Mr. Assan had 492 tickets left after the movie. He started with 2,009 tickets. How many tickets did Mr. Assan sell?

Answers

Answer 1

Answer:

1,517

Step-by-step explanation:

2,009 - 492 = 1,517

Answer 2
2,009-492=1,575
He started out with 2,009 he had 492 left over so subtract that from the amount he started out with and you get the answer

Related Questions

Kobe drinks
cup of juice each day. He has
juice left. For how many days will it last?
Show your answer as a multiplication
equation with 1/3 as a factor. Remember,
you can write 2 1/3 as a fraction.

Answers

1/6 _12/85/907 4456

first put h then a then aaaaaaaaaaaaaaaaaaaaaaa then hah

Find m=FGP if m=FGP = x + 8, m=FGH = 100°, and
m=PGH =6x + 8
Please Please help, no links

Answers

6x+8=100
6x=92
X= 15.33 or x =15 1/3

Solve 1/3(3.2×1.4)2.8

Simplify your answer​

Answers

4 68⁄375 is the purpose answer

The sum of the angles of a polygon is 2160. How many sides does the polygon have?

Answers

Answer:

14 sides

Step-by-step explanation:

Sum of the interior angles of a polygon is given by the formula (n-2)180°. So (n-2)180° = 2160°. So the polygon has 14 sides.

A football field is a rectangle 80 meters wide and 110 meters long. Coach Trevor asks his players to run from one corner to the other corner by running diagonally across the field. What is the distance from one corner of the field to the other corner? Answer choices are rounded to the nearest meter.

Answers

Answer:

136

Hypothenus² = Opposite² + Adjacent²

H²= 110² + 80²

H²= 18500

H= √18500

H = 136m

The ceiling of Stacy's living room is a square that is 25 ft long on each side. Stacy
knows the diagonal of the ceiling from corner to corner must be longer than 25 ft,
but she doesn't know how long it is.
Solve for the length of the diagonal of Stacy's ceiling in two ways:
(a) Using the Pythagorean Theorem.
(b) Using trigonometry.
Round each answer to the nearest whole number and make sure to show all your
work. (Hint: the answers should be the same!)
Please help !!!

Answers

Answer:

A. 35 ft.

B. 35 ft

Step-by-step explanation:

Please see attached photo for diagram.

A. Determination of the diagonal using pythagorean theorem.

A square has all sides equal. Thus, the diagonal of the square can be obtained as follow:

Ist leg (L₁) = 25 ft

2nd leg (L₂) = 25 ft

Diagonal (d) =?

d² = L₁² + L₂²

d² = 25² + 25²

d² = 625 + 625

d² = 1250

Take the square root of both side

d = √1250

d = 35 ft

B. Determination of the diagonal using trigonometry.

Since all the sides in a square are equal, the angle between each leg will be 90°. Thus, the diagonal will bisect the angle between the two leg equally i.e

Angle between Diagonal and each leg = 90/2 = 45°

Finally, we shall determine the length of the diagonal. This can be obtained as follow:

Angle θ = 45°

Opposite = 25 ft

Hypothenus = d

Sine θ = Opposite / Hypothenus

Sine 45 = 25 / d

0.7071 = 25 / d

Cross multiply

0.7071 × d = 25

Divide both side by 0.7071

d = 25 / 0.7071

d = 35 ft

Which fraction is equivalent to 12/27? help

Answers

[tex]\begin{gathered}\dfrac{12}{27}=\dfrac{12:3}{27:3}=\dfrac{4}{9}\\\\\dfrac{12}{27}=\dfrac{12\cdot2}{27\cdot2}=\dfrac{24}{54}\\\\\dfrac{12}{27}=\dfrac{4}{9}=\dfrac{4\cdot2}{9\cdot2}=\dfrac{8}{18}\\\vdots\end{gathered}[/tex]

Hope This Helps You

Answer:

[tex]\huge\boxed{Answer\hookleftarrow}[/tex]

Fractions equivalent to [tex] \frac{12}{27} [/tex] are :-

1st Fraction :-

[tex] \frac{12 \div 3}{27 \div 3} \\ = \frac{4}{9} [/tex]

2nd Fraction :-

[tex] \frac{12 \times 2}{27 \times 2} \\ = \frac{24}{54} [/tex]

3rd Fraction :-

[tex] \frac{12 \times 3}{27 \times 3} \\ = \frac{36}{81} [/tex]

3 fractions equivalent to [tex] \frac{12}{27} [/tex] are [tex] \frac{4}{9} , \: \frac{24}{54} , \: \frac{36}{81} [/tex]

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ

# ꧁❣ RainbowSalt2²2² ࿐

In the triangle below..

