Identify the two types of incorrect decisions in a hypothesis test. For each incorrect decision, what symbol is used to represent the probability of making that type of error?
Choose the correct answer below.
A. A Type 1 error is rejecting a true null hypothesis, whose probability is denoted α
A Type Il error is not rejecting a false null hypothesis, whose probability is denoted β
B. A Type 1 error is not accepting a true null hypothesis, whose probability is devoted α
A Type Il error is accepting a false null hypothesis, whose probability is denoted β
C. A Type I error is not rejecting a false null hypothesis, whose probability is denoted α.
A Type Il error is rejecting a true null hypothesis, whose probability is denoted β
D. A Type 1 error is accepting a false null hypothesis, whose probability is denoted α
A Type Il error is not accepting a true null hypothesis, whose probability is denoted β

Answer:

answer is \/

Step-by-step explanation:

Answer:

8

Step-by-step explanation:

0.20 x 40 = 8

Therefore, 20% of 40 is 8

Answer:

The 2009 Nobel Peace Prize was awarded to United States President Barack Obama for his "extraordinary efforts to strengthen international diplomacy and cooperation between people".

Step-by-step explanation:

The 2009 Nobel Peace Prize was awarded to United States President Barack Obama for his "extraordinary efforts to strengthen international diplomacy and cooperation between people".

just the first one 11 ........

The the success rate of the student is PHYS>MATH. Therefore, the correct answer is Option A.

We can calculate the success rate of the student by calculating the z-score of each of the courses. The z-score is calculated as (x-μ)/σ, where x is the individual score, μ is the mean of the data, and σ is the standard deviation of the data.

For Physics, we have x=60, μ=49, and σ=11. So the z-score is (60-49)/11=1.09.

For Mathematics, we have x=58, μ=55, and σ=16. So the z-score is (58-55)/16=0.19.

Since the z-score of Physics is greater than the z-score of Mathematics, the student's success rate in Physics is greater than the student's success rate in Mathematics.

Therefore, the correct answer is Option A.

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Answer:

OMg whats there ikdd im tring

Step-by-step explanation: Im starting to solve it

The height of the rocket is increasing when 0< t < 3 and decreasing when 3 < t < 6.

Option C is correct.

From the graph,

It is observed that , In interval 0< t < 3 , slope of graph is positive. Therefore, the height of the rocket is increasing

It is observed that , In interval 3 < t< 6 , slope of graph is negative. Therefore, the height of the rocket is decreasing.

Therefore, option C is correct.

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The graph is a downward-opening parabola opening downward with its vertex at (2,0). Therefore, the correct option is C.

The equation y = -16t^2 + 64t + 16 represents the path of a projectile launched from a 16-ft-tall tower. To determine the correct graph, we can analyze the equation. The coefficient of t^2 (-16) is negative, indicating a downward-opening parabola. The coefficient of t (64) determines the horizontal shift of the graph, and in this case, t = 4 represents the maximum height of the projectile. The constant term (16) represents the initial height of the tower.

Considering these factors, we find that the correct graph of the equation is option C. It depicts a downward-opening parabola with its vertex at (2,0). The parabola starts at an initial height of 16 ft (the tower's height) and descends symmetrically from its vertex.

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Answer:

Barbados won the Bronze.

Step-by-step explanation:

The information indicates that Jamaica finished before Barbados, but behind Trinidad which means that Trinidad was the first one, then Jamaica and the third one was Barbados:

1. Trinidad

2. Jamaica

3. Barbados

Then, it indicates that Haiti finished before Guyana, but behind Barbados which indicates that Haiti was in 4th place after Barbados and  the last one was Guyana:

1. Trinidad

2. Jamaica

3. Barbados

4. Haiti

5.Guyana

According to this, the answer is that Barbados won the Bronze.

Answer:

80

Step-by-step explanation:

Let the total number of statues be s.  Then 0.75s = 60, and s = (4/3)(60 statues) = 80

He has 80 statues total.

15h - 25 dollars is an expression to describe his spendings and earnings in a day.

Any mathematical statement that includes numbers, variables, and an arithmetic operation between them is known as an expression or algebraic expression. In the phrase 4m + 5, for instance, the terms 4m and 5 are separated from the variable m by the arithmetic sign +.

Peter makes 15 dollars an hour, so if he works for h hours, he earns:

15h dollars

Peter spends 25 dollars a day on transportation and food, so his total spending can be expressed as:

25 dollars

Therefore, his total earnings minus his total spending can be expressed as:

15h - 25 dollars

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Answer:

V = 960 cm^3

Step-by-step explanation:

Volume of a rectangular prism = L * W * H

V = 12 * 8 * 10

V = 960 cm^3

Answer:

d. 960 cm^3

Step-by-step explanation:

The formula for volume is length x width x height. To solve you have to multiply 12 by 8 by 10 to get 960

Answer:

6.2 miles

Step-by-step explanation:

10 kilometers=.62 miles

.62*10= 6.2 miles

The 99% confidence interval of the true mean is given as follows:

8.56 million < μ < 16.78 million.

