Please help will mark Brainliest. An object is dropped from the roof of a building. After 3.5 seconds, the object strikes the ground. A.) After 2 seconds, what is the speed of the object? B.) At what speed does the object strike the ground? C.) Find the height from which the object was dropped. Show Work

Answer:

ok, I don't see the question.

Explanation:

Answer:

It's A v=2pi/T

Explanation:

I took the test and got it correct.

The correct formula that can be used to find the tangential speed of an orbiting object is : ( A ) v = 2π r /T

Tangential speed is the speed or velocity of an object moving in a circular path is calculated as 2π r/T where T = time it takes to complete one rotation and   2π r is angular velocity( w ).

Therefore from the options listed above the correct expression for the tangential speed is v =2π r /T

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Answer: (B) non-stochastic effects such as severe burns and radiation sickness resulting from the short-term, high-level exposure

Explanation: edgeunity

The impact of best for Gertrude to consider when planning what may happen to the character is non-stochastic effects.

It is that impact where incidence and severity based on dose.

Since as per the given situation, Gertrude writes a short story so here the character should be considered as the non-stochastic effects like burning and the radiation sickness that leads from the short term and high level of exposure.

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The ball is hit with an initial vertical velocity of

(147 m/s) sin(38º) ≈ 90.5 m/s

Recall that

v ² - u ² = 2 a ∆y

where u and v are initial and final velocities, respectively; a is acceleration; and ∆y is displacement.

Vertically, the ball is in freefall, so it is only subject to acceleration due to gravity, with magnitude g = 9.80 m/s² in the downward direction. At its maximum height, the ball has zero vertical velocity (v = 0) and the displacement is equal to the maximum height, so

0² - (90.5 m/s)² = 2 (-g) ∆y

∆y = (90.5 m/s)² / (2g)

∆y ≈ 418 m

Answer:

The generated sound wave will not be able to reflect off of the object.

Explanation:

The statement that best describes this situation is: The generated sound wave will not be able to reflect off of the object.

An ultrasound machine is a device that is used to capture images in the human body for review by a medical examiner. The machine gives off sound waves that are reflected off body structures.

So, for the ultrasound machine being described, the absence of kidney stones will cause a non-reflection of the object to be captured.

Since the machine is in good working condition, the sound wave will be generated.

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Answer:

Explanation:

The constant acceleration of any object, neglecting air resistance and friction, is always -9.8. Proof:

[tex]s(t)=-4.9t^2+13[/tex] which is the position of this feather before it is dropped. The first derivative of position is velocity, so the velocity function for the feather is:

[tex]v(t)=-9.8t[/tex]. We could find the velocity that the feather is experiencing at 3 seconds, but that is not what we are being asked. What we are being asked is the acceleration of the feather at 3 seconds. So we find the acceleration function of the feather:

a(t) = -9.8

It turns out that the time doesn't matter to acceleration due to gravity because feathers and elephants all fall under the same pull.

Explanation:

the answers are the first 3.

Answer:

4.6

Explanation:

Ans is 4.6 b coz the difference b/w 4.6 and the other values is comparitively the largest.

Answer:

960N

Explanation:

Given parameters:

Mass of the motorcycle = 240kg

Acceleration of the motorcycle  = 4m/s²

Unknown:

Driving force of the motorcycle  = ?

Solution:

According to the Newton's second law of motion "the force on a body is the product of mass and acceleration".

    Force  = mass x acceleration

Insert the parameters and solve;

   Force  = 240 x 4  = 960N

Answer:

The answer is D & B

Explanation:

I took the quiz on this.  I hope this helps!

The two statements describe events that help drive tectonic plate movement are:

B. Convection currents cause hotter magma to rise and cooler magma to sink

D. Subduction plates cause cooling at convergent boundaries

A tectonic plate (also called lithospheric plate) is a massive, irregularly shaped slab of solid rock, generally composed of both continental and oceanic lithosphere.

Plate size can vary greatly, from a few hundred to thousands of kilometers across; the Pacific and Antarctic Plates are among the largest.

Plate thickness also varies greatly, ranging from less than 15 km for young oceanic lithosphere to about 200 km or more for ancient continental lithosphere (for example, the interior parts of North and South America).

Tectonic plates, large slabs of rock that divide Earth’s crust, move constantly to reshape the Earth’s landscape. The system of ideas behind plate tectonics theory suggests that Earth's outer shell (lithosphere) is divided into several plates that glide over the Earth’s rocky inner layer above the soft core (mantle).

The plates act like a hard and rigid shell compared to Earth's mantle. The mantle sits between Earth's dense, very hot core and its thin outer layer, the crust.

