please help meeeeeeeewwewe

Answer: M equals 7. So it would be b^7. When you multiply exponents you add them. When you divided them you subtract

Step-by-step explanation:

The equivalent expression will be b⁵.

Algebraic expressions are the idea of expressing numbers using letters or alphabets without specifying their actual values. The basics of algebra taught us how to express an unknown value using letters such as x, y, z, etc.

Given an expression b¹⁰/b⁵,

We need to find an equivalent expression for the same,

So,

Using the identity,

mᵃ ÷ mᵇ = mᵃ ÷ mᵇ

= m⁽ᵃ⁻ᵇ⁾

Therefore,

b¹⁰/b⁵ = b⁽¹⁰⁻⁵⁾

= b⁵

Hence, the equivalent expression will be b⁵.

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Answer:

it would be 28.44 sorry if it does not help

Answer:

1 Chair= $1.25     1 table= $8.25

Step-by-step explanation:

5c+3t=31

2c+6t= 52

-2(5c+3t=31)

-10c-6t=-62

+

2c+6t=52

= -8c=-10

/-8      /-8

c= 1.25 or 1 1/4

2c+6t=52

2(1.25)+6t=52

2.5+6t=52

-2.5        -2.5

6t= 49.5

/6      /6

t= 8 1/4

Answer:

14/3 or 4.6

Step-by-step explanation:

you would do 3.5 divided by .75 (=^w^=)

Answer:

it is

Step-by-step explanation:

Answer:

132 yards

because its a hexagon so all sides are the same, meaning you do 22×6 = 132

Answer:

9

Step-by-step explanation:

20-11=9

☁️ Answer ☁️

9

Take 11 away from 20

Have a nice day noona/hyung.

Answer:

B

Step-by-step explanation:

3/8 + 2/8 = 5/8

Answer:

The answer is "4.8, 3.84, and 1.96".

Step-by-step explanation:

Given:

[tex]\to p = 0.2\\\\\to q = 1 - p = 1 - 0.2 = 0.8\\\\\to n = 24\\\\[/tex]

By using the binomial distribution:

[tex]\to Mean(\mu) = n \times p = 24 \times 0.2 = 4.8\\\\\to variance (\sigma^2) = n \times p \times q = 24 \times 0.2 \times 0.8 = 3.84\\\\\to Standard \ deviation (\sigma) = \sqrt{n \times p \times q} = \sqrt{24 \times 0.2 \times 0.8} = 1.96[/tex]

Answer: B

Step-by-step explanation: i looked it up ans it said b how this helps :>

Answer:

False

Step-by-step explanation:

In a rhombus, the diagonals are always perpendicular.

The statement is false as the number of terms in the equation is not two

The equation is given as

11 + 9k = 6n

Consider an equation represented as

a + b = c

The variables a, b and c are the terms of the equation

This means that the equation 11 + 9k = 6n has the following terms

11, 9k and 6n

The number of these terms is 3

So, the equation has three terms

Hence, it is false that the equation has two terms

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Answer:

−12+6

Step-by-step explanation:

[tex]\frac{3x+2+5(x-6)}{x^{2} -36}=\frac{8x-28}{(x+6)(x-6)}[/tex]

Answer:

a person jumping on a trampoline

Answer: 172

Step-by-step explanation:

Answer: Mechanical Pencils are $0.60

Colored Pencils are $0.80

Step-by-step explanation:

18c+22m=27.60

c-m=.20

+m    +m

so c= .20+m

Susitituete 18(.20+m)+22m=27.60

                  3.6+18m  +22m=27.60

                                    40m=27.60

                                      40m=24

                                         m=.60

c=.20+(.60)

c=.80

Answer:

[tex]x = 0 \: y = - 2 \: \: \: \: x = 1 \: y = \frac{ - 13}{9} [/tex]

Answer:

X= ( 18/5 , 0)

Y= (0,-2)

Step-by-step explanation:

substitute 0 for y and solve for x

-5x+9(0) = -18

-5X + 0 = -18

-5X= - 18 - 0

-5X = -18

X = - 18/-5

X = 18/5

solve for Y

-5(0) +9y = -18

= 9y = -18

y= -2

Answer:

1) 2+(3)=5

2) 5=5 is true

3) 1=-(2)+3

4) 1=1 is true

Step-by-step explanation:

Hello!

