Answers
The question is incomplete,I will complete the question and provide the answer.
Due to the nature of the question,I will sketch an answer/solution to the question and submit it as an attachment.
So you will be having two attachments,
1) The question
2) The solution
From the options given in the first attachment with is the question,the correct answer is option C.
1 AND 2 ARE GOING UP.
Proper explanation using sketch and arrows is given in the second attachment which shows the solution to the question.
Related Questions
A 1150 kg car is on a 8.70° hill.
Using X-Y axes tilted down the
plane, what is the y-component
of the weight?
Answers
Answer:
Explanation:
y-component = - mgcos(8.7)
= - (1150)(9.81)cos(8.7)
= - 11151.69378
= - 11151.69 N
The weight of the y-component is 11140.33N.
How to find the weight of the y-component?
To find the weight of the y-component:
Given,
Car weight = 1150 kg
Anfle = 8.70 degree
weight = mg = 1150 * 9.8
= 11270 N
Y-component = mg cos∅
= 11270 * cos(8.70)
= 11140.33N
The aspect that pushes proper or left is referred to as the x-factor, and the element that pushes up or down is known as the y-component.
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1. When asteroids collided some of the broken materials fall into Earth's orbit. What do
astronomers call the debris when it hits planet Earth?
(2 Points)
meteors
meteoroids
meteorites
metabots
Answers
Before they meet Earth -- meteoroids
While they're falling -- meteors
After they hit the ground -- meteorites
If a 46 kg person walks up two floors in the Physics building (about 10 meters up), this person's potential energy has increased by _____ J.a. 1400 J b. 10,000 J. c. 1000 J. d. 100 J
Answers
Answer:
B. 10000 J
Explanation:
The possible answers are not related to the statement at all. The correct statement is:
If a 100 kg person walks up two floors in the Physics building (about 10 meters up), this person's potential energy has increased by:
From definitions of work and gravitational potential, we get the following formula to calculate the change experimented in the person's potential energy after walking up two floors in the Physics building:
[tex]\Delta U_{g} = m\cdot g \cdot \Delta z[/tex] (1)
Where:
[tex]\Delta U_{g}[/tex] - Change in the gravitational potential energy, measured in joules.
[tex]m[/tex] - Mass of the person, measured in kilograms.
[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.
[tex]\Delta z[/tex] - Change in height, measured in meters.
If we know that [tex]m = 46\,kg[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] and [tex]\Delta z = 10\,m[/tex], then the change in the gravitational potential energy is:
[tex]\Delta U_{g} = (100\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (10\,m)[/tex]
[tex]\Delta U_{g} = 9807\,J[/tex]
The choice that best approximates this answer is B.
An object moves at constant speed in a circle. Which of the following is true:
A. A net force in the direction of motion acts on the object.
B. A net force pointing away from the center of the circle acts on the object.
C. A net force pointing towards the center of the circle acts on the object.
D. The net force acting on the object is zero.
Answers
which state can you infer that average home prices are the highest? Florida California Texas New York
Answers
Answer:
California
Explanation:
just took the test
The state you can infer where average home prices are the highest is California. Option B. This is further explained below.
What is an average home price?Generally, an average home price refers to a cumulative average to the house or home pricing in a state.
In conclusion, California has the highest average home prices highest in America.
Read more about House
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Why are the coral reefs suffering? (site 2) explain
Answers
Answer:
bcuz ov yo fat mamma
Explanation:
Answer:
Water pollution
Explanation:
9. What distance is a book from the floor if the book contains 196 Joules of potential energy and has a mass of 5 kg?
Answers
Answer:
the book is 4 meters from the floor
Explanation:
Use the formula for potential energy:
U = m g h
196 J = 5kg 9.8m/s^2 h
h = 196 / (5*9.8 ) m
h = 4 m
Friction that occurs in gases and liquids is called
Answers
I WILL GIVE BRAILYEST!!! What is the mass of an object moving at a velocity of 5 m/s if the momentum of the object is 50 kg•m/s?
a. 250 kg
c. 10 Kg
b. .002 Kg
d. 45 Kg
Answers
Answer:
a. 250kg I think it's the right answer. hope it helps:)
Answer:
C.10
Explanation:
because when you divide 50 divided by 5 = 10
What is the wavelength of light falling on double slits separated by 2.00 μm if the third-order maximum is at an angle of 60.0∘?
Answers
Answer:
λ = 5.773 x 10⁻⁷ m = 577.3 nm
Explanation:
In order to solve this problem we will use the grating equation:
mλ = d Sin θ
where,
m = order = 3
λ = wavelength of light = ?
d = slit separation = 2 μm = 2 x 10⁻⁶ m
θ = angle = 60°
Therefore,
(3)λ = (2 x 10⁻⁶ m)Sin 60°
λ = 1.732 x 10⁻⁶ m/3
λ = 5.773 x 10⁻⁷ m = 577.3 nm
The particle accelerator at CERN can accelerate an electron through a potential
difference of 80 kilovolts. Calculate
(a) The kinetic energy (in keV) of the electron
Answers
Answer:
K.E = 1.28 × 10^-17 KeV
Explanation:
Given that a particle accelerator at CERN can accelerate an electron through a potentialdifference of 80 kilovolts.
To Calculate the kinetic energy (in keV) of the electron, let us first find the electron charge which is 1.60 × 10^-19C
The kinetic energy = work done
K.E = e × kV
Substitute e and the voltage into the formula
K.E = 1.60 × 10^-19 × 80
K.E = 1.28 × 10^-17 KeV
Therefore, the kinetic energy is approximately equal to 1.28 × 10^-17 KeV
what are the formulae of momentun and their time of use
Answers
Answer:
???????????????????????????
Select all correct answers....Covalent compounds
Answers
Robin would like to shoot an orange in a tree with his bow and arrow. The orange is hanging yf=5.00 myf=5.00 m above the ground. On his first try, Robin looses the arrow at v0=35.0 m/sv0=35.0 m/s at an angle of θ=30.0°θ=30.0° above the horizontal. The arrow has an initial height of y0=1.50 m,y0=1.50 m, and its tip is x=60.0 mx=60.0 m away from the target orange. Treating the arrow as a point projectile and neglecting air resistance, what is the height of the arrow once it has reached the horizontal position xx of the orange? Use g=9.81 m/s2g=9.81 m/s2 for the acceleration due to gravity.
Answers
Answer:
h' = 55.3 m
Explanation:
First, we analyze the horizontal motion of the projectile, to find the time taken by the arrow to reach the orange. Since, air friction is negligible, therefore, the motion shall be uniform:
s = vt
where,
s = horizontal distance between arrow and orange = 60 m
v = initial horizontal speed of the arrow = v₀ Cos θ
θ = launch angle = 30°
v₀ = launch speed = 35 m/s
Therefore,
60 m = (35 m/s)Cos 30° t
t = 60 m/30.31 m/s
t = 1.98 s
Now, we analyze the vertical motion to find the height if arrow at this time. Using second equation of motion:
h = Vi t + (1/2)gt²
where,
Vi = Vertical Component of initial Velocity = v₀ Sin θ = (35 m/s)Sin 30°
Vi = 17.5 m/s
Therefore,
h = (17.5 m/s)(1.98 s) + (1/2)(9.81 m/s²)(1.98 s)²
h = 34.6 m + 19.2 m
h = 53.8 m
since, the arrow initially had a height of y = 1.5 m. Therefore, its final height will be:
h' = h + y
h' = 53.8 m + 1.5 m
h' = 55.3 m
A ball of mass 0.600 kg is carefully balanced on a shelf that is 2.20 m above the ground. What is its gravitational potential energy?
Answers
Answer:
Explanation:
Gravitational potential energy = mass x height of object x g
g is gravitational acceleration .
Gravitational potential energy of the ball = .600 x 2.20 x 9.8
= 12.936 J .
12.9 J .
Mr Jones launches an arrow horizontally at a rate of 40m/s off of a 78.4 m cliff towards the south, how far south does the arrow travel. (Step 2, you need the previous questions answer to answer correctly
a. 118.4 m south
b 1936 m south
C 2 m south
d 640 m south
Answers
Answer:c
Explanation:its the answer because its the answer
giving brainliest to first one who gets this right
Answers
a. Nitrogen, Oxygen,and Carbon Dioxide
hope im right but I dont really know
a pot of water at 20.0ºC is warmed to 100º when 40000cal is added. what is the mass of the water?
Answers
Answer:
500 g
Explanation:
m = Mass of water
c = Specific heat of water = [tex]1\ \text{cal/g}^{\circ}\text{C}[/tex]
[tex]\Delta T[/tex] = Temperature difference = [tex]100-20=80^{\circ}\text{C}[/tex]
Q = Heat added = 40000 cal
Heat is given by
[tex]Q=mc\Delta T\\\Rightarrow m=\dfrac{Q}{c\Delta T}\\\Rightarrow m=\dfrac{40000}{1\times 80}\\\Rightarrow m=500\ \text{g}[/tex]
The mass of water is 500 g.
why is it more painful to walk on gravel with your shoes off then on (3 marks please)
Answers
Answer:
Because shoes protect our feet from some of the most harmful platforms
Gravel has some small pebbles on it sometimes (or other sharp objects)
Gravel is pretty hard.
