I'm spending my last 10 points on this please help me

Answer:

The equation will be. c= 1200 / 240 + 6 = 440. C=440 (I don't know if this is correct)

Answer:

3(2q+1)

Step-by-step explanation:

6q+2

3(2q+1)

The standard equation of a line is y = mx+ b

where:

The y-intercept is the point where the line cuts the y-axis

For the equation y = -2x -4

For the equation y = -5/2x

Find the graphs attached.

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The cost of book has to be less than or equal to 26.39.

The amount of money Elena can buy has to be less than or equal to $30. Thus, the inequality sign to be used is the less than or equal to sign.

(1 + tax)cost of books + cost of bus fare ≤ value of the gift

1.08c + 1.5 ≤ 30

In order to determine the maximum cost of books, take the following steps:

Combine similar terms

1.08c  ≤ 30 - 1.5

Add similar terms together

1.08c  ≤ 28.50

Divide both sides of the equation by 1.08

c  ≤ 28.50 / 1.08

c  ≤ 26.39

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Answer:

2/9.

Step-by-step explanation:

There are 2 multiples of 4 in the 9 cards, 4 itself and 8.

So the required Probability is 2/9.

F, G, and H all lie on the same line. If FG/GH = 1, then FG = GH, which is to say the distance between F and G is equal to the distance between G and H. This means either F and H are the same point, or G is the midpoint of F and H.

They're not the same point, because the x-coordinate of H is 7 times that of F. So G must be halfway between F and H.

Then the x-coordinate of G is

(a + 7a)/2 = 8a/2 = 4a

Answer:

where is the equation??

pls attach that

[tex]\red{\bf{ {Answer = \: \: - 48}}} [/tex]

[tex]\qquad[/tex] [tex]\twoheadrightarrow\sf \underbrace {-22 \times 3} + \underbrace {12 \times 2} - \underbrace {6\times 2} + 4 + 2[/tex]

We carry out the three multiplications.

[tex]\qquad[/tex] [tex]\twoheadrightarrow\sf \underbrace {-66 \: + \: 24} \: - \: 12 \: + \: \underbrace {4 \: + \: 2}[/tex]

Now we make the ones that are marked.

[tex]\qquad[/tex] [tex]\twoheadrightarrow\sf \underbrace {-42} \: \: - 12 \: \: + \underbrace {6} \: \: [/tex]

[tex]\qquad[/tex] [tex]\twoheadrightarrow\sf \underbrace {-36 \: \: \: - \: \: \: 12}[/tex]

[tex]\qquad[/tex] [tex]\twoheadrightarrow\sf -48[/tex]

Answer:

My friend is farthest from my school

Step-by-step explanation:

Let the distance from the movie store to school be x and the distance from the grocery store to school be y

Using Cosine rule,

x²= 10²+7² - 2×10×7Cos120

x²= 149 -140(-0.5)

x²= 149+70

x²= 219

x= √219

= 14.8miles

y²= 10²+7² - 2×10×7Cos100

y²= 149 -140(-0.1736)

y²=149+24.2704

y²=173.2704

y=√173.2704

y=13.4miles

Answer:USE SUBSTITUTION METHOD. Algebra work right here

Step-by-step explanation:

Answer:

1/4

Step-by-step explanation:

This is because you want to get x alone, so if you divide -12 on one side you have to do it on the other side, so you get -3/-12 which can be divided by -3 to be simplified to 1/4. Hope this helps!

Answer:

Step-by-step explanation:

-12x = -3

x = 12 : -3

x = 1/4

--------------------

check

-12 * 1/4 = -3

-3 = -3

the answer is good

Answer:

discriminant= 100, nature of the root= real numbers.

Step-by-step explanation:

discriminant formula: b^2-4ac

-2^2-4(6)(-4)

4+96=100.

Answer:

C) 5 seconds

Step-by-step explanation:

[tex]h = - 16t {}^{2} + 64t + 80[/tex]

When the ball hits the ground, the height is 0.