The t-distribution is used when the standard deviation for the population is not known, and the bounds of the confidence interval are given according to the equation presented as follows:

[tex]\overline{x} \pm t\frac{s}{\sqrt{n}}[/tex]

The variables of the equation are listed as follows:

The critical value, using a t-distribution calculator, for a two-tailed 99% confidence interval, with 10 - 1 = 9 df, is t = 3.2498.

The parameter values for this problem are given as follows:

[tex]\overline{x} = 12.67, s = 4, n = 10[/tex]

The lower bound of the interval is then given as follows:

[tex]12.67 - 3.2498 \times \frac{4}{\sqrt{10}} = 8.56[/tex]

The upper bound of the interval is then given as follows:

[tex]12.67 + 3.2498 \times \frac{4}{\sqrt{10}} = 16.78[/tex]

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None of the options are reducible polynomial

From the question, we have the following parameters that can be used in our computation:

The list of options

The variable Q means rational numbers

So, we can use the rational root theorem to test the options

So, we have

(a) 4x³ + x - 2

Roots = ±(1, 2/1, 2, 4)

Roots = ±(1, 1/4, 2, 1, 1/2)

(b) 3x³ - 6x² + x - 2

Roots = ±(1, 2/1 ,3)

Roots = ±(1, 1/3, 2, 2/3)

(c) 5x³ + 9x² - 3

Roots = ±(1, 3/1 ,5)

Roots = ±(1, 1/5, 3, 3/5)

See that all the roots have rational numbers

And we cannot determine the actual roots of the polynomial.

Hence, none of the options are reducible polynomial

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The difference between the maximum and minimum value of x^2y^3 is determined by finding the product at the extreme values.

Given that two positive numbers x and y with a maximum value of 4 add up to 5, we can solve for the minimum value of x and y. Since the maximum value for x and y is 4, we assume that one number is 4 and the other number is 1, as they add up to 5.

Calculating the product x^2y^3 for these values, we have (4^2)(1^3) = 16. To find the maximum value of x and y, we need to distribute the sum of 5 unevenly between them. By assigning x = 1 and y = 4, we get (1^2)(4^3) = 64.

Therefore, the difference between the maximum and minimum value of x^2y^3 is 64 - 16 = 48.

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The expected number of women in the survey who have group A blood is 48.

To calculate the expected number, we assume that sex and blood type are independent variables. This means that the proportion of women with group A blood would be the same as the proportion of men with group A blood.

Out of 100 men surveyed, 40 had group A blood. This corresponds to a proportion of 40/100 = 0.4.

Since sex and blood type are assumed to be independent, we can assume that the proportion of women with group A blood is also 0.4.

To find the expected number of women with group A blood, we multiply the proportion by the total number of women surveyed:

Expected number of women with group A blood = Proportion of women with group A blood * Total number of women surveyed

Expected number of women with group A blood = 0.4 * 120 = 48

Therefore, the expected number of women in the survey who have group A blood is 48.

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The curvature k(t) of the Eequation r(t) =  (-2sint) i + (-2sint) j + (-cost) k will be [tex]\frac{2\sqrt{2} }{(8cos^2t + sin^2t)^{3/2}}[/tex]

Given r(t) = (-2sint) i + (-2sint) j + (-cost) k

We can clearly see that r(t) is a vector equation of t.

If r(t): R→R³ is a vector-valued function of a real variable with independent scalar output variables x, y & z

where, r(t) = {x, y, z}

Where x = (-2sint) , y = -2sint and z = -cost

We know that the curvature to be

|| r'(t) X r"(t) ||  /  ||r'(t)||³

This implies we need to find the determinant of the cross product of the derivative and double derivative of the equation r(t) for the numerator

r'(t) =  (-2cost) i + (-2cost) j + (sint) k

r"(t) =  (2sint) i + (2sint) j + (cost) k

hence we get || r'(t) X r"(t) || to be

[tex]\left|\begin{array}{ccc}i&j&k\\-2cost&-2cost&sint\\2sint&2sint&cost\end{array}\right|[/tex]

[tex]= \left|\begin{array}{ccc}-2cost&sint\\2sint&cost\end{array}\right| i - \left|\begin{array}{ccc}-2cost&sint\\2sint&cost\end{array}\right|j + \left|\begin{array}{ccc}-2cost&-2cost\\2sint&2sint\end{array}\right|k[/tex]

= -2i + 2j

Hence the magnitude will be

√(2² + 2²)

= 2√2 units

magnitude of r'(t) is

[tex]\sqrt{(2sint)^2 + (2sint)^2 + (cost)^2}[/tex]

= [tex]\sqrt{8cos^2t + sin^2t}[/tex]

Hence we get the curvature to be

[tex]\frac{2\sqrt{2} }{(\sqrt{8cos^2t + sin^2t})^3}[/tex]

simplifying this will give us

[tex]\frac{2\sqrt{2} }{(8cos^2t + sin^2t)^{3/2}}[/tex]

Hence the curvature k(t) will be [tex]\frac{2\sqrt{2} }{(8cos^2t + sin^2t)^{3/2}}[/tex]

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Correct Question

Find the curvature k(t) of the curve r(t) = (-2 sin t)i + (-2 sin t)j + (-1 cost)k

Answer:

Dining Hall = 24 square meters

Kitchen = 48 square meters

Together = 72 square meters

Using the appropriate depreciation table, MACRS 5 years, the total depreciation amount for 2020, assuming the taxpayer opted out of Sec. 179 in the year of purchase and other assumption, is B) $8,640.

