The graph below shows the conservation of energy for a skydiver jumping out
of a plane and landing safely on the ground. Which energy is represented by
line C?

The force required to punch a hole 1 cm in diameter in a steel sheet is 0.176 x 10¹³ N.

The force is defined as the shear stress or pressure applied per unit area.

F = P/A

Given is a steel sheet whose thickness t = 5mm = 5x 10⁻³ m, shearing strength P = 2.76 × 10⁸ N/m², diameter of hole d = 1cm = 1x 10⁻² m

The area to be punched A = πd xt

A = π x 1x 10⁻² x5x 10⁻³

A = 15.7 x 10⁻⁵ m²

The force required to punch a hole is

F = 2.76 × 10⁸ /  15.7 x 10⁻⁵

F = 0.176 x 10¹³ N.

Thus, the punching force is  0.176 x 10¹³ N.

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Iron forms an oxide when exposed to air is a true property about this element.

This is an element which has magnetic properties and forms an oxide when exposed to air.

Iron forms ferric oxide in the presence of oxygen which is the brown like color seen in the form of rust.

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Answer:

The separation of visible light into its different colors is known as dispersion. It was mentioned in the Light and Color unit that each color is characteristic of a distinct wave frequency; and different frequencies of light waves will bend varying amounts upon passage through a prism

Explanation:

Answer: endurance, strength, balance, flexibility

Explanation:

walking, jogging, swimming, biking

The current flowing through the lamp is  1.833A

The current is the stream of charges which flow inside the conductors when connected across the end of voltage.

From the Ohm's law, V =IR

Here, R is the proportionality constant called resistance of the resistor

A lamp with a resistance of 60 Ohms is plugged into a 110-Volt household circuit.

I = V/R

Put the values, we get

I = 110/60

I = 1.833A

Thus, the current flowing through the lamp is  1.833A

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Answer:

It is showing the wavelength.

Explanation: Hope it helps you:)))

have a good day

Answer:

D. from a separate pool than is the control group.

Explanation:

in the picture the person answers is backwards but...

hope this helps have a nice day

The minimum force required to lift the box at constant velocity is determined as 274.4 N.

The minimum force required to lift the box at constant velocity is the tension in one of the pulleys, and the magnitude is calculated as follows;

2T = mg

where;

2T = mg

T = mg/2

T = (56 x 9.8)/2

T = 274.4 N

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Answer:

300 J

Explanation:

Given :

Work done by the force :

Note :

Answer:

6 m/s

Explanation:

Average velocity = Total distance covered / Time taken to cover distance

Finding Average Velocity :

⇒ 20 m + 40 m / 2 s + 8 s

⇒ 60 m / 10 s

⇒ 6 m/s

a body covers a distance of 20 m in 2 second and then covers 40 metre in next it s8 on a straight line calculate its velocity.

So the Average velocity is 6m/s²

Answer:

tan is 15 for that triangle

Answer:

c. 1.33

Explanation:

edmentum

The force on one of the wires is determined as 1.76 x 10⁻⁴ N/m.

The force between the two parallel wire is calculated as follows;

F = μI²L/2πr

where;

F = (4π x 10⁻⁷ x 6.5² x 1.5)/(2π x 0.048)

F = 2.64 x 10⁻⁴ N

F/L =  2.64 x 10⁻⁴ N / 1.5

F/L = 1.76 x 10⁻⁴ N/m

Thus, the force on one of the wires is determined as 1.76 x 10⁻⁴ N/m.

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The angular velocity of the stepped cylinder is determined as 2.35 rad/s.

The centripetal acceleration of the cylinder is calculated as follows;

F = ma

a = F/m

a = 40/ 36

a = 1.11 m/s²

a = v²/r

v² = ar

v² = 1.11 x 0.2

v² = 0.222

v = 0.47 m/s

v = ωr

ω = v/r

ω = 0.47/0.2

ω = 2.35 rad/s

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Hi there! :)

We can begin by doing a summation of forces on the ball. In the horizontal direction, we have the force of tension:
[tex]F_{Net} = T[/tex]

The tension force results in a centripetal force experienced by the ball. The equation of centripetal force is equivalent to:
[tex]F_C = m\omega^2 r[/tex]

[tex]F_C[/tex] = Centripetal force (N)
m = mass of ball (0.22 kg)

ω = angular speed of ball(? rad/sec, must convert rpm to rad/sec)

r = radius/length of string (1.0 m)

We must begin by converting rpm to rad/sec:

[tex]\frac{50 rev}{min} * \frac{2\pi rad}{1 rev}* \frac{1 min}{60 sec} = 5.236 \frac{rad}{s}[/tex]

Now, we can set tension equal to the centripetal force and solve. [tex]T = F_{Net} = F_C\\\\T = m\omega^2 r\\\\T = (0.22)(5.236^2)(1) = \boxed{6.031 N}[/tex]

Answer:

Light waves are electromagnetic waves while sound waves are mechanical waves. :)

Answer:

Recycling of paper cannot be reversed thus making it an irreversible change

Explanation:

When we recycle paper an entirely new product can be made which cannot be changed back to paper

Answer:

B

Explanation:

Electric charges and magnetic dipoles

Answer:

A person with impairment of organs of equilibrium would compensate for their lack of sensory information by their eyes therefore if their eyes are closed they aren't able to sense their location in space accurately (Proprioception)

Explanation:

The amount of energy needed to boil away the water at the initial temperature  is 301,248 J.

