The two uniform, slender rods B1and B2, each of mass 2kg, are pinned together at P, and then B1is suspended from a pin at O. (This arrangement is called a double pendulum.) The counterclockwise couple C0, having moment 150????⋅m, is applied to B2beginning at t=0. Find the angular accelerations of B1and B2upon application of the couple, and the force exerted on B2at P.
Answers
Answer:
hello the diagram relating to this question is attached below
a) angular accelerations : B1 = 180 rad/sec, B2 = 1080 rad/sec
b) Force exerted on B2 at P = 39.2 N
Explanation:
Given data:
Co = 150 N-m ,
a) Determine the angular accelerations of B1 and B2 when couple is applied
at point P ; Co = I* ∝B2'
150 = ( (2*0.5^2) / 3 ) * ∝B2
∴ ∝B2' = 900 rad/sec
hence angular acceleration of B2 = ∝B2' + ∝B1 = 900 + 180 = 1080 rad/sec
at point 0 ; Co = Inet * ∝B1
150 = [ (2*0.5^2) / 3 + (2*0.5^2) / 3 + (2*0.5^2) ] * ∝B1
∴ ∝B1 = 180 rad/sec
hence angular acceleration of B1 = 180 rad/sec
b) Determine the force exerted on B2 at P
T2 = mB1g + T1 -------- ( 1 )
where ; T1 = mB2g ( at point p )
= 2 * 9.81 = 19.6 N
back to equation 1
T2 = (2 * 9.8 ) + 19.6 = 39.2 N
Related Questions
Tarnish is produced by a redox reaction that occurs when a metal reacts with
a nonmetallic compound. The green tarnish on a copper penny might be
produced by a reaction between copper and hydrogen sulfide. What occurs
during this reaction?
A. Hydrogen sulfide acts as an acid, and copper acts as a base.
B. Copper atoms gain electrons from sulfur atoms.
C. A double-replacement reaction takes place.
D. Copper atoms lose electrons to sulfur atoms.
Answers
Answer:
Copper atoms lose electrons to sulfur atoms
Explanation:
a p e x (:
Some material consisting of a collection of microscopic systems is kept at a high temperature, so that all excited states are populated and can participate in emission of photons. A photon detector capable of detecting photon energies from infrared through ultraviolet observes photons emitted with energies of 0.3 eV, 0.5 eV, 0.8 eV, 2.0 eV, 2.5 eV, and 2.8 eV. These are the only photon energy observed.
a) Draw and label a possible energy-level diagram for one of the microscopic systems, which has 4 bound states. On the diagram, indicate the transitions corresponding to the emitted photons. Explain briefly.
b) The material is now cooled down to a very low temperature, and the photon detector stops detecting photon emissions. Next a beam of light with a continuous range of energies from infrared thorugh ultraviolet shines on the material, and the photon detector observes the beam of light after it passes through the material. What photon energies in this beam of light are observed to be significantly reduced in intensity ("dark absorption lines")? Explain briefly.
Answers
Answer:
The responses to this question can be defined as follows:
Explanation:
During energy exchange E=hv, electrodes spring through one orbit to another
Please find the image file in the attachment.
Its absorption layer comprises 0.3 eV, 0.5 eV., 0.8 eV, 2.0 eV, 2.5 eV again, as light passes via material at low temperature those lines absorbed in the strata called absorption stratum.
mention & reasons why the ability to adapt to change is
important for improvement of your quality of life.
Answers
Answer:
The ability to adapt is important because :
1) It helps in the survival of human beings.
2) It brings more variation to the human kind.
3) It helps the species from getting endangered or extinct.
4) It brings transformation in the adapting kind.
Hope this helps you☺️☺️
If a ball rolls down a hill at a speed of 6.5m/s for 7s, how far did it travel?
Answers
Answer:
DABABY CONVERTIBLE LESS GOOO HA YE YE
Type the correct answer in each box. Round your answers to the nearest hundredth.
A ball with a mass of 1.5 kilograms is tied to the end of a rope. The ball is pulled to a height of 0.5 meters above the ground and released.
The ball has
joules of potential energy at position B. At position A, all of the energy changes to kinetic energy. The velocity of the ball at position A is
meters/second. Assume there’s no air resistance. Use g = 9.8 m/s2 , PE = m × g × h, and .
Answers
Hi there!
[tex]\large\boxed{PE = 7.35 J, \text{ }v \approx 3.13 m/s}[/tex]
To find the potential energy of the ball at B, we can use the equation:
PE = mgh
Plug the given gravity, mass, and height:
PE = (1.5)(0.5)(9.8) = 7.35 J
At A, all of this potential energy is changed to kinetic energy, so we can use the following equation:
v = √2KE/m
Plug in the solved for energy and mass:
v = √2(7.35)/1.5
Solve:
v ≈ 3.13 m/s
If the motion of B is uniformly accelerated, at what time will both graphs have
exactly the same slope? Explain.
Answers
Answer:
Im just here for the points man sorry
Explanation:
A classic demonstration illustrating eddy currents is performed by dropping a permanent magnet inside a conducting cylinder. The magnet does not go into free fall. Instead it reaches terminal velocity and can take a few seconds to drop a length of about a meter. Suppose the mass of the magnet is 70 g and width of 1.0 cm. It falls with a terminal velocity of 10 cm/s and the length of the pipe is 80 cm. The magnitude of the Joule heating from the eddy currents is approximately:________
Answers
Answer:
The correct solution is "0.69 N".
Explanation:
The given values are:
Mass of magnet,
m = 70 g
or,
= 0.07 kg
Width,
= 1.0 cm
Velocity,
= 10 cm/s
Length of the pipe,
= 80 cm
Whenever the velocity is constant, then the net force which is acting on the magnet will be "0".
On the magnet,
The up-ward force will be:
⇒ [tex]F=mg[/tex]
On substituting the values, we get
⇒ [tex]=0.07\times 9.8[/tex]
⇒ [tex]=0.69 \ N[/tex]
Question 4 of 10 A student measures the time it takes for two reactions to be completed. Reaction A is completed in 39 seconds, and reaction B is completed in 50 seconds. What can the student conclude about the rates of these reactions? A. The rate of reaction B is higher B. The rate of reaction A is higher. C. The rates of reactions A and B are equal.
Answers
Answer:
B. the rate of reaction is higher
Explanation:
places where computers is used
Answers
Answer:
Banks and financial.
Business.
Communication.
Defense and military.
Education.
Internet.
Medical.
Transportation.
etc..
Answer:
Super markets
Hospitals
Industries
Explanation:
In supermarket's computers helps them manage and organise data .
An object moves in a circle with a period of 0.025 hours. What is its frequency in Hz?
Answers
Frequency, is defined as the rate of rotation, or the number of rotations in some unit of time. Angular frequency, , is the rotation rate measured in radians. These three quantities are related by f = 1 T = ω 2 π .
what is frequency ?The frequency is the number of oscillation per unit time and it is used for defining the cyclic process like rotation, oscillation, wave etc.
The SI unit of the frequency is denoted as Hertz and the symbol λ represents it where one hertz means the wave completed one cycle in one second.
The frequency which explains the phenomenon of oscillatory and vibration like the mechanical vibration, sound signals, light, frequency waves etc. The “period” represented as the time required by the wave for one oscillation, i.e., it is inversely proportional to the frequency.
If the flashes, then the period is the time between the two flashes. And the frequency is the total number of flashes per second.
For more details regarding frequency, visit
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You're an electrical engineer designing an alternator (the generator that charges a car's battery). Mechanical engineers specify a 10-cmcm-diameter rotating coil, and you determine that you can fit 250 turns in this coil. To charge a 12-VV battery, you need a peak output of 17 VV when the alternator is rotating at 1500 rpm.
What do you specify for the alternator's magnetic field?
Answers
Answer:
13.78 mT
Explanation:
The peak voltage ε = ωNAB where ω = angular speed of coil = 1500 rpm = 1500 × 2π/60 rad/s = 50π rad/s = 157.08 rad/s, N = number of turns of coil = 250, A = area of coil = πr² where r = radius of coil = 10 cm = 0.10 m,
A = π(0.1 m)² = 0.03142 m² and B = magnetic field strength
So,
B = ε/ωNA
substituting the values of the variables into the equation given that ε = 17 V
So, B = ε/ωNA
B = 17 V/(157.08 rad/s × 250 turns × 0.03142 m²)
B = 17 V/(1233.8634 rad-turns-m²/s)
B = 0.01378 T
B = 13.78 mT
How are rainbows made?
Answers
Answer:
when it rains and at the same time it sunny there would appear a rainbow
What is the wavelength associated with 0.113kg ball traveling with velocity of 43 m/s?
Answers
Answer:
Wavelength = 1.36 * 10^{-34} meters
Explanation:
Given the following data;
Mass = 0.113 kg
Velocity = 43 m/s
To find the wavelength, we would use the De Broglie's wave equation.
Mathematically, it is given by the formula;
[tex] Wavelength = \frac {h}{mv} [/tex]
Where;
h represents Planck’s constant.
m represents the mass of the particle.
v represents the velocity of the particle.
We know that Planck’s constant = 6.6262 * 10^{-34} Js
Substituting into the formula, we have;
[tex] Wavelength = \frac {6.6262 * 10^{-34}}{0.113*43} [/tex]
[tex] Wavelength = \frac {6.6262 * 10^{-34}}{4.859} [/tex]
Wavelength = 1.36 * 10^{-34} meters
The greatest ocean depths on the Earth are found in the Marianas Trench near the Philippines. Calculate the pressure (in atm) due to the ocean at the bottom of this trench, given its depth is 10.3 km and assuming sea water density is constant all the way down. atm
Answers
Answer:
[tex]P = 103867260[/tex] atm
Explanation:
The pressure at the bottom of any liquid column is equal to product of density of the liquid , gravitational acceleration constant (g) and height of the water column
Thus, [tex]P = \rho*g*h[/tex]
Substituting the given values, we get -
[tex]P = 1029[/tex] kg/m3 [tex]* 9.8[/tex] m/s^2 [tex]*10.3 *1000[/tex] meters
[tex]P = 103867260[/tex] atm
Difference between corpuscular theory and wave theory
Answers
Answer:
Explanation:
Isaac Newton argued that the geometric nature of reflection and refraction of light could only be explained if light were made of particles, referred to as corpuscles, because waves do not tend to travel in straight lines.
The energy an object possesses due to its motion
Answers
Amount:
Mechanical energy is the energy possessed by an object due to its motion or its stored energy of position. Mechanical energy can be either kinetic (energy of motion) or potential (energy of position). An object that possesses mechanical energy is able to do work.
Q1. Helmut rides 5km in 2h on his bike. His speed was *
a) 10km/h
b) 2.5km/h
c) 0.4km/h
d) 2.5km
Q2. A plane is travelling at 250km/h and must reach a target that is 3h 58min away. The distance to the target is. *
a) 1000km
b) 89500km
c) 62.5km
d) not enough information
Answers
Answer:
Speed of bike = 2.5 km/h
Distance travel = 1,000 km (Approx.)
Explanation:
Given:
Distance cover by Helmut = 5 km
Time taken = 2 hour
Find:
Speed of bike
Computation:
Speed = Distance / Time
Speed of bike = 5 / 2
Speed of bike = 2.5 km/h
Given:
Speed of plane = 250 km/h
time taken = 3 hr 58 min = 3.967 hr
Find:
Distance travel
Computation:
Distance = Speed x time
Distance travel = 250 x 3.967
Distance travel = 991.669
Distance travel = 1,000 km (Approx.)
How much current is drawn by a television
with a resistance of 43 Ω that is connected
across a potential difference of 112 V?
Answer in units of A.
Answers
Answer:
Explanation:
v = ir
v/r = i
112/43 = i
2.60 ≈ i
These two questions are connected to the figure.
Answers
Answer:
A, and E
Explanation:
A swift blow with the hand can break a pine board. As the hand hits the board, the kinetic energy of the hand is trans- formed into elastic potential energy of the bending board, if the board bends far enough, it breaks. Applying a force to the center of a particular pine board deflects the center of the board by a distance that increases in proportion to the fore. Ultimately the board breaks at an applied force of 800 N and a deflection of 1.2 cm.
a. To break the board with a blow from the hand, how fast must the hand be moving? Use 0.50 kg for the mass of the hand.
b. If the hand is moving this fast and comes to rest in a dis- tance of 1.2 cm, what is the average force on the hand?
Answers
(a) The velocity is "6.2 m/s".
(b) The average force is "800.83 N".
According to the question,
Force,
F = 800 NDeflection,
x = 1.2 cm= [tex]1.2\times 10^{-2} \ m[/tex]
As we know,
The work done,
→ [tex]W = F\times d[/tex]
[tex]= 800\times 1.2\times 10^{-2}[/tex]
[tex]= 9.6 \ J[/tex]
(a)
Given:
Mass of hand,
m = 0.50 kgNow,
→ [tex]\frac{1}{2} mv^2 = 9.6 \ J[/tex]
[tex]v = \sqrt{\frac{2\times 9.6}{0.50} }[/tex]
[tex]= 6.2 \ m/s[/tex]
(b)
→ [tex]v^2 = u^2 +2ax[/tex]
→ [tex]a= \frac{v^2}{2x}[/tex]
[tex]= \frac{(6.2)^2}{2\times 1.2\times 10^{-2}}[/tex]
[tex]= 1601.67 \ m/s^2[/tex]
hence,
The average force will be:
→ [tex]F_{avg} = m\times a[/tex]
[tex]= 0.50\times 1601.67[/tex]
[tex]= 800.83 \ N[/tex]
Thus the above answers are correct.
Learn more:
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someone is pushing a shopping cart and maintaining the same applied force. another person keeps adding items into the cart increasing the mass of cart. what would happen to the acceleration?
Answers
Answer:
The rate of acceleration slow
Explanation:
Force (N) = mass (kg) × acceleration (m/s²) , because acceleration multiply by mass it a inverse relationship
A certain gas is compressed adiabatically. The amount of work done on the gas is 800 J. What is the change in the internal (thermal) energy of the gas?
Answers
Answer:
800J
Explanation:
Using the formula for change in the internal energy of a system
∆U = Q - W
Q = heat added to the system
W =workdone by system.
We know the process is an adiabatic one then, there no addition/ removal of heat, then Q= 0
(∆U = -W )
Then substitute for W, we have
∆U = -[-800]
∆U= 800J
∆U = 800J
Which two mixtures are homogeneous?
Answers
Answer:
sand and air
Explanation:
air is a mix of carbon dioxide and oxygen and sand is a mix of rocks and stuff
A proton moving at v1 = 7.0 Mm/s collides elastically head-on with a second proton moving in the opposite direction at v2 = 8.3 Mm/s. (a) Find the velocity of the first proton after the collision. (b) Find the velocity of the second proton after the collision
Answers
Answer:
(a) The final velocity of the first proton after the collision = 8.3 m/s in the opposite to its initial direction
(b) The final velocity of the second proton after the collision = 7 m/s in the opposite to its initial direction
Explanation:
The given parameter of the protons are;
The velocity of the first proton, v₁ = 7.0 Mm/s
The velocity of the second proton, v₂ = -8.3 Mm/s
The type of collision = Elastic collision
In an elastic collision, the kinetic and momentum energies are conserved, therefore, we have, for the initial and final momentums;
(m₁·v₁ + m₂·v₂)₁ = (m₁·v₁ + m₂·v₂)₂
1/2·(m₁·v₁² + m₂·v₂²)₁ = 1/2·(m₁·v₁² + m₂·v₂²)₂
Where, m₁ = m₂ or the protons, we get;
(v₁ + v₂)₁ = (v₁ + v₂)₂
(v₁² + v₂²)₁ = (v₁² + v₂²)₂
Therefore;
7.0 - 8.3 = v₁ + v₂
-1.3 = v₁ + v₂...(1)
7.0² + (-8.3)² = v₁² + v₂²
117.49 = v₁² + v₂²...(2)
From equation (1), we have;
v₁ = -1.3 - v₂
Plugging the value v₁ = -1.3 - v₂ in equation (2) gives;
117.49 = v₁² + v₂² = (-1.3 - v₂)² + v₂² = 2·v₂² + 12·v₂ + 1.69
∴ 2·v₂² + 2.6·v₂ + 1.69 - 117.49 = 0
2·v₂² + 2.6·v₂ - 115.8 = 0
Using the quadratic formula, we have;
v₂ = (-2.6 ± √(2.6² - 4×2×(-115.8)))/(2 × 2)
∴ v₂ ≈ -8.3 m/s or 7 m/s
When v₂ ≈ -8.3, v₁ = -1.3 - v₂ ≈ -1.3 - (-8.3) = 7
When v₂ ≈ 7, v₁ = -1.3 - v₂ ≈ -1.3 - (7) = -8.3
Therefore, the final velocity of the first proton after the collision = 8.3 m/s in the opposite to its initial direction
(b) The final velocity of the second proton after the collision = 7 m/s in the opposite to its initial direction.
1. The process of producing energy by utilizing heat trapped inside the earth's
surface is called
A) Hydrothermal energy
C) Solar energy
B) Geo-Thermal energy
D) Wave energy
Answers
Answer:
B
Explanation:
The process is called Geo-Thermal energy because it's an inexhaustible source of energy
Answer ) Geo thermal energy.
Mars can have bigger mountains than the Earth because it has a smaller mass and surface gravity.
True
False
Answers
Answer:
True
Explanation:
5. How does a jack make changing a tire easier?
Answers
Answer: An jack makes changing a tire easier because it lifts up the car to get the tire off of the ground.
Explanation:
En una balanza de fábrica se determina la masa de un cuerpo y se obtiene
1 M kg 280
con
un error aparente
1 1 0,5 a
M kg
. En un laboratorio, se hace lo mismo con otro cuerpo y
se determina
2 M g 23,545
con un error
2 2 0,001 a
M g .
¿Dónde se cometió mayor erro
Answers
A 100-n object and a 50-n object are placed on scales a and b respectively inside an elevator ascending with constant velocity 3.0m/s which statement below correctly describes the readings on the scales inside the elevator
Answers
Answer: b
Explanation:
The reading of the scale of the elevator ascending with constant velocity is 150 N.
Reading of the scale
The reading of the scale on the elevaor is calculated by applying Newton's second law of motion;
R = m(a + g)
R = ma + mg
R = F + W
where;
a is the acceleration of the objectsAt constant velocity, the acceleration of the object is zero (0).
R = 0 + 100 + 50
R = 150 N
Thus, the reading of the scale of the elevator ascending with constant velocity is 150 N.
Learn more about reading of scale here: https://brainly.com/question/2516315
Polarizing windows, filters, etc. are often used to reduce the amount of light that enters the lens of a camera or into a room or a car. A library atrium has an overhead skylight that lets in too much light during the day which heats up the interior of the library far too much. The building engineer installs new double paned polarizing sky lights to reduce the intensity. If sunlight, which is unpolarized, has an average intensity of 1250 W/m^2.
Required:
What angle should the polarizing axis of the second pane of the window make with the polarizing axis of the first pane of the window in order to reduce the intensity of the sunlight to 33% of the original value?
Answers
Answer:
The answer is "[tex]35.6^{\circ}[/tex]"
Explanation:
The sunlight level of the first panel:
[tex]I_1 = \frac{I_o}{2}[/tex]
When the light of this intensity passes through the second window:
[tex]I_2 = I_1 \cos^2 \theta\\\\I_2 = \frac{I_o}{2} \cos^2 \theta[/tex]
[tex]\frac{I_2}{I_o} = 0.33 (33\%) \\\\[/tex]
therefore,
[tex]0.33 = \frac{1}{2} \cos^2 \theta\\\\\cos^2 \theta = 0.66\\\\\cos \theta = \sqrt{0.66} = 0.8124\\\\\theta = \cos^{-1}( 0.8124) = 35.6^{\circ}\\\\[/tex]