Answers

Answer:

44

Step-by-step explanation:

Step 1: Create an equation to solve for ∠Z

Recall that trig ratio tangent = Opposite over Adjacent

Opposite of ∠Z = 75 and adjacent of ∠Z = 79

Hence, [tex]tan(z)=\frac{75}{79}[/tex]

We now solve for z

Step 1: Multiply each side by the inverse of tan ( tan ) ^-^1

[tex]tan(z)*tan^-^1=z\\tan^-^1(\frac{75}{79} )=43.51213147[/tex]

We're left with z = 43.51213147

Our last step is to round to the nearest degree,

We get that ∠Z = 44

The answer is 44 hope this helps

Help me pls !!!!! Rlly need it

Answers

Answer:

its ajwhwowhwkwuquwwyqkqhqoagwkw6shsossgsjiwhesishsisjsjsishwiwgaisujwwisu

Answer:



Solution: jajajajajajajjajajajaj

A semi-circle with a diameter of 6 cm sits on top of an isosceles trapezoid. Find the area of the entire figure.

Answers

Answer:

86.13 cm²

Step-by-step explanation:

the area of the entire fig =

(½×3.14×3²) + (½×(10+6)×9)

= (14.13)+(72) = 86.13

PLEASE HELP! 20 POINTS!!

The tops of two tables in a furniture store are similar rectangles as shown below.


The length of the larger tabletop is 12 feet. What is its width, x?

Answers

Answer:

X = 8

Step-by-step explanation:

WILL GIVE BRAINLIST
MATH




CONVERT EACH MEASUREMENT

SHOW STEPS ALL


9 1/8 lbs to ounces

Answers

Answer:

146 Ounces.

Step-by-step explanation:

9.125 [tex](\frac{1}{8})[/tex] lbs to ounces.

Multiply the mass value by 16.

To Check Work:

Divide 146 by 16 which equals [tex]\frac{73}{8}[/tex]/ 9.125.

Divide 146 by 9.125 [tex](\frac{1}{8})[/tex] which equals 16.

An advertising company charges $40 per half - page advertisement and $75 per full-page advertisement. Michael has a budget of $800 to purchase 13 advertisements. A) Define a variable for each unknown. Write a system of equations to represent the situation. B( How many half-page advertisements does Michael purchase? Show Your Work. C) How many full-page advertisements does Michael purchase? Show your Work. ( Will Mark Brainliest but have to show work) Answer A, B & C. No links or nonsense answers please.​

Answers

A) let h = number of half page ads and f = number of full page ads
40h + 75f = 800. Assuming budget is fully spent
h + f = 13

B) 75h + 75f = 975 (multiplying the second equation by 75)
35h = 175 (subtracting the first equation)
h = 5
Michael purchases 5 half page adverts

C) 5 + f = 13 (Substituting for h in second equation)
f = 8
Michael purchases 8 full page adverts

The number of half page advertisements that Michael purchased is 5 while the full page advertisements is 8.

Let the number of half page ads be represented by h

Let the number of full page ads be represented by f.

Therefore, the system of equations to represent the situation will be:

h + f = 13 ....... i

40h + 75f = 800 ........ ii

From equation i,

h = 13 - f ....... equation iii

Put the value of h into equation ii

40h + 75f = 800

40(13 - f) + 75f = 800

520 - 40f + 75f = 800

Collect like terms

75f - 40f = 800 - 520

35f = 280

f = 280/35

f = 8

The number of full-page advertisements that Michael purchased is 8.

Since h + f = 13

h + 8 = 13

h = 13 - 8

h = 5

The number of half page advertisements that Michael purchased is 5.