[tex]0 = - 16t {}^{2} + 64t + 80[/tex]

Factor out the greatest common factor: 16

[tex]0 = - 16(t {}^{2} - 4t - 5)[/tex]

Find numbers whose sum is -5 and product is - 4.

Those numbers are - 5 and 1: - 5 × 1 = - 5, - 5 + 1 = - 4

[tex]0 = - 16(t - 5)(t + 1)[/tex]

[tex]t - 5 = 0[/tex]

Or

[tex]t + 1 = 0[/tex]

So,

[tex]t = 5[/tex]

Or

[tex]t = - 1[/tex]

Since time cannot be a negative value the correct answer is 5 seconds.

Answer: 6

Step-by-step explanation:

13-7=6

The man’s son. Since the man has no brothers and the father of the man in the photograph is the man’s father’s son, the father of the man in the photograph must be the man. That means that the man in the photograph is the man’s son.

Answer:

n = 11

Step-by-step explanation:

n+5=2n-6

you add 6 on both sides and you get

n+11=2n

you then subtract n on both sides and get

11=n

Step-by-step explanation:

n+5 = 2n - 6 -> Original equation

5 = n - 6 -> Take n away from both sides

11 = n -> Add 6 to both sides

n = 11 -> Final answer

*Remember, we are trying to get n by using inverse operations.

Answer:

-2 - 16 = -18

Step-by-step explanation:

-y+4c

You take the values for c and y and substitute them in the original equation.

It would then look like:

-(2) + 4(-4)

Solving that would be -2 -16 = -18

Answer:

-18

Step-by-step explanation:

-(2)+4(-4)    Plug in the values of y and c.

-2+(-16)       Simplify.

-2-16

-18

Hope this helps you out!! Have an amazing day <3

Answer:

gang gang shii

Step-by-step explanation:

gang gang.

Step-by-step explanation:

6)

[tex]k = \frac{6}{4} \\ k = \frac{3}{2} [/tex]

7)

[tex] \frac{ab}{mn} = \frac{bc}{no} = \frac{cd}{op} = \frac{da}{pm} [/tex]

8)

[tex]y = 8 ( \frac{3}{2} ) \\ y = 12[/tex]

[tex]z = 6 ( \frac{3}{2} ) \\ z = 9[/tex]

9)

[tex]5k = 8 \\ k = \frac{8}{5} \\ x( \frac{8}{5}) = 32 \\ x = 20ft[/tex]

Step-by-step explanation:

We have that

[tex](x + \frac{1}{x} ) {}^{2} = 3[/tex]

We are trying to find the number value so that we can apply in the later equation.

Qe first simplify.

Remeber that

[tex](a + b) {}^{2} = a {}^{2} + 2ab + {b}^{2} [/tex]

Also remeber that

[tex] \frac{1}{x} = {x}^{ - 1} [/tex]

so

[tex](x + x {}^{ - 1} ) {}^{2} = {x}^{2} + 2x {}^{0} + {x}^{ - 2} = 3[/tex]

We then simply remeber that x^0=1 so

[tex] {x}^{2} + 2 + \frac{1}{ {x}^{2} } = 3[/tex]

Multiply both sides by x^2.

[tex] {x}^{4} + 2 {x}^{2} + 1 = 3 {x}^{2} [/tex]

Subtract both sides by 3x^2

[tex] {x}^{4} - {x}^{2} + 1 = 0[/tex]

Notice that x^4= (x^2)^2.

So our reformed equation is

[tex]( {x}^{2} ) {}^{2} - {x}^{2} + 1 = 0[/tex]

Let a variable , w equal x^2. This means that we subsitute variable, w in for x^2.

[tex]w {}^{2} - w + 1 = 0[/tex]

Now we use the quadratic formula

[tex] w = \frac{ - b + \sqrt{b {}^{2} - 4ac } }{2a} [/tex]

and

[tex]w = - b - \frac { \sqrt{b {}^{2} - 4ac } }{2a} [/tex]

Let a=1 b=-1 and c=1.

