknown gas that has a volume of 72.5 mL at a temperature of 68C, and a pressure of 0.980 atm and a mass of 0.207 g.

Answers

Answer:

81.5g/mol

Explanation:

Molar mass is the ratio between mass of a substance (In this case, 0.207g) and moles presents in this mass.

To solve this question we must find the moles of the gas in order to obtain the molar mass using:

PV = nRT

PV / RT = n

Where P is pressure = 0.980atm

V is volume in Liters = 0.0725L

R is gas constant = 0.082atmL/molK

T is absolute temperature = 68°C + 273.15 = 341.15K

0.980atm*0.0725L / 0.082atmL/molK*341.15K = n

2.54x10⁻³ moles = n

Thus, the molar mass of the gas is:

0.207g / 2.54x10⁻³ moles

81.5g/mol

HELP PLEASE!!!!!!!!!!!!

Answers

Answer:

it is a practical question..ASAP

A chalice contains a 2.01M solution of ammonium chlorite in 2.36 liters of solvent - calculate the number of moles.

Answers

Answer:

4.74 mol

Explanation:

Molarity = [tex]\frac{mol}{L}[/tex]

2.01 M = [tex]\frac{mol}{2.36 L}[/tex]

(2.01 M)(2.36 L) = 4.74 mol

calculate the molar solubility of baso4 in a 0.250 m solution of nahso4? ka for hso4- = 1.2 x 10-2.

Answers

The required answer for the molar solubility of BaSO4 in a 0.250 M solution of NaHSO4 is 1.05 × 10-5 M.

Explanation: Molar solubility is defined as the number of moles of a solute that can dissolve per liter of solution before the solution becomes saturated. It can be determined by calculating the equilibrium concentration of the solute using the solubility product expression for the given ionic compound, BaSO4. We are given the concentration of NaHSO4 and the acid dissociation constant for HSO4-.

The balanced chemical equation is:BaSO4(s) ↔ Ba2+(aq) + SO42-(aq)We are assuming the solution is dilute and that the ionic strength is low. Therefore, we can simplify the expression for the solubility product to:Ksp = [Ba2+][SO42-]The expression for the acid dissociation constant of HSO4- is:Ka = [H+][SO42-]/[HSO4-]

The first step is to calculate the concentration of HSO4-. We can use the equilibrium expression for the acid dissociation reaction to solve for [HSO4-]:Ka = [H+][SO42-]/[HSO4-]Rearranging the expression and solving for [HSO4-]:[HSO4-] = [H+][SO42-]/Ka[HSO4-] = (0.250 × x)/(1.2 × 10-2)[HSO4-] = 20.8333 × xThe molar solubility of BaSO4 in a 0.250 M solution of NaHSO4 is x. At equilibrium, the concentration of Ba2+ and SO42- are both x. Using the solubility product expression:Ksp = [Ba2+][SO42-]Ksp = x2x = sqrt(Ksp)[BaSO4] = x = sqrt(Ksp) = sqrt(1.1 × 10-10) = 1.05 × 10-5 MTherefore, the molar solubility of BaSO4 in a 0.250 M solution of NaHSO4 is 1.05 × 10-5 M.

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A map that includes the number of sunny days in South America would be used to study what​

Answers

Answer:

the tables below pull together numbers on the amount of sunshine that each US state usually has a year. there's information by state on the annual average dor percent, hours and days of sun

A map that includes the number of sunny days in South America would be used to study the total amount of sunlight the country receives.

What is a map?

A map is a symbolic depiction emphasizing relationships between elements of some space, such as objects, regions, or themes.

Many maps are static, fixed to paper or some other durable medium, while others are dynamic or interactive. Although most commonly used to depict geography, maps may represent any space, real or fictional, without regard to context or scale, such as in brain mapping, DNA mapping, or computer network topology mapping.

The space being mapped may be two dimensional, such as the surface of the earth, three dimensional, such as the interior of the earth, or even more abstract spaces of any dimension, such as arise in modeling phenomena having many independent variables.

Although the earliest maps known are of the heavens, geographic maps of territory have a very long tradition and exist from ancient times.

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