The odds that it will snow tomorrow are 9 to 6. What is the probability that it will not snow tomorrow?a) 0.1818
b) 0.2222
c) 0.1111
d) 0.1667
e) 0.8182

Answers

Answer 1

Answer:

a) 0.1818

Step-by-step explanation:

Given that:

The odd that it'll snow tomorrow is 9 to 6

The probability that it will snow tomorrow  [tex]=\dfrac{9}{9+6}[/tex]

[tex]=\dfrac{9}{15}[/tex]

= 0.6

The probability that it'll not snow tomorrow [tex]= 1 - \dfrac{9}{15}[/tex]

[tex]= \dfrac{15-9}{15}[/tex]

[tex]=\dfrac{6}{15}[/tex]

= 0.4

Let assume that the odd that it'll snow tomorrow is 9 to 2

The probability that it will snow tomorrow  [tex]=\dfrac{9}{9+2}[/tex]

[tex]=\dfrac{9}{11}[/tex]

= 0.8181

The probability that it'll not snow tomorrow  [tex]= 1 - \dfrac{9}{11}[/tex]

[tex]= \dfrac{11-9}{11}[/tex]

[tex]=\dfrac{2}{11}[/tex]

= 0.1818

Answer 2

None of the  options is correct.

Probability that it will not snow tomorrow = 0.4

The odds of an event E is defined as formulated in equation (1)

[tex]\rm Odd\; of\; event\; E = P(E)/P(\bar E) = P(E)/(1-P(E)).......(1)[/tex]

Let P(E) represents the probability that it will snow tomorrow.

Let event E represents the event that " it will snow tomorrow "

So the odds of the event that it will snow tomorrow

[tex]\rm \dfrac{P(E)}{P(\bar E)} =\dfrac{9}{6} = \dfrac{P(E)}{1-P(E)}.......(2)[/tex]

On solving equation (2) we get

[tex]\rm P(E) = \dfrac{9}{15}[/tex]

So the probability that it will snow tomorrow is 9/15

Hence the probability that it will not snow tomorrow

[tex]\rm P(\bar E) = 1- \dfrac{9}{15} = \dfrac{6}{15} =\bold{0.4}[/tex]

Probability that it will not snow tomorrow = 0.4

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https://brainly.com/question/7538150


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∵ The complex fraction is [tex]\frac{\frac{8}{9}}{8}[/tex]

∵  [tex]\frac{\frac{8}{9}}{8}[/tex] = [tex]\frac{8}{9}[/tex] ÷ 8

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