Answer:
solid to gas or gas to liquid
Explanation:
welcome
Answer:
solid to gas or gas to liquid
Explanation:
Edge
What is the best way to dress for an outdoor trip in cold weather?
A. Wear several thin layers and a waterproof top layer.
B. Wear two layers of heavy clothing and a waterproof jacket.
C. Wear dark colors for insulation.
D. Wear only cotton clothing.
Answer:
A: wear several thin layers and a waterproof top layer
Explanation:
The most common cause of hypothermia is getting wet. Wet clothes combined with wind can pull heat away from the body very quickly. Wool is a good insulator even when it is wet, but wet cotton will bolster heat loss. When dressing for cold weather, put on several thin layers, rather than one or two heavy ones, and top with windproof and waterproof outer layers.
The best way to dress for an outdoor trip in cold weather is to wear several thin layers and a waterproof top layer, the correct option is A.
What is insulation?Insulation is a type of material used to create barriers to the transmission of the form of energy which either is in form of heat or electricity.
For outdoor trips in cold weather, several thin layers act as better insulating barriers for heat transfer.
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what causes the air to move?
Answer:
Movement of air caused by temperature or pressure differences is wind.
Explanation:
This is due to the rotation of the Earth beneath the moving air, which causes an apparent deflection of the wind to the right in the northern hemisphere, and left in the southern hemisphere.
Answer:
Air moves because of wind
Explanation:
Air moves due to a difference of air pressure which can be caused by different temperatures. Air pressure is the push caused by the particles in the air. Hope this helps
Who is son of nation
Explanation:
well the father of nation is Mahtma Gandhi.
An underwater mountain system formed by diverging oceanic plates is______
Mid-Ocean Ridges
Mountain Formation
Boundary Type That Create Mountain
Divergent Boundary
Answer:
Mid-Ocean Ridges
Explanation:
The mid-ocean ridges is an underwater mountain system formed by diverging oceanic plates.
This mid - ocean ridge is one of the prominent land mass on the earth surface. At a diverging center, two tectonic plates are pulling apart from one another. This creates a space which allows for magma to rise up. The magma then crystallize to form an extensive ridge network known as the mid - oceanic ridge. The continental expression of the ridge can only be found in IcelandWhat is the gravitational force between two identical 50,000 kg asteroids whose centers of mass are separated by 1000 m?
Answer:
The gravitational force between the two masses is 1.668575 × 10⁻¹¹ N
Explanation:
The given parameters are;
The mass of the two asteroids having gravitational attraction, are m₁ = m₂ = m = 50,000 kg
The separation distance between their centers, r = 1,000 m
The gravitational attraction force, F, between the two masses is given as follows;
[tex]F =G\dfrac{m_{1}m_{2}}{r^{2}}[/tex]
Where;
G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²
m₁ = m₂ = m
Substituting the values gives;
[tex]F =6.67430 \times 10^{-11} \times \dfrac{50,000 \times 50,000}{1000^{2}} = 1.668575 \times 10^{-7} \ N[/tex]
The gravitational force, F, between the two masses = 1.668575 × 10⁻¹¹ N.
The gravitational force between the two identical asteroids is 1.67 × 10⁻⁷ Newton.
Given the data in the question
Since the asteroids are identical
Mass of the asteroids; [tex]m_1 = m_2 = 50000kg[/tex]Distance between the centers of the masses; [tex]r = 1000m[/tex]Gravitational force; [tex]F =\ ?[/tex]
To determine the gravitational force between two identical asteroids, we use the Newton's law of universal gravitation:
[tex]F = G\frac{m_1m_2}{r^2}[/tex]
Where [tex]m_1[/tex] is mass of object 1, [tex]m_2[/tex] is mass of object 2, r is the distance between centers of the masses and G is the Gravitational constant ( [tex]6.67408 * 10^{-11} m^3/kgs^2[/tex] )
We substitute our values into the equation
[tex]F = (6.67408 * 10^{-11} m^3/kgs^2) \frac{50000kg*50000kg}{(1000m)^2} \\\\F = \frac{0.166852kgm^3/s^2}{1000000m^2}\\\\ F = 1.67 * 10^{-7}kg.m/s^2\\\\F = 1.67 * 10^{-7}N[/tex]
Therefore, the gravitational force between the two identical asteroids is 1.67 × 10⁻⁷ Newton.
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Having good etiquette and sports ethics will make you a more respected player.
Answer:
this is true
Explanation:
just did the it on edg 2020
Answer:
True
Explanation:
what is the process of subduction
Answer:
Subduction is a geological process that takes place at convergent boundaries of tectonic plates where one plate moves under another and is forced to sink due to high gravitational potential energy into the mantle. Regions where this process occurs are known as subduction zones.
Which type of heating system includes fans to circulate warm air?
(DIsclaimer: Unless you have an explanation on how you got your answer, don't bother awnesering.)
A. Radiant heating
B. Electric baseboard heating
C. Forced-air heating
D. Hot water heating
Answer:
C.Forced air
Explanation:
HVAC system
"By far the most common HVAC system in modern North American homes is the forced-air system that uses a furnace with a blower fan that delivers warmed air to the various rooms of the home through a network of ducts."
So can you please mark me brainliest?
What part of the plant takes in carbon dioxide?
1.Roots
2.Stomata
3.Minerals
4.Soil
The answer is number 2 stomata.
Equations of Motion 2D - Will mark the brainliest
A cannon on horizontal ground, at point C, is used to target a point T 25m behind a narrow wall. Unfortunately the cannon is damaged and can only fire at a 45 ∘ angle and at one speed.
a. If the cannonball leaves the cannon at u =35ms −1 at what distance d must the cannon be placed in front of the wall in order to hit the target, if the wall is ignored and the target is at the same height as the cannon
b. The wall is 15.0m high. Does the cannonball actually go over the wall and hit the target? If so, by how much?
Answer:
Using the range formula S = V^2 * sin 2 theta / g
So the cannonball should travel
S = 35^2 * sin 90 / 9.8 = 125 m
Then the cannon should be placed 100 m from the wall
H = Vy t - 1/2 g t^2 height of cannonball after time t
Vy = 35 * sin 45 = 24.7 m/s vertical speed of cannonball
Vx = 35 * cos 45 = 24.7 m/s
t = 100 m / 24,7 m/s = 4.04 sec time for cannonball to reach wall
H = Vy t - 1/2 g t^2 height of cannonball after time t
H = 24.7 * 4.04 - 1/2 * 9.8 * 4.04^2 = 19.8 m
19.8 m - 15 m = 4.8 m cannonball clears wall by 4.8 m
The projectile launch ratios allow to find the results on the cannonball launch questions are:
a) The canyon is at x = 100 m from the wall.
b) The bullet hits the wall at a height of 4.8 m above the height of the wall.
Projectile launching is an application of kinematics where there is no acceleration on the x-axis and the y-axis is gravity acceleration.
A) Indicate that the initial speed of the bullet is v = 35 m/s with an angle θ=45º, which is the distance from the wall. The target is 25 m behind the wall, in the attachment we have a scheme of the system.
Let's find the range that is the horizontal distance for which the height is zero.
[tex]R = \frac{v_p^2 \ sin \ 2\theta}{g}[/tex]
Let's calculate.
R = [tex]\frac{35^2 \ sin ( 2 45(}{9.8}[/tex]
R = 125 m
Therefore the canonl must be 100 m from the wall.
B) The height of the wall is y = 15m, the blah manages to pass it and by how much.
We use trigonometry to find the components of velocity.
v₀ₓ = v₀ cos θ
[tex]v_{oy}[/tex] = v₀ sin θ
v₀ₓ = 34 cos 45 = 24.7 m / s
[tex]v_{oy}[/tex] = vo sin 45 = 24.7 m / s
Let's find the time it takes for the cannonball to travel the x = 100 m
[tex]v_x = \frac{x}{t} \\ t = \frac{x}{v_x}[/tex]
t = [tex]\frac{100}{35 \ cos 45 }[/tex]
t = 4.04 s
Let's find the height for this time.
y = [tex]v_[oy}[/tex] t - ½ g t²
Let's calculate
y = 24.7 4.04 - ½ 9.8 4.04²
y = 19.8 m
This height is greater than the height of the wall h = 15m, therefore the cannoball passes the wall, by a difference in height.