At subduction zones, a convergent boundary occurs when two tectonic plates push together. When an ocean plate and a continental plate collide, the ocean plate slides under the continental plate, and bends downward.

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Answer:

Explanation:

we know that

F=ma

F=28 N

a=4 m/s²

m=F/a

m=28/4

m=7 kg

Answer:

hinata for sure

Explanation:

seems reasonable

Answer:

The elements in the reactants are the same as the elements in the products

Explanation:

The condition for a balanced equation is as follows :

The number of atoms for each element in reactant = Number of atoms for each element in product.

Total charge on reactant and product must be same.

The example of a balanced equation is:

Reaction of carbon and hydrogen :

[tex]C+2H_2\rightarrow CH_4[/tex]

No. of carbon atom on Carbon on LHS = 1

No. of carbon atom on Hydrogen on LHS = 4

No. of carbon atom on Carbon on RHS = 1

No. of carbon atom on Hydrogen on RHS = 4

So, for a balanced equation, The elements in the reactants are the same as the elements in the products. Hence, the correct option (a).

Answer:

The answer is A

Explanation:

Answer:

A.) 5s

B.) 2.29s

C.) 39.6 m/s

Explanation:

Given that a kid throws a rock off the edge of a cliff 60.0 m high. When he drops the rock, it takes 5,0sec for it to reach the ground below.

a.) Determine the time it takes to reach the ground below,

The time is 5s

b.) How long would it take the rock to hit the ground if he threw it down with a speed of 15m/sec?

Using the second equation of motion:

H = Ut + 1/2gt^2

Substitute all the parameters into the formula

60 = 15t + 1/2 × 9.8 × t^2

60 = 15t + 4.9t^2

Multiply all by 10

49t^2 + 150t - 600

t^2 + 3.06t = 12.24

( t + 1.53)^2 = 12.24 + 2.3409

t + 1.53 = sqrt ( 14.5809)

t = 3.82 - 1.53

t = 2.29s

is hit stmight upward and reach a maximum height of 80.0 m.

Using the third equation of motion

V^2 = U^2 - 2gH

At maximum height, V = 0

0 = U^2 - 2 × 9.8 × 80

U^2 = 1568

U = sqrt ( 1568)

U = 39.6 m/s

Answer:

The correct answer is A. 8.0. In 2011, no fertiziler was added to the soil so the pH was not affected.

Answer:

Final velocity, V = 2.1213 m/s.

Explanation:

Given the following data;

Force, F = 1.50N

Mass, m = 0.2kg

Displacement, S = 30cm to meters = 30/100 = 0.3m

To find the acceleration;

Force is given by the multiplication of mass and acceleration.

Mathematically, Force is given by the formula;

[tex] F = ma[/tex] .......equation 1

Where;

Making acceleration (a) the subject, we have;

[tex]Acceleration (a) = \frac{F}{m}[/tex]

Substituting into the above equation, we have;

[tex]Acceleration, a = \frac{1.5}{0.2}[/tex]

Acceleration, a = 7.5m/s²

Now to find the final velocity, we would use the third equation of motion;

[tex] V^{2} = U^{2} + 2aS [/tex] .....equation 2

Where;

Note: Since the trolley is starting from rest, we know that it's initial velocity is 0.

Substituting the values into equation 2, we have;

[tex] V^{2} = 0^{2} + 2*7.5*0.3[/tex]

[tex] V^{2} = 0 + 4.5[/tex]

[tex] V^{2} = 4.5[/tex]

Taking the square root, we have;

[tex] V = \sqrt {4.5}[/tex]

V = 2.1213 m/s.

Therefore, the speed of the trolley after accelerating from rest through 0.3 m, if friction is negligible is 2.1213 m/s.

Final Velocity = 14m/s

Displacement = 56m

Explanation:

U (initial velocity) = 2m/s

A (acceleration) = 3m/s^2

T (time) = 4s

v (final velocity) = ?

S (displacement) = ?

FIRST FIND FINAL VELOCITY:

[tex]a = \frac{v - u}{t} [/tex]

(i) Multiply both sides by t:

[tex]a \times t = v - u[/tex]

(ii) Add u to both sides:

[tex](a \times t) + u = v[/tex]

(iii) rearrange formula:

[tex]v = (a \times t) + u[/tex]

v = ( 3 × 4 ) + 2

v = 12 + 2

v = 14m/s

SECOND FIND DISPLACEMENT:

[tex]v = \frac{s}{t} [/tex]

(i) Multiply both sides by t:

[tex]v \times t = s[/tex]

(ii) Rearrange formula:

[tex]s = v \times t[/tex]

s = 14 × 4

s = 56m

Not sure why it isn't one of the options but im pretty sure I did all the steps right...