This problem is about relating parallel and perpendicular lines with a given point.

What we need to know here is that parallel lines will have equal slopes, while perpendicular lines will have opposite and reciprocal slopes.

Using this information, let's look at the first part.

We are asked to find a parallel line to the line [tex]y=6x-6[/tex] that passes through the point [tex](4,-3)[/tex].

Since we know that parallel lines have the same slope and we are given a point, we can solve for the y-intercept after setting up and equation.

[tex]y=6x+b[/tex]

[tex]-3=6(4)+b[/tex]

[tex]b=-27[/tex]

So the line would be [tex]y=6x-27[/tex].

Let's look at the second part, where we are asked to find a perpendicular line that passes through the same point.

We know that perpendicular lines have an opposite reciprocal of a slope, and using that information, we can go through the same process and solve for the equation.

[tex]y=-\frac{1}{6}x+b[/tex]

[tex]-3=-\frac{1}{6}(4)+b[/tex]

[tex]b=-\frac{7}{3}[/tex]

So the line would be [tex]y=-\frac{1}{6}x-\frac{7}{3}[/tex].

Hope this helps!

Answer:

30 or 60 both work

Step-by-step explanation:

please make me branlest

Answer:

<g = 129°

alternate interior angles

Step-by-step explanation:

hope this helps! :)

G is 129°

Angles g and f are vertical angles.

the image is to show why :)

8x+2+70°+80° = 180°

8x+132° = 180°

8x = 180°- 132°

x = 48°/8

Hence, x = 6

Answer:

Step-by-step explanation:

The sum of two interior angles in a triangle is equal to the exterior angle that is supplementary to the third interior angle

for first triangle

90 + 53 = u

143 = u

for the other triangle

102 + x = 4x + 6

102 = 4x + 6 - x

102 = 3x + 6 subtract 6 from both sides

96 = 3x divide both sides by 3

32 = x

Answer:

[tex]y = 2.096[/tex] or [tex]y = \frac{2\sqrt5+6}{5}}[/tex]

Step-by-step explanation:

Given

[tex]y = \frac{4}{x} + \sqrt x + 0.2 - 5x[/tex]

[tex]x = \frac{4}{5}[/tex]

Required

Find y

[tex]y = \frac{4}{x} + \sqrt x + 0.2 - 5x[/tex]

Substitute [tex]x = \frac{4}{5}[/tex]

[tex]y = \frac{4}{4/5} + \sqrt{4/5} + 0.2 - 5 * 4/5[/tex]

[tex]y = 5 + \sqrt{4/5} + 0.2 - 4[/tex]

Collect like terms

[tex]y = \sqrt{4/5} + 5 + 0.2 - 4[/tex]

[tex]y = \sqrt{\frac{4}{5}} + 1.2[/tex]

Split the surd

[tex]y = \frac{\sqrt4}{\sqrt5}} + 1.2[/tex]

[tex]y = \frac{2}{\sqrt5}} + 1.2[/tex]

Rationalize

[tex]y = \frac{2\sqrt5}{\sqrt5*\sqrt5}} + 1.2[/tex]

[tex]y = \frac{2\sqrt5}{5}} + 1.2[/tex]

Take LCM and add

[tex]y = \frac{2\sqrt5+1.2*5}{5}}[/tex]

[tex]y = \frac{2\sqrt5+6}{5}}[/tex]

or solve as:

[tex]y = \frac{2*2.24+6}{5}}[/tex]

[tex]y = \frac{10.48}{5}[/tex]

[tex]y = 2.096[/tex]

Answer:

In this problem, first we need to draw a circle of radius 3 cm having a center at point O. Now, take a point P at a distance of 5.5 cm from the center of the circle. Draw a line joining the point O and P. Now draw a perpendicular bisector of the line OP that cuts OP at M.