[tex]w = \frac{1 + \sqrt{1 - 4(1)} }{2} [/tex]

[tex]w = \frac{1 - \sqrt{1 - 4} }{2} [/tex]

Now, we get

[tex]w = \frac{1}{2} + \frac{i \sqrt{3} }{2} [/tex]

and

[tex]w = \frac{1}{2} - \frac{ i\sqrt{3} }{2} [/tex]

Now since we set both of these to the x^2 we solve for x.

and

[tex] {x}^{2} = \frac{1}{2} + \frac{i \sqrt{3} }{2} [/tex]

and

[tex] {x}^{2} = \frac{1}{2} - \frac{i \sqrt{3} }{2} [/tex]

We can represent both of these as complex number in the form of a+bi. Next we can convert this into trig form which is

[tex] {x}^{2} = 1( \cos(60) + i \: \sin(60) [/tex]

and

[tex] {x}^{2} = 1( \cos(300) + i \: sin(300))[/tex]

Next we take the sqr root of 1 which is 1, and divide the degree by two.

[tex] {x} = 1( \cos(30) + i \: sin \: 30)[/tex]

and

[tex]x = 1( \cos(150) + i \: sin(150)[/tex]

We are asked for the 2nd root so just add 180 degrees to this and we have

[tex]x = 1 \cos(210) + i \: sin \: 210)[/tex]

and

[tex]x = 1( \cos(330) + i \: sin(330)[/tex]

which both simplified to

[tex]x = - \frac{ \sqrt{3} }{2} - \frac{1}{2} i[/tex]

and

[tex]x = \frac{ \sqrt{3} }{2} - \frac{1}{2} i[/tex]

Now we must find

x^18+x^12+x^6+1.

We just use demovire Theorem. Which is a complex number raised to the nth root is

[tex] {r}^{n} (cos(nx) + i \: sin(nx)[/tex]

So let plug in our first root.

[tex]1( \cos(330 \times 18)) + i \: sin \: (330 \times 18))) + 1( \cos(12 \times 330)) + i \: sin(12 \times 330) + 1( \cos(6 \times 330) + i \: sin(6 \times 330))) + 1[/tex]

To save time we multiply the angle and use rules of terminals angle and we get

[tex]1( \cos(180) + i \sin(180) ) + 1( \cos(0) + i \: sin \:( 0) + 1( \cos(180) + i \: sin(180) + 1[/tex]

And we get

[tex] - 1 + 1 + - 1 + 1 = 0[/tex]

So one of the answer is x=0

And the other, let see

[tex]1 \cos(210 \times 18) + i \: \sin(210 \times 18) + 1 \: cos(210 \times 12) + i \: sin(210 \times 12) + 1 \cos(210 \times 6) + \:i sin(210 \times 6) + 1[/tex]

[tex] \cos(180) + i \: sin(180) + 1 \cos(0) + i\sin(0) +1( \cos(0) + i \sin(0) + 1[/tex]

We get

[tex] - 1 + 1 + 1 + 1 = 2[/tex]

So our answer are 2.

So the answer to the second part is

0 and 2.

Answer:

Step-by-step explanation:

The goal in scientific notation is to express a value in terms of a number that contains a single unit before the decimal point.  

Examples:

10000:  1.0 x 10^4

23456:  2.3456x10^4

In both cases, the x10^4 is telling us to multiply the first number by 10,000.  10^4 is the same as 10x10x10x10 = 10,000

The justification for scientific notation is that is makes expression large and small numbers much easier, as well as reduces errors due to an incorrectly placed decimal.

An example:  Divide 2500000000 by 5000.  That would normally require setting up a long-hand division problem that not only wastes paper and pencil, but is also prone to decimal point errors.