Answer:

a)   y ’= 0.068 m ,  b)   m_lead = 2,599 kg

Explanation:

a) To solve this exercise, let's use Archimedes' law, which establishes that the pressure of the water is equal to the weight of the dislodged liquid.

Let's write the forces in the equilibrium condition

            B - W = 0

            B = W

Thrust is

            B = ρ_liquid g V_water

Body weight is

             W = m g

the definition of density

           ρ_body = m / V

we substitute

            W = ρ_body g V_body

The volume of the body is

          V_body = L³

The volume of water is

          V_agua = y L²

we substitute

           ρ_liquid g and L2 = rho_body g L3

           ρ_liquid y = ρ_body L

           y = L ρ_body /ρ_liquid

let's calculate

          y = 651/100 0.195

          y = 0.1269 m

this is the distance from the bottom of the cube, the distance from the top of the cube

          y ’= 0.195 -y

          y '= 0.195 - 0.1269

          y ’= 0.068 m

b) In this case the equilibrium equation is

          B - W_body - W_lead = 0

          B = W_body + W_lead

          ρ_liquido g V_liquido = ρ_body g V_body + m_lead g = 0

          ρ_liquid L3 = ρ_body L3 + m_lead = 0

          m_lead = L3 (ρ_liquid - ρ_body)

let's calculate

          m_lead = 0.195 3 (1000 - 651)

          m_lead = 2,599 kg

Answer:

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Explanation:

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Answer:

Increasing force tends to increase acceleration while increasing mass tends to decrease acceleration. Thus, the greater force on more massive objects is offset by the inverse influence of greater mass. Subsequently, all objects free fall at the same rate of acceleration, regardless of their mass.

If the mass increases, it's harder to accelerate

Because force tends to rise with mass while mass tends to decrease with force, mass is sometimes referred to as the difficulty of accelerating an item. As a result, the greater mass's inverse effect balances out the larger force exerted on more massive objects.

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Answer:

57,000,000,000(fifty-seven billion)

Explanation:

19000000000/ 1/3 = 57000000000

Answer:

Power = 5.916 Kw

Explanation:

Given:

Current = 290 A

Volt = 20.4 V

Find:

Power

Computation:

Power = IV

Power = (290)(20.4)

Power = 5916 w

Power = 5.916 Kw

Answer:

A.

Explanation:

I got it right ;)

Answer:

Chemical energy ---> Electrical energy ---> Light energy

Explanation:

Answer:

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question we have

workdone = 50 × 10

We have the final answer as

Hope this helps you

Answer:

1.6s

Explanation:

Given that A 1.20 kg solid ball of radius 40 cm rolls down a 5.20 m long incline of 25 degrees. Ignoring any loss due to friction,

To know how fast the ball will roll when it reaches the bottom of the incline, we need to calculate the acceleration at which it is rolling.

Since the frictional force is negligible, at the top of the incline plane, the potential energy = mgh

Where h = 5.2sin25

h = 2.2 m

P.E = 1.2 × 9.8 × 2.2

P.E = 25.84 j

At the bottom, K.E = P.E

1/2mv^2 = 25.84

Substitutes mass into the formula

1.2 × V^2 = 51.69

V^2 = 51.69/1.2

V^2 = 43.07

V = 6.56 m/s

Using the third equation of motion

V^2 = U^2 + 2as

Since the object started from rest,

U = 0

6.56^2 = 2 × a × 5.2

43.07 = 10.4a

a = 43.07/10.4

a = 4.14 m/s^2

Using the first equation of motion,

V = U + at

Where U = 0

6.56 = 4.14t

t = 6.56/4.14

t = 1.58s

Therefore, the time the ball rolls when it reaches the bottom of the incline is approximately 1.6s

Answer:

  force is exerted on a charge carrying particle by a MAGNETIC FIELD only when the particle moves PERPENDICULAR the field lines. If a charged particle moves parallel to the magnetic field, the force exerted by the magnetic field on the charged particle is_ ZERO

Explanation:

This complementation exercise refers to the magnetic force that the formula has

         F = q v x B

where the bold letters indicate vents and the x the vector product. The module of this product is

         F = qv B sin θ

where θ  is the angle between the speed and direction of the magnetic field.

It can be seen that for the force to be different from zero, the angle must not be parallel θ  = 0

        sin 0 = 0

the maximum value is obtained for an angle of θ  = 90º

       sin 90 = 1

Using these concepts we see that the missing words are.

  force is exerted on a charge carrying particle by a MAGNETIC FIELD only when the particle moves PERPENDICULAR the field lines. If a charged particle moves parallel to the magnetic field, the force exerted by the magnetic field on the charged particle is_ ZERO_______

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