I’m completely lost on these stoichiometry problems

Im Completely Lost On These Stoichiometry Problems

Answers

Answer 1

Answer:

1) 4.21 x 10^24 molecules of Fe2O3

2) 36.416g of O2

Explanation:

1) First, find moles of Fe2O3 by using the mole ratio of 3:2. Fe2O3 has a coefficient of 2, and O2 has a coefficient of 3 thus making their mole ratio 2:3. Then, multiply 10.5 moles of O2 by 2/3 which equals 7 moles of Fe2O3. Finally, convert moles of Fe2O3 to molecules by multiplying it by Avogadro's number.

10.5 mol x 2/3= 7 mol Fe2O3

7 mol multiplied by 6.02 x 10^23 = 4.21 x 10^24 molecules

2) First, convert grams of KClO3 to moles by dividing it by its molar mass(approximately 122.5 g), which equals .759 mol. Then find moles of O2 by multiplying .759 mol KClO3 by the mole ratio of O2 to KClO3, which is 3:2. That equals 1.138 moles of O2. Finally, convert moles to grams by  multiplying 1.138 mol by the molar mass of O2 (approximately 32g). 36.416g of O2 is your final answer.

93g KClO3/ 122.5g = .759 mol KClO3

.759 mol x 3/2= 1.138 mol O2

1.138 mol x 32g= 36.416g O2

Answer 2

Answer:

See Explanations ...  I'll have to deliver my explanation in two posts. One is beyond the limits allowed.    

Explanation:

Stoichiometry is very easy if you understand the relationship between the 'mole' and the balanced chemical equation. Let's start by defining the 'mole'

The 'mole' of substance is the mass of substance (element or compounds) that contains 1 Avogadro's Number ( = 6.02 x 10²³ ) of particles. The mass of substance that does contain 1 Avogadro's Number of particles is 1 formula weight of substance (also, molecular weight of substance). That is,

1 mole = 1 formula wt. = 1 mole weight = 1 Avogadro's Number = 6.02 x 10²³ particles of substance.

So, assuming you can determine formula weight then that value expressed in terms of grams is a 'Gram Formula Weight'; that is, 1 GFW = 1 mole wt.

At this point it is assumed that you understand how to balance simple chemical equations by inspection. That is, by the Law of Mass Balance ...

total mass of reactants = total mass of products

In problem 1 you are given iron (Fe) + molecular oxygen (O₂) => iron(III) oxide (Fe₂O₃)  ...   4Fe + 3O₂ => 2Fe₂O₃   ... ∑mass R = ∑mass P.

Now, focus on the coefficients of each substance, that is, 4 for Fe, 3 for O₂ and 2 for Fe₂O₃. These values (coefficients) are moles of each substance in a special type of equation called the 'Standard Equation'. The Standard Equation is one which when balanced its coefficients are in the smallest whole number mole ratio of substance. That is the equation above is showing 4 moles of Fe, 3 moles of O₂ and 2 moles of Fe₂O₃.  This is  important in that most balanced equations that will be given in textbook problems will be in Standard Form.

From the Standard Form, the coefficients can be doubled, or divided in half, or whatever multiple or fraction one desires. The reaction would still perform in correct proportions. However, the multiples or fractions would not be in Standard Form. Most, if not all, stoichiometry problems will provide only the Standard Form.

Example, let's take the given equation above (from problem 1)

4Fe + 3O₂ => 2Fe₂O₃.

Both of the following are in correct proportions and will react with respect to the proportions YOU choose ...

(multiply by 2) => 8Fe + 6O₂ => 4Fe₂O₃.

(dividing by 2) => 2Fe + 3/2O₂ => Fe₂O₃.

Both are balanced and conform to the Law of Mass Balance but are not in Standard Form. Oh, and the Standard Form equations are assumed to be at 0°C and 1 atm, even if not specified in the problem. You may not need that now, but will become important in Gas Laws.

Let's move on to stoichiometry calculations. There are several methods being taught within the chemed. community, but I'm going to focus only on using mole ratios.  

My approach begins with this rule => convert reaction data to moles, solve using mole ratios and convert to needed dimension at the end of the problem. This will simplify a lot of problems once you understand what it's about.