Mr Johnson launches an arrow horizontally at a rate of 40m/s off of a 78.4 m cliff towards the south, how much time does it take before the arrow hits the ground below (step 1 of a quesiton will need this answer for a future question)
a 2 seconds
b. 1 second
c.4 seconds
d 19.6
Answers
Answer:c
Explanation:
Which statement best describes energy and matter in a closed system? (2 po
O Energy and matter flow into and out of the system.
Energy can flow into and out of the system but matter cannot.
Energy and matter are contained within a closed system.
O There is no energy in a closed system; there is matter.
Answers
Answer:
Energy can flow into and out of the system but matter cannot.
Explanation:
In a closed system, energy can flow in and out of the system but matter cannot.
A closed system prevents double way flow of matter. A closed system conserves matter.For an isolated system, energy and matter cannot flow out of the system.
For open systems, energy and matter can flow out of the system.
Such systems are used for certain thermodynamics experiment.
pls help quick. the number line shows the starting and ending velocities for ball 1 what's the change in velocity of ball 1 calculate the value mathematically and check using the number line
Answers
Answer:
The starting velocity for ball 1 is 1.00 meter/second. Its ending velocity is 0.25 meter/second.
The change in velocity for ball 1 is 0.25 – 1.00 = -0.75 meter/seconds
The flywheel of an engine has moment of inertia 1.9 kg m2 about its rotation axis. What constant torque is required to bring it up to an angular speed of 537 rev/min in 6.78 s, starting from rest, in N-m
Answers
Answer:
τ = 15.76 N-m
Explanation:
For rigid bodies, the net external torque acting on a rotating body, is equal to the product of the moment of inertia about its rotation axis, times the angular acceleration of the body, as follows:[tex]\tau = I * \alpha (1)[/tex]
Since I is a given of the question, we need to find out the angular acceleration.By definition, the angular acceleration is the rate of change of the angular velocity with respect to time:α = Δω/Δt = (ωf-ω₀) / (tfi-t₀)Since ω₀ = 0, and choosing t₀ =0, as tfi is a given, we need just to find out ωf.We have this value in rev/min, so we need first to convert it to rad/sec, as follows:[tex]537 rev/min * (1min/60 sec)*(2*\pi *rad/rev) = 17.9 * \pi rad/sec (2)[/tex]
Replacing in the definition of α, we have:α = 17.9*π rad/sec / 6.78 s = 8.29 rad/sec²Replacing I and α in (1), we finally get:τ = 15.76 N-m.
In the Bohr model of the hydrogen atom, an electron in the 1st excited state moves at a speed of 2.19 106 m/s in a circular path having a radius of 5.29 10-11 m. What is the effective current associated with this orbiting electron?
Answers
Answer:
I = 1.05x10⁻³ A
Explanation:
By definition, an electric current is the rate of charge flow at a given time:
[tex] I = \frac{q}{t} [/tex]
Where:
q: is the electrons charge = 1.602x10⁻¹⁹ C
t: is the time
In a circular motion, the time is given by:
[tex] t = T = \frac{2\pi}{\omega} = \frac{2\pi}{v/r} = \frac{2\pi r}{v} [/tex]
Where:
ω: is the angular speed = v/r
v: is the speed = 2.19x10⁶ m/s
r: is the radius = 5.29x10⁻¹¹ m
[tex] t = \frac{2\pi r}{v} = \frac{2\pi 5.29 \cdot 10^{-11} m}{2.19 \cdot 10^{6} m/s} = 1.52 \cdot 10^{-16} s [/tex]
Now, the effective current is:
[tex] I = \frac{q}{t} = \frac{1.602 \cdot 10^{-19} C}{ 1.52 \cdot 10^{-16} s} = 1.05 \cdot 10^{-3} A [/tex]
Therefore, the effective current associated with this orbiting electron is 1.05x10⁻³ A.
I hope it helps you!
Which of the following requires the expenditure of more work?
a. Lifting a 110 newton [N] weight a height of 3 meters [m].
b. Exerting a force of 60 pounds-force [lbf] on a sofa to slide it 30 feet [ft] across a room.
