speed = 40 m/s
Explanation:
Since the object is dropped, V0y = 0.
Vy = V0y - gt
= -(10 m/s^2)(4 s)
= -40 m/s
This means that its velocity is 40 m/s downwards. Its speed is simply 40 m/s.
The speed acquired by a freely falling object 4 seconds after being dropped from a rest position would be 40 meters/seconds.
What are the three equations of motion?There are three equations of motion given by Newton
The first equation is given as follows
v = u + at
the second equation is given as follows
S = ut + 1/2×a×t²
the third equation is given as follows
v² - u² = 2×a×s
Keep in mind that these calculations only apply to uniform acceleration.
As given in the problem, we have to find the speed acquired by a freely falling object 4 seconds after being dropped from a rest position,
By using the first equation of motion,
v = u + at
initial velocity(u) = 0 m/s
acceleration(a) = 10 m/s²
v = 0 + 10×4
v = 40 meters/seconds
Thus, the speed acquired by a freely falling object 4 seconds after being dropped from a rest position would be 40 meters/seconds.
Learn more about equations of motion from here,
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pls solve this:
if u solve this, I will surely mark u as brilliant
Answer: The frequency of a pendulum is [tex]0.2 s^{-1}[/tex].
Explanation:
Time period is defined as the time required to produce complete wave.
As we know that the frequency and time are inversely proportional to each other.
That means,
[tex]\nu =\frac{1}{T}[/tex]
Where,
[tex]\nu[/tex] is frequency of pendulum
T is time period
Given:
Time period = 5 seconds
Now putting all the given values in the above formula, we get the frequency of the pendulum.
[tex]\nu =\frac{1}{T}\\\\\nu =\frac{1}{5s}\\\\\nu =0.2s^{-1}[/tex]
Therefore, the frequency of a pendulum is [tex]0.2 s^{-1}[/tex].
g A ball is tossed straight up from the surface of a small, spherical asteroid with no atmosphere. The ball rises to a height equal to the asteroid's radius and then falls straight down toward the surface of the asteroid. What forces, if any, act on the ball while it is on the way up
Answer:
Only a decreasing gravitational force that acts downward
Explanation:
The gravitational force is the gravitational pull which attract a mass of smaller size by the mass of a bigger size. It is the force which attract two masses close to each other.
In the context, when a ball is tossed up from the surface of an asteroid that have no atmosphere, the ball rises up and then falls back to the surface of the asteroid. The ball falls back because the gravitational pull of the asteroid pulls back the ball to its surface. Thus a decreasing gravitational force acts on the ball in the downward direction while the ball is in its way up.
An electric field has a positive test charge of 5.00 C placed in it. The force on the test charge is
6.000 N. The magnitude of the electric field at the location of the test charge is
o 30.0 NVC
0 1.20 N/C
0 120, NVC
O 3.00 N/C
01.02 N/C
Answer:
yes
Explanation:
this means the answer is yes
PLEASE HELPPPPPPP!!!!!!!!!!
Answer:
F' = 800 N
Explanation:
The electrical force between charges is 400 N.
The electrical force between two charges is given by :
[tex]F=k\dfrac{q_1q_2}{r^2}[/tex]
If q₁' = 2q₁, new force becomes,
[tex]F'=k\dfrac{q_1'q_2'}{r^2}\\\\F'=k\dfrac{2q_1\times q_2}{r^2}\\\\F'=2\times F\\\\F'=2\times 400\\\\F'=800\ N[/tex]
So, the new force becomes 800 N.
You push on a box with a force of 300 N directly north. Another person pushes the box with a
force of 600 N directly east. What is the resultant force?
Answer:
[tex]resultant \\ \: F = \sqrt{ {300}^{2} + {600}^{2} } \\ = \sqrt{450000} \\ = 670.82 \: newtons[/tex]
Instead of changing the the frequency you can change the tension to produce the next higher harmonic. What percentage of the tension would produce the next higher harmonic?
Answer:
[tex]\frac{T}{T_o} = ( 1 + \frac{1}{n} )^2[/tex]
Explanation:
This is a string resonance exercise, the wavelengths in a string held at the ends is
λ = 2L₀ / n
where n is an integer
the speed of the wave is
v = λ f
f = v /λ
the speed of the wave is given by the characteristics of the medium (string)
v = [tex]\sqrt{\frac{T}{\mu } }[/tex]
we substitute
f = [tex]\frac{n}{2L_o} \ \sqrt{\frac{T}{\mu } }[/tex]
to obtain the following harmonic we change n → n + 1
f’ = [tex]\frac{n+1}{2L_o} \ \sqrt{\frac{T_o}{\mu } }[/tex]
In this case, it tells us to change the tension to obtain the same frequency.
f ’= \frac{n}{2L_o} \ \sqrt{\frac{T}{\mu } }
how the two frequencies are equal
[tex]\frac{n+1}{2L_o} \sqrt{\frac{T_o}{ \mu } } = \frac{n}{2L_o} \sqrt{\frac{T}{\mu } }[/tex]
(n + 1) [tex]\sqrt{T_o}[/tex] = n [tex]\sqrt{T}[/tex]
[tex]\frac{T}{T_o} = ( \frac{n+1}{n} )^2[/tex]
[tex]\frac{T}{T_o} = ( 1 + \frac{1}{n} )^2[/tex]
this is the relationship of the voltages to obtain the following harmonic,
Jack drops a stone from rest off of the top of a bridge that is 21.0 m above the ground. After the stone falls 7.0 m, Jill throws a second stone straight down. Both rocks hit the water at the exact same time. What was the initial velocity of Jill's rock
Answer:
v = 19 m/s
Explanation:
Since both rocks hit the water at the same time, and we know the total height of the bridge, we can get the time that it takes to the first rock to travel this height, due it is said that it was dropped, using the following kinematic equation:[tex]\Delta h = \frac{1}{2} * g * t^{2} (1)[/tex]
Replacing by the givens (Δh =21 m and g = 9.8 m/s2), and solving for t we get:[tex]t = \sqrt{\frac{2*21m}{9.8m/s2}} = 2.1 s (2)[/tex]
Now we need the time traveled by the first rock when it fell 7 m, that when the second rock was thrown, because the difference between the total time and this one will be the flight time for the second rock.We can use the same equation (1) replacing Δh by 7 m, and solving for t, in (2) as follows:[tex]t = \sqrt{\frac{2*7m}{9.8m/s2}} = 1.2 s (3)[/tex]
So, the total flight time for the second rock it was just the difference between (2) and (3):[tex]t_{2} = t_{tot} - t_{1} = 2.1 s - 1.2 s = 0.9 s (4)[/tex]
Since we know the total distance traveled, and the time of flight, we can use the same kinematic equation than in (1) but now taking into account the initial speed for the second rock, as follows:[tex]\Delta h = v_{o}* t_{2} + \frac{1}{2}* g*t_{2} ^{2} (5)[/tex] Since we know the value of Δh = 21 m and t₂ =0.9s, replacing in (5) and solving for v₀, we get:[tex]v_{o} =\frac{(\Delta h -\frac{1}{2}*g*t^{2})}{t_{2} } = \frac{(21m-(\frac{1}{2}*9.8m/s2*(0.9s)^{2}) ) }{(0.9m)} = 19.0 m/s (6)[/tex]
which was the initial velocity of Jill's rock taking as positive the down ward direction.a force in the opposite direction
of the motion
forces: forces applied to an object in opposite directions that are not equal in size. Unbalanced forces result in a change in motion. friction: the force that opposes the motion or tendency toward motion of two objects that are in contact.
Question
1 point
An object of mass 8.0 kg is falling vertically through the air. The drag force acting on the object is 60N. What is the best estimate of the acceleration of
the object?
Answer:
here's the pdf for it
IB QuestionbankExplanation:
Objects 1 and 2 attract each other with a electrostatic force
of 72.0 units. If the distance separating Objects 1 and 2 is
tripled, then the new electrostatic force will be _units.
Answer:
8 units
Explanation:
From the question given above, the following data were obtained:
Initial force (F₁) = 72 units
Initial distance apart (r₁) = r
Final distance apart (r₂) = tripled = 3r
Final force (F₂) =.?
The final force between the two objects can be obtained by using the following formula:
F₁r₁² = F₂r₂²
72 × r² = F₂ × (3r)²
72r² = F₂ × 9r²
Divide both side by 9r²
F₂ = 72r² / 9r²
F₂ = 8 units
Therefore, the final force between the two objects is 8 units
compare the time period of two pendulums of length 4m and 9m
area= length × length
area = 4m × 9m
ans 36
Two identical particles each of mass M and charge Q are placed a certain distance apart. If they are in equilibrium
under mutual gravitational and electric force then calculate the order of Q/M in SI units.
Answer:
Q / m = 8.61 10⁻¹¹ C / kg
Explanation:
For this exercise we use the gravitational force of attraction
[tex]F_g = G \frac{m_1m_2}{r^2}[/tex]
the electric force
[tex]F_e = k \frac{q1q2}{r^2}[/tex]
indicate that the two forces are equal
G m₁ m₂ / r² = k q₁ q₂ / r²
they also say that the two masses are equal and the two charges are equal
G m² = k Q²
Q / m = [tex]\sqrt{\frac{G}{k} }[/tex]
we calculate
Q / m = [tex]\sqrt{\frac{6.67 \ 10^{-11} }{8.99 \ 10^9} }[/tex]
Q / m = [tex]\sqrt{ 0.7419 \ 10 ^{-20}}[/tex]
Q / m = 0.861 10⁻¹⁰
Q / m = 8.61 10⁻¹¹ C / kg
A Carnot engine with an efficiency of 30% operates with a high-temperature reservoir at 188oC and exhausts 2000 J of heat each cycle. What are (a) the heat input per cycle and (b) the Celcius temperature of the low-temperature reservoir
Answer:
a) The heat input per cycle is 2857.143 joules.
b) The temperature of the low-temperature reservoir is 49.655 °C.
Explanation:
a) The efficiency of the Carnot engine is defined by the following formula:
[tex]\eta_{th} = 1-\frac{T_{L}}{T_{H}} = 1 - \frac{Q_{L}}{Q_{H}}[/tex] (1)
Where:
[tex]T_{L}[/tex] - Low temperature reservoir, in Kelvin.
[tex]T_{H}[/tex] - High temperature reservoir, in Kelvin.
[tex]Q_{L}[/tex] - Heat output, in joules.
[tex]Q_{H}[/tex] - Heat input, in joules.
[tex]\eta_{th }[/tex] - Engine efficiency, no unit.
If we know that [tex]\eta_{th} = 0.3[/tex] and [tex]Q_{L} = 2000\,J[/tex], the heat input of the Carnot engine is:
[tex]\eta_{th} = 1 - \frac{Q_{L}}{Q_{H}}[/tex]
[tex]\frac{Q_{L}}{Q_{H}} = 1 - \eta_{th}[/tex]
[tex]Q_{H} = \frac{Q_{L}}{1-\eta_{th}}[/tex]
[tex]Q_{H} = \frac{2000\,J}{1-0.3}[/tex]
[tex]Q_{H} = 2857.143\,J[/tex]
The heat input per cycle is 2857.143 joules.
b) If we know that [tex]T_{H} = 461.15\,K[/tex] and [tex]\eta_{th} = 0.3[/tex], then the temperature of the low-temperature reservoir:
[tex]\eta_{th} = 1 - \frac{T_{L}}{T_{H}}[/tex]
[tex]\frac{T_{L}}{T_{H}} = 1 - \eta_{th}[/tex]
[tex]T_{L} = T_{H}\cdot (1-\eta_{th})[/tex]
[tex]T_{L} = (461.15\,K)\cdot (1-0.3)[/tex]
[tex]T_{L} = 322.805\,K[/tex]
[tex]T_{L} = 49.655\,^{\circ}C[/tex]
The temperature of the low-temperature reservoir is 49.655 °C.
When using Fleming's Left Hand Rule to determine the direction of the force on an electron moving in a magnetic field, the velocity vector (V) is represented by the direction of your ___________.
thumb
index finger
middle finger
None of the above
Help pleaseeeeee!!! I really need it today :)
Answer:
i'd say 1kg-----5m-----5kg but im not to sure
Explanation:
II. Magnetic fields Magnets and magnetic fields EM 115 We have observed that magnets interact even when they are not in direct contact. In electrostatics we used the idea of an electric field to account for the interaction between charges that were separated from one another. For magnetic interactions, we similarly define a magnetic field. A. Obtain a compass from a tutorial instructor. I. Use the compass to explore the region around a bar magnet. Describe the behavior of the compass needle both near the poles of the magnet and in the region between the poles.
Solution :
We all know that a bar magnet have two poles, the north pole and the south pole. These poles interacts with each other. The ends of the magnets having similar poles will push each other away while the poles with like charges will pull each others towards it.
The compass needle is also a magnet having south polarity as well as north polarity. When the compass needle is close to the bar magnet, it is opposite to the poles or along the poles. The compass needle shows the direction or is pointed towards the north. So when the compass needle is placed near the north pole of the bar magnet, the pointer of the compass needle points towards the north, i.e. it gets deflected because of he like charges. And when it is placed near the south pole of the magnet, it gets attracted towards it and is pointed towards the pole.
Now as we move the compass needle from the poles to the region that is between the poles, the compass needle pointer points towards the north direction every time. It show a deflection always. If we place the magnetic lines, we will see that the magnetic lines will exit from the north poles and enters the south pole of the bar magnet.
A battery has an EMF of 12 Volts, internal resistance of 0.5 Ohms, and its terminal voltage is measured to be 13 Volts. The battery is ________ and has a current of ____ Amps passing through.
Answer:
The battery is charging and has a current of 2Amps passing through.
Explanation:
Given;
EMF of the battery, E = 12 V
internal resistance, r = 0.5 ohms
terminal voltage of the battery, ΔV = 13 volts
When the terminal voltage is greater than the EMF of the battery, the battery is being charged, allowing currents to pass in a reverse direction.
ΔV = E - Ir
ΔV - E = -Ir
13 - 12 = -0.5I
1 = -0.5I
I = 1 / -0.5
I = -2 A
The negative sign indicates the reverse direction of the current.
Therefore, the battery is charging and has a current of 2Amps passing through.
Consider a solid sphere and a solid disk with the same radius and the same mass. Explain why the solid disk has a greater moment of inertia than the solid sphere, even though it has the same overall mass and radius.
Answer:
Explanation:
In a Solid sphere; the moment of inertia around its geometrical axis can be expressed by using the formula:
[tex]\mathtt{I_s = \dfrac{2}{5} M_s R^2_s}[/tex]
For the solid disk; the moment of inertia around the central axis is:
[tex]\mathtt{I_D= \dfrac{1}{2}M_DR_D^2}[/tex]
Suppose [tex]M_D = M_S[/tex]; then we can say both to be equal to M
As well as [tex]R_D = R_S[/tex]; then that too can be equal to R
Now;
[tex]\mathtt{I_s = \dfrac{2}{5} M R^2} --- (1)[/tex]
[tex]\mathtt{I_D= \dfrac{1}{2}MR^2}---(2)[/tex]
Multiplying equation (1) by 2, followed by dividing it by 2; we have:
[tex]\mathtt{I_s= \dfrac{2}{5}MR^2} \times \dfrac{2}{2}[/tex]
[tex]I_s = \dfrac{4}{5} \times \dfrac{1}{2}MR^2 \\ \\ I_s = \dfrac{4}{5}\times I_D \\ \\ I_s > I_D[/tex]
That light has a dual nature is referring to light: having energy and momentum. having high- or low-energy photons. acting as waves and particles. undergoing pair production.
Answer:
Option C, acting as waves and particles
Explanation:
Light has dual nature because it acts both as a wave and particle. It has high energy particle i.e photons and it also behave as an electromagnetic wave. This property of light is studied under the quantum mechanics. Einstein also proved that light is a stream of photons possessing both electrical and magnetic properties.
Hence, option C is correct
Explain what resonance is and give one example of a destructive outcome of resonance. Also give one example of a non-destructive outcome of resonance. Use details to support your answer.
Answer:
resonance is when a body is made to vibrate with the frequency of another body without touching it.
Explanation:
example of destructive: soldiers matching on a bridge unanimously can make the bridge collapse.
Answer:hi
i like ears
and lemon
and poetry
Explanation:
Explain how you would have to change the experimental set-up (electric field strength, drift chamber length, and/or buf
Answer:
Please find the complete question in the attached file.
Explanation:
In this statement, the weak electromagnetic field that has been used when with the range of resistance to start measuring the mobility of even an ion with both the counter-charge utilization as well as the DC is the potential for using so that we can always obtain a desired electrical field and modify the drift chamber lengthy and gas pressures buffered.
Will mark Brainliest!
All elements on the periodic table are neutral because they have the same number of electrons as what other particle?
A. Protons
B. Photons
C. Atomic mass
D. Neutrons
what is the light synthesis ?
Answer:
Photosynthesis, the process by which green plants and certain other organisms transform light energy into chemical energy. ... During photosynthesis in green plants, light energy is captured and used to convert water, carbon dioxide, and minerals into oxygen and energy-rich organic compounds.
Explanation:
thank me later
Last stage of a medium mass star
White Dwarf Stage
This ring is called a planetary nebula. when the last of the helium atoms in the core are fused into carbon atoms, the medium size star begins to die. Gravity causes the last of the star's matter to collapse inward and compact. This is the white dwarf stage.The number of proton is equal to the number of _____ in an atom
Answer:
THE NUMBER OF PROTON IS EQUAL TO THE NUMBER OF ATOMIC NUMBER(Z) IN AN ATOM
Explanation:
PLZ MARK ME BRAINLIEST
Answer:
Explanation:
The number of proton is equal to the number of electron in an atom.
The solid metallic sphere is replaced with a hollow insulating shell of radius a. A charge Q is spread uniformly over the hollow spherical shell. What is the electric field strength inside the hollow shell at r
Answer:
Zero
Explanation:
It is given that the charge is uniformly spread at the surface of hollow spherical shells.
There is no charge with in the hollo shell. hence, with zero charge the electric field intensity is also zero.
Thus,
Magnitude of the electric field strength inside the hollow shell at r is zero
Describe the Compton Effect
one of the lady spartans was falling to the ground after dunking the winning basket. At the end of her fall, she was falling 4 m/s. If she was 60kg, how much potential energy did she have at the top of her jump?
Answer:
15 is the correct answer I.t.
Question 5 of 10
Which of the following best describes a property of water?
O A. Dissolving very few substances
B. Remaining liquid over a narrow range of temperatures
C. Having low surface tension
D. Requiring a lot of energy to change temperature
Answer:
B
Explanation:
water do not have a solid shape and that makes it take to shape of a container etc
Answer:
D. Requiring a lot of energy to change temperature
Explanation:
because im right n ur wrong
What is the essential concept of the photon theory of light?
Answer:
Cause it gives us internet