18 out of 20 to percentage
Answer:
90%
Step-by-step explanation:
Find the slope of the line.
Please Help
will someone help me with this?
height of movable brigde 37cm
width of movable brigde 85 cm
Which set of numbers is in DESCENDING order?
* 1 point
WILL GIVE BRANLIEST
55, -8, -2, -282
55, -2, -8, -282
-282, -8, -2, 55
-282, 55, -8, -2
Find the sum of the following arithmetic series:
(a) 6-5-16 - .... -115 (b) 21
(c) 13 + 6 -1 - .... -106
Find the sum of the first 500 odd numbers.
Answer:
12345678910
Step-by-step explanation:
CHARRRRRRRRR joke lang bestie
I need help in this algebra problem plz
Answer:
X+2
Step-by-step explanation:
The quadrilateral shown is a rectangle. What is m∠ZVY?
A) 39°
B) 59°
C) 61°
D) 119°
Answer: hey bro i can solve this for you but you need to show the quadrilateral. without it i can't solve it.
Step-by-step explanation:
Question 7 (5 points)
Find the distance between a point (-3, 4) and a vertical line at x = 4.
A) -7
B) 8
O
C) 1
OD 7
Answer:
D.7
Step-by-step explanation:
[tex] 4 - ( - 3) = 4 + 3(because \: - \times - ) \: it \: is \: positive \\ = 7[/tex]
please help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
√11 = 3.31....
option 1. Irrational: √11 = 3.3
Answer:
Irrational [tex]\sqrt{11}[/tex] = 3.3
Step-by-step explanation:
Have a nice day!! :)
Question 3 (Fill-In-The-Blank Worth 3 points) (04.04) Point R is at (2, 1.2) and Point T is at (2, 2.5) on a coordinate grid. The distance between the two points is such as 8.2.) (Input numbers and decimal point only, Answer for Blank 1:
9514 1404 393
Answer:
1.3
Step-by-step explanation:
The two points are on the same vertical line, so the distance between them is the distance between their y-coordinates:
2.5 -1.2 = 1.3
The distance between the two points is 1.3 units.
the y coordinate is 7 more than the x coordinate
Answer:
if you have the value of x then y =x +7
Plsssss help it is khan academy!!!
Giving brainliest!!!!!
Answer:
434 [tex]cm^3[/tex]
Step-by-step explanation:
volume of bottom: 6 x 10 x 5 = 300 [tex]cm^3[/tex]
volume of top:
[tex]V = (\frac{4}{3}\pi r^3)/2\\\\= (\frac{4}{3}\pi(4)^3)/2\\[/tex]
≈ 134.041 [tex]cm^3[/tex]
300 + 134.041 = 434.041
they want to the nearest tenth, so it would just be 434.0
A trader buys 30 shirts for #x each. He sells
them all for #y each. What is his profit
Help me out pls, i’m new to this whole hypotenuse thing
Answer:
x = 6.5
Step-by-step explanation:
Reference angle = 54°
Length of Side opposite to 54° = x
Hypotenuse = 8 cm
Recall: SOHCAHTOA.
Apply SOH:
Sin 54 = Opp/Hyp
Sin 54 = x/8
x = 8*sin 54
x = 6.47213595 ≈ 6.5 cm (nearest tenth)
The average of an electrician's hourly wage and a plumber's hourly wage is $33. One day a contractor hires an electrician for 7hr of work and the plumber for 4hr of work and pays a total of $396 in wages. Find the hourly wage for the electrician and for the plumber.
Answer:
Electrician = 44
Plumber = 22
Step-by-step explanation:
Let :
Electrician Hourly wage = x
Plumber's hourly wage = y
Average = 33
(x + y ) /2 = 33
x + y = 66 - - - - (1)
7x + 4y = 396 - - - (2)
From (1)
x = 66 - y
Put x = 66 - y in (2)
7(66-y) + 4y = 396
462 - 7y + 4y = 396
-3y = - 66
y = 22
x = 66 - 22
x = 44
Electrician = 44
Plumber = 22
PLS ANSWER QUICK! Thanks!
Answer:
The correct answer would be [tex]a=\sqrt{c^2-b^2}[/tex]
Step-by-step explanation:
given [tex]a^2+b^2=c^2[/tex] we want to solve for a
How?
We can do this by using basic algebra ( isolating the variable (a ))
Step 1 subtract [tex]b^2[/tex] from each side
[tex]a^2+b^2-b^2=a^2\\c^2-b^2=c^2-b^2[/tex]
now we have [tex]a^2=c^2-b^2[/tex]
step 2 take the square root of each side
[tex]\sqrt{a^2} =a\\\sqrt{c^2-b^2} =\sqrt{c^2-b^2}[/tex]
we're left with [tex]a=\sqrt{c^2-b^2}[/tex]
Hence your answer is A
What's another name for qualitative variables?
Answer:
A qualitative variable, also called a categorical variable, is a variable that isn't numerical.
A sample of 1300 computer chips revealed that 50% of the chips do not fail in the first 1000 hours of their use. The company's promotional literature states that 47% of the chips do not fail in the first 1000 hours of their use. The quality control manager wants to test the claim that the actual percentage that do not fail is different from the stated percentage. Make the decision to reject or fail to reject the null hypothesis at the 0.01 level.
Answer:
The pvalue of the test is 0.03 > 0.01, which means that we fail to reject the null hypothesis at the 0.01 level.
Step-by-step explanation:
The company's promotional literature states that 47% of the chips do not fail in the first 1000 hours of their use. The quality control manager wants to test the claim that the actual percentage that do not fail is different from the stated percentage.
This means that at the null hypothesis we test that the proportion is 47% = 0.47, that is:
[tex]H_0: p = 0.47[/tex]
And at the alternate hypothesis, we test that the proportion is different from 47%, that is:
[tex]H_a: p \neq 0.47[/tex]
The test statistic is:
[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, [tex]\sigma[/tex] is the standard deviation and n is the size of the sample.
47% is tested at the null hypothesis:
This means that [tex]\mu = 0.47, \sigma = \sqrt{0.47*0.53}[/tex]
A sample of 1300 computer chips revealed that 50% of the chips do not fail in the first 1000 hours of their use.
This means that [tex]n = 1300, X = 0.5[/tex]
Value of the test statistic:
[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
[tex]z = \frac{0.5 - 0.47}{\frac{\sqrt{0.47*0.53}}{\sqrt{1300}}}[/tex]
[tex]z = 2.17[/tex]
Pvalue of the test and decision:
The pvalue of the test is the probability that the proportion differs from 0.47 by at least 0.5 - 0.47 = 0.03, which is P(|Z| > 2.17), which is 2 multiplied by the pvalue of Z = -2.17
Z = -2.17 has a pvalue of 0.015
2*0.015 = 0.03
The pvalue of the test is 0.03 > 0.01, which means that we fail to reject the null hypothesis at the 0.01 level.
What is the volume of the solid generated when the region in the first quadrant bounded by the graph of y=x^3, the x-axis, and the vertical line x=2 is revolved about the x-axis?
Show work.
A
[tex]4[/tex]
B
[tex] \frac{128}{7} [/tex]
C
[tex]4\pi[/tex]
D
[tex] \frac{128\pi}{7} [/tex]
Answer:
The first thing we need to do is to find the area bounded by:
y = x^3
y = 0
between:
x = 0 and x = 2
This is the integral of the given function between x = 0 and x = 2, written as:
[tex]\int\limits^2_0 {x^3} \, dx = \frac{2^4}{4} - \frac{0^4}{4} = 2^2 = 4[/tex]
This means that the area of the bounded region is 4 square units.
