What is the perimeter of this polygon?

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a
24 units
b
22 units
c
28 units
d
26 units

Answer:

D

Step-by-step explanation:

Answer:

scalene trangle

Step-by-step explanation:

Answer:

x

Step-by-step explit can only be a function if every input has its own output

Answer The Greatest Common Factor of 16, 40, 68 is 4. But the GCF of 16s^3t, 40s^5 and 68t^2 is 1, as there are no common terms for these given alphanumeric terms.

Step-by-step explanation:

Answer:

x= -730/363

Step-by-step explanation:

9x-6=729×3(x+2) multiply

9x-6=2187(x+2) remove the paranthesis

9x-6=2187x+4374 move the terms

9x-2187x=4374+6 collect like terms calculate

-2178x=4380 divide both sides

Answer:

Sum of the first five terms of the geometric sequence in which a1=5 and r=1/5 is [tex]\mathbf{S_n=\frac{781}{125} }[/tex]

Step-by-step explanation:

We need to find sum of the first five terms of the geometric sequence in which a1=5 and r=1/5

The formula used to find sum of the geometric sequence is: [tex]S_n=\frac{a(r^n-1)}{r-1}[/tex]

Where a is the first term, r is the common ratio and n is the number of terms

Now finding sum of the first five terms of the geometric sequence

We have a=5, r=1/5 and n=5

Putting values in the formula:

[tex]S_n=\frac{a(r^n-1)}{r-1}\\S_n=\frac{5((\frac{1}{5}) ^5-1)}{\frac{1}{5}-1}\\S_n=\frac{5(\frac{1}{3125}-1)}{\frac{1-5}{5}}\\S_n=\frac{5(\frac{1-3125}{3125})}{\frac{-4}{5}}\\S_n=\frac{5(\frac{-3124}{3125})}{\frac{-4}{5}}\\S_n=5(\frac{-3124}{3125})}\times{\frac{-5}{4}}\\S_n=\frac{781}{125}[/tex]

So, sum of the first five terms of the geometric sequence in which a1=5 and r=1/5 is [tex]\mathbf{S_n=\frac{781}{125} }[/tex]

Answer:

A. Dennis can complete less than 24 questions.

Step-by-step explanation:

Let x represent the remaining number of questions to be completed.  He can complete each of them in 5/2 minutes each; this gives us the expression 5/2x.

He has already spent 10 minutes; this gives us 5/2x+10.

He has less than 70 minutes to spend; this gives us the inequality

5/2x+10<70

Subtract 10 from each side:

5/2x+10-10 < 70-10

5/2x < 60

Divide both sides by 5/2:

5/2x÷5/2 < 60÷5/2

x < 60/1 ÷ 5/2

To divide fractions, flip the second one and multiply:

x < 60/1 × 2/5

x < 120/5

x < 24

Answer:

Dennis can complete fewer than 24 questions.

Step-by-step explanation:

Answer:

3 • 74509

I this is right

Hello.

To find this, divide the cost per amount.

In this case, the cost of the tickets is $27, and the amount is 3.

Divide 27 by 3.

27 / 3 = 9

Each ticket costs $9.

Answer:

$9 per ticket

Step-by-step explanation:

all you do is divide 27 by 3 and get 9

Answer:

5

Step-by-step explanation:

80 divided by 8 = 10 divided by 2 = 5

Answer:

They are congruent bc they are the same size and shape

Answer:

Congruent by SAS

Step-by-step explanation:

As given by the diagram, we have two congruent sides already. From the set of parallel lines, we see that two angles are congruent because they are corresponding. Luckily, this angle falls between the two congruent sides, which gives you the proof of SAS.

Answer:

190,750 decreased by 9% is 173,582.5

Step-by-step explanation:

Answer:

-8n+64

Step-by-step explanation:

Answer:

a.3.30

Step-by-step explanation:

Answer:

3.30

Step-by-step explanation:

Because I did le Quiz

Answer:

[tex]x = 16[/tex]

Step-by-step explanation:

Given

[tex]log_{16}(x) + log_4(x) + log_2(x) = 7[/tex]

Required

Solve for x

[tex]log_{16}(x) + log_4(x) + log_2(x) = 7[/tex]

Change base of 16 and base of 4 to base 2

[tex]\frac{log_2(x)}{log_2(16)} + \frac{log_2(x)}{log_2(4)} + log_2(x) = 7[/tex]

Express 16 and 4 as 2^4 and 2^2 respectively

[tex]\frac{log_2(x)}{log_2(2^4)} + \frac{log_2(x)}{log_2(2^2)} + log_2(x) = 7[/tex]

The above can be rewritten as:

[tex]\frac{log_2(x)}{4log_22} + \frac{log_2(x)}{2log_22} + log_2(x) = 7[/tex]

[tex]log_22 = 1[/tex]

So, we have:

[tex]\frac{log_2(x)}{4*1} + \frac{log_2(x)}{2*1} + log_2(x) = 7[/tex]

[tex]\frac{1}{4}log_2(x) + \frac{1}{2}log_2(x) + log_2(x) = 7[/tex]

Multiply through by 4

[tex]4(\frac{1}{4}log_2(x) + \frac{1}{2}log_2(x) + log_2(x)) = 7 * 4[/tex]

[tex]log_2(x) + 2}log_2(x) + 4log_2(x) = 28[/tex]

[tex]7log_2(x) = 28[/tex]

Divide through by 7

[tex]\frac{7log_2(x)}{7} = \frac{28}{7}[/tex]

[tex]log_2(x) = 4[/tex]

Apply the following law of logarithm:

If [tex]log_ab = c[/tex] Then [tex]b = a^c[/tex]

So, we have:

[tex]x = 2^4[/tex]

[tex]x = 16[/tex]

Answer:

Step-by-step explanation:

−2 1/6 divided by 1 1/4:

1) to divide that mixed number we'll need to turn it into an improper fraction:

[tex] - 2\frac{1}{6} = - ( \frac{6 \times 2 + 1}{6} ) = - \frac{13}{6} \\ 1 \frac{1}{4} = \frac{4 \times 1 + 1}{4} = \frac{5}{4} [/tex]

2) now let's divide it, reciprocating 1 1/4 and multiplying both fractions one by another:

[tex] - \frac{13}{6} \times \frac{4}{5} = - \frac{52}{30} = - \frac{26}{15} [/tex]

3) Hence the answer is -26/15

Answer:

Amish driving buggies and using horses and mules instead of tractors

Step-by-step explanation:

Answer:  -6 and 6

Step-by-step explanation:  

Possible factors that could produce 3x² + 6x +3 are  (x + 1)(3x + 3)

the solution for values of x: x+1=0, x= -1  3x+3=0,  3x= -3 . x= -1 . Same.

Possible factors that could produce 3x² - 6x +3 are  (x - 1)(3x - 3)

the solution for values of x: x-1=0, x= 1  3x-3=0,  3x= 3 . x= 1 . Same.

From the attached graph of the possible equations, you can see that 9 and -9 won't produce ONE real solution. They each have "zeros" at two points on the x-axis. That is two solutions that would make x = 0.

The equations with -6 and +6 each touch the x-axis at only one point each.

y-1= ±3/10(x-2)

Im not sure how to get this answer but my teacher gave it to me so i hope this helps!

The equation of the asymptote of the given hyperbola is; y - 1 = ±(3/10)(x - 2)

We are given the equation of the hyperbola as;

[(y - 1)²/9] - [(x - 2)²/100] = 1

We can rewrite this equation as;

[(y - 1)²/3²] - [(x - 2)²/10²] = 1

The general equation form of hyperbola is;

[(y - k)²/a²] - [(x - h)²/b²] = 1

Comparing this general form to our given equation we can see that;

k = 1

h = 2

a = 3

b = 10

Now the equation of the asymptote of a hyperbola follows the general formula;

y = ±[a(x - h)/b] + k

Plugging in the relevant values gives us;

y = ±(3/10)(x - 2) + 1

y - 1 = ±(3/10)(x - 2)

Read more about hyperbola asymptotes at;https://brainly.com/question/12919612

Answer:

P(A∩B) = 0.12

Step-by-step explanation:

Given:

Students receive financial aid P(A) = 40% = 0.4

Students receive financial aid and first generation P(B/A) = 30% = 0.3

Find:

Probability [Selected student receives financial aid and is first generation college student] P(A∩B)

Computation:

P(A∩B) = P(A) x P(B/A)

P(A∩B) = 0.4 x 0.3

P(A∩B) = 0.12

Answer: 2800 dollars in intrest

Step-by-step explanation:

Answer:

1. y=3x+2

2. slope=3 It represents the rate of which the panda gained weight over the course of 4 weeks

3. 2 It represents the weight of the panda at the first week

Step-by-step explanation:

Answer:

776

Step-by-step explanation:

Answer:

2.31 and 3.31

Step-by-step explanation:

since .81 is repeating, we can assume .31 does too

Answer:

Can you show the pie chart please.

Step-by-step explanation:

Answer:

show pie chart

Step-by-step explanation:

Answer:

-7/10

Step-by-step explanation:

Answer:

you got you must be so Mad rn that I'm not helping you with your question Jiggle what you going to do with that big old behind

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

I'm pretty sure it's C

Answer:

not sure but b or c because it says less than

Step-by-step explanation:

Answer:

Slope = 7

Y intercept = 23

Step-by-step explanation:

(can I get brainliest now)

Answer:

1.5 repeating

Step-by-step explanation: