Seawater fills a tank to a depth of 12 ft. If the specific gravity of seawater is 1.03 and the atmospheric pressure at this location is 14.8 psi, the absolute pressure (psi) at the bottom of the tank is most nearly:______.
A. 5.4
B. 20.2
C. 26.8
D. 27.2
E. 10.8
Answer: (b)
Explanation:
Given
Depth of tank is [tex]h=12\ ft\ \text{or}\ 3.65\ m[/tex]
Specific gravity of seawater is [tex]S.G.=1.03[/tex]
Pressure difference due to column of water is
[tex]\Rightarrow \Delta P=\rho gh\\\Rightarrow \Delta P=1.03\times 10^3\times 9.8\times 3.65\\\Rightarrow \Delta P=36.84\times 10^3\ Pa\ \text{or}\\\Rightarrow \Delta P=5.34\ psi[/tex]
So, absolute pressure is given by
[tex]\Rightarrow P_{abs}=P_{atm}+\Delta P\\\Rightarrow P_{abs}=14.8+5.34\\\Rightarrow P_{abs}=20.14\approx 20.2\ psi[/tex]
Thus, option (b) is correct.
In the early 1900s, it was proposed that the law of conservation of mass should be simultaneously considered with the law of conservation of energy to explain particular phenomena. Thus, a theory of conservation of mass-energy was proposed. Which of the following reasons could provide evidence to support the proposed theory?
A. After charged particles travel a complete loop around a circuit, the electric potential energy of the charged particles does not change, but the number of available charged particles that can move through the circuit is reduced. This is because charged particles are used in order for circuit elements to operate correctly.
B. After a photon of light is absorbed by certain metals, electrons are found to be ejected from the metals. This is because the energy contained in the massless photon is used to eject an electron with mass out of the metal.
C. After particles of a hot gas collide with other particles in the gas, the initial combined mass of all particles of the gas immediately before the collisions occur is not equal to the final combined mass of all particles immediately after the collisions. This is because some of the particles in the gas are destroyed in the collisions.
D. After the decay of certain unstable nuclei, the initial mechanical energy of an unstable nucleus is not equal to the final mechanical energy of the resultant particles immediately after the decay process. This is because some of the available mechanical energy is converted into a particle that was originally not accounted for.
Answer:
B. After a photon of light is absorbed by certain metals, electrons are found to be ejected from the metals. This is because the energy contained in the massless photon is used to eject an electron with mass out of the metal.
Explanation:
Before, in the early days, it was proposed to form a combined theory by joining the theory of conservation of mass and the theory of conservation of energy and form a combined theory of conservation of mass-energy. It was done to explain a particular theory of [tex]$\text{photoelectric effect}$[/tex].
The [tex]$\text{photoelectric effect}$[/tex] is the emission of the electrons form the surface of a metal when light energy strikes on it. Here, in this phenomenon, both mass and energy is conserved.
When the light strikes a metal surface, electrons gets ejected from the surface. The energy of the photon is used to eject the electron form the metal surface.
How are the Northern Lights are formed.
Answer:
Bottom line: When charged particles from the sun strike atoms in Earth's atmosphere, they cause electrons in the atoms to move to a higher-energy state. When the electrons drop back to a lower energy state, they release a photon: light. This process creates the beautiful aurora, or northern lights.Explanation:
^-^I hope it's help uA. What is the change in internal energy for each of the following situations? q = 7.9 J out of the system and w = 3.6 J done on the system q = 1.5 J into the system and w = 7.5 J done on the system
Answer: [tex]-4.3\ J,\ 9\ J[/tex]
Explanation:
Given
(a)
Heat transfer [tex]Q=-7.9\ J\quad \text{taken}[/tex]
Work done [tex]W=-3.6\ J\quad \text{on the system}[/tex]
Change in the internal kinetic energy is
[tex]\Delta U=Q-W\\\Rightarrow \Delta U=-7.9-(-3.6)\\\Rightarrow \Delta U=-4.3\ J[/tex]
(b)
Heat transfer [tex]Q=1.5\ J\quad \text{given}[/tex]
Work done [tex]W=-7.5\ J\quad \text{on the system}[/tex]
Change in the internal kinetic energy is
[tex]\Delta U=Q-W\\\Rightarrow \Delta U=1.5-(-7.5)\\\Rightarrow \Delta U=9\ J[/tex]
