The height of an arrow is shot upward at an initial velocity of 40 meters per second can be modeled by h=40t-5t^2 where h is the height in meters and t is the time in seconds. Find the time is take for the arrow to reach the ground. Can someone please explain this to me thanks

The representation of the vector in trigonometry form is t = 13 ❬cos 112.62°, sin 112.62°❭

The representation of complex number in polar form is expressed as;

y = r(cosФ + isinФ)

where;

r is the modulus

Ф is the argument

Given the vector t = –5i + 12j, the modulus of the vector is given as;

r = √(-5)²+(12)²

r = √25 + 144

r = √169

r = 13

Determine the angle between the vectors

Ф = arctan(-12/5)

Ф = -67.38

Since tan is negative in the second quadrant, hence;

Ф = 180 - 67.38

Ф = 112.62°

The representation of the vector in trigonometry form is t = 13 ❬cos 112.62°, sin 112.62°❭

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Answer:

1) Area of frame: [tex]140cm^2[/tex] ; Area of picture: [tex]40cm^2[/tex] ; Total Area: [tex]180cm^2[/tex].      

2) Area 1 =  [tex]48cm^2[/tex] ; Area 2 = [tex]12cm^2[/tex] ; total area = [tex]60cm^2[/tex] [first answer line : [tex]60cm^2[/tex]]

Step-by-step explanation:

1. So to answer this question, you have to find the inner photo area first (which you will then subtract from the overall rectangle area to get the photo frame area).

To find area, you multiply length x width. For this question, there are not enough measurements given to initially multiply length and width. So, assuming that the photo is centered on the frame and the frame width is consistent along all sides, you find the difference between the overall length (12) and the picture length (5).

12 - 5 = 7

The leftover area (outside of the picture) is 7 cm (half of seven on both sides), so one side can be assumed to be : 3.5 cm

this means that 15 cm - 3.5 cm of both sides lengths (difference between the two lengths given) is the height of the photo, 15 - 3.5(2) = 8

So, the dimensions/measurements of the photo are 5 cm by 8 cm.

This means that the inner photo area is 40 (5 x 8) cm

The area of the frame will be the area of the total rectangle [12 x 15] - the inner photo area [40].  [ (12)(15) - 40 ]

[180 - 40] = 140 cm

(area is measured in squared units, so the area of the frame should be written as [tex]140cm^{2}[/tex] ; and the area of the photo should be written as [tex]40cm^{2}[/tex])

The total area is the entire area of the rectangle: (12)(15) = 180. (This should be written as [tex]180cm^2[/tex])

--------------------------------------

2) Finding the area of a shape that isn't a simple rectangle is easier if you separate the shape into smaller rectangles. I will separate the two rectangles into 4 x 12 and 2 x 6 [6 cm would be the remaining side length if you remove the length of 4].

{you can separate the shape in multiple ways, so my answer is only one answer to this problem out of other splits.}

as mentioned, the area is length x width.

4 x 12 = 48.

2 x 6 = 12. Once again, you should write area in squared units.

(the area 1 should be written as [tex]48cm^{2}[/tex] ; the area 2 should be written as [tex]12cm^2[/tex])

you can combine the separated areas (add them) to find the total area. 48 + 12 = 60.

(the total area should be written in squared units also, so the total area should be written as: [tex]60cm^2[/tex])

The area of the figure is [tex]60cm^2[/tex]

The number that is not irrational is [tex]1.\overline{45}[/tex]. The correct option is the second option [tex]1.\overline{45}[/tex]

From the question, we are to determine which of the given options is not irrational

Irrational numbers are the set of real numbers that cannot be expressed in the form of a fraction, p/q, where p and q are integers.

[tex]1.\overline{45}[/tex]  is a repeating decimal and it can be expressed as a fraction

[tex]1.\overline{45} = \frac{144}{99}[/tex]

∴ [tex]1.\overline{45}[/tex] is not an irrational number. It is a rational number

The other options cannot the expressed as a fraction.

Hence, the number that is not irrational is [tex]1.\overline{45}[/tex]. The correct option is the second option [tex]1.\overline{45}[/tex]

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For the given relation, the coefficient is (1/5) and the exponent is 1.

For a relation of the form:

[tex]y = a*x^n[/tex]

a is the coefficient and n is the exponent.

