m || n, find the value of x.
m
n
(6x+16)⁰
(8x-18)°
Please help! I’ll give good review

The correct answer is option B which is u = ( x³ + 1).

The polynomial having a degree of two or the maximum power of the variable in a polynomial will be 2 is defined as the quadratic equation and it will cut two intercepts on the graph at the x-axis.

Given expression is as follows:-

16(x³ + 1)² − 22(x³ + 1) − 3 = 0

Put u = ( x³ + 1) the equation will become:-

16u² -22u-3 = 0

Now the above equation has become a quadratic equation.

Therefore the correct answer is option B which is u = ( x³ + 1).

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1 + 2 + 3 + 4 + 5 + 95 + 96 + 97 + 98 + 99. = 500

Answer:

500

Step-by-step explanation:

rearrange the sum as

(99 + 1) + (98 + 2) + (97 + 3) + (96 + 4) + (95 + 5)

= 100 + 100 + 100 + 1000 + 100

= 5 × 100

= 500

Answer:

Choice C:   [tex]m=\frac{1}{2}; y=\frac{1}{2} x+4[/tex]

Step-by-step explanation:

To find your slope do:

[tex]\frac{y^2-y^1}{x^2-x^1}[/tex]

[tex]\frac{3-4}{-2-0}=\frac{-1}{-2} =\frac{1}{2}[/tex]

that's how you get 1/2

4 is just the y-int.

The required equation of line passes through (0, 4) and (-2, 3),  has slope of m = 1/2 , is y = 1/2x + 4. Option C is correct.

The equation is the values of two expressions that are equal.

The slope of the line is the tangent angle made by the line with horizontal. i.e. m =tanx where x in degrees.

The slope of the equation line passing through (0, 4) and (-2, 3)
[tex]m=\frac{y_2-y_1}{x_2-x_1} \\m = (3 - 4) / (-2-0)\\m = -1/-2\\m = 1/2[/tex]

Strand form of the equation of the line,
[tex]y-y_1 = m(x-x_1)[/tex]
Putting values in the standard form of the equation of the line.

y - 4 = 1/2 * (x - 0)
y = 1/2 * x + 4
[tex]y = \frac{1}{2} x + 4[/tex]

Thus, the required equation of line passes through (0, 4) and (-2, 3),  has slope of m = 1/2 , is y = 1/2x + 4. Option C is correct.

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The order the investments from least to greatest return,

tax bracket is 22% and tax-free yield is 3%  <  tax bracket is 35% and tax-free yield is 3%  <  tax bracket is 24% and tax-free yield is 4%  <  tax bracket is 12% and tax-free yield is 5%  <  tax bracket is 12% and tax-free yield is 5%

A fraction is written in the form of p/q, where q ≠ 0.

Fractions are of two types they are proper fractions in which the numerator is smaller than the denominator and improper fractions where the numerator is greater than the denominator.

We know the value of a fraction gets larger when the numerator becomes larger and the denominator gets smaller.

Given, Each tile shows an investor’s tax bracket along with the tax-free yield of a bond the investor purchased.

(tax-free yield)/(100 - tax bracket).

Now, tax bracket is 24% and tax-free yield is 5%.

= 5/100 - 24.

= 5/76.

= 0.0658.

Similarly,

tax bracket is 12% and tax-free yield is 5%

= 0.0641.

tax bracket is 22% and tax-free yield is 3%

= 0.0384.

tax bracket is 24% and tax-free yield is 4%

= 0.0526.

tax bracket is 35% and tax-free yield is 3%

= 0.0461.

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The option (C) f(x) = (x+2)(x-3)²(x+4) is correct because in the graph the minimum value of function is less than 40.

Polynomial is the combination of variables and constants systematically with "n" number of power in ascending or descending order.

[tex]\rm a_1x+a_2x^2+a_3x^3+a_4x^4..........a_nx^n[/tex]

We have a graph of a polynomial.

From the graph we can clearly see there is three x-intercept where the value of a polynomial function becomes zero.

The minimum value of function is less than 40

At x = 3, f(3) = 0

At x = -2, f(-2) = 0

At x = -4, f(-4) = 0

Thu graph of a function will be:

[tex]\rm y\ =\ \left(x+2\right)\left(x-3\right)^{2}\left(x+4\right)[/tex]

Thus, the option (C) f(x) = (x+2)(x-3)²(x+4) is correct because in the graph the minimum value of function is less than 40.

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The complete question is

"Triangle QST is isosceles, and Line segment R T bisects AngleT. Triangle Q S T is cut by bisector R T. The lengths of sides S T and Q T are congruent. Line segments S R and R Q are congruent. Angles S T R and R T Q are congruent. What is true about AngleQRT?

Select two options. Measure of angleQRT = 90° Measure of angleQRT = Measure of angleSRT AngleQRT Is-congruent-to AngleSTQ Measure of angleQRT = 2*Measure of angleRTQ AngleQRT Is-congruent-to AngleRTQ"

The true about AngleQRT options are A abd B; ∠QRT = 90 and ∠QRT = ∠SRT

Two triangles are said to be congruent if the length of the sides is equal, a measure of the angles are equal and they can be superimposed.

Given information;

The triangle QST is isosceles with QT ≅ ST.

The ∠STR and ∠RTQ are congruent.

Now, consider two triangles ∠QTR and ∠STR

In the following triangle

TR  ≅  TR

QTR ≅ STR

QT ≅ ST

Now, according to SAS rule, two congruent triangles have congruent corresponding to their sides,

1. QR ≅ SR

2. QRT ≅ SRT

Since the above two angles are congruent so, they will have the same measure

That will be 90 degree.

Hence, The correct options are; ∠QRT = 90 and ∠QRT = ∠SRT

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Answer:

Its Option C.

Step-by-step explanation:

I took this quiz and got this correct, atleast I think...??

Answer:

20

Step-by-step explanation:

Answer:

the one above me is WRONG, its 40 i swear i just did the unit test

Step-by-step explanation:

The rise from the ground by the skateboard is 5.5 inches

The length of the skateboard is given as:

Length (l) = 18 inches

The angle of elevation (x) is

x = 17∘

Represent the height with h.

The value of h is calculated using the following tangent ratio:

tan(x) = h/l

Make h the subject

h = l * tan(x)

Substitute known values

h = 18 * tan(17)

Evaluate

h = 5.5

Hence, the rise from the ground by the skateboard is 5.5 inches

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Answer: 5.3

Step-by-step explanation:

S​OH-CAH-TOAsin 17=oppositehypotenuse=x18sin 17=hypotenuseopposite​=18x​sin 17=sin 17=  x1818x​sin 171=1sin 17​=  x1818x​18 sin 17=18 sin 17=  xxx=5.262690...≈5.3x=5.262690...≈5.3

The point at which three or more lines intersect is the point of concurrency.

The point were three lines meet or intersect is a point of concurrency.

In other words, a point of concurrency is where three or more lines intersect in one place.

This point of concurrency is a single point shared by three or more lines.

Perpendicular bisectors, and altitudes are concurrent in every triangle.

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Answer:

concurrency

Step-by-step explanation:

Look above for more

∠ KGH is equal to 77°. This is arrived at by using the knowledge of the total angles in Parallel Lines.

According to the laws of lines and angles, the total number of angles that can exist on a straight line is 180°.

If ∠CED = 25° and ∠BFL = 78°, then: ∠KGH = 180-(25+78), which is equals 77°. This is because the total angles on a straight-line total 180°

Recall that in angles in parallel lines:

Hence,

We can derive ∠LKJ because it is congruent with ∠BGJ.

To get ∠BGJ, we must get ∠LFH because both of them are interior angles and sum up to 180°.

To get ∠LFH, we must subtract ∠BFL from 180° because they are both angles on a straight line.

Hence ∠LFH = 180 - 78 = 102°

Recall that ∠LFH and ∠BGJ are interior angels. Hence

∠BGJ = 180 - 102 = 78°.

Since ∠BGJ is a corresponding ∠ with ∠LKJ, therefore

∠LKJ = 78°

∠ALM is ∠BFL because they are both corresponding angles and are therefore congruent.

     2. The name given to the triangle mentioned above is Obtuse      

          Triangle. This is because one of the angles exceeds 90°.

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They spend about three hours a day online

Answer:

32m²

Step-by-step explanation:

r=

[tex] \frac{c}{2\pi } [/tex]

r=20/(2×3.14)= 3.18m

A=pi r² = 3.14x3. 18² = 32m²

Tess and Jack are both correct with their claims

The attached image completes the question

From the complete question, we have the following highlights

The above properties represent a square

A rhombus can also have the above properties when the vertices are at 90 degrees

Hence, Tess and Jack are both correct with their claims

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We will use graphical way to solve these

Graph both

The solutions are

None of the above

The range of possible values that best describes an estimate for the population parameter is; (0.5, 0.8)

The range of possible values that best describes an estimate for the population parameter is; (0.5, 0.8).

When we are talking about population parameters, we also have to look at the way of estimating the population, we have to add two extremes and divide by 2.

Thus, the correct one is;

(0.5 + 0.8)/2 = 0.65

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Answer: 450

Step-by-step explanation:

The volume is (1/2)(5)(12)(15)=450.

Answer:

i hope this will help you

Answer:

would need to see the graph

Step-by-step explanation:

see answer advice

Answer:

ok umm this looks hard can u give mor info?

Step-by-step explanation:

Answer:

x=9

y=4

z=4

Step-by-step explanation:

9x-13=7x+5

9x-7x=5+13

2x=18

x=18/2=9

3y=12

y=12/3=4

11z-41=5z-17

11z-5z=-17+41

6z=24

z=24/6=4

Answer:

3.94

Step-by-step explanation:

3.944     rounded to nearest hundredth  = 3.94    becuase the thousandth digit is <5  you do not change the hundredth

The following needs to be purchased in addition to renter's insurance;

Renter’s insurance is a policy which covers the loss of people renting or subletting a property. It helps to protect against loss of properties within the insured apartment.

Here are some problems covered by renters insurance:

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Answer:

Number 40 appeared in Pattern B. Also, according to the rule, each pattern will increase.

Step-by-step explanation:

Let's develop each sequence. Remembe that the rule is "add 15", that's what we need to create each sequence starting from the given initial number.

Pattern A.



Pattern B.



Pattern C.



As you can observe, number 40 appeared in Pattern B. Also, according to the rule, each pattern will increase

Answer:

36

Step-by-step explanation:

If x = 2 and y = -3...

xy^2=

(2)(-3)^2 =

-6^2 =

36

XY times 2=

(-6)(2) =

-12

Answer:

18

Step-by-step explanation:

First you must fill input the values into their variable counterparts:

xy^2 turns into: 2 * -3 ^2

Since there isn't a parenthesis around x AND y, the exponent only applies to the y value.

-3 ^2 = 9, so 2 x 9 = 18

xy^2 = 18 if x =2 and y = -3

Answer:84

Step-by-step explanation:

Okay. Are you taking calc? Dv/dt =d/dt(L(t)^3)=d/dt[(sqrt(14)+2t)^3]= 6(Sqrt(14)+2t)^2)=44. We defined t=0 to be time at which length is sqrt(14). Does that work?

The degree of a polynomial is the highest exponent of the algebraic expression.

[tex]6 {x}^{2} \: + \: {x}^{ \boxed{ \bold{9}}} \: + \: 5 {x}^{7} \: + \: 20 {x}^{6} [/tex]

Step-by-step explanation:

Vertical asymptote can be Identites if there is a factor only in the denominator. This means that the function will be infinitely discounted at that point.

For example,

[tex] \frac{1}{x - 5} [/tex]

Set the expression in the denominator equal to 0, because you can't divide by 0.

[tex]x - 5 = 0[/tex]

[tex]x = 5[/tex]

So the vertical asymptote is x=5.

Disclaimer if you see something like this

[tex] \frac{(x - 5)(x + 3)}{(x - 5)} [/tex]

x=5 won't be a vertical asymptote, it will be a hole because it in the numerator and denominator.

Horizontal:

If we have a function like this

[tex] \frac{1}{x} [/tex]

We can determine what happens to the y values as x gets bigger, as x gets bigger, we will get smaller answers for y values. The y values will get closer to 0 but never reach it.

Remember a constant can be represent by

[tex]a \times {x}^{0} [/tex]

For example,

[tex]1 = 1 \times {x}^{0} [/tex]

[tex]2 = 2 \times {x}^{0} [/tex]

And so on,

and

[tex]x = {x}^{1} [/tex]

So our equation is basically

[tex] \frac{1 \times {x}^{0} }{ {x}^{1} } [/tex]

Look at the degrees, since the numerator has a smaller degree than the denominator, the denominator will grow larger than the numerator as x gets larger, so since the larger number is the denominator, our y values will approach 0.

So anytime, the degree of the numerator < denominator, the horizontal asymptote is x=0.

Consider the function

[tex] \frac{3 {x}^{2} }{ {x}^{2} + 1} [/tex]

As x get larger, the only thing that will matter will be the leading coefficient of the leading degree term. So as x approach infinity and negative infinity, the horizontal asymptote will the numerator of the leading coefficient/ the leading coefficient of the denominator

So in this case,

[tex]x = \frac{3}{1} [/tex]

Finally, if the numerator has a greater degree than denominator, the value of horizontal asymptote will be larger and larger such there would be no horizontal asymptote instead of a oblique asymptote.