Depreciation refers to the gradual expensing of a long-term asset.

Under the MACRS 5 years for a light equipment, the depreciation rate applicable to the second year is 32%.

The cost of the truck = $27,000

Purchase date = April 5, 2019

Depreciation rate = MACRS 5 years

Depreciation rate for the second year under the MACRS 5 years table = 32%

Depreciation amount for 2020 = $8,640 ($27,000 x 32%)

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Answer:

45 minutes

Step-by-step explanation:

1 1/2 hours = 90 minutes

90 - 45 = 45

The statement x > 0 and y < 0 must be true for any point (x, y) located in Quadrant IV.

If the point (x, y) is in Quadrant IV, it means that the x-coordinate is positive and the y-coordinate is negative. In Quadrant IV, the x-values are positive, as they are to the right of the y-axis, and the y-values are negative, as they are below the x-axis.

Therefore, the correct statement is:

x > 0 and y < 0.

In Quadrant IV, the x-values are greater than 0, indicating a positive x-coordinate, and the y-values are less than 0, indicating a negative y-coordinate. This is because in Quadrant IV, the x-axis is to the right of the y-axis, and the y-axis is below the x-axis.

Hence, the statement x > 0 and y < 0 must be true for any point (x, y) located in Quadrant IV.

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The forecasted sales for February through April are as follows:

February: 19.5, March: 25.65, April: 30.755. The forecasted sales for May is approximately 35.928.

Exponential smoothing is a time series forecasting method that assigns weights to past observations, with the weights decreasing exponentially as the observations get older. The smoothed value for a particular period is a weighted average of the previous smoothed value and the actual value for that period.

To calculate the smoothed values and forecast sales using exponential smoothing with α = 0.3, we start with the initial forecast for January, which is given as 18. Then, for February, we use the formula:

Smoothed value (February) = α * Actual sales (February) + (1 - α) * Smoothed value (January)

= 0.3 * 25 + 0.7 * 18 = 19.5

Similarly, for March:

Smoothed value (March) = α * Actual sales (March) + (1 - α) * Smoothed value (February)

= 0.3 * 34 + 0.7 * 19.5 = 25.65

And for April:

Smoothed value (April) = α * Actual sales (April) + (1 - α) * Smoothed value (March)

= 0.3 * 40 + 0.7 * 25.65 = 30.755

Finally, for the forecasted sales in May:

Forecasted sales (May) = Smoothed value (April) = 30.755

Therefore, the forecasted sales for May, using exponential smoothing with α = 0.3, is approximately 35.928.

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Answer:

you fo to the fourth box on there and put - then go to the box after that and put 1

Step-by-step explanation:

sorry if im wrong

Answer:

Maximum, and (0, -2)

Step-by-step explanation:

a. Using intersection of events probability of FUA is 0.0165

b. Using complement rule, the probability of F'UA is 0.9835

To find the probabilities, we can use the given information and apply the appropriate probability rules.

(a) FUA represents the event that the driver is female, 24 years old or less, and is involved in a fatal vehicle accident.

We can calculate this probability using the formula: P(FUA) = P(F ∩ A), where ∩ denotes the intersection of events.

P(FUA) = P(F) * P(A|F)

Given information:

P(F) = 0.2868 (probability that the driver is female)

P(A) = 0.1828 (probability that the driver is 24 years old or less)

P(A|F) = 0.0576 (probability that the driver is 24 years old or less given that the driver is female)

P(FUA) = 0.2868 * 0.0576 ≈ 0.0165

Therefore, the probability of FUA is approximately 0.0165.

(b) F'UA represents the event that the driver is not female, 24 years old or less, and is involved in a fatal vehicle accident.

We can calculate this probability using the complement rule: P(F'UA) = 1 - P(FUA).

P(F'UA) = 1 - P(FUA) ≈ 1 - 0.0165 ≈ 0.9835

Therefore, the probability of F'UA is approximately 0.9835.

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Answer:

6/ y^8

Step-by-step explanation:

Sam has a 4/5 expected value of scoring each time she shoots from the free-throw line.

This means that the probability of her missing her first shot is 1/5. The expected value of the number of free-throws that Sam will score before her first miss is therefore 1/(1/5) = 5.

The variance of the number of free-throws that Sam will score before her first miss is (1−p)/p²

, where p is the probability of success.

In this case, p=4/5, so the variance is (1−4/5)/(4/5)²

=16/25.

= 4/5

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Answer:

Nacho Average Minos

Step-by-step explanation:

z=11.25-10/1.5 = 1.25/1.5 = 0.834

z=11.25-12/1 = -0.75/1 = -0.75