In this case, we have:

[tex]y = \frac{x}{5}[/tex]

This can be rewritten to:

[tex]y = \frac{1}{5}*x^1[/tex]

So we can see that the coefficient is (1/5), and the exponent is 1.

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Answer:

[tex] \pink{\boxed{{\colorbox{white}{Answer}}}}[/tex]

C. 29

Step-by-step explanation:

[tex] \pink{\boxed{{\colorbox{white}{- MsTiyana}}}}[/tex]

Answer:

The angle of rotational symmetry is 4

The dimensions of the rectangle are length 156 m and a width of 65m, and a perimeter P = 442m

For a rectangle of length L and width W, the diagonal is:

[tex]D = \sqrt{L^2 + W^2}[/tex]

Here we know that the diagonal is 169m.

And the ratio of the length to the width is 12:5

This means that:

W = (5/12)*L

Replacing all that in the diagonal equation:

[tex]169 = \sqrt{((5/12)^2*L^2 + L^2} \\\\169^2 = (25/144)*L^2 + L^2 = ( 25/144 + 1)*L^2\\\\\frac{169}{\sqrt{25/144 + 1} } = L = 156[/tex]

So the length is 156 meters, and the width is:

W = (5/12)*156 m = 65m

Finally, the perimeter is:

P = 2*(L + W) = 2*(156 m + 65m) = 442m

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Answer:

[tex]\bf \sf \dfrac{1}{3}[/tex]

Take points: (6, 2), (3, 1)

[tex]To \ find \ proportionality = \sf \dfrac{y_2-y_1}{x_2-x_1}[/tex]

Insert values

[tex]\rightarrow \sf \dfrac{1-2}{3-6}[/tex]

Simplify

[tex]\rightarrow \sf \dfrac{-1}{-3}[/tex]

Cancel out the negatives

[tex]\rightarrow \sf \dfrac{1}{3}[/tex]

Answer:

B) [tex]\frac{1}{3}[/tex]

Step-by-step explanation:

When y varies directly with x, the relationship is [tex]y=kx[/tex] where [tex]k[/tex] is the constant of proportionality. Hence, [tex]k=\frac{y}{x}[/tex].

So, your answer would not be correct because you did [tex]\frac{x}{y}[/tex] instead of [tex]\frac{y}{x}[/tex], so the correct option would be the reciprocal, or [tex]\frac{1}{3}[/tex].

Hey there!

-1/2 (1/4 * - 3/8)

= -1/2(1/4)(-3/8)

= -1/2(-3/32)

= 3 / 64

Therefore, your answer should be:

3/64

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

Answer:

I don't no ok ok ok ok ok ok ok ok ok

The probability that it rains at most 2 days is 0.00005995233 and the variance is 0.516

The given parameters are:

The probability that it rains at most 2 days is represented as:

P(x ≤ 2) = P(0) + P(1) + P(2)

Each probability is calculated as:

[tex]P(x) = ^nC_x * p^x * (1 - p)^{n - x}[/tex]

So, we have:

[tex]P(0) = ^7C_0 * (92\%)^0 * (1 - 92\%)^{7 - 0} = 0.00000002097[/tex]

[tex]P(1) = ^7C_1 * (92\%)^1 * (1 - 92\%)^{7 - 1} = 0.00000168821[/tex]

[tex]P(2) = ^7C_2 * (92\%)^2 * (1 - 92\%)^{7 - 2} = 0.00005824315[/tex]

So, we have:

P(x ≤ 2) =0.00000002097 + 0.00000168821 + 0.00005824315

P(x ≤ 2) = 0.00005995233

Hence, the probability that it rains at most 2 days is 0.00005995233

This is calculated as:

Mean = np

So, we have:

Mean = 7 * 92%

Evaluate

Mean = 6.44

Hence, the mean is 6.44

This is calculated as:

σ = √np(1 - p)

So, we have:

σ = √7 * 92%(1 - 92%)

Evaluate

σ = 0.718

Hence, the standard deviation is 0.718

We have:

σ = 0.718

Square both sides

σ² = 0.718²

Evaluate

σ² = 0.516

This represents the variance

Hence, the variance is 0.516

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If the ordered pair (1, 0) represents the function F(x), then the ordered pair (0, 1) represents the inverse of F(x). Option A is correct.

A connection between independent variables and the dependent variable.is defined by the function.

The complete question is

"If (1,0) is an ordered pair of the function f(x), which of the following is an ordered pair of the inverse of f(x)?

