Identify a segment parallel to segment ZY

the answer is 35 I did a lot of work I can't show you here

Answer:

#2. 6x3.14=1080 which is more than 18

Answer:

A. A triangle can be equilateral and obtuse at the same time

Step-by-step explanation:

All angles in an equilateral triangle are 60° therefore they cannot be above 90° and less than 180°

Answer:

A) 9/2x3/8

Step-by-step explanation:

Answer: k = 8

Step-by-step explanation:

-3k + 30 = 6

-3k = -24

k = 8

Answer:

k = 8

Step-by-step explanation:

6 = -3(k - 10)

Divide each side by -3

6/-3 = -3/-3 *(k - 10)

-2 = k-10

Add 10 to each side

-2+10 = k-10+10

8 = k

Answer:

27.5

Step-by-step explanation:

Answer:

Step-by-step explanation:

110/4 is 27.5

Answer:

[tex]y = \frac{2}{z} - \frac{x}{z}[/tex]

Step-by-step explanation:

Given

[tex]x + zy = 2[/tex]

Required

Rewrite to show y-intercept

We have: [tex]x + zy = 2[/tex]

Subtract x from both sides

[tex]zy = 2-x[/tex]

Divide both sides by z

[tex]y = \frac{2}{z} - \frac{x}{z}[/tex]

The y intercet is: [tex]\frac{2}{z}[/tex]

9514 1404 393

Answer:

  4. (d) 4.38 in³

  5. (b) 19 gallons

  6. (a) 6.4 yd³

Step-by-step explanation:

4. The equation can be rearranged to find the compressed volume.

Multiply both sides by the compressed volume:

  (compression ratio)×(compressed volume) = (expanded volume)

Divide both sides by the compression ratio:

  (compressed volume) = (expanded volume)/(compression ratio)

Fill in the numbers and do the arithmetic.

  compressed volume = 46.0 in³/(10.5/1) = 4.38 in³

The compressed volume is about 4.38 in³.

__

5. The area to be covered is 3170 ft². We want to cover it twice, so the total area we want to cover is 2×3170 ft² = 6340 ft². One gallon of paint covers 350 ft². We want to find the smallest integer number of gallons n such that ...

  n×(350 ft²) ≥ 6340 ft²

Dividing by the coefficient of n, we have ...

  n ≥ 6340/350 ≈ 18.11

The smallest integer value of n is 19. 19 gallons of paint will be needed.

__

6. The quantity of sand needed (q) is proportional to the area to be covered, so we have ...

  q/(400 yd²) = (1.6 yd³)/(100 yd²)

Multiplying both sides of this equation by 400 yd² gives ...

  q = (1.6 yd³)(400/100) = 6.4 yd³

6.4 yd³ of sand will be needed.

Answer:

[tex]f(x) = \frac{10}{x} - 4 \\ \delta \: f(x) = \frac{f(8) - f(2)}{2} \\ = \frac{(\frac{10}{8} - 4) - ( \frac{10}{2} - 4)}{2} \\ = \frac{ \frac{ - 11}{4} - 1}{2} \\ = \frac{ \frac{ - 15}{4} }{2} \\ = - \frac{15}{8} [/tex]

Answer:

C. 13 gallons

Step-by-step explanation:

150 divided by 6 is 25. 325 divided by 25 is 13.

To travel 325 miles the van needs C. 13 gallons of gas.

A unitary method is a mathematical way of obtaining the value of a single unit and then deriving any no. of given units by multiplying it with the single unit.

Given, A van travels 150 miles on 6 gallons of gas.

So, In one gallon the van travels (150/6) = 25 miles.

∴ To travel 325 miles the van needs (325/25) = 13 gallons of gas.

learn more about the unitary method here :

https://brainly.com/question/28276953

#SPJ2

Answer:

Can you insert a picture?  and then I could help you.

Step-by-step explanation:

Answer:

Brianne would earn 5 dollars an hour so the graph should look something like this.

Answer:

Step-by-step explanation:

I dont know how to do the box thing, but I added all the things and boys read more.

girls:1870

boys:1952

The diffrence (when subracting) is 82

Answer:

45.584

;)

Have a nice day

Answer: The answer would be y = x + 8

Step-by-step explanation:

Given:

Consider the rule of a sequence is:

[tex]T_n=\dfrac{n^2-n}{2}[/tex]

To find:

The 6th term generated by the given rule.

Solution:

We have,

[tex]T_n=\dfrac{n^2-n}{2}[/tex]

Substituting [tex]n=6[/tex] in the above rule, we get

[tex]T_6=\dfrac{6^2-6}{2}[/tex]

[tex]T_6=\dfrac{36-6}{2}[/tex]

[tex]T_6=\dfrac{30}{2}[/tex]

[tex]T_6=15[/tex]

Therefore, the 6th term generated by the given rule is 15.

Answer:

third

Step-by-step explanation:

arctan of ( opp/adj) = arctan( 10/15 )

the shadow is 15 so 10 must be the height of the streetlight and

arctan (10/15) is the angle between the ground and the line from the edge of the shadow to the top of the streetlight

Answer:

M(x)  =  452,56 in

Step-by-step explanation:

The volume of the open box is  500 in³

V = Area of the base times height

V(b) =  x² * h               where x is the side of the square and h the heigh

Then     500 =  x²*h

Total material to use is: material of the base + material of 4 sides

material of the base is  x²

material of one side is x*h  we have 4 sides then  4*x*h

Total material M(b)

M(b)  =  x²  +  4*x*h

And    as    h  =  500/ x²

M(x)  =  x²  +  4* x* 500/x²

M(x)  =  x²  +  2000/x

Tacking derivatives on both sides of the equation

M´(x)  =  2*x   - 200/x²

M´(x)  =  0         2*x  -  200/x²  = 0

x³ -  100  =  0

x³   =  100

x   =  4,64 in

And By substitution     h  =  500/x²

h  =  500/(4,64)²           h  =  23,22  in

How do we know that x = 4,64 make V(x) minimum

we get the second derivative

M´´(x)  =  2  +  200*2x/ x⁴    =  2  +  400/x³

M´´(x) is always positive

M´´(x) > 0     then M(x) has a minimum for  x= 4,64 in

The least amount of material is:

M(x)  =  x²    +    2000/x

M(x)  =  (4,64)²  *  2000/4,64

M(x)  = 21,53  +  431,03

M(x)  =  452,56 in

Answer:

BC = 6.9

Step--step explanation:

Reference angle = 30°

Adjacent = BC

Hypotenuse = 8

Apply trigonometric function, CAH:

Cos 30° = Adj/Hypotenuse

Cos 30° = BC/8

8*Cos 30° = BC

6.92820323 = BC

BC = 6.9 (to the nearest tenth)

Answer:

63%.

Step-by-step explanation:

There are 12 scores below 45 and total number of scores = 19.

So percentile rank= (12/19) * 100

=  63%.

Answer:

B) positive x-axis.

Step-by-step explanation:

angle to be in standard position, its vertex is at the origin and the initial side lies along the positive x axis

Answer:

Positive x axis

Step-by-step explanation:

The angle lies in standard position means it begins from Q1

The first side must be x axis

Then in Q1 x>0 so it's positive x axis

Hello there I hope you are having a great day :) Cindy has a chocolate box whose length is 12 cm, height of 8 cm, and width of 6 cm. Find the volume of the box?

V = L x W x H

Volume = length x Width x Height.

12cm x 6cm x 8cm = V = 576cm^3

so the answer is 576cm^3

Hopefully that helps you :)

Step-by-step explanation:

VOLUME : is the quality of three deamination place enclosed by a closed surface it is the space that substance or shape or keep use or contains it is measured in cubic units

A RACTANGULAR :is a three dimensional figure it has length wind and height

let us analysis the problem above

length =12 cm

height = 8 cm

width=6 cm

v=1 x w x h

=(12 CM) x (8 CM) x (6 CM)

the value of the box is 576 CM ³

Answer:

104 softballs

Step-by-step explanation:

26 x 4 = 104

Answer:

Hello! answer: x = 40

Step-by-step explanation:

These are vertical angles meaning they will have the same measure.

40 × 3 = 120 120 - 16 = 104 therefore x = 40 hope that helps!

Answer:

D

Step-by-step explanation:

It is D because there are only 3 sides given. I understand where you were going with B, but there is no angle given, (and you cannot prove one either), so the answer is simply D.

A - There is no angle, triangle does not matter

B - There is no angle, triangle is correct

C - It is similar, they have the same scale factor

D - There are 3 sides, and the triangle is correct

Answer:

Step-by-step explanation:

Cos(A + B) = Cos(A)*Cos(B) - Sin(A)*Sin(B)

Find The Hypotenuse of A

Tan(A) = Opposite / Adjacent

Tan(A) = 15/8

Opposite = 15

Adjacent = 8

Hypotenuse = c

c^2 = opposite^2 + Adjacent^2

c^2 = 15^2 + 8^2

c^2 = 225 + 64

c^2 = 289

sqrt(c^2) = sqrt(289)

c = 17

Find the opposite of B

Adjacent = 12

Hypotenuse = 37

Opposite = b

adjacent^2 + opposite^2 = hypotenuse^2

12^2 + b^2 = 37^2

144 + b^2 = 1369

b^2 = 1369 - 144

b^2 = 1335

b = 35

Definitions

Sin(A) = Opposite / hypotenuse = 15/17

Sin(B) = opposite / hypotenuse =  35/37

Cos(A) = 8/17

Cos(B) = 12/37

Answer

Cos(A + B) = Cos(A)*Cos(B) - Sin(A)*Sin(B)

Cos(A + B) = 8/17 * 12/37 - 15/17*35/37

Cos(A + B) = 96/629 - 525/629

Cos(A + B) = -429/629

Let u = (1, 0) and v = (0, 1). Then

T (u) = (2*1 - 3*0, 1 + 4, 5*0) = (2, 5, 0)

T (v) = (2*0 - 3*1, 0 + 4, 5*1) = (-3, 4, 5)

=>   T (u) + T (v) = (-1, 9, 5)

but

T (u + v) = T (1, 1) = (2*1 - 3*1, 1 + 4, 5*1) = (-1, 5, 5)

=>   T (u + v) ≠ T (u) + T (v)

which means T does not preserve addition, so it is not linear.