3. How do you think a hot air balloon works?
Answer:hot air
Explanation:Hot air goes up, so when you put it in a hot air balloon fire is placed at the oppening to creat hot air and lift the balloon! :)
Physics part 1
I need help answering these
Answer:
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Which of the following statements about the electromagnetic spectrum is true?
A. It moves slower than the speed of light
B. It's consisting of waves of varying lengths
C. the slowest is wavelengths are orange and red
D. Scientist can only detect waves of visible light
Answer:
B. its consist of waves of varying lengtu
Maglev, a vehicle that glides above a magnetic field without touching a track, make a 624-mile trip in 4 hours. What is the speed of the vehicle?
Answer:
The speed of the vehicle is 156 miles per hour.
Explanation:
Let suppose that the Maglev, that is, a vehicle who works on the principle of superconductive magnetic levitation, moves at constant speed. Hence, the speed of the vehicle ([tex]v[/tex]), in miles per hour, is defined by this kinematic model:
[tex]v = \frac{s}{t}[/tex] (1)
Where:
[tex]s[/tex] - Travelled distance, in miles.
[tex]t[/tex] - Time, in hours.
If we know that [tex]s = 624\,mi[/tex] and [tex]t = 4\,h[/tex], then the speed of the vehicle is:
[tex]v = \frac{624\,mi}{4\,h}[/tex]
[tex]v = 156\,\frac{mi}{h}[/tex]
The speed of the vehicle is 156 miles per hour.
A student removes a 10.5 kg stereo amplifier from a shelf that is 1.82 m high. The amplifier is lowered at a constant speed to a height of 0.75 m. What is the work done by (a) the person and (b) the gravitational force that acts on the amplifier
Answer:
(a) the work done by the student is 110.1 J
(b) The gravitational force that acts on the amplifier is 102.9 N
Explanation:
Given;
mass of the amplifier, m = 10.5 kg
initial position of the amplifier, x₀ = 1.82 m
final position of the amplifier, x₁ =0.75 m
The dispalcement of the amplifier Δx = x₁ - x₀ = 1.82 m - 0.75 m = 1.07 m
(b) The gravitational force that acts on the amplifier;
F = mg
F = 10.5 x 9.8
F = 102.9 N
(a) the work done by the student is calculated as;
W = FΔx
W = 102.9 x 1.07
W = 110.1 J
4) The SI unit of time is second. why?
Answer:
Second, fundamental unit of time, now defined in terms of the radiation frequency at which atoms of the element cesium change from one state to another. The second was formerly defined as 1/86,400 of the mean solar day—i.e., the average period of rotation of the Earth on its axis relative to the Sun.
source britannica
Explanation:
At 2:00, Alice was traveling in a car at 40 miles/hour. She then slows down, and at 4:00, she was traveling at 20 miles/hour.
What was Alice’s average acceleration between 2:00 and 4:00?
Show your complete calculation and state your answer with the correct units.
Answer:
-10miles/hr²
Explanation:
a = ∆v/∆t
Where:
a = acceleration (miles/hr²)
∆V = change in velocity (miles/hr)
t = time (hour)
The change in time is from 2:00 - 4:00 ∆t = 2 hours.
The distance covered is as follows: 20miles/hour - 40 miles/hr
∆v = -20miles/hr
Using a = ∆v/∆t
a = -20/2
a = -10miles/hr²
please help for 21! will mark brainliest
The answer for this question is D
A cart weighing 40 pounds is placed on a ramp incline 15 degrees to the horizon. The cart is held in place by a rope inclined 60 degrees to the horizontal. find the force that the rope must exert on the cart to keep it from rolling down the ramp.