A. (0,1)

B. (0,0)

C. (1,0)

D. (1,1)"

Functions help to represent graphs and equations. A function is represented by the two variables one is dependent and another one is an independent function.

The relation between them is shown as y if dependent and x is the independent variable.

If the ordered pair (1, 0) represents the function F(x), then the ordered pair (0, 1) represents the inverse of F(x).

F(x)∈ (1, 0)

F⁻¹(x)∈(0, 1)

Hence, option A is correct.

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Answer:

$1912.50

Step-by-step explanation:

5.5% of $1500 is 82.50

so 82.50×5(years)

=412.5 + 1500

=1912.50

Answer:

You will need this formula

Total = Principal * e ^ (rate * years)

where 'e' equals 2.718281828459

Total = 1,500 * 2.718281828459 ^ (.055 * 5)

Total = 1,500 * 2.718281828459 ^ (.275)

Total = 1500 * 1.31653067486762

Total = 1,974.80

formula www.1728.org/rate2.htm

Calculator located here: https://www.1728.org/compint.htm

Step-by-step explanation:

Answer:

68 square meters

Step-by-step explanation:

The hexagon is made up of two trapezoids. Use the formula to find the area of each trapezoid then add those two areas together.

Area of a trapezoid (add the two bases together, multiply by the height then divide by 2):

[tex]A = \frac{1}{2} (b_{1}+b_{2})h[/tex]

Top trapezoid:

[tex]A = \frac{1}{2} (5 + 12)4\\A = \frac{1}{2} (17)4\\A= \frac{1}{2} (68)\\A = 34[/tex]

Bottom trapezoid (identical to the top trapezoid):

[tex]A = \frac{1}{2} (5 + 12)4\\A = \frac{1}{2} (17)4\\A= \frac{1}{2} (68)\\A = 34[/tex]

Add the areas together:

34 + 34 = 68

Answer:

The answer is B.) 3

Step-by-step explanation:

Answer:

jesse got right

Step-by-step explanation:

branliest.

Answer:

2

Step-by-step explanation:

g/5 - h is equal to 20/5 - 2

equal to 20 divided by 5 is equal to 4(20÷5=4)

then 4minus h which is 4- 2 =2

therefore the answer is 2

I hope this helps you

Answer:

45q^10

Step-by-step explanation:

First, we can separate the equation to make it simpler to understand.

5*q^4*9*q^6

Then we group terms that we can multiply:

(5*9)*(q^4*q^6)

Then we simplify

45*q^10

45q^10

Answer:

Yes

Step-by-step explanation:

The sum must be greater than 8 it can't be 7 anyway. Sums can be 9, 10 or 12. P = (4+3+1)/36 = 3/36

Answer:

  £850

Step-by-step explanation:

We can compute the left-over amount by comparing that to the amount spent.

__

Written as ratios, we have ...

  spent : left-over = 3/8 : 1 -3/8 = 3/8 : 5/8 = 3 : 5

Writing this using fractions, we have ...

  left-over / spent = 5 / 3

Solving for left-over gives ...

  left-over = spent × (5/3) = £510×5/3 = £850

Nate had £850 left over.

_____

Additional comment

Nate's money totaled £510 +850 = £1360.

The fraction spent is £510/£1360 = 3/8, as required.

Answer:

see the attachment photo!

Answer:

Step-by-step explanation:

(3k,4k,5k)

sea k=2

la terna es:

(6,8,10)

sea k=5

la terna sería:

(15,20,25)

Step-by-step explanation:

so, "- 1" is also part of the square root ?

sqrt(x - 1) = x - 3

it is clear that for any value x < 1 we have no solution in R (as this makes the argument of the square root negative, and there is so real number solution for the square root of negative numbers).

now square the whole equation.

x - 1 = (x - 3)² = x² - 6x + 9

x² - 7x + 10 = 0

the general solution for quadratic equations is

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case

a = 1

b = -7

c = 10

x = (7 ± sqrt(49 - 4×1×10))/(2×1) =

= (7 ± sqrt(49 - 40))/2 = (7 ± sqrt(9))/2

x1 = (7 + 3)/2 = 10/2 = 5

x2 = (7 - 3)/2 = 4/2 = 2

x2 is probably (given the answer options) not a valid solution for the original problem, as it represents the negative solution of sqrt(x - 1).

sqrt(2 - 1) = 2 - 3

± 1 = -1

remember, every square root has always 2 solutions : a positive and a negative one.

your teacher clearly only wanted the positive solution, which is x1 = 5.

so, yes,

C. x = 5

is the correct answer.

but please send your teacher my regards and comments. he/she has to state that only the positive solution to the square root is required/allowed.

because, formally, also x = 2 is a valid solution.

and therefore, C. AND D. are correct answers !!!!