Answers
Answer:
The correct answer is option B
Explanation:
Step one:
given data
a. force F= 110N
distance s= 3meters
we know that work= Force* distance
work= 110*3
Work= 330Joules
Step two:
data
Force= 60 pounds
distance= 30 ft
convert pounds to Newton
1 pound= 4.44822N
60 pounds= 60*4.44822
=266.9N
convert ft to meteres
1 ft = 0.3048meter
30ft= 0.3048*30
=9.144N
we know that work= Force* distance
work= 266.9N*9.144N
Work= 2440.53Joules
What is the force used when a 7 kg bowling ball is rolled with an acceleration of 3 m /s2? Use the formula to find the force in Newtons (N): F = 7 kg × 3 m/s2
Answers
Answer:
21 Newtons
Explanation:
Force= mass * acceleration
Force= 7 kg * 3 m/s^2
Force= 21 Newtons
HELP ASAP!!!
Which graph shows the change in velocity of an object in free fall?
Answers
Answer:
the graph that show Change in velocity is no A
The graph that showing the velocity with respect to time for a free falling body is figure C where, the downward velocity will be higher due to the acceleration due to gravity.
What is velocity?Velocity of a moving body is the measure of the distance covered per unit time. Thus, it is the ratio of distance to the time. Velocity is expressed in the units of Km/h, m/s. miles/h, ft./s etc.
The rate of change of velocity is called acceleration. The acceleration by the force of a gravitational field is called acceleration due to gravity g having the value 9.8 m/s².
The velocity - time graph shows a diagonal relation for a free falling body. A free falling body is initially at rest and falls downward with the negative velocity with the acceleration due to gravity. Therefore, figure B shows the change in velocity of a free falling body.
To find more on velocity, refer here:
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The chemical equation below shows that hydrogen and oxygen chemically react to form water.
Which of these is true?
A.
Water is a pure substance and has the same properties as oxygen.
B.
Water is a pure substance and has the same properties as hydrogen.
C.
Hydrogen and oxygen are pure substances that have identical properties to each other.
D.
Hydrogen, oxygen, and water are pure substances that each have different properties.
Answers
Answer:
D
Explanation:
Hydrogen, oxygen, and water are pure substances that each have different properties.
Although the 3 of them are pure substances, but they nonetheless have different properties. These properties could either be their physical properties, or their chemical properties. This is particularly so because since Oxygen and Hydrogen the major components in water have different properties, it is only right if their product, water, has different properties also.
Answer:
D
Explanation:
got it right on study island
What is the acceleration of gravity, in m/s2, on the surface (or outer limit) of Venus? The mass of Venus is 4.87 1024 kg and its radius is 6.05 106 m.
Answers
Answer:
8.9 m/[tex]s^{2}[/tex]
Explanation:
From Newton's law of universal gravitation,
F = [tex]\frac{GMm}{R^{2} }[/tex] .............. 1
and from Newton's second law of motion,
F = mg ........... 2
Equating the two expression,
mg = [tex]\frac{GMm}{R^{2} }[/tex]
g = [tex]\frac{GM}{R^{2} }[/tex]
Given that: mass of Venus = 4.87 x [tex]10^{24}[/tex] Kg, radius = 6.05 x [tex]10^{6}[/tex] and G = 6.67 x [tex]10^{-11}[/tex] N[tex]m^{2} Kg^{-2}[/tex]
Thus;
g = [tex]\frac{6.67*10^{-11}*4.87*10^{24} }{(6.05*10^{6} )^{2} }[/tex]
= [tex]\frac{3.24829*10^{14} }{3.66025*10^{13} }[/tex]
= 8.87450
g = 8.9 m/[tex]s^{2}[/tex]
the acceleration of gravity on the surface of Venus is 8.9 m/[tex]s^{2}[/tex].
At an air show a jet flies at speed 1500 km/h on a day when the speed of sound is 342 m/s. What is the angle of the shock cone
Answers
Answer:
55 degrees
Explanation:
Given that an air show a jet flies at speed 1500 km/h on a day when the speed of sound is 342 m/s.
From the question above, we can get the below parameters
Object speed (V) = 1500 km/h
Sound speed ( v) = 342 m/s
Convert km/h to m/s
(1500 × 1000)/3600
Jet speed V = 416.67 m/s
Let's first calculate the mash number M.
M = V/v
M = 416.67 / 342
M = 1.2183
Formula for the angle of the shock cone is reciprocal of mash number. That is,
Sin Ø = 1 / M
Sin Ø = 1 / 1.2183
Sin Ø = 0.8208
Ø = sin^-1(0.8208)
Ø = 55 degree
Therefore, the angle of the shock cone is approximately 55 degrees