Δy = y -h
Δy = 19.8-15
Δy = 4.8 m
In conclusion, using the projectile launch ratios we can find the results on the cannonball launch questions are:
a) The canyon is at x = 100 m from the wall.
b) The cannonball hits the wall at a height of 4.8m above the height of the wall.
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After 20 seconds, a 200-kg object increases its velocity from 15 m/s to 40 m/s. Determine the impulse applied to the object. (Also show your work so I can understand it better and ty)
Answer:
Imp_{1-2}=5000[kg*m/s]
Explanation:
In order to solve this problem, we must use the principle of conservation of momentum, which is defined as the product of mass by Velocity.
It must be defined that the impulse after the force is applied is equal to the momentum before the impulse applied on the body.
ΣPbefore = ΣPafter
P = momentum = m*v [kg*m/s]
In this way, we will construct the following equation.
[tex](m_{1}*v_{1})+ Imp_{1-2}=(m_{1}*v_{2})[/tex]
where:
m₁ = mass of the object = 200 [kg]
v₁ = velocity of the object before the impulse = 15 [m/s]
v₂ = velocity of the object after the impulse = 40 [m/s]
Now replacing:
[tex](200*15) + Imp_{1-2} = (200*40)\\Imp_{1-2}=5000[kg*m/s][/tex]
Andy took a bus and then walked from his home to downtown. For the
first 1.6 hour, the bus drove at an average speed of 15 km/h. For the
next 0.4 hours, he walked at an average speed of 4.5 km/h. What was
the average speed for the whole journey?
Answer:
Av = 12.9 [km/h]
Explanation:
We must remember that the average speed is defined as the relationship between the space traveled over a certain time.
[tex]Av = x/t[/tex]
where:
Av = average speed [km/h]
x = distance [km]
t = time [hr]
For when he was on the bus
The distance can be calculated by clearing the equation, for the term of the distance
[tex]x_{1}= A_{v}*t\\x_{1}= 15*1.6\\x_{1}=24[km][/tex]
For when Andy was walking
[tex]x_{2}=A_{v}*t\\x_{2}=4.5*0.4\\x_{2}=1.8 [km][/tex]
Now the total time is the sum of 1.6 + 0.4 = 2 [hr], and the total distance is the sum of the distances calculated above.
[tex]x = 24 + 1.8\\x = 25.8 [km][/tex]
The average speed is calculated using the ratio of space to time.
[tex]Av = 25.8/2\\Av = 12.9 [km/h][/tex]
Define Continental Drift
Answer:
the gradual movement of the continents across the earth's surface through geological time.
Answer:
Continental drift is the hypothesis that the Earth's continents have moved over geologic time relatives to each other.
what is the significance of second law of thermodynamics
Answer: Second law of thermodynamics is very important because it talks about entropy and 'entropy dictates whether or not a process or a reaction is going to be spontaneous'.
Explanation:
A map of earthquakes and volcanoes on Earth shows that they do not occur in evenly distributed areas, but they also do not occur randomly over Earth's surface. Describe what GPS measurements show about the distribution of locations where earthquakes and volcanoes occur.
Determine the momentum of a 25kg freshman football player moving southward at 2m/s.
Answer:
50 kg*m/s southward
Explanation:
p=mv
=25kg(2m/s)
=50 kg*m/s
a 110 volt wall outlet supplies power to a stereo with a resistance of 10 ohms. how much current is flowing through the stereo?
Answer:
look in internet u can find online converter and there u will get a rel answer
Explanation:
Pls help, I have a test on this, with explanation.