OK, for problem 1 ...

How many molecules of Fe₂O₃ can be produced from 10.5 moles of O₂?

Given the Standard Form equation 4Fe + 3O₂ => 2Fe₂O₃.

Now, write (neatly) the equation and list the givens under the specific substances ...

             4Fe +       3O₂         =>     2Fe₂O₃.

              ex*     10.5 moles       ? molecules       note: ex* = excess (not used)

In this problem, since O₂ is already in terms of moles no conversion needed.

What you need to focus on is the relationship between the coefficients of O₂ and Fe₂O₃. Note that the coefficient of Fe₂O₃ is SMALLER than the coefficient of O₂. This means that the number of moles of Fe₂O₃ formed will be smaller than moles of O₂ given, that is 10.5 moles. How much smaller? Easy Calculation => Take the coefficient of O₂ and the coefficient of Fe₂O₃ and make a ratio of the numbers that will make 10.5 SMALLER. That is, you should use 2/3(10.5) to get a smaller number, not 3/2(10.5) because that would give a larger number and inconsistent with the ratio given in the balanced equation.      

So, moles of Fe₂O₃ produced = 2/3(10.5) moles Fe₂O₃ = 7 moles Fe₂O₃. Note that 7 moles is smaller than 10.5 moles.

Now, the number of molecules of Fe₂O₃ is also an easy calculation.

Remember that 1 mole contains 6.02 x 10²³ particles, then 7 moles would contain ...

= 7 moles Fe₂O₃  x  6.02 x 10²³ molecules Fe₂O₃/mole Fe₂O₃

= 4.21 x 10²⁴ molecules Fe₂O₃.  

Go to 2nd post for problem 2 solution.


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The freezing point of the solution is -3.53°C.

The Chemical equation of the HBr is -

              HBr → H⁺ + Br ⁻

Initial -     1         0      0

Final -      1-α     α       α

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   m(molality = mass of solute / solvent (Kg))

                        Δ T f  = (1 + α) × 1.86 × (mass/molar mass ) / solvent

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  putting the values in above equation -

                           = (1 + 0.9) × 1.86 × (8.1 × 1000) / 81 × 100(gm)

                              ΔT = 3.53°C

    Then freezing point T f =  T° f - ΔT

                            = 0 - 3.53°C

                           T f = -3.53°C

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Complete Question -

What is the freezing point of a solution containing 8.1 g HBr in 100gm. water assuming the acid to be 90% ionised:

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This is because the freezing point depression of a solution is proportional to the molality of the solute. The molar mass of NaCl is 58.44 g/mol, so the solution has a molality of 0.25 m. Using the formula for freezing point depression, ΔTf = i Kf m, where i is the van't Hoff factor (2 for NaCl), Kf is the freezing point depression constant (1.86°C/m), and m is the molality, we can calculate that the freezing point depression of this solution is 0.46°C, resulting in a freezing point of -4.4°C.
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Answers

Answer:

400 meters

Explanation:

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The classification of each protein is:

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After solving the equation benzene is 2.698 kg is the correct answer.

Description of the answer

1 day = 24 hrs = 24×60 minute = 1440 minutes

concentration of benzene in groundwater = 5 mg/l

100 gallon = 378.541 L

100 gallon/minute = 378.541 L/minute

100 gallon (378.541 l) benzene contaminated groundwater is being pumped per minute, therefore the volume of groundwater being pumped in one day (i.e. 1440 minutes) = (378.541 × 1440) l = 545099.04L

Since 1 l groundwater is contaminated with 5 mg benzene, therefore 545099.04 l groundwater is contaminated with = (545099.04 × 5) mg = 2725495.2 mg = 2725.495 g = 2.725 kg

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K2SO4 has the most ions out of the options, which means its freezing point will degrade the most.

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Which aqueous solution with a concentration of "0.1 M" will have the lowest freezing point

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The rate law for first order kinetics is

K=(2.303/T)×log(a/a-x)

half life=0.693/K

Where

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t - time passed by the sample

a - initial amount of the reactant

a-x - amount left after the decay process

K=0.693/half life

K=0.693/ 8

 =0.086

0.086=(2.303/ 32)×log( 136/a-x)

0.086=0.07×log( 136/a-x)

1.22=log( 136/a-x)

136/a-x=16.5

a-x=8.242g

Therefore, 8.242g will be left after 32 days.