The amount of energy needed to boil the water at the given is calculated as follows;

Q = mcΔθ

where;

density of water = 1000 g/L

mass = density x volume

mass of water = 1000 g/L x 1.6 L = 1,600 g

Q = 1600 g x 4.184 J/g⁰C x (100⁰C - 55 ⁰C)

Q = 301,248 J

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ANSWER:

C = carbon

Al = aluminium

H = hydrogen

O = oxygen

Na = sodium

I hope it helps u dear (^^)

The rocket's x- and y-coordinates relative to its launching point will be -0.975 and -0.219 m/sec, respectively.

The change of displacement with respect to time is defined as the velocity.  Velocity is a vector quantity. it is a time-based component.

Velocity at any angle is resolved to get its component of x and y-direction.

Given data;

V = 100m/s

θ=550°

t= 142 sec

The given velocity is resolved into the component as:

[tex]\rm V_X=Vcos \theta \\\\ V_y = Vsin\theta[/tex]

The x coordinate of the rocket:

[tex]\rm V_x = 100 cos \ 550^0 \\\\ V_x = -0.975616[/tex]

The y coordinate of the rocket:

[tex]\rm V_y =100 sin \ 550^0 \\\\ V_y = -0.219484[/tex]

Hence, the x-and y- coordinates of the rocket relative to its firing point will be -0.975 and -0.219 m/sec.

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This feather weighs heavier on earth than on Mars hence it is better that the feather falls on you in Mars than on earth.

The term weight refers to the effect of the gravitational pull on an object. The acceleration due to gravity on earth is about 9.8m/s^2. The weight of this feather on earth is about 4.80 Kg *  9.8m/s^2 = 47 N

On the planet Mars, the weight is;

4.80 Kg * (0.38 * 9.8m/s^2) = 18 N

This feather weighs heavier on earth than on Mars hence it is better that the feather falls on you in Mars than on earth.

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Answer:

The (latent) heat of vaporization (∆Hvap) also known as the enthalpy of vaporization or evaporation, is the amount of energy (enthalpy) that must be added to a liquid substance, to transform a given quantity of the substance into a gas.

The enthalpy of vaporization is a function of the pressure at which that transformation takes place. The heat of vaporization diminishes with increasing temperature and it vanishes completely at a certain point called the critical temperature (Critical temperature for water: 373.946 °C  or 705.103 °F,  Critical pressure: 220.6 bar = 22.06 MPa  = 3200 psi ).

The radius of a magnesium atom is 0.160nm. The radius of a nucleus is about 1/10000 that of an atom.

The nucleus is an organelle that contains the DNA i.e. genetic material and other materials which is required for cellular processes. It is only found in eukaryotic cells that is responsible for controlling the processes of the cell.

So we can conclude that the radius of a magnesium atom is 0.160nm which is equals to about 1/10000 radius of that atom.

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Answer:

179 m

Explanation:

Given:

v₀ = 96.0 km/h × (1000 m/km) × (1 h / 3600 s) = 26.67 m/s

a = 0 m/s²

t = 6.7 s

Find: Δx

Δx = v₀ t + ½ at²

Δx = (26.67 m/s) (6.7 s) + ½ (0 m/s²) (6.7 s)²

Δx = 179 m

Explanation:

We know that,

Magnitude of a unit vector is 1.

and, magnitude of a vector in the form [tex] \sf a \hat{i}+b \hat{j} + c \hat{k} [/tex]

is [tex] \sf \sqrt{a^2+b^2+c^2 } [/tex]

The given vector is,

[tex]\sf \vec{A}= 0.3 \hat{i} + 0.4 \hat{j} + B \hat{k}[/tex]

Magnitude of the given vector is,

[tex]\sf | \vec{A}|= \sqrt{(0.3)^2+(0.4)^2+B^2} =1[/tex]

[tex]\sf \sqrt{0.09+0.16+B^2}=1[/tex]

[tex]\sf 0.25+B^2=1[/tex]

[tex]\sf B^2=1-0.25=0.75[/tex]

[tex]\sf B = \sqrt{0.75} ≈ 0.87[/tex]