Answer:
the answer is B
Explanation:
we assume that all of these springs have tha same k , the spring constant
elastic energy for the initial system = Ep1= [tex]\frac{kd^{2} }{2}[/tex]
for the new changed system , the spring constant = k1+k2 = k+k = 2k , but the displacement is also reduced to 0.5 d
so Ep2 = [tex]\frac{2k(0.5d)^{2} }{2} = \frac{kd^2}{4}[/tex]
so the new total Ep stored in the new system is 1/2Ep
hope it helps
A shopper walks westward 2.8 meters in the first 5 minutes and then eastward 9.2 meters in the next 10 minutes. What is the shopper's total travel distance?
Answer:
12m
Explanation:
Given parameters:
Distance walked westward = 2.8m
Time of travel = 5min
Distance walked eastward = 9.2m
Time of travel = 10min
Unknown:
The total shopper's travel distance = ?
Solution:
Total distance traveled is the sum of the length of path covered by a body. It is a scalar quantity.
Total distance = distance walked westward + distance walked eastward
Total distance = 2.8m + 9.2m = 12m
A small first-aid kit is dropped by a rock climber who is descending steadily at -1.25 m/s. After 2.5 seconds, what is the velocity of the first aid kit and how far is the kit below the climber?
4. A car, initially traveling east with a speed of
5.0 m/s, is accelerated uniformly at 2.0 m/s2 east for
10 s along a straight line. During this 10 s
interval the car travels a total distance of
A. 50 m
B. 60 m
C. 100 m
✓ D. 150 m
Answer:
150 m
Explanation:
Given,
u=5m/s
a=2m/s2
t=10s
v=?
s=?
Now,
v=u+at
=5+2×10
=5+20
=25m/s
So,
s=u+v/2×t
=5+25/2×10
=30/2×10
=15×10
=150m
Write a letter to a Friend congratulating her / him for her excellent result in annual examination. class 5 the
Answer:
ok will do that
Explanation:
Which of the following concerning thermal energy flow be correct?
Heat would flow from a hot cup of coffee to a room temperature table.
Heat would flow from a cold glass of lemonade to your hand.
Heat would flow from an ice cube to your hand.
Heat would flow from your hand to a hot cup of coffee.
Answer:
Heat would flow from a hot cup of coffee to a room temperature table.
Explanation:
Thermal energy will flow from a hot cup of coffee to a room temperature table.
Heat is a form of thermal energy which is the average kinetic energy of the particles of system.
Typically heat flows from a place system at high temperature to one with a low temperature. Heat never flows from a cold to a hot bodyHeat moves from a hot to a cold body in a system.How much net force is required to accelerate a 6 kg toy car initially at rest to a velocity of 2m/s in 4s?
Answer:
3N
Explanation:
Given parameters:
Mass of toy car = 6kg
Initial velocity = 0m/s
Final velocity = 2m/s
Time = 4s
Unknown:
Net force = ?
Solution:
The net force is given by;
Force = mass x acceleration;
Force = mass x [tex]\frac{v - u}{t}[/tex]
v is the final velocity
u is the initial velocity
t is the time taken
Now insert the parameters and solve;
Force = 6 x [tex]\frac{2 - 0}{4}[/tex] = 3N
If your problem 50 joules of work lifting a 10 - box from to a shelf how high is the segregation
Answer:
5m
Explanation:
Given parameters:
Work done in lifting the box = 50J
Force applied = 10N
Unknown:
Height of lifting the box = ?
Solution:
Work done is the produce of force and distance;
Work done = Force x distance
Now to find the height;
Work done = Force x height;
50 = 10 x h
h = 5m
A balloon-powered car rolls across the floor at a speed of 0.711 m/s. How long does it take to cover 8.25 m?
Answer:
11.6 seconds
Explanation:
8.25/0.711=11.6
What would take more work: a 10 kg bowling ball lifted 1 meter off the ground, or a 1 kg laptop lifted 10 meter off the ground? Explain how you arrived at your answer. PLEASE HELP!!!!!!!!!! 50 POINTSSSSS
Answer:
10kg ball
Explanation:
a laptop is a lot less in weight so you have to use less force to lift it
Answer:
10 kg bowling ball
Explanation:
A h e m.
