The R and S loci are 35 m.u. apart. If a plant of genotype is selfed, what progeny phenotypes will be seen and in what proportions

Answers

Answer 1

Complete question:

The R and S loci are 35 m.u. apart. If a plant of genotype RS/rs is selfed, what progeny phenotypes will be seen and in what proportions

Answer:

R-/S- = 0.6052 R-/ss = 0.1443rr/S- = 0.1443rr/ss = 0.1056

Explanation:

Available data:

R-S are 35 mu apartCross: RS/rs   x   RS/rs

First, we need to recognize the parental gametes and the recombinant ones.

Cross:

Parentals)     RS/rs    x      RS/rs

Gametes) RS  Parental   ⇒  Equal to the parental genotype

                 rs   Parental   ⇒  Equal to the parental genotype

                 Rs  Recombinant   ⇒  Product of recombination

                 rS   Recombinant   ⇒  Product of recombination

We know that genes are 35 MU apart from each other. The map unit is the distance between the pair of genes for which every 100 meiotic products, one of them results in a recombinant one.  

To calculate the recombination frequency, we have to know that 1% of recombinations = 1 map unit = 1cm. And that the maximum recombination frequency is always 50%.  

According to this information, if 1 MU = 1% recombination frequency, then

35MU --------- 35% recombination frequency = 0.35

Now, let us calculate the frequency of each gamete type.

35 map units = 35 % of recombination in total  

                      = % Rs + % rS  

                      = 17.5% Rs + 17.5% rS

Now, if the recombination frequency equals 35% then the parental frequency is 100% - 35% = 65%

65 % parental frequency = % of RS + % rs  

                                          = 32.5% RS + 32.5% rs

The frequency of each gamete is

RS  ⇒ Parental  ⇒  32.5% (65% / 2) = 0.325rs  ⇒ Parental ⇒ 32.5% (65% / 2) = 0.325Rs  ⇒ Recombinant  ⇒ 17.5% (35% / 2) = 0.175rS  ⇒  Recombinant ⇒  17.5% (35% / 2) = 0.175

F1 Genotypes and Proportions

RS/RS = 0.325 x 0.325 = 0.1056     RS/Rs = 2x 0.325 x 0.175 = 0.1137RS/rS = 2x 0.325 x 0.175 =0.1137   rs/rs = 0.325 x 0.325 = 0.10562rs/RS = 2x 0.325 x 0.325 = 0.2112rs/Rs = 2x 0.325 x 0.175 = 0.1137rs/rS = 2x 0.325 x 0.175 = 0.1137Rs/rS = 2x 0.175 x 0.175 = 0.061Rs/Rs = 0.175 x 0.175 = 0.0306rS/rS = 0.175 x 0.175 = 0.0306

F1 Phenotypes and Proportions

R-/S- = 0.1056 + 0.1137 + 0.1137 + 0.2112 + 0.061 = 0.6052 R-/ss = 0.1137 + 0.0306 = 0.1443rr/S- = 0.1137 + 0.0306 = 0.1443rr/ss = 0.1056

Answer 2

If R and S loci are 35 m.u. apart and a plant of genotype RS/rs is selfed, then the progeny phenotypes will be 0.606 RS; 0.106 rs; 0.144 Rs and 0.144 rS.

In this case, it is imperative to estimate gamete frequencies

RS = 0.65% / 2 = 0.325rs  = 0.65% / 2 = 0.325Rs  (recombinant) = 0.35 / 2 = 0.175rS (recombinant) = 0.35 / 2 = 0.175

In consequence, the F1 genotypes will be RS/RS = 0.1056  (i.e., 0.325 x 0.325); RS/Rs = 0.1137; RS/rS = 0.1137; rs/rs = 0.10562; rs/RS = 0.2112; rs/Rs = 0.1137; rs/rS = 0.1137; Rs/rS = 0.06; Rs/Rs = 0.0306; and rS/rS = 0.0306.

Finally, it is possible to obtain phenotypic frequencies by summing genotypic frequencies for each case in particular.

In conclusion, if R and S loci are 35 m.u. apart and a plant of genotype RS/rs is selfed, then the progeny phenotypes will be 0.606 RS; 0.106 rs; 0.144 Rs and 0.144 rS.

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Answers

Answer:

1-by transfecting small interfering RNAs against target genes of interest

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Explanation:

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Answer:

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Answer:

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Un proyecto se considera un esfuerzo temporario asociado a un conjunto de actividades las cuales son planificadas de antemano a fin de producir un determinado producto y/o servicio. Por ejemplo, en el área de biología molecular y biotecnología, un proyecto podría consistir en la planificación de las actividades necesarias para sintetizar una hormona en particular (insulina) utilizando plantas como biorreactores. Las etapas o fases por las cuales debe transitar cualquier proyecto de índole tecnológico son: 1-planteamiento de un problema: cual es la necesidad que impulsa el desarrollo del bien y/o servicio; 2-búsqueda de información relacionada al proyecto: en el ejemplo citado, cual es la especie de planta más factible de ser utilizada como biorreactor para producir insulina, cuales son los materiales requeridos para llevar a cabo este proceso, etc; 3-diseño y planificación del proyecto: cuales son los plazos estipulados para la puesta a punto del proyecto, cómo obtener los recursos necesario para llevar a cabo estas actividades, evaluación de los riesgos a los que se enfrenta el producto/servicio, etc; 4-construcción del proyecto: consiste en llevar a cabo las actividades delimitadas en el paso anterior, y 5-evaluación y divulgación: consiste en la obtención final del producto y/o servicio, como así también de las medidas de publicidad (divulgación) que tienen como objetivo crear un nicho de mercado para el producto/servicio.

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Answer:

attacks the outermost phosphorous group of the incoming nucleotide.  

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Answers

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Explanation:

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Explanation:

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Answers

Answer:

false

Explanation:

because I have don't get be few job days people and of will am to a on in the next time we come in for our meeting tomorrow morning to get some the information on how we will be working with our current client on our own so I don't am the a to make do I get have job that I am not going the the process best I I'm you me the chain

Answer:

no it's false.

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Answers

Answer:

True

Explanation:

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Light penetrates the clear water of the open ocean more deeply than it does lake
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What does this observation best indicate?
A Phytoplankton provides nutrients to consumers in the ecosystem.
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Answers

The answer is A: phytoplankton provides nutrients to consumers in the ecosystem.

Hope this helps:)

The given observation best indicates that the phytoplankton provides nutrients to consumers in the ecosystem.

What do you mean by Ecosystem?

An ecosystem may be defined as a place or an area where organisms of different species are present together and interact with one another for their need.

Phytoplanktons belong to lower trophic levels in the aquatic ecosystem. The organisms of higher trophic levels depend on it for the need of energy.

Therefore, the given observation best indicates that the phytoplankton provides nutrients to consumers in the ecosystem.

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