Answer: [tex]14.64\ N[/tex]
Explanation:
Given
Inclination of ramp is [tex]\theta=15^{\circ}[/tex]
Rope is inclined [tex]\phi=60^{\circ}[/tex] to the horizontal
Weight of cart [tex]W=40\ lb[/tex]
from the diagram, rope is at angle of [tex]45^{\circ}[/tex] w.r.t ramp
Sine component of weight pulls down the cart Cosine component of force applied through rope held it at the position
[tex]\Rightarrow 40\sin 15^{\circ}=F\cos 45^{\circ}\\\\\Rightarrow F=40\cdot \dfrac{\sin 15^{\circ}}{\cos 45^{\circ}}\\\\\Rightarrow F=40\times 0.366\\\Rightarrow F=14.64\ N[/tex]
How is a continuous spectra is formed?
Answer:
Hello There!!
Explanation:
They are produced by the photodissociation of negatively charged hydrogen ions (H−).
hope this helps,have a great day!!
~Pinky~
A drunken sailor stumbles 550 meters north, 500 meters northeast, then 450 meters northwest. What is the total displacement and the angle of the displacement
Answer:
Resultant displacement = 1222.3 m
Angle is 88.3 degree from +X axis.
Explanation:
A = 550 m north
B = 500 m north east
C = 450 m north west
Write in the vector form
A = 550 j
B = 500 (cos 45 i + sin 45 j ) = 353.6 i + 353.6 j
C = 450 ( - cos 45 i + sin 45 j ) = - 318.2 i + 318.2 j
Net displacement is given by
R = (353.6 - 318.2) i + (550 + 353.6 + 318.2) j
R = 35.4 i + 1221.8 j
The magnitude is
[tex]R = \sqrt{35.4^{2}+1221.8^{2}}R = 1222.3 m[/tex]
The direction is given by
[tex]tan\theta =\frac{1221.8}{35.4}\\\\\theta = 88.3^{o}[/tex]
A string has a linear density of 8.5 x 10-3 kg/m and is under a tension of 280 N. The string is 1.8 m long, is fixed at both ends, and is vibrating in the standing wave pattern shown in the drawing. Determine the
a. speed.
b. wavelength
c. frequency of the traveling waves that make up the standing wave.
Answer:
a) [tex]v=181.497m/s[/tex]
b) [tex]\lambda=1.2[/tex]
c) [tex]F=151.248hz[/tex]
Explanation:
From the question we are told that:
Linear density [tex]\rho=8.5 x 10-3 kg/m[/tex]
Tension [tex]T= 280 N[/tex]
Length of string [tex]l= 1.8 m[/tex]
a)
Generally the equation for Speed of travelling wave is mathematically given by
[tex]v=\sqrt{\frac{T}{\rho}}[/tex]
[tex]v=\sqrt{\frac{280}{8.5*10^{-3}}[/tex]
[tex]v=181.497m/s[/tex]
b)
From the Drawing
Wavelength is given as
[tex]\lambda=\frac{2L}{3}[/tex]
[tex]\lambda=\frac{2*1.8}{3}[/tex]
[tex]\lambda=1.2[/tex]
c)
Generally the equation for Frequency of travelling wave is mathematically given by
[tex]F=\frac[v}{\lambda}[/tex]
[tex]F=\frac[181.497}{1.2}[/tex]
[tex]F=151.248hz[/tex]
A ball is dropped out of a window and hits the ground at 14.5 m/s. How long did it take to fall to the ground?
Answer:
Explanation:
Use the one-dimensional equation:
[tex]v_f=v_0+at[/tex] which says that the final velocity of a falling object is equal to its initial velocity times the acceleration of gravity times the time it takes to fall. We have the final velocity, -14.5 (negative because its direction is down and down is negative), initial velocity is 0 (because it was held still by someone before it was dropped), and acceleration is -9.8 (negative again, because direction is down while acceleration increases). Filling in:
-14.5 = 0 - 9.8t and
-14.5 = -9.8t so
t = 1.5 seconds
magnetism/ magnetic field ana magnetic forces
Answer:
Magnetism is a physical phenomenon that manifests itself in a force acting between magnets or other magnetized or magnetisable objects, and a force acting on moving electric charges, such as in current-carrying cables. The force action takes place by means of a magnetic field, which is generated by the objects themselves or otherwise. There are natural and artificial magnets. All magnets have two poles called the north pole and the south pole. The north pole of one magnet repels the north pole of another magnet and attracts the south pole of another magnet; the same with south poles.
How long would it take a 4,560 watt motor to raise a 166 kg piano to an apartment window
15 meters above the ground?
Answer:
Explanation:
We need the power equation here:
P = W/t where W is work and is defined as
W = F*displacement.
Force is a measure in Newtons, which is also weight. We have the mass of the piano, but we need to find the weight:
w = mg so
w = 166(9.8) so
w = 1600N, rounded to the correct number of sig dig. We use that now in the power equation:
[tex]4560=\frac{(1600)(15)}{t}[/tex] and isolating the unknown:
[tex]t=\frac{(1600)(15)}{4560}[/tex] so
t = 5.3 seconds
Is a measurement is precuse it must also be accurate
Fill in the blanks. Power station produce electricity at __________.
Answer:
heat
Explanation:
heat is the answer hdhhdhdhdhdhdhdhdhdhd
The index of refraction of n-propyl alcohol is 1.39. Find the angle of refraction of light in that medium if light comes from air with an angle of incidence of 55 degrees.
Answer:
36.11 degrees
Explanation:
index of refraction n = sin i/sinr
i is the angle of incidence
r is the angle of refraction
Substitute into the expression
1.39 = sin55/sin(r)
1.39 = 0.8191/sin(r)
sin(r) = 0.8191/1.39
sin(r) = 0.5893
r = arcsin(0.5893)
r = 36.11
hence the angle of refraction of light is 36.11 degrees
PLEASE HELPPPPPP ME PLS PLS
please someone help me full out the blanks
To find the specific heat capacity of a solid of mass 600 g whose temperature was 40oC, it was placed in a calorimeter that contains 25 g of water 10oC. The mixture reached a final temperature of 25oC. How much is the metal's specific heat capacity? (Cwater = 4180 J/Kg.K)
500J/Kg.K
250J/Kg.K
174J/Kg.K
2000J/Kg.k
Answer and I will give you brainiliest
Answer:
m of solid = 600g = 0.6kg
T=40°C
It was placed in a calorimeter that contains 25g(0.025kg) of water at 10°C
Now. We would have considered the calorimeter in this solving because it will be at the same temp as the water which it is holding. Example... If you put a hot water inside a Cup... The cup itself will become hot and have the same temp as the water you put in it ...
But in this question... We'll Ignore the Calorimeter and the heat gained by it since no parameter was given for it and also We don't know the material which the calorimeter is made of.
So
Since the Solid is at a higher temp(40°)... It will lose heat to water; which is at a lower temp.
From the question... THE EQUILIBRIUM TEMPERATURE REACHED IS 25°C
Then
Temp Change for solid(heat loss) = 40-25=15°C
Temp Change for water(heat gain)= 25-10 =15°C
Heat lost by solid = Heat gained by water
MC∆T = MC∆T
0.6 x C x 15 = 0.025 x 4180 x 15
C= 0.025x4180x15÷(0.6x15)
C= 174.16 ~ 174J/Kg.K.
OPTION C IS LEGIT
PLEASE HELP! Daniel is 50.0 meters away from a building. He observes that his line-of-sight to the tip of the building makes an angle of 63.0° with the
horizontal. What is the height of the building?