It would be easy to lift 1kg laptop 20 meters without breaking a sweat and would be less than your body weight. But a 10kg bowling ball is that x10 so its heavier
A physics student swings a tennis ball connected to a rope in a vertical circle with a constant speed of 6.29 m/s. The ball has a period of 0.5 seconds. Determine the length of the rope (the radius of the circle.
Answer:
r = 0.5 m
Explanation:
First we find the angular speed of the ball by using its period:
ω = θ/t
For the time period:
ω = angular speed = ?
θ = angular displacement = 2π rad
t = time period = 0.5 s
Therefore,
ω = 2π rad/0.5 s
ω = 12.56 rad/s
Now, for the radius:
v = rω
r = v/ω
where,
v = linear speed = 6.29 m/s
r = radius = ?
r = (6.29 m/s)/(12.56 rad/s)
r = 0.5 m
The table shows the diameters of four different types of electrical wire. If the
resistance of the four wires is ranked from highest to lowest, how does the
resistance of a wire used to power clothes dryers rank?
Resistance of a wire used to power clothes dryers rank comes out to be Third. Therefore the correct answer is D.
What is resistance?
Resistance is the obstruction of electrons in an electrically conducting material.
The mathematical relation for variation in resistance with length is given by
R = ρ*L/A
where r is resistance
ρ is the resistivity constant for
L is the length of the wire
A is an area of the cross-section for the wire
From the above relation that resistance is inversely proportional to the area of the wire keeping other parameters constant.
Resistance of a wire used to power clothes dryers rank comes out to be Third. Therefore the correct answer is D.
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An 856 kg drag race car accelerates from rest to 105 km/h in .934s. What change in momentum does the force produce? Answer in units of kg • m/s
Part 2: what average force is exerted on the car? Answer in N
Hello!
Topic: Dinamic
Value to calculate: Force
First, we have to calculate the aceleration, for that, lets aplicate the formula:
[tex]\boxed{a=\frac{V-Vi}{t} }[/tex]
How the final velocity is in km/h, we have to convert it on m/s, so:
m/s = km/h / 3,6
m/s = 105 / 3,6
m/s = 29,16
Then, lets replace formula according problem information:
[tex]a = \dfrac{29,16m/s-0m/s}{0,934s}[/tex]
[tex]a =31,22\ m/s^{2}[/tex]
Now, how we have the aceleration, lets applicate second law of newton for calculate the force produced:
[tex]\boxed{F=ma}[/tex]
Replace and resolve it:
F = 856 kg * 31,22 m/s^2
F = 26724,32 kg * m/s^2
Then the force is of 26724,32 kg * m/s^2
But how we know an 1 kg * m/s^2 = 1 N
Then the average of the force is of 26724,32 N
(1) The change in momentum of race car is 89880 kg-km/h.
(2) The average force exerted on the car is of 96231.26 N.
Given data:
The mass of race car is, m = 856 kg.
The initial speed of car is, u = 0 km/h.
The final speed of car is, v = 105 km/h.
The time interval is, t = 0.934 s.
1)
The change in the impact due to average force is known as momentum change. The expression for the change in momentum is given as follows,
[tex]\Delta P = m(v-u)[/tex]
Solving as,
[tex]\Delta P = 856 \times (105-0)\\\\\Delta P = 89880 \;\rm kg.km/h[/tex]
Thus, we can conclude that the change in momentum of race car is 89880 kg-km/h.
2)
Now, use the concept of impulse-momentum which says that the impulse is equal to change in momentum. Which means,
[tex]I = \Delta P[/tex]
And impulse is,
[tex]F \times t = \Delta P\\\\F = \dfrac{\Delta P}{t}[/tex]
Solving as,
[tex]F = \dfrac{89880}{0.934}\\\\F = 96231.26 \;\rm N[/tex]
Thus, we can conclude that the average force exerted on the car is of 96231.26 N.
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