Do the same problem with scientific notation:

Count the places you want to move the decimal point backwards to just beyond the 5 in 2500000000.  It takes nine steps to move the decimal point to between the 2 and 5:  2.5 followed by 8 zeros.  That's a total of next steps to go in front of the 5.  This is written 2.5 x 10^9

5000 is represented by 5.0x10^4

Now when we divide the same numbers, but in scientific format, it is easier to see the answer:

(2.5x10^9)/(5.0x10^4)

2.5/5 = 0.5

10^9/10^4 = 10^5  [The exponents are subtracted when dividing with exponents:  9-4 = 5]

Put them together to find the final answer:  0.5x10^5

Then move the decimal point one spot to the right and reduce the exponent by 1:

5.0x10^4

------

Add exponents when multiplying:  10^3 x 10^5 = 10^8  (3+5=8)

Subtract when dividing:  10^7/10^2 = 10^5  (7-2=5)

Multiply when there is an exponent raised to another exponent:  (10^4)^3 = 10^12 (4x3 = 12)

Answer:

12000000000

Step-by-step explanation:

did I add too many zeros????

10 to the 5 is multiply by 10 five times (100,000)

100,000 x 3 = 300,000

For the second thing, 10 to the 4 = 10,000

10,000 x 4 = 40,000

300,000 x 40,000 = 12000000000

Answer:

x = 15

Step-by-step explanation:

(4x - 30) and (2x) are alternate angles and are congruent , then

4x - 30 = 2x ( subtract 2x from both sides )

2x - 30 = 0 ( add 30 to both sides )

2x = 30 ( divide both sides by 2 )

x = 15

Answer:

D.

Step-by-step explanation:

Answer:

-71

Step-by-step explanation:

Answer:

-71

Step-by-step explanation:

[-18+(-22)]-43+12

=(-18+22)-43+12

=-40-43+12

=-83+12

=-71

Note that

10² = 100

0.08² = 0.0064

and

101.6064 = 100 + 1.6 + 0.0064

It also happens that

1.6 = 2 • 10 • 0.08

which means

101.6064 = 100 + 1.6 + 0.0064

101.6064 = 10² + 2 • 10 • 0.08 + 0.08²

101.6064 = (10 + 0.08)²

101.6064 = 10.08²

which means

√101.6064 = 10.08

which, to one decimal place, is approximately 10.1.

Angles theorem and Reflexive property of congurence

The solution is

Each diagonal of a parallelogram separates it into two congruent triangles

So , ΔABC ≅ ΔCDA

Opposite angles are congruent

So , ∠B ≅ ∠D

What is a Parallelogram?

A parallelogram is a simple quadrilateral with two pairs of parallel sides. The opposite or facing sides of a parallelogram are of equal length and the opposite angles of a parallelogram are of equal measure

The four types are parallelograms, squares, rectangles, and rhombuses

Properties of Parallelogram

Opposite sides are parallel

Opposite sides are congruent

Opposite angles are congruent.

Same-Side interior angles (consecutive angles) are supplementary

Each diagonal of a parallelogram separates it into two congruent triangles

The diagonals of a parallelogram bisect each other

Given data ,

Let the parallelogram be ABCD

Now , AC is a diagonal of the parallelogram

According to the postulates of parallelogram

Opposite sides are parallel

Opposite sides are congruent

Opposite angles are congruent

Same-Side interior angles (consecutive angles) are supplementary

Each diagonal of a parallelogram separates it into two congruent triangles

The diagonals of a parallelogram bisect each other

And ,

From the figure , we can deduct that ΔABC ≅ ΔCDA by

Angle A is congruent to angle C, and angle D is congruent to angle B

So , from congruent triangle theorem ΔABC ≅ ΔCDA

And ,

∠B ≅ ∠D

Because Opposite angles are congruent of a parallelogram

Hence , Each diagonal of a parallelogram separates it into two congruent triangles

So , ΔABC ≅ ΔCDA

Opposite angles are congruent

So , ∠B ≅ ∠D

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Answer:

B.(x − 5)(x − 3)(x + 2)

Hope you could get an idea from here.

Doubt clarification - use comment section.