Now, if we do a full rotation around the x-axis, the volume generated will be equal to the area that we obtained times 2*pi units.
The volume is:
V = (4 square units)*(2*pi units) = 8*pi cubic units.
(Notice that no option coincides with this, there may be a mistake in the options)
A student records the repair cost for 22 randomly selected dryers. A sample mean of $98.78 and standard deviation of $15.49 are subsequently computed. Determine the 95% confidence interval for the mean repair cost for the dryers. Assume the population is approximately normal. Step 1 of 2 : Find the critical value that should be used in constructing the confidence interval. Round your answer to three decimal places.
Answer:
The critical value that should be used is T = 2.0796.
The 95% confidence interval for the mean repair cost for the dryers is between $91.912 and $105.648.
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 22 - 1 = 21
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 21 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.95}{2} = 0.975[/tex]. So we have T = 2.0796, which is the critical value that should be used.
The margin of error is:
[tex]M = T\frac{s}{\sqrt{n}} = 2.0796\frac{15.49}{\sqrt{22}} = 6.868[/tex]
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 98.78 - 6.868 = $91.912
The upper end of the interval is the sample mean added to M. So it is 98.78 + 6.868 = $105.648
The 95% confidence interval for the mean repair cost for the dryers is between $91.912 and $105.648.
4 * (3.4+2)-(56 divided by 7)= 13.6, please give an explanation to this problem!!
Answer:
[tex]=13.6[/tex]
Step-by-step explanation:
[tex]\mathrm{Remove\:parentheses}:\quad \left(a\right)=a[/tex]
[tex]=4\left(3.4+2\right)-\frac{56}{7}[/tex]
[tex]=21.6-8[/tex]
[tex]\mathrm{Subtract\:the\:numbers:}\:21.6-8=13.6[/tex]
[tex]=13.6[/tex]
Which type of sequence is shown? 5, 10, 15, 20, 25, . . .
geometric
both arithmetic and geometric
arithmetic
neither arithmetic nor geometric
Answer:
Arithmetic Sequence
Step-by-step explanation:
In Arithmetic sequence each term increases by adding/subtracting some constant k. This is in contrast to a geometric sequence where each term increases by dividing/multiplying some constant k.
(NO LINKS) A space shuttle travels at 2.6 x 10,000 feet per second. An hour is 3.6 x 1,000 seconds. This expression can be used to find the number of feet the space shuttle travels in an hour. How many feet does the shuttle travel in an hour?
Answer:
1) 7.22 ft in a hr & 2) Choice C. y = 0.50x + 2
Step-by-step explanation:
1) Space shuttle
2.6 x 10,000 = 26,000ft
3.6 x 1,000 = 3,600 seconds = 1 hr
26,000/3,600 = 7.22 ft in a hr
2) Taxi company
y = 0.50x + 2
3 cm
.
.
5 cm
If the base is halved and the height is quadrupled, then which of the following statements
about its area will be true?
Answer:
I think 7
Step-by-step explanation:
if the moon is purple then what toothpaste do u use on your but
Evaluate the expression: -(8 - 12) + 6° + (-4)2.
Answer:
-4 + 6°
Step-by-step explanation:
- (8 - 12) + 6° + (- 4)2 = - ( - 4) + 6° - 8 = 4 + 6° - 8 = - 4 + 6°
Someone please help me answer this!1
Answer:
16 km is the answer
Step-by-step explanation:
a (Colton to parents' house) = 12 km
b = ?
c (parents' house to grandparents' house) = 20 km
According to the Pythagoras theorem,
a² + b² = c²
12² + b² = 20²
144 + b² = 400
b² = 400 - 144
b² = 256
b = 16
∴ Colton is 16 km away from his grandparents' house.