Read related link on:

https://brainly.com/question/24429956

A) Do the following lengths form a right triangle? Prove it by SHOWING YOUR WORK. 0 6 8 9

Answers

Answer:

friend me on here and imma send you the link Step-by-step explanation:

Let ​g(t)= t−16 t−4. a. Make two​ tables, one showing the values of g for t=15​.9, 15​.99, and 15.999 and one showing values of g for t=16​.1, 16​.01, and 16.001. b. Make a conjecture about the value of limt→16 t−16 t−4.

Answers

Answer:

[tex]\lim_{t \to \ 16} (t-16)(t-4) =0[/tex]

Step-by-step explanation:

g(t)= (t-16)(t-4)

(a) Then, we have,

t                       g(t)

15.9                 -1.19

15.99            -0.1199

15.999       -0.011999

Also, we have,

t                         g(t)

16.1                     1.21

16.01                 0.1201

16.001             0.012001

(b) We can see, from the above table that as 't' tends to 16 from the left hand side, the value of g(t)= (t-16)(t-4) is tending to 0 from the negative direction.

Similarly, from the second table, we can see that as 't' tends to 16 from the right hand side, the value of g(t)= (t-16)(t-4) is tending to 0 from the positive direction.

Thus, we can say that [tex]\lim_{t \to \ 16-} (t-16)(t-4)[/tex] & [tex]\lim_{t \to \ 16+} (t-16)(t-4)[/tex], i.e., the left hand limit and right hand limit of g(t)= (t-16)(t-4), at t=16, both exist and is both equal to 0.

Since both these limits exist and are equal, we can say, [tex]\lim_{t \to \ 16-} (t-16)(t-4) = \lim_{t \to \ 16+} (t-16)(t-4) = \lim_{t \to \ 16} (t-16)(t-4) = 0[/tex]

Find the sum of the first four terms of the geometric series 5 + 50 + 500+....

Answers

The answer is 5 + 50 + 500+5000= 5555

I NEEED HELPPPPPPPPP!!!!!

Answers

I believe the answer would be 50

for homework lawl
Evaluate each expression when x is 4 and y is 6.
(6-x)3 + y

Answers

Maybe I'm not sure 0
You just plug in 4 for x and then 6 for y. So it would be (6-4)3+6.

Then use the order of operations.

So (6-4)3+6=(10)3+6=30+6=36

So the answer is 36

the equation s=2√5x can be used to estimate the speed ,s,of a car in milles per hour, given the length in feet ,x, of the tire marks it leaves on the ground .A card travelling 90 miles per hour came to a sudden stop according to the equation ,how long would the tire marks be for this car A 355 feet B 380 feet C 405 feet D 430 feet

Answers

Answer:

405 feet

Step-by-step explanation:

s = 2 * (√5) * 90

s = 2 * 201.246117975

s = 402.49223595

Closest estimate

405 feet

Answer:

Since The equation that depicts the motion of the Car is given.

The speed in terms of the tire marks...

s= 2√5x

where x is the tire marks(in feet.)

s is the speed(miles per hr)

We can't use the speed in Miles per hr when the tire mark is feet.

1mile = 5280ft

90miles x 5280ft/1mile = 475,200ft/hr

Making x the subject

x= s/2√5

x= 475/200/(2√5 )

=106,257ft

I still can't see what I'm missing or You sure you didn't forget to add something else to the question?

Calculate the radius of the below. Show all work.

Area -0.25 ft

Answers

Answer:

r ≈ 0.28

Step-by-step explanation:

[tex]r=\sqrt{\frac{A}{\pi } }[/tex]

[tex]r=\sqrt{\frac{0.25}{\pi } }[/tex]

0.28209

≈ 0.28

Hi I need help plz help

Answers

Answer: 120

Step-by-step explanation:

5/3 X 4/3 X 2= 40/9

40/9 Divided by 1/3

40/3

Find the values of X and Y. Show your work.

Answers

Answer:

x = 6

y = 24

Step-by-step explanation:

Recall: length of corresponding sides of similar figures are proportional to each other.

Thus:

4/12 = x/18 = 8/y

Find x:

4/12 = x/18

1/3 = x/18

Cross multiply

3x = 18

3x/3 = 18/3

x = 6

Find y:

4/12 = 8/y

1/3 = 8/y

Cross multiply

y = 8*3

y = 24

how to do this.If you dont understand my language use the english​

Answers

Nisbah sebara : nisbah yg mempunyai bentuk terendah yg sama

Pasangan nisbah yang berkadaran : nisbah yg mempunyai bentuk terendah yg sama

PROBLEM 1. Veldora walked around the circular pool. The circular pool has a
diameter of 3 meters. What is the distance that Veldora has walked?
Step 1 – Read and understand
What is asked in the problem? ____________________________
What do you know of the problem?________________________
Step 2 – Plan
What must be done to solve the problem? _________________
Step 3 – Solve and answer ___________________________
Carry out the plan & write the final answer. _______________
Step 4 – Check
Is the answer correct? _______________________
PROBLEM 2. How much greater is the circumference of the circle with a diameter of
12m than another circle with a radius of 5m?
Step 1 – Read and understand
What is asked in the problem? ____________________________
What do you know of the problem?_______________________
Step 2 – Plan
What must be done to solve the problem?_________________
Step 3 – Solve and answer ________________________
Carry out the plan & write the final answer._______________
Step 4 – Check
Is the answer correct?_________

Answers

Answer:

9.42m

Step-by-step explanation:

I took this on a test. Was extremely difficult, but I remembered the answer after my 4th retake

Easy variable question pls help

Answers

Answer:

z = -4 1/2

Step-by-step explanation:

1. First change the mixed fractions to improper fractions so it's easier

[tex]\frac{16}{5\\}/(z-\frac{1}{2}) = \frac{8}{3}/(z+\frac{1}{3})[/tex]

2. Simplify

[tex]\frac{32}{5(2z-1)} = \frac{8}{3z+1}[/tex]

3. Cross multiply

[tex]32(3z+1) = 5(2z-1) * 8[/tex]

4. Simplify again (distributive property)

[tex]32(3z+1) = 40(2z-1)[/tex]

5. Distributive property

[tex]32(3z+1) -> 96z+32[/tex]  

[tex]40(2z-1) -> 80z-40[/tex]

[tex]96z+32=80z-40[/tex]

6. Subtract 32 from both sides

[tex]96z+32-32 = 80z-40-32[/tex]

7. Simplify

[tex]96z = 80z-72[/tex]

8. Subtract 80 from both sides

[tex]96z-80z=80z-72-80z[/tex]

9. Simplify

[tex]16z=-72[/tex]

10. Divide both sides by 16

[tex]\frac{16z}{16}=\frac{-72}{16}[/tex]

11. Simplify

[tex]z=-\frac{9}{2} -> also = -4\frac{1}{2}[/tex]

Sorry if it was too long but hope this helps! :)

And also try using symbolab cuz it gives step by step explanations it's really good!

What is the perimeter of a square whose area is 64 square kilometers?
.
A 16 km
B.32 km
c. 64 km
D.256 km

Answers

90% sure that it’s A because 64/16=4

5(k+2)-3(k+2) combine to make simpiler

Answers

Answer:

2k + 4

Step-by-step explanation:

David,

Start by performing the indicated multiplication:

5(k+2)-3(k+2) becomes 5k + 10 - 3k - 6.

Next, combine like terms:  5k - 3k + 10 - 6 becomes 2k + 4

This 2k + 4 is the desired simpler result.

Find the measurement of 1
What’s the answer and how do you do it

Answers

Answer:

68

Step-by-step explanation:

Determine the following indefinite integrals. Check your work by differentiation.