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The oxygen atom in the water molecule has two lone pairs, one of which could be used to form a bond with a proton and, therefore, the water molecule could act as a base in a reaction. Since water has the potential to act both as an acid and as a base, water is amphoteric.

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Use bond enthalpies to estimate the enthalpy change for each of the following reactions.
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H2O2(g)+2CO(g)→H2(g)+2CO2(g)
3H2C=CH2(g)→C6H12(g)

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The enthalpy changes for each of the following reactions are:

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a. The acid on the left is H₂O and its conjugate base on the right is OH⁻.

b. The base on the left is HONH₂ and its conjugate acid on the right is HONH₃⁺.

Chemical reactions between acids and bases always produce its conjugate base and its conjugate acid. According to Bronsted-Lowry

Acid on the left side of a chemical reaction always donates a proton (H⁺)Its conjugate base on the right side of a chemical reaction is the remaining acid after the acid is donated.Base on the left side of a chemical reaction always accepts a proton (H⁺)Its conjugate acid on the right side of a chemical reaction is the remaining base after the base accepts a proton.

HONH₂ + H₂O ⇄ HONH₃⁺ + OH⁻

HONH₂ becomes HONH₃⁺
HONH₂ accepts a proton, so HONH₂ is a base
HONH₃⁺ is a conjugate acidH₂O becomes OH⁻
H₂O donates a proton, so H₂O is an acid
OH⁻ is a conjugate base


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The correct classification of the following compounds are as follows:

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Inorganic compounds are those not containing carbon atoms or containing carbon atoms ionically bound to other atoms.

However, not all carbon-containing compounds are organic. For example, carbon dioxide is an inorganic compound; although it has a carbon atom it has no C-C or C-H bonds.

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a sample of n2(g) effuses through an orifice in 125 seconds. how long will it take the same amount of propane, c3h8, to effuse through the same orifice under the same conditions?

Answers

After solving the equation the Molecular mass is 254 s is the answer.

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First we calculate,

Molecular mass of propane C3H8

= 3 x 12 + 1 x 8

= 44 gm/ml

Now, calculate amount of propane, c3h8, to effuse through the same orifice under the same conditions:-

[tex]t_{N2}[/tex]/[tex]t_{C3H8}[/tex] = [tex]\sqrt{28 gm/ml/ 44gm/ml}[/tex]

               = 0.49

[tex]t_{C3H8}[/tex] = 125 s/0.49

         = 254 s is the answer.

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the accompanying photo shows the reaction between a solution of cd(no3)2 and one of na2s.

Answers

The Precipitate formed is of CdS and the ions remaining are Na+ and NO3-.

The complete balanced chemical reaction is as follows:

Cd(NO3)2 + Na2S → CdS + 2NaNO3

Precipitation in an aqueous solution is the process of converting a dissolved component into an insoluble solid from a supersaturated solution. The precipitate is the solid that forms. In chemistry, a solid generated by a change in a solution, usually owing to a chemical reaction or a temperature shift that reduces the solubility of a solid.

A chemical may precipitate when its concentration exceeds its solubility. This can be caused by temperature fluctuations, solvent evaporation, or solvent mixing. A severely supersaturated solution precipitates more quickly.

A chemical reaction can result in the development of a precipitate. A white precipitate of barium sulphate is created when a barium chloride solution combines with sulphuric acid.

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What is the substrate process?

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A substrate in biology can be either a chemical that an enzyme can operate on or the surface that an organism (such as a plant, fungus, or animal) lives on. A substrate in geology is the surface of a rock or sediment where chemical and biological processes take place.

Geology describes it as the layer of rock or other elements that lies beneath the soil. For instance, a page is a substrate for ink to stick to, rock is a substrate for fungi, and NaCl is a substrate for a chemical reaction. The basic material on which processing is carried out is referred to as the substrate in the fields of materials science and engineering. This surface might be employed to create new films or material layers, like deposited coatings. It might serve as the foundation for the bonding of paint, adhesives, or sticky tape.