A. 174 m
B. 110 m
C. 98 m
D. 50 m
Answer:
The height of building should be 98.13 m plus the height of Daniel. Since the 63° was measured from his eye level.
Explanation:
A current is maintained in a simple circuit that consists of a resistor between the terminals of an ideal battery. If the battery supplies energy at a rate of W, how large is the resistance
Answer:
Resistance is as large as 2.8 ohm
Explanation:
Complete question
A 3.0 A current is maintained in a simple circuit that consists of a resistor between the terminals of an ideal battery. If the battery supplies energy at a rate of 25 W, how large is the resistance?
Solution -
The relation between Power and current is as follows
P = I^2*R
R = P/I^2
Were P = Power
R = resistance and
I = current
Given-
P = 25 W
I = 3.0 A
Substituting the given values, in above equation, we get -
R = 25/3.0^2
R = 2.8 ohm
which of the following is not a good working habit in doing an embroidery
Answer:
Where is following ??
Post proper Ques
The diagram shows a transistor used in a circuit.
A signal with a small change in voltage is input into a circuit that includes a transistor connected to 4 resistors and 2 capacitors. The signal output from the transistor has a much larger change in voltage than the input.
What does the diagram show?
an NPN transistor used as an amplifier
an NPN transistor used as a switch
a PNP transistor used as an amplifier
a PNP transistor used as a switch
Answer:
a PNP transistor used as an amplifier
Explanation:
The diagram show a PNP transistor used as an amplifier.PNP transisitor having one 2 P type and the 1 N type of semiconductor.
What is PNP transistor?This bipolar PNP junction transistor is made up of three layers of semiconductor material, two of which are P-type & one of which is N-type. It consists of three terminals.
The transistor's emitter allows it to supply the majority of charge carriers. In relation to the ground, the emitter always is forward biased.
As a result, the base receives the vast majority of charge carriers. A transistor's emitter is strong and of modest size.
The collector collects the vast majority of the charge carrier delivered by the emitter. Reverse bias is always present at the collector-base junction.
The charge collector region is moderately mixed and capable of collecting the charge.
The diagram shows a transistor used in a circuit.
A signal with a small change in voltage is input into a circuit that includes a transistor connected to 4 resistors and 2 capacitors. The signal output from the transistor has a much larger change in voltage than the input.
The diagram show a PNP transistor used as an amplifier.
Hence option C is correct.
To learn more about the PNP transistors refer to the link;
https://brainly.com/question/1492057
Many adventures like to go rafting on the Colorado River through Grand Canyon National Park. There are many locations where the river becomes more narrow, both the distance between the canyon walls as well as the depth changes due to debris like boulders on the bottom of the river; this leads to changes in the water speed. In the park, the Colorado River has an average width of 100m and an average depth of 8m, and an average speed of 3 m/s. At the Lava Falls Rapids, the river has an average width of about 25m and an average depth of about 15m. What is the approximate speed of the water in this location
Answer:
6.4 m/s
Explanation:
Given that :
The average width of the Colorado river = 100 m
Average depth of the river is = 8 m
Therefore, area = [tex]$A_1= 100 \ m \times 8 \ m$[/tex]
Speed of the river, [tex]$v_1 = 3 \ m/s$[/tex]
After the lava falls on the river,
Width of the river becomes = 25 m
Depth of the river became = 15 m
Therefore, area = [tex]$A_2= 25 \ m \times 15 \ m$[/tex]
Now, since the volume flow rate of the Colorado river is same, then from the Continuity equation,
[tex]$Q_1=Q_2$[/tex]
[tex]$A_1v_1=A_2v_2$[/tex]
∴ [tex]$100 \times 8 \times3 = 25 \times 15 \times v_2$[/tex]
[tex]$v_2=\frac{100 \times 8 \times 3}{25 \times 15}$[/tex]
= 6.4 m/s
Therefore, the speed of the river in this location is 6.4 m/s