∫4x^1/3-x^-1/3dx

Answers

Answer:

[tex]\displaystyle \int { \Big( 4x^\bigg{\frac{1}{3}} - x^\bigg{\frac{-1}{3}} \Big) } \, dx = 3x^\bigg{\frac{4}{3}} - \frac{3x^\bigg{\frac{2}{3}}}{2} + C[/tex]

General Formulas and Concepts:

Calculus

Differentiation

DerivativesDerivative Notation

Derivative Property [Multiplied Constant]:                                                           [tex]\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)[/tex]

Derivative Property [Addition/Subtraction]:                                                         [tex]\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)][/tex]

Basic Power Rule:

f(x) = cxⁿf’(x) = c·nxⁿ⁻¹

Integration

IntegralsIndefinite IntegralsIntegration Constant C

Integration Rule [Reverse Power Rule]:                                                               [tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]

Integration Property [Multiplied Constant]:                                                         [tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]

Integration Property [Addition/Subtraction]:                                                       [tex]\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx[/tex]

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle \int { \Big( 4x^\bigg{\frac{1}{3}} - x^\bigg{\frac{-1}{3}} \Big) } \, dx[/tex]

Step 2: Integrate

[Integral] Rewrite [Integration Property - Addition/Subtraction]:               [tex]\displaystyle \int { \Big( 4x^\bigg{\frac{1}{3}} - x^\bigg{\frac{-1}{3}} \Big) } \, dx = \int {4x^\bigg{\frac{1}{3}}} \, dx - \int {x^\bigg{\frac{-1}{3}}} \, dx[/tex][1st Integral] Rewrite [Integration Property - Multiplied Constant]:             [tex]\displaystyle \int { \Big( 4x^\bigg{\frac{1}{3}} - x^\bigg{\frac{-1}{3}} \Big) } \, dx = 4\int {x^\bigg{\frac{1}{3}}} \, dx - \int {x^\bigg{\frac{-1}{3}}} \, dx[/tex][Integrals] Reverse Power Rule:                                                                   [tex]\displaystyle \int { \Big( 4x^\bigg{\frac{1}{3}} - x^\bigg{\frac{-1}{3}} \Big) } \, dx = 4 \bigg( \frac{3x^\bigg{\frac{4}{3}}}{4} \bigg) - \frac{3x^\bigg{\frac{2}{3}}}{2} + C[/tex]Simplify:                                                                                                         [tex]\displaystyle \int { \Big( 4x^\bigg{\frac{1}{3}} - x^\bigg{\frac{-1}{3}} \Big) } \, dx = 3x^\bigg{\frac{4}{3}} - \frac{3x^\bigg{\frac{2}{3}}}{2} + C[/tex]

Step 3: Check

Differentiate the answer.

Rewrite [Derivative Property - Addition/Subtraction]:                                 [tex]\displaystyle \frac{d}{dx} \bigg[ 3x^\bigg{\frac{4}{3}} \bigg] - \frac{d}{dx} \bigg[ \frac{3x^\bigg{\frac{2}{3}}}{2} \bigg] + \frac{d}{dx} \bigg[ C \bigg][/tex]Rewrite [Derivative Property - Multiplied Constant]:                                   [tex]\displaystyle 3\frac{d}{dx} \bigg[ x^\bigg{\frac{4}{3}} \bigg] - \frac{3}{2}\frac{d}{dx} \bigg[ x^\bigg{\frac{2}{3}} \bigg] + \frac{d}{dx} \bigg[ C \bigg][/tex]Basic Power Rule:                                                                                         [tex]\displaystyle 3 \bigg( \frac{4}{3}x^\bigg{\frac{1}{3}} \bigg) - \frac{3}{2} \bigg( \frac{2}{3}x^\bigg{\frac{-1}{3}} \bigg)[/tex]Simplify:                                                                                                         [tex]\displaystyle 4x^\bigg{\frac{1}{3}} - x^\bigg{\frac{-1}{3}}[/tex]

∴ we have found the answer.

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

Book: College Calculus 10e

A car is 3 times as old as its tires were when it was as old as the tires Are now.
When it’s tires are as old as the car is now,the car will be a year older than the tires are now.
What are the present ages of car and tires?

Answers

Answer:

Present age of the car = 1.5 years and the tires are 0.5 years old.

Step-by-step explanation:

Let the present age of the car be x years and that of the tires be y years.

x = 3y

x = y + 1

3y = y + 1

2y = 1

y = 0.5.

x = 3*0.5 = 1.5.

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