The substrate in biochemistry is a molecule that an enzyme reacts with. Chemical processes involving the substrate are catalyzed by enzymes (s). One or more products are created from the substrate, and they are then released from the active site. After that, another substrate molecule can be taken up by the active site.

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The conjugate acid of CH3COO- is _____________. The conjugate acid of F- is _______________. The conjugate acid of CN- is ______________. The conjugate acid of PO43- is _____________.The conjugate base of CH3COOH is _________________. The conjugate base of HCl is ______________. The conjugate base of H2SO4 is _________________. The conjugate base of H2S is _______________. The conjugate base of H3PO4 is _________________. The conjugate base of NH4+ is ___________________.Na2HPO4 is soluble and exists in two units of the cation Na+ and one unit of the anion __________________. The conjugate base of this anion is _____________________. Na3PO4 is soluble and exists in three units of the cation Na+ and one unit of the anion ___________________. The conjugate acid of this anion is __________________.

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So that is base. However, this base (CH 3COO) is actually a derivative of the acid (CH 3COOH), which is why CH 3COO is an acid's conjugate base. What distinguishes a conjugate base from an acid hbr?

H2CO3 is the conjugate acid. acid carbonate. What is CH3COO's conjugate acid? The conjugate acid for the acetate ion is acetic acid. What is the CH3COO- conjugate acid? What does the term conjugate base mean? An acid's conjugate base is what is left over after the acid has contributed its proton. Example: HX is the acid, and X- is the conjugate base. An acid's conjugate base is what is left over after the acid has contributed its proton.  Acid is HX, while base is conjugate.

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What would be the freezing point of an aqueous solution containing 17g of c2h5oh in 1000g of water?

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The freezing point of an aqueous solution containing 17g of c2h5oh in 1000g of water −0.69 degree celcius

What is freezing point?

When the temperature of a liquid falls below its freezing point, it transforms into a solid. According to the internationally accepted definition, freezing is the solidification phase change of a liquid or the liquid content of a substance caused by cooling.

Most substances have the same melting and freezing points; however, certain substances have different solid-liquid transition temperatures. Agar, for example, exhibits hysteresis in its melting and freezing points. It melts at 85 °C (185 °F) and solidifies at 32 °C to 40 °C (89.6 °F to 104 °F).

Hence, the freezing point of an aqueous solution containing 17g of c2h5oh in 1000g of water −0.69 degree celsius

△T f = K f × m B ×w A. w B ×1000

​ =1.86× 46×100017×1000

​ =0.69

∴ Freezing point of solution =0−0.69=−0.69 degree celsius

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How many molecules of gold are in a gold ring that has a mass of 8.87 g

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We are aware that one Avogadro constant (N a=6.022*1023; Na =6.022*1023 ) equals one mole of any substance. Since MM=197 g/mol --> n= 8.87 g/197 g/mol 0.450*10-2 mol in this instance.

When given a mass, how do you calculate the number of molecules?

Determine the substance's molecular weight in units of one mole, then divide the molar mass value by the molecular mass, and multiply the result by the Avogadro constant to get the required number of molecules.

What constituents of gold are there?

Auric chloride (AuCl3) and chloroauric acid are the most prevalent gold compounds (HAuCl4). Aqua regia is a solution made by combining one component of nitric acid with three parts of hydrochloric acid (because it dissolved gold, the King of Metals).

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Is starch an ionic or covalent compound?

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Starch is a covalent compound because no ions is present in it.

A covalent bond is made from the mutual sharing of one or more pairs of electrons between two atoms. These electrons in a covalent bond are simultaneously attracted by the two atomic nuclei. A covalent bond is formed when the difference between the electronegativities of two atoms is too small for an electron transfer to occur and to form ions.

Starch is composed of long chains of glucose molecules that are bonded together through covalent bonds called glycosidic bonds. As starch contains covalent bonds it it, so it is a covalent compound.

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If a ball is bounced from a building which ball is the Kinetic energy the highest? (photo attached) [i was stuck because one of the balls hit the ground and bounced back up]​

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Answer: The place where the kinetics energy is the highest is where the ball struck the ground.

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