Answer:

$0.36

Step-by-step explanation:

To convert between gallons, quarts, pints, and cups it can be helpful to memorize this:

2 Cups in a Pint

2 Pints in a Quart

4 Quarts in a Gallon

We can work backwards using this, finding that there are 4 quarts in a gallon, 8 pints in a gallon, and 16 cups in a gallon.

Since we have 2 gallons, we must multiply the number of cups by 2 to get 32 cups in 2 gallons.

Now we can solve for the price per cup by dividing the cost of all 2 gallons by how many cups are in it (32.)

$11.52 / 32 = $0.36

That is the answer

- Kan Academy Advance

Problem 13

x = central angle = 360-105 = 255 degrees

r = 8 = radius

A = sector area

A = (x/360)*pi*r^2

A = (255/360)*pi*8^2

A = 142.41887

I used the calculator's stored value of pi to get the most accuracy possible.

Round that decimal value however you need to. The same applies to the other questions as well.

========================================================

Problem 14

x = central angle = 114 degrees

r = radius = unknown

A = sector area = 36 square cm

A = (x/360)*pi*r^2

36 = (114/360)*pi*r^2

36*(360/114) = pi*r^2

113.68421 = pi*r^2

r^2 = 113.68421/pi

r^2 = 36.18681

r = sqrt(36.18681)

r = 6.015547

========================================================

Problem 15

x = area of the full circle

The pizza slice shown has an area of 49 square meters.

This is 68/360 of a full circle, which means,

sector area = (68/360)*(full circle area)

49 = (68/360)*x

x = 49*(360/68)

x = 259.41176

Answer:

13)  142.4 in²

14)  6.0 cm

15)  259.4 m²

Step-by-step explanation:

Formula

[tex]\textsf{Area of a sector of a circle}=\left(\dfrac{\theta}{360^{\circ}}\right) \pi r^2[/tex]

(where r is the radius and [tex]\theta[/tex] is in degrees)

Given:

Substitute the given values into the formula and solve for A:

[tex]\implies \textsf{Area}=\left(\dfrac{255^{\circ}}{360^{\circ}}\right) \pi 8^2[/tex]

[tex]\implies \textsf{Area}=\dfrac{136}{3} \pi[/tex]

[tex]\implies \boxed{\textsf{Area}=142.4\: \sf in^2 \:(nearest\:tenth)}[/tex]

Given:

Substitute the given values into the formula and solve for r:

[tex]\implies 36=\left(\dfrac{114^{\circ}}{360^{\circ}}\right) \pi r^2[/tex]

[tex]\implies \dfrac{36 \cdot 360}{114 \pi}=r^2[/tex]

[tex]\implies r^2=\dfrac{2160}{19 \pi}[/tex]

[tex]\implies r=\sqrt{\dfrac{2160}{19 \pi}}[/tex]

[tex]\implies \boxed{r=6.0\: \sf cm\:(nearest\:tenth)}[/tex]

Given:

Substitute the given values into the formula and solve for r²:

[tex]\implies 49=\left(\dfrac{68^{\circ}}{360^{\circ}}\right) \pi r^2[/tex]

[tex]\implies \dfrac{49 \cdot 360}{68 \pi}= r^2[/tex]

[tex]\implies r^2=\dfrac{4410}{17 \pi}[/tex]

[tex]\textsf{Area of a circle} = \pi r^2[/tex]

[tex]\implies \textsf{Area of a circle N} =\dfrac{4410}{17 \pi} \cdot \pi[/tex]

[tex]\implies \textsf{Area of a circle N} =\dfrac{4410}{17}[/tex]

[tex]\implies \boxed{\textsf{Area of a circle N} =259.4\: \sf m^2\:(nearest\:tenth)}[/tex]

Answer:

1/12 more red rice then white rice

Step-by-step explanation:

3/4 = 0.75

2/3 = 0.666666....

Clearly Red rice is more but it will be difficult to state how much more in decimal form so we must use fraction form :

3/4 = 9/12

2/3 = 8/12

So there is 1/12 more red rice then white rice

Hope this helped and have a good day

Answer:

a ) Electronically , by reviewing billing receipts

Step-by-step explanation:

The main purpose of controlling inventory is to make sure that the optimal amount of products are being kept.

Therefore, option A is correct.

Check the picture below.

[tex]~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ Q(\stackrel{x_1}{-4}~,~\stackrel{y_1}{9})\qquad U(\stackrel{x_2}{2}~,~\stackrel{y_2}{3}) ~\hfill QU=\sqrt{[ 2- (-4)]^2 + [ 3- 9]^2} \\\\\\ ~\hfill \boxed{QU=\sqrt{72}} \\\\\\ U(\stackrel{x_1}{2}~,~\stackrel{y_1}{3})\qquad A(\stackrel{x_2}{-3}~,~\stackrel{y_2}{-2}) ~\hfill UA=\sqrt{[ -3- 2]^2 + [ -2- 3]^2} \\\\\\ ~\hfill \boxed{UA=\sqrt{50}}[/tex]

[tex]A(\stackrel{x_1}{-3}~,~\stackrel{y_1}{-2})\qquad D(\stackrel{x_2}{-9}~,~\stackrel{y_2}{4}) ~\hfill AD=\sqrt{[ -9- (-3)]^2 + [ 4- (-2)]^2} \\\\\\ ~\hfill \boxed{AD=\sqrt{72}} \\\\\\ D(\stackrel{x_1}{-9}~,~\stackrel{y_1}{4})\qquad Q(\stackrel{x_2}{-4}~,~\stackrel{y_2}{9}) ~\hfill DQ=\sqrt{[ -4- (-9)]^2 + [ 9- 4]^2} \\\\\\ ~\hfill \boxed{DQ=\sqrt{50}}[/tex]

now, let's take a peek at that above, DQ = UA and QU = AD, so opposite sides of the polygon are equal.

Now, let's check the slopes of DQ and QU

[tex]D(\stackrel{x_1}{-9}~,~\stackrel{y_1}{4})\qquad Q(\stackrel{x_2}{-4}~,~\stackrel{y_2}{9}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{9}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{-4}-\underset{x_1}{(-9)}}} \implies \cfrac{9 -4}{-4 +9}\implies \cfrac{5}{5}\implies \cfrac{1}{1}\implies 1 \\\\[-0.35em] ~\dotfill[/tex]

[tex]Q(\stackrel{x_1}{-4}~,~\stackrel{y_1}{9})\qquad U(\stackrel{x_2}{2}~,~\stackrel{y_2}{3}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{3}-\stackrel{y1}{9}}}{\underset{run} {\underset{x_2}{2}-\underset{x_1}{(-4)}}} \implies \cfrac{3 -9}{2 +4}\implies \cfrac{-6}{6}\implies \cfrac{-1}{1}\implies -1[/tex]

keeping in mind that perpendicular lines have negative reciprocal slopes, let's notice that the reciprocal of 1/1 is just 1/1 and the negative of that is just -1/1 or -1, so QU has a slope that is really just the negative reciprocal of DQ, those two lines are perpendicular, thus making a 90° angle, and their congruent opposite sides will also make a 90°, that makes QUAD hmmm yeap, you guessed it.

The length has [tex]\frac{3.5}{0.5}=\boxed{7}[/tex]

The width has [tex]\frac{2.5}{0.5}=\boxed{5}[/tex]

The height has [tex]\frac{1.5}{0.5}=\boxed{3}[/tex]

Answer:

The National Housing Act of 1937 established guidelines for maximum rents for low-income families.  Originally the maximum rent threshold was set at 20%, however this increased to 30% in 1981 (and has remained at this level ever since).  This figure is used to determine how much of your gross monthly income you should spend on rent.

The 28% Rule is used for determining how much of your gross monthly income should be used for a mortgage, however the FHA's threshold is a little higher at 31% of your gross monthly income on a mortgage.

Renting:

30% of $1,250 = 0.3 × 1250 = $375

Mortgage 28% Rule:

28% of $1,250 = 0.28 × 1250 = $350

Mortgage 31% FHA:

31% of $1,250 = 0.31 × 1250 = $387.50

Therefore, discounting the higher FHA's threshold, the maximum amount to budget for housing is: