A 1.20 kg solid ball of radius 40 cm rolls down a 5.20 m long incline of 25 degrees. Ignoring any loss due to friction, how fast will the ball be rolling when it reaches the bottom of the incline?
Answer:
1.6s
Explanation:
Given that A 1.20 kg solid ball of radius 40 cm rolls down a 5.20 m long incline of 25 degrees. Ignoring any loss due to friction,
To know how fast the ball will roll when it reaches the bottom of the incline, we need to calculate the acceleration at which it is rolling.
Since the frictional force is negligible, at the top of the incline plane, the potential energy = mgh
Where h = 5.2sin25
h = 2.2 m
P.E = 1.2 × 9.8 × 2.2
P.E = 25.84 j
At the bottom, K.E = P.E
1/2mv^2 = 25.84
Substitutes mass into the formula
1.2 × V^2 = 51.69
V^2 = 51.69/1.2
V^2 = 43.07
V = 6.56 m/s
Using the third equation of motion
V^2 = U^2 + 2as
Since the object started from rest,
U = 0
6.56^2 = 2 × a × 5.2
43.07 = 10.4a
a = 43.07/10.4
a = 4.14 m/s^2
Using the first equation of motion,
V = U + at
Where U = 0
6.56 = 4.14t
t = 6.56/4.14
t = 1.58s
Therefore, the time the ball rolls when it reaches the bottom of the incline is approximately 1.6s
4- If the length of the pendulum 28 cm and the mass of the bullet (projectile) is 70 g, and the mass of the block 240 g, and the maximum angle reached is ϴ = 44˚. Answer the followings:
a. The maximum height reached.
b. The mechanical energy after collision.
c. The bullet velocity.
bhai I know this answer if you mark as brain last you see my attachment
Which type of star cluster is shown?
Answer:
♡ madeline here ♡
you forgot the attachment, luv ☆
have a great day!
- madeline/madi ✧･ﾟ: *✧･ﾟ:･ﾟ✧*:･ﾟ✧･ﾟ
Explanation:
OPENNNN
I AM CORRECT AND DATS MY NAMEEE OO I BE LIKE 2POC CHAINS:);)
there are approximately 19 billion chickens in the world. If one third of them like to cross the road, how many chickens have gone to the other side?
Answer:
57,000,000,000(fifty-seven billion)
Explanation:
19000000000/ 1/3 = 57000000000
A small child has a wagon with a mass of 10 kilograms. The child pulls on the wagon with a force of 2 Newton’s. What is the acceleration of the wagon?
PHYSICS
Mass = 10 kg
Force = 2 N
Acceleration = ____?
Answers :
[tex]f \: = m \times a[/tex]
2 = 10 × a
2 / 10 = a
0,2 m/s² = a ✅
PLZ HELP!! List properties of ions.
Which TWO statements describe events that help drive tectonic plate movement
A. Energy from the sun heats magma beneath earths surface
B. Convection currents cause hotter magma to rise and cooler magma to sink
C. Thermal energy from earths core is transferred outward to the mantle by conduction
D. Subduction plates cause cooling at convergent boundaries
Answer:
The answer is D & B
Explanation:
I took the quiz on this. I hope this helps!
The two statements describe events that help drive tectonic plate movement are:
B. Convection currents cause hotter magma to rise and cooler magma to sink
D. Subduction plates cause cooling at convergent boundaries
What is a tectonic plate?A tectonic plate (also called lithospheric plate) is a massive, irregularly shaped slab of solid rock, generally composed of both continental and oceanic lithosphere.
Plate size can vary greatly, from a few hundred to thousands of kilometers across; the Pacific and Antarctic Plates are among the largest.
Plate thickness also varies greatly, ranging from less than 15 km for young oceanic lithosphere to about 200 km or more for ancient continental lithosphere (for example, the interior parts of North and South America).
Tectonic plates, large slabs of rock that divide Earth’s crust, move constantly to reshape the Earth’s landscape. The system of ideas behind plate tectonics theory suggests that Earth's outer shell (lithosphere) is divided into several plates that glide over the Earth’s rocky inner layer above the soft core (mantle).
The plates act like a hard and rigid shell compared to Earth's mantle. The mantle sits between Earth's dense, very hot core and its thin outer layer, the crust.
At subduction zones, a convergent boundary occurs when two tectonic plates push together. When an ocean plate and a continental plate collide, the ocean plate slides under the continental plate, and bends downward.
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You are traveling down the highway when you notice a cop 200 meters ahead of you. For the next 5 seconds, you step on the bake to avoid a speeding ticket. The brake causes an acceleration on your car of -2.0 m/s^2.
Answer:
ok, I don't see the question.
Explanation:
A shopping cart given an initial velocity of 2.0 m/s undergoes a constant acceleration of 3.0 m/s2. What is the cart’s displacement after the first 4.0 s of its motion?
What is your car's initial velocity?
How long is the cart accelerating for?
What is the acceleration of the cart?
Write the equation you will use to solve this problem.
What is the displacement of the shopping cart?
32 m
10 m
55 m
80 m
Final Velocity = 14m/s
Displacement = 56m
Explanation:
U (initial velocity) = 2m/s
A (acceleration) = 3m/s^2
T (time) = 4s
v (final velocity) = ?
S (displacement) = ?
FIRST FIND FINAL VELOCITY:
[tex]a = \frac{v - u}{t} [/tex]
(i) Multiply both sides by t:
[tex]a \times t = v - u[/tex]
(ii) Add u to both sides:
[tex](a \times t) + u = v[/tex]
(iii) rearrange formula:
[tex]v = (a \times t) + u[/tex]
v = ( 3 × 4 ) + 2
v = 12 + 2
v = 14m/s
SECOND FIND DISPLACEMENT:
[tex]v = \frac{s}{t} [/tex]
(i) Multiply both sides by t:
[tex]v \times t = s[/tex]
(ii) Rearrange formula:
[tex]s = v \times t[/tex]
s = 14 × 4
s = 56m
Not sure why it isn't one of the options but im pretty sure I did all the steps right...
If a 28-N force causes a rock to accelerate at 4 m/s/s, what is the mass of the rock?
Answer:
Explanation:
we know that
F=ma
F=28 N
a=4 m/s²
m=F/a
m=28/4
m=7 kg
A wave with a frequency of 230 Hz has a wavelength of 0.25 meters. At what speed will this wave travel?
feather is dropped from 13 m high after it has fallen 3 m what is its acceleration
Answer:
Explanation:
The constant acceleration of any object, neglecting air resistance and friction, is always -9.8. Proof:
[tex]s(t)=-4.9t^2+13[/tex] which is the position of this feather before it is dropped. The first derivative of position is velocity, so the velocity function for the feather is:
[tex]v(t)=-9.8t[/tex]. We could find the velocity that the feather is experiencing at 3 seconds, but that is not what we are being asked. What we are being asked is the acceleration of the feather at 3 seconds. So we find the acceleration function of the feather:
a(t) = -9.8
It turns out that the time doesn't matter to acceleration due to gravity because feathers and elephants all fall under the same pull.
A motorcycle has a mass of 240 kg and accelerates at a rate of 4 m/s2
Work out the driving force of the motorcycle.
Solution:
Using
F = m a
F = 240 x 4
F = 960 N
Answer:
960N
Explanation:
Given parameters:
Mass of the motorcycle = 240kg
Acceleration of the motorcycle = 4m/s²
Unknown:
Driving force of the motorcycle = ?
Solution:
According to the Newton's second law of motion "the force on a body is the product of mass and acceleration".
Force = mass x acceleration
Insert the parameters and solve;
Force = 240 x 4 = 960N
wave length of sodium light is 5893A express in nanometre
Answer:
589.3 nm
Explanation:
The wavelength of a sodium light is 5893 A.
We need to find the wavelength in nm.
[tex]5893\ A=5893\times 10^{-10}\ m[/tex]
Also, [tex]1\ nm=10^{-9}\ m[/tex]
[tex]5893\ A=5893\times 10^{-9}\times 10^{-1}\ m\\\\=5893\times 10^{-1}\ nm\\\\=589.3\ nm[/tex]
So, the wavelength of sodium light is 589.3 nm.
Parallel circuits:
O A. provide more than one path for current flow.
O B. will have positive charges flowing in one branch, negative charges
in the other.
C. always need more voltage than series circuits.
O D. are rarely used in the wiring in homes.
Answer:
Provide more than one path for current flow. (answer option A)
Explanation:
When one connects resistors in parallel, one provides more than a single path for the current to flow. The current separates on each branch according to the resistance it experiences.
A force of 1.50 N acts on a 0.20 kg trolley so as to accelerate it along an air track. The track and force are horizontal and in line. How fast is the trolley going after acceleration from rest through 30 cm, if friction is negligible?
Answer:
Final velocity, V = 2.1213 m/s.
Explanation:
Given the following data;
Force, F = 1.50N
Mass, m = 0.2kg
Displacement, S = 30cm to meters = 30/100 = 0.3m
To find the acceleration;
Force is given by the multiplication of mass and acceleration.
Mathematically, Force is given by the formula;
[tex] F = ma[/tex] .......equation 1
Where;
F represents force.m represents the mass of an object.a represents acceleration.Making acceleration (a) the subject, we have;
[tex]Acceleration (a) = \frac{F}{m}[/tex]
Substituting into the above equation, we have;
[tex]Acceleration, a = \frac{1.5}{0.2}[/tex]
Acceleration, a = 7.5m/s²
Now to find the final velocity, we would use the third equation of motion;
[tex] V^{2} = U^{2} + 2aS [/tex] .....equation 2
Where;
V represents the final velocity measured in meter per seconds. U represents the initial velocity measured in meter per seconds. a represents acceleration measured in meters per seconds square. S represents the displacement measured in meters.Note: Since the trolley is starting from rest, we know that it's initial velocity is 0.
Substituting the values into equation 2, we have;
[tex] V^{2} = 0^{2} + 2*7.5*0.3[/tex]
[tex] V^{2} = 0 + 4.5[/tex]
[tex] V^{2} = 4.5[/tex]
Taking the square root, we have;
[tex] V = \sqrt {4.5}[/tex]
V = 2.1213 m/s.
Therefore, the speed of the trolley after accelerating from rest through 0.3 m, if friction is negligible is 2.1213 m/s.
Two lenses with focal lengths 10cm and 20cm and made of same material are placed coaxially
separated by distance d. The value of d such that the system is achromatic is
A) 20 om
) 30cm
C) 10 cm
D) 15 cm
There is more than one answer
Explanation:
the answers are the first 3.
Answer:
4.6
Explanation:
Ans is 4.6 b coz the difference b/w 4.6 and the other values is comparitively the largest.
Identify the wavelength of this wave.
Answer:
A
Explanation:
The line(A) goes throughout the entire picture. So therefore choice A would be it's length.
Superman strikes a golf ball on the ground at a 38 degree angle above the horizontal at 147 m/s. What is the maximum height the golf ball reaches?
255 m
418 m
687 m
1103 m
The ball is hit with an initial vertical velocity of
(147 m/s) sin(38º) ≈ 90.5 m/s
Recall that
v ² - u ² = 2 a ∆y
where u and v are initial and final velocities, respectively; a is acceleration; and ∆y is displacement.
Vertically, the ball is in freefall, so it is only subject to acceleration due to gravity, with magnitude g = 9.80 m/s² in the downward direction. At its maximum height, the ball has zero vertical velocity (v = 0) and the displacement is equal to the maximum height, so
0² - (90.5 m/s)² = 2 (-g) ∆y
∆y = (90.5 m/s)² / (2g)
∆y ≈ 418 m
Which condition must be met in order for an equation to be balanced? The elements in the reactants are the same as the elements in the products. There are fewer elements in the reactants than there are in the products. The number of atoms in the reactants is greater than the number of atoms in the products. The number of atoms in the reactants equals the number of atoms in the products
Answer:
The elements in the reactants are the same as the elements in the products
Explanation:
The condition for a balanced equation is as follows :
The number of atoms for each element in reactant = Number of atoms for each element in product.
Total charge on reactant and product must be same.
The example of a balanced equation is:
Reaction of carbon and hydrogen :
[tex]C+2H_2\rightarrow CH_4[/tex]
No. of carbon atom on Carbon on LHS = 1
No. of carbon atom on Hydrogen on LHS = 4
No. of carbon atom on Carbon on RHS = 1
No. of carbon atom on Hydrogen on RHS = 4
So, for a balanced equation, The elements in the reactants are the same as the elements in the products. Hence, the correct option (a).
Answer:
The answer is A
Explanation:
Look at the Kunoichi's of Naruto but as a Gang.
Who do you think looks the baddest out of the group(but in a good way)?
My opinion is Hinata...just saying
Answer:
hinata for sure
Explanation:
seems reasonable
An ultrasound machine is being used to try to identify potential kidney stones. The machine is working properly and no kidney stones are found. Which statement best describes this situation? The generated sound wave will not be able to reflect off of the object. The sound wave will not be generated, so there will be no echoes received. The echoes will be made but will not be able to be received by the machine. The machine will not be able to process the received echoes into images.
Answer:
The generated sound wave will not be able to reflect off of the object.
Explanation:
The statement that best describes this situation is: The generated sound wave will not be able to reflect off of the object.
What is an Ultrasound Machine?An ultrasound machine is a device that is used to capture images in the human body for review by a medical examiner. The machine gives off sound waves that are reflected off body structures.
So, for the ultrasound machine being described, the absence of kidney stones will cause a non-reflection of the object to be captured.
Since the machine is in good working condition, the sound wave will be generated.
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Gertrude writes a short story in which the main character must enter a nuclear-powered spaceship’s engine room that has lost its shielding in order to prevent the engine from flooding the rest of the ship with radiation. The main character is not wearing protective gear.
What effects are best for Gertrude to consider when planning what may happen to the character?
non-stochastic effects such as possible DNA mutations later in life resulting from the short-term, high-level exposure
non-stochastic effects such as severe burns and radiation sickness resulting from the short-term, high-level exposure
stochastic effects such as possible DNA mutations that are unlikely to occur from the single, low-level exposure
stochastic effects such as severe burns and radiation sickness resulting from the long-term, low-level exposure
Answer: (B) non-stochastic effects such as severe burns and radiation sickness resulting from the short-term, high-level exposure
Explanation: edgeunity
The impact of best for Gertrude to consider when planning what may happen to the character is non-stochastic effects.
What are non-stochastic effects?
It is that impact where incidence and severity based on dose.
Since as per the given situation, Gertrude writes a short story so here the character should be considered as the non-stochastic effects like burning and the radiation sickness that leads from the short term and high level of exposure.
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What is conflict resolution?
Open with
Part 2. Problem Solving
Directions: Follow the GUESS Method of solving problem to get full credit for your works
1. A kid throws a rock off the edge of a cliff 60.0 m high. When he drops the rock, it takes 5,0
sec for it to reach the ground below.
a.) Determine the time it takes to reach the ground below, and
b.) How long would it take the rock to hit the ground if he threw it down with a speed of 15
m/sec?
is hit stmight upward and reach a maximum height of 80.0 m.
Answer:
A.) 5s
B.) 2.29s
C.) 39.6 m/s
Explanation:
Given that a kid throws a rock off the edge of a cliff 60.0 m high. When he drops the rock, it takes 5,0sec for it to reach the ground below.
a.) Determine the time it takes to reach the ground below,
The time is 5s
b.) How long would it take the rock to hit the ground if he threw it down with a speed of 15m/sec?
Using the second equation of motion:
H = Ut + 1/2gt^2
Substitute all the parameters into the formula
60 = 15t + 1/2 × 9.8 × t^2
60 = 15t + 4.9t^2
Multiply all by 10
49t^2 + 150t - 600
t^2 + 3.06t = 12.24
( t + 1.53)^2 = 12.24 + 2.3409
t + 1.53 = sqrt ( 14.5809)
t = 3.82 - 1.53
t = 2.29s
is hit stmight upward and reach a maximum height of 80.0 m.
Using the third equation of motion
V^2 = U^2 - 2gH
At maximum height, V = 0
0 = U^2 - 2 × 9.8 × 80
U^2 = 1568
U = sqrt ( 1568)
U = 39.6 m/s
can someone help me???
Answer:
The correct answer is A. 8.0. In 2011, no fertiziler was added to the soil so the pH was not affected.
Adam takes a bus on a school field trip. The bus route is split into the five legs listed in the table. Find the average velocity for each leg of the trip. Then arrange the legs of the trip from highest velocity to lowest. Leg Distance (km) Time (min) A 18 9 B 25 15 C 24 8 D 48 12 E 15 7 leg A leg B leg C leg D leg E
Answer:
The answer is:
VA= 33 m/S
VB= 27.8 m/s
VC= 50 m/s
VD=66.7 m/s
VE=35.7 m/s
So, the Legs from the highest velocity to the lower are:
D - C - E - A - B
The explanation:
we are going to use the velocity formula:
Velocity = distance (m) / time (s)
So,
A) when D = 18 Km = 18000 m
and t = 9 min = 9*60 =540 s
So V = 18000m/ 540 S
= 33 m/S
B) when D = 25 Km = 25000 m
and t = 15 min = 15 * 60 = 900 S
So V = 25000m / 900S
= 27.8 m/s
C) when D = 24 Km = 24000 m
and t = 8 min = 8 * 60 = 480 s
So V = 24000m / 480s
= 50 m/s
D) when D = 48 Km = 48000 m
and t = 12 min = 12 * 60 = 720 s
So V = 48000 m / 720s
=66.7 m/s
E) when D = 15 km = 15000m
and t = 7 min = 7 * 60 = 420 s
So V = 15000m / 420s
= 35.7 m/s
a mule pulls a cart of milk 10 meters, with a force of 50 newtons calculate the work done by the mule
Answer:
500 JExplanation:
The work done by an object can be found by using the formula
workdone = force × distance
From the question we have
workdone = 50 × 10
We have the final answer as
500 JHope this helps you
Which formula can be used to find the tangential speed of an orbiting object? v = StartFraction 2 pi r over T EndFraction v = StartFraction square root of 2 pi r over T EndFraction v = GStartFraction m Subscript central Baseline over r EndFraction v = rStartFraction (m Subscript central Baseline) over G EndFraction
Answer:
It's A v=2pi/T
Explanation:
I took the test and got it correct.
The correct formula that can be used to find the tangential speed of an orbiting object is : ( A ) v = 2π r /T
Tangential speedTangential speed is the speed or velocity of an object moving in a circular path is calculated as 2π r/T where T = time it takes to complete one rotation and 2π r is angular velocity( w ).
Therefore from the options listed above the correct expression for the tangential speed is v =2π r /T
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