Enter the measure of YVZ in degrees
Answer:
(3x+5)+(2x) = 90
5x + 5 = 90
5x = 85
x = 17
YVZ = 3×17 +5
=56°
what is the value of x?
mong 500 marriage license applications chosen at random in a givenyear, there were 48 in which the woman was at least one year older than the man, and among400 marriage license applications chosen at random six years later, there were 68 in which thewoman was at least one year older than the man. Construct a 99% confidence interval for thedifference between the corresponding true proportions of marriage license applications in whichthe woman was at least one year older than the man. Interpret the CI in the context of theproblem.
Answer:
CI 99% = ( 0,022 ; 0,126 )
Step-by-step explanation:
First sample
n₁ = 500
x₁ = 48
p₁ = x₁ / n₁ = 48 / 500 p₁ = 0,096 p₁ = 9,6 %
Second sample
n₂ = 400
x₂ = 68
p₂ = x₂ / n₂ = 68 / 400 p₂ = 0,17 p₂ = 17 %
CI = 99 % significance level α = 1 % α = 0,01
z(c) for α = 0,01 is from z- table z(c) = 2,325
CI = ( p₂ - p₁ ) ± z(c) *√ p*q* ( 1/n₁ + 1 / n₂ )
Where
p₂ - p₁ = 0,17 - 0,096 = 0,074
p = ( x₁ + x₂ ) / n₁ + n₂
p = ( 48 + 68 ) /( 500 + 400)
p = 116/ 900 p = 0,1288 and q = 1 - p q = 0,8712
z(c) *√ p*q* ( 1/n₁ + 1 / n₂ ) = 2,325 * √ 0,1288*0,8712 ( 1 / 500 + 1/ 400)
2,235 * 0,02247
z(c) *√ p*q* ( 1/n₁ + 1 / n₂ ) = 0,052
Then
CI 99 % = 0,074 ± 0,052
CI 99% = ( 0,022 ; 0,126 )
The difference between the groups shows that the proportion in the second group was bigger than in the first group.
The CI in the context of the problem is CI 99% = ( 0,022 ; 0,126 )
What will be the Solution of This problem?
Given first sample is
n₁ = 500
x₁ = 48
[tex]P_{1} =\dfrac{X_{1} }{n_{1} }[/tex] [tex]P_{1} =\dfrac{48}{500}[/tex]
p₁ = 0,096 p₁ = 9,6 %
Given second sample
n₂ = 400
x₂ = 68
[tex]P_{2} =\dfrac{X_{2} }{n_{2} }[/tex] [tex]P_{2} =\dfrac{68}{400}[/tex]
p₂ = 0,17 p₂ = 17 %
Since given CI = 99 % so significance level α = 1 % α = 0,01
From Z-Table z(c) for α= 0,01 is = 2,325
CI = [tex](P_{2} -P_{1}[/tex] ± [tex]Z(c)\sqrt[2]{p\times q} (\dfrac{1}{n_{1} } +\dfrac{1}{n_{2} } )[/tex]
Where
p₂ - p₁ = 0,17 - 0,096 = 0,074
[tex]P= \dfrac{X_{1} +X_{2} }{n_{1}+n_{2} }[/tex]
[tex]P=\dfrac{48+68}{500+400}[/tex]
[tex]P=\dfrac{116}{900}[/tex]
p = 0,1288 and q = 1 - p q = 0,8712
[tex]Z(c)\sqrt[2]{p\times q} (\dfrac{1}{n_{1} } +\dfrac{1}{n_{2} } )[/tex] [tex]2325\times\sqrt[2]{0.1288\times 0.8712} (\dfrac{1}{500_{} } +\dfrac{1}{400_{} } )[/tex]
[tex]Z(c)\sqrt[2]{p\times q} (\dfrac{1}{n_{1} } +\dfrac{1}{n_{2} } )=0.052[/tex]
Then
CI 99 % = 0,074 ± 0,052
CI 99% = ( 0,022 ; 0,126 )
Hence the difference between the groups shows that the proportion in the